Test yourself! - Calculating square roots

[@flyingspirit3549]

Very useful and well presented review of the rules of arithmetic in this area! Thanks for posting this.

[@lawrence31415]

I wanted to share with fellow viewers an interesting story involving the square root of 2. It is said that the person who proved that the square root of 2 is an irrational number ended up getting thrown off a boat (the Pythagoreans believed that all numbers should be rational). So, the main lesson from this story is: NEVER do math while you're on a boat filled with irrational people.

[@davepowder4020]

Came for the math by lovely Susanne, left with a new Dad Joke!

[@wernerschwarze910]

nice, but Hippasos of Metapont, who is considered the discoverer of irrational numbers, was a Pythagorean ; )

[@lawrence31415]

@@davepowder4020 there you go: you got to learn two new fun things from a KZbin video!

[@lawrence31415]

@@wernerschwarze910 that is true! Hippasus's discovery was considered a serious heresy by fellow Pythagoreans since it contradicted their accepted view that everything in the world/universe is based entirely on whole numbers and their ratios. This is what happens when a group of scholars refuses to eat beans, but that is a story for another time!

[@poivre22]

From metal to math. Some people live interesting lives. You are talented at both! 👍❤

[@Rick-tt6yq]

I wish I had you as my math teacher…I would have even stayed late for extra homework.

[@johnsnyder7021]

I appreciate your step-wise approach to the solution. Nothing left out. It is so helpful. Thanks, Suzanne.

[@neilbeacher17]

You’re really helping me keep up with my daughters’ homework - thank you!

[@decipheringenglishleaveitt3812]

Susanne's explanation is correct and clear. But in a real quiz you don't have much time. Do the math in your head just by looking at the question. As to #4: 8=2^3, so the square root of 8 is 2*√2. √2*√2 is 2. It's 3*5*2*2=60 BTW Remembering integer powers of single-digit prime numbers can be very useful; 2,4,8,16,32... 3,9,27,81... 5,25,125,625... 7,49,343...etc

[@lawrence31415]

The Joy of Square Roots: this should be a fun video! Have a nice Saturday and weekend, Susanne!

[@RyanLewis-Johnson-wq6xs]

2Sqrt[7]+3Sqrt[7]=5Sqrt[7] Sqrt[5]+2Sqrt[3]+8Sqrt[5]-7Sqrt[3]=9Sqrt[5]-5Sqrt[3] Sqrt[2]*Sqrt[18]=6 3Sqrt[2]*5Sqrt[8]=60 It’s in my head.

[@jerryeldridge1690]

Thanks for the puzzle. I tried to solve this with python3's sympy library and algebraic numbers writing x**2 - a for sqrt(a) and reducing all problems to a set of these. For two numbers like x**2 - a and y**2 - b I used two of them. Then I used remainder = sp.div(numerator,denominator)[1] so that (sqrt(2)-3)**4 is sp.div((x-3)**4,x**2-2)[1] mod-ing by the algebraic number polynomials. This worked for most problems you presented. A few had more than one number which I tried to do: sp.div(sp.div(sp.div(expression,p1)[1],p2)[1],p1) which worked on the one that calculated to 6 or 60 or whatever. The fractions did not involve polynomial division, sp.div, but merely fractions in terms of x,y. I only needed two variables x,y. But of course this is more complicated that what you presented but it was an alternate way to calculate using sympy. Its hard to calculate ZZ[x,y]/I for ideal I=(p1,p2).

[@tarun1982]

New viewer here. I always love the way you start of the video wishing your viewers with the sweetest smile and voice. Thanks and keep going.

[@MathQueenSusanne]

Aaaaw, thank you so much for your kind words! Have a nice weekend!

[@zipponvr7043]

you have unexpectedly pleasant voice, usually people from Germany or Austria speak like Arnold Schwarzenegger

[@clivemitchell3229]

This is basic stuff - some of which I didn't know! Thank you.

[@RyanLewis-Johnson-wq6xs]

Sqrt[8]÷Sqrt[2]=2 (15Sqrt[12])/(6Sqrt[27])=1.6 recurring=5/3=1 2/3 final answer

[@Maverick0813]

🎉 Hello Susanne, it's amazing that KZbin recommend this video to me and I feel like knowing this person on the video cover. Congratulations on building another channel and this math tutorial idea is absolutely awesome!

[@richardl6751]

Another way for #6: For the top, factor out a 4 giving 30√3. For the bottom, factor out a 9 giving 18√3. The √3 cancel giving 30/18 = 1 and 2/3. I was always taught to reduce fractions.

[@frankverdonck3416]

Wauw Suzanne, you make algebra so easy to (re)learn. Greetings from Belgium Keep up the good work

[@DemonXT]

Very well presented! I found myself to solve these after a long time absence from math xD very good brush up on some calculation principles.

[@merkulus-n5v]

Happy Saturday! Love your videos.

[@jbmbryant]

Took maybe 10 sec in my head. Fun stuff!

[@laszloszabo2366]

We have 2 equations please find the value of c a^2 + b^2 = c^2 and E=m*c^2

[@utedalheimer1742]

Dankeschön ❤❤

[@fouadsharif2327]

Su.....you are a legend.....keep up the good work Tiger 🐅....👍👍💯💯

[@israelgonzalez677]

Love it ❤

[@juergenilse3259]

2*sqrt(7)+3*sqrt(7)=(2+3)*sqrt(7)=5*sqrt(7) sqrt(5)+2*sqrt(3)+8*sqrt(5)-7*sqrt(3)=1*sqrt(5)+8*sqrt(5)+2*sqrt(3)+7*sqrt(3)= (8+1)*sqrt(5)+(2-7)*sqrt(3)=9*sqrt(5)+(-5)*sqrt(3)=9*sqrt(5)-5*sqrt(3) sqrt(2)*sqrt(18)?sqrt(2*18)=sqrt836)=6 3*sqrt(2)*5*sqrt(8)=3*5*sqrt(2)*sqrt(8)=15*sqrt(16)=15*4=60 sqrt(8)+sqrt(2)=sqrt(4*2)+sqrt/2)=sqrt(4)*sqrt(2)+sqrt(2)=2*dqrt(2)+sqrt(2)=3*sqrt(2) (15*sqrt(12))/(6*sqrt(27))=(15*sqrt(4*3))/(6*sqrt(9*3))= (15*sqrt(5)*sqrt(3))/(6*sqrt(9)*sqrt(3))=(15*2*sqrt(3))/(6*3*sqrt(3))=30/18=5/3=1 2/3

[@SoundFriendly]

Can we move to solving the Chebyshev function?

[@gregjennings9442]

X^n . Y^n = (XY)^n. Basic product rule. Should learn in Algebra I, if not in grade school.

[@Birol731]

My way of solution ▶ 1) 2√7 + 3√7 = 5√7 2) √5+ 2√3 + 8√5 - 7√3 = 9√5 -5√3 3) √2* √18 = √36 = √6² = 6 4) 3√2* 5√8 = 15√16 = 15√4² = 15*4 = 60 5) √8 : √2 = √4*2 : √2 = 2√2 : √2 = 2 6) 15√12 / 6√27 = 15√4*3 / 6√9*3 = 15√2²*3 / 6√3²*3 = 30√3 / 18√3 = 30/18 = 5/3

[@PreservationEnthusiast]

60.... can do it in my head so simple.

[@munireid77]

Wünsche dir viel Erfolg auf dem englischen Kanal! :)

[@djelalhassan7631]

Beautiful

[@m.h.6470]

Solutions: (1) 2√7 + 3√7 = 5√7 (2) √5 + 2√3 + 8√5 - 7√3 = 9√5 - 5√3 (3) √2 * √18 = √2 * √(2 * 9) = √2 * √2 * √9 = 2 * 3 = 6 (4) 3√2 * 5√8 = 3 * 5 * √2 * √8 = 15 * √(2 * 8) = 15 * √16 = 15 * 4 = 60 (5) √8 / √2 = √(8/2) = √4 (6) 15√12 / (6√27) = 5√(4 * 3) / (2√(9 * 3)) = 5√4√3 / (2√9√3) = 5 * 2 / (2 * 3) = 5/3

[@antoniopereira8571]

Olá Suzanne.Maravilhosa.Voz e didática hipnotizante.Super recomendo🎉 9:08 🎉 9:08 9:08 9:08 🎉🎉🎉🎉

[@doctorrusty]

For problem #4, isn’t the answer either 60 or -60 since the square root of 16 is 4 or -4? Or am I overlooking something?

[@decipheringenglishleaveitt3812]

The opposite is not necessarily true. The square root of a number greater than or equal to 0 is always greater than or equal to 0.

[@veijolalli326]

sqrt(2)*sqrt(4)*sqrt(2)=4

[@JackBlack-ii1ip]

First date questions?

[@MathQueenSusanne]

Try it out and tell me how it went 😅

[@yassertariqvideo]

Neat.

[@zbigniewdubrawa7176]

30 pierwiastkow z 2

[@rodeoron451]

I love your logic and your math skills, but when you said you were looking for the solution I expected an answer, not another problem.

[@morphilou]

15 x 4=60 5 sec pas besoin de faire tout cela

[@DominickAngelo]

You show us how to do different operations with radicals, but you don’t show us how to calculate radicals.

[@ron827]

Great math lesson but the intro is VERT gay.