The Composition of Injective(one-to-one) Functions is Injective Proof

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Proof that the composition of injective(one-to-one) functions is also injective(one-to-one)

[@sairajdas6692]

Very crisp. Very helpful.

[@nawareagan7720]

short and clear....thumbs up

[@serinacat4781]

very clear and easy thank you life saver

[@TheMathSorcerer]

glad it helped!!

[@livepoetry6230]

Thank you Sir

[@mephisto745]

Hello thanks for the vid. The counter-statement is it true ? And how to prove it ?

[@carloverona]

hello! quick question if there is only one of them that is injective, will that make the composition injective too?

[@TheMathSorcerer]

Not always no

[@carloverona]

is there a way we can make a formal proof for this? also thank you so much for the reply!

[@TheMathSorcerer]

Ya you need to make up some examples where it doesn't work, so find one function that is injective, one that is not, and just make sure the composition is not. Actually just take identify function f(x)= x which is injective and any non injective function, then the composition is not injective 👍

[@MrPlvvvk]

Wouldn't this be a proof by converse?

[@TheMathSorcerer]

[@tornikeonoprishvili6361]

კარგი ვიდეოა. (just google translate it)

[@blackhole1222]

გეთანხმები