The Density of states in a Quantum well Structure

[@Abrogator91]

These lectures are getting me through my semiconductor devices class. Thank you so much for posting these.

[@russellazure9316]

Probably the clearest explanation that I’ve seen so far on this topic. Thanks a lot!

[@takhellambamkritibala3840]

Sir, at 19:00, when we find the density of states in the k-space for a quantum well, shouldn't we divide it by LxLy instead of LxLyLz, as we are referring to area in real space here, though in bulk, we refer to the volume in real space

[@gulwareena]

yes yes

[@neilz7242]

Professor is correct. The number of states in bulk dk area is still the same as the calculation by area. Lz is required to calculate the density of states per volume

[@laks318]

Heavenly❤❤❤!!!thank you immensely dear Sir...

[@tanbhirhasan]

Great informative video. Thank you.

[@tahamohssein7726]

thank you so much, is a wonderful lecture. I need the reference for this lecture please!

[@RAJARJUNRA]

Quality of education is found in iit s of india

[@curiousbit9228]

Why do we include only the area of the first quadrant??

[@brittokhan5278]

I want to know about the students. Are they btech students or Mtech?

[@mouleeswarang.s1023]

a great lecture BTW why everyone are in the same costume in all these lectures

[@renuramansahu]

For the students part, I guess it is the same video clip played everytime.

[@emircanbaltac5005]

thanks amazing informations

[@ghaziandar3689]

Fermi Dirac distribution by p.R shnoy

[@mooow522]

very clearly! THANKS!

[@marcos1289]

10:40

[@waqarali9166]

much appreciated.

[@subhammahapatra5089]

Thank you sir

[@hudamh7479]

Why the area is 2*pi k dk it is an area of circle pi sqr(k)??

[@sunmathi2290]

We need the area of 'dk' thickness ring. so the circumference of 'k' radius ring=2 pi k, then multiply the thickness'dk', we get 2 pi k dk. Another method, the area of the outer ring minus(-) the area of an inner ring. = pi (k+dk)^2 - 2 pi k^2 = pi (k^2+2kdk+dk^2-k^2) = pi 2kdk+dk^2 =2 pi kdk . (here dk^2 is negligibly small)

[@t_a7923]

@@sunmathi2290 ooh dea you took so much effort in replying❤❤❤..I didn't had this doubt but u a reply is gonna make it clear for ones who have confusion...

[@陳敏號]

amazing

[@gulwareena]

Lz should not appear in the equation

[@victorvas3864]

Thanks

[@Thehealthmatters23]

What is Ec?

[@t_a7923]

Ec is the energy at lowest point in conduction band...Ev is the energy at highest point in valence band...Ec and Ev are respectively called CB and VB edges..👍happy studying😉😁 edit: thus all energy values in CB will be greater than Ec and that in VB will be lesser than Ev.. The gap between these band given by Ec -Ev gives the band gap.

[@devikatg4352]

Thnx sir

[@new-jj5il]

❤

[@nandanvaidya2266]

Did anybody get the answer in order of 25? :D

[@21_brajeshmishra28]

Yeah

[@lalitaaggarwal62]

@@21_brajeshmishra28 actually in the order of 23 and that too will be for (per m^3 )but he has stated the answer in (per cm^3). That's why 10^18 fits.