The Double Squeeze in Bridge - Making Squeeze Plays Simple with Adam Parrish - Lesson 3

Learn bridge online with Adam Parrish: learnbridgeonline.com/adam-pa...
What if we have potential winners in three suits? The double squeeze!
We’ve seen how a squeeze works with two potential winners, so how do things change when we have three potential winners? It’s still the same three basic ingredients.
Potential winners - we have 3 potential winners here not just the 2.
One loser - we still need only one trick left that we might lose.
Transportation - making sure we can get to our potential winner once a defender is forced to make it a winner.
Continue learning about double squeezes in bridge here: learnbridgeonline.com/lesson/...
♠♥♦♣♠♥♦♣♠♥♦♣
#bridge #contractbridge #learnbridgeonline
Learn how to play bridge online at learnbridgeonline.com/

[@murthyayyagari2189]

Great explanation Adam..

[@martinepstein3332]

Well done, very helpful

[@zihanqiao2850]

I have one question, how can you know the north should discard heart when you see west discards a club? I guess it is because the 1NT bidding. But if there is no other information, how can you make sure it will a case that west guards spade and east guards heart and then how will you make the decision to discard which card from dummy's hand?

[@molough]

For this Double Squeeze to work West must have the HQ and East must have the S8. So if that's the only way that you can make your contract, then you must play for that to be the case.

[@carloingravalloba]

Since only this ending is possible, it is necessary to correctly read the cards played in order to establish the right orientation of the unilateral ones in the major suits (since abstractly the squeeze in question works even if the positions are reversed). Given the bidding of 1NT ( and then X) and since in the first rounds 14 points are shown playing on the honors of split Clubs the remaining cards must be the J of Clubs with the Queen of Hearts in the West.

[@belyi3]

East bid 2♠ in response to West's double, so presumably has at least 4 spades. By the time you play the squeeze card (♦7) you've seen three of them, so you can place East with ♠8. If instead East held ♠A43 ♥Q542, surely they would have bid 2♥.

[@armantookmanian1938]

At 4:50 with four cards remaining, you know EW have 8 cards, one of which is the singleton S8 and another is the singleton HQ. They don't have any Diamonds (trump) so their remaining 6 cards are all clubs. West must have the HQ or he wouldn't have tried taking the HK after seeing Dummy's length and East's discouraging H2 on the HA opening lead. If the S8 is also in the West hand, he has 2 Clubs and East has 4, so the only way to make all four tricks is if West's club holding is the CQJ doubleton. A very tricky West might try dropping the CJ on the D7, hoping South has the CT and will try to play CK-CA thinking he can drop the Q.