That was fantastic. I hope this channel is still active.
@sadececansu9Ай бұрын
Thank you for those high quality videos.. It has been 6 years now and it is appreciable helpful. Greetings from Turkey
@Ajax26965 жыл бұрын
Thank you so much for everything you're doing! Keep up the good work. I wish I could help translating but I'm busy with college XD
@FlippingPhysics5 жыл бұрын
You are very welcome! Perhaps you can do some translating after college?
@WorkDayPegasus5 жыл бұрын
One thing I am not understanding: why is 2,0*10^20 N the force the moon is pulling on the earth? Isn't it the earth pulling on the moon with that force, and we have to use another constant for G to find moon's pulling power on earth? Or is this a matter of principle, where both pull at eachother at equal force? Can I please get a clearup on this? Edit: Well, i found that I do not fully comprehend yet what UNIVERSAL gravitational constant is, except from being universal.
@carultch3 жыл бұрын
Like forces in general per Newton's third law, gravity is a two way street. Earth pulls on the moon, and the moon pulls on Earth with an equal and opposite force. Both bodies experience the mirror image of the force they apply to the other body. Why then does the moon orbit the Earth and not the other way around? It is because the Earth has a lot more inertia... about 80 times as much inertia. For every meter that the moon moves for its orbit around the Earth, Earth should only move 1.25 centimeters. Indeed the Earth does move, as both worlds orbit a common center of mass, called a barycenter. The barycenter is located at about 75% of Earth's radius from its center. The moon orbits this point, and the Earth wobbles around this point. This behavior is a lot more pronounced in systems where the bodies are closer in mass, such as binary star systems, and the Pluto-Charon system, where the barycenter is external to both bodies.
@carultch3 жыл бұрын
The universal constant of gravitation is a constant of proportionality to make the multiplication and division among the masses and radial distance consistent with the experimental results. You can read about the Cavendish experiment, if you are curious to know how this constant was measured.
@giovannirojas39527 жыл бұрын
Starting at 3:55 is the stuff you're saying related to Kepler's Laws?
@FlippingPhysics7 жыл бұрын
It is related to the concept of satellites in orbit which is what Kepler's Laws are about. It is probably most related to Kepler's 3rd law.
@ptyptypty32 жыл бұрын
so, how do we figure the NEW time of arrival of the moon onto the earth if the Acceleration DOES Change along the Path to earth? In a sense this alot like finding the WORK done on the Moon to pull it toward the Earth.. a changing Force.. perhaps Integration?
@nohelyBELLY4682 жыл бұрын
The ending was little dark ;-; ... but overall great content!!! :D
@Jake1234-p6t2 жыл бұрын
How did you get 6.67*10^-11?
@karhukivi2 жыл бұрын
Look up the Cavendish experiment.
@OnePieceFan47652 жыл бұрын
I know this is probably late but it’s just a constant using the symbol G
@Santiago-wl3xv4 жыл бұрын
Thanks for the video. I require simplification.
@FlippingPhysics4 жыл бұрын
Glad to help.
@anilkumarsharma89012 жыл бұрын
Itni force hain to uski energy ka use kyon nahin kartey hain????
@aaditiwar1 Жыл бұрын
kyuki hum ko aikh chees bana na hoga jo moon se aur bhara hai energy collection kiliye
@XxPlayMakerxX1317 жыл бұрын
Cool
@fredd2985 жыл бұрын
lmao Raivat
@yourfaveshay2 ай бұрын
I’m literally losing my mind because I can’t plug this into my calculator (I have the ti-30xa)
@FlippingPhysics2 ай бұрын
I show how to plug this into a calculator in this video: kzbin.info/www/bejne/ZmiToYCNeZVkmacsi=_xLELWVmP-9IDcRu&t=146