I find the little math problems very interesting. However, you talk waaaaaaayyyyyyyyyy too much. Every time I try to watch one of your videos your constant repeating of every detail begins to drive me crazy by the 2 minute mark.
@terry_willis11 ай бұрын
John needs to label each problem with a difficulty level (saying "Many will get this wrong" does not help us). Joseph, in your case, you are learning and getting better, so the easier problems get boring to you. So with a difficulty level label, you could skip the easy peasy ones and do the harder ones.
@utha266511 ай бұрын
The videos are aimed at someone that has no experience with this type problem. You can always skip parts of the video you don't like, like I do.
@C-man55310 ай бұрын
Exactly.
@saeedzafar704111 ай бұрын
Overexplained. This is a short video on KZbin, not a 45 min class.
@harrymatabal84488 ай бұрын
I totally agree
@TravisMcGee1518 ай бұрын
@@harrymatabal8448Maybe you guys don’t realize that the longer the viewing time the more they get paid. Those who put videos out purposely drag them out for the $.
@mpicard8 ай бұрын
Depends on who you are. Sounds like you guys dont need any explqnation. This longer version will truly help a lot of people struggling to truly understand the fundamentals.
@JuneT487 ай бұрын
Totally agree. All videos have very interesting content but presented laboriously slowly. I am constantly scrolling forward to get to the point.
@michellepopkov9409 ай бұрын
As Monty Python would say: GET ON WITH IT!
@brucecorbettn9bh3988 ай бұрын
I’m 73 years old trying to refresh relearn this stuff. I remember my calculus teacher saying throw away your notebook, but I did. I see some of this stuff and say to myself, at one time I knew this and it was easy. But the fact is, if you no longer use the math you will lose it. So, don’t ever stop.
@MichaelGWandrey10 ай бұрын
Just in my head this reduced to Sqrt (8 /3) and then to 2 * Sqrt(2/3) Which I think is the simplest process and simplest answer. By definition 2/3 is a rational number and taking SQRT of it is valid
@rogergriffiths33458 ай бұрын
Yes, it’s as simple as that 👍. A waste of just over 17 min of anyone’s time
@iangraham87111 ай бұрын
I got an A in maths at High School (UK A-level, just prior to University), but i don't think i ever knew that the product of the square roots of two numbers is equal to the square root of the product of those two numbers. It was 40 years ago, but thanks for this.
@twentyrothmans730810 ай бұрын
Similar, but first year Maths at Uni, but I suspect that it just disappears through inactivity. Half the fun is reading other peoples' solutions, and their reasoning.
@KenFullman9 ай бұрын
If you did A level maths you definitely did know that rule. If you have many values to multiply together, it doesn't matter which order you multiply them in, the result will be the same. So call your first number (AxA), call your second number (BxB) So The product of those two numbers could be (AxA)(BxB) But if you take the product of their square roots, you'd get (AxB) Which is the square root of (AxB)(AxB) which is (AxB) squared But like I say, it doesn't matter what order you do the multiplication so (AxA)(BxB) =(AxB)(AxB) = (AxB) squared So I'm pretty sure, at one time, you must have known this.
@Steve-pu4zx11 ай бұрын
1.63299.....
@davidlockwood991511 ай бұрын
Far too long. Drives you nuts.
@clipperledgard52410 ай бұрын
After all this, do you know the answer? Or you just know another way to represent the same expression?
@peacemaker112211 ай бұрын
Well i got 1.63 and checked with my calculator and it thinks the same, how are we both wrong?
@56edb10 ай бұрын
I did sq rt of 8 divided by sq rt 3 and got 1.63 on my calculator. When i pressed the equal button gave me 2/3 sq rt 6.
@dustmaker10008 ай бұрын
This is why I always struggled on tests…. I calculated (sq rt of 16 x sq rt of 1.5)/3….. or (4*sq rt of 1.5)/3……. This calculates to the same answer of approx 1.63 but this instructor says if the answer isn’t (2* sq rt 6)/3 then the answer is wrong even though the end calculated number is the same
@panlomito11 ай бұрын
I turned SQR(8) into 2SQR(2). Then multiplied by SQR(3) is 2 x SQR(2x3) = 2SQR(6)... and divided by 3 gives 2SQR(6)/3 OR (2/3)SQR(6)
@baseline338 ай бұрын
I’m pushing 90. My working life was spent in the telecommunications business. The only time I needed to work out the square root of anything was to pass the maths exams as part of my technical studies.
@faiththrower79517 ай бұрын
😂😂😂😂😂
@danieldennis983111 ай бұрын
2√6/3
@sirechoe123610 ай бұрын
I worked it out on pen and paper the way I did it 55 years ago. I came up with 1.633. You know 3x3=9, too much. 2x2=4, too much. Keep breaking both numbers down from there. 2.8x2.8=7.84, too small. 1.7x1.7=2.89, too small. next is 2 place decimals followed by 3 place decimals.
@stuartyoung572811 ай бұрын
If a transcendental number such as pi or e in the denominator, then it's stuck there.
@alext882811 ай бұрын
Not really. You can always multiply by the dirigible of the recipient.
@devonwilson577611 ай бұрын
Greetings. The answer is 2/3 times the square root of 6. The square root of 6 divided by the square root of 3 is the square root of 8 times the square root of 3 all divided by the square root of 3 times the square root of 3. That is (8^1/2×3^1/2)÷ 3^1/2×3^1/2= 24^1/2÷ (3^(1/2+1/2))=2(6^1/2)÷3^1= 2/3(6^1/2)=1.6, rounded. I guess that one would go through all this work to show an understanding of working with radicals. Why else, when you can simply divide 8^1/2 by 3^1/2 to get 1.6?
@stuartyoung572811 ай бұрын
Two thirds the square root of six.
@jimyoung-gy9lx9 ай бұрын
You take too long to get to the poiht 😩
@johnwsimpson31539 ай бұрын
(2/3)x(sqrt(6) ) and 2x(sqrt(2/3)) are both correct answers. They are equal to each other. The instructor got the first one, and the second is the result if the instructor's ban on square roots in the denominator is ignored. There is nothing wrong with square roots in the denominator. Irrational numbers and rational numbers are both real numbers. There is nothing wrong with dividing by an irrational number. The result will not be a rational number, but it will be a real number.
@matsonnerby11 ай бұрын
To be honest, I don’t understand why one of these is a question, and the other is an answer.
@aryusure194311 ай бұрын
@matsonnerby Indeed! But he never tells all the story. So we have to figure out the logic by ourselves sometimes. See my comment if you will. I try to fill the void.
@gavindeane367011 ай бұрын
Exactly.
@stevereade48586 ай бұрын
Square both sides, divide, take square root. (8exp0.5/3exp0.5)exp2=xexp2. x=(8/3)exp0.5 Cuts several (confusing) steps!
@albertmoore44458 ай бұрын
Dad, can you help me with this birdhouse I'm building, you're a math professor. Sure, Son, what is the problem? I'm supposed to make the short side the square root of 8 divided by the square root of 3 inches long, and I don't know how long that is. Oh, that's easy, it's 2 times the square root of 6 over 3! Thanks, Dad!
@PYTHAGORAS1018 ай бұрын
This seems a bit convoluted and while the result is correct, it is not quite satisfactory to me. The result of the division of two square roots is always the square root of the division of the integers. So, the answer is simply sqrt (8/3) = sqrt (2.666...) = 1.633
@TheMathManProfundities6 ай бұрын
What's with all the rubbish about turning an irrational problem into a rational one? That would be alchemy and is not possible. And guess what, you failed, your answer is still irrational. Probably your worst statement was that you can't divide by √3, yes you can, even with your unnecessary rational restriction (√3/√3 is rational). All you've done here is to simplify an expression, rationality has nothing to do with it.
@AndrewJ-u9o6 ай бұрын
Would be much simpler to say the way to get rid of the irrational denominator is to multiply the numerator and denominator by the denominator. Then, using the rules of exponents, the denominator becomes 3 and the numerator becomes the sq rt of the products, ie. sq rt of numerator and denominator, which is 24. Then one can look for factors of 24, one of which is a perfect square (4x6), 4 being a perfect square. etc.
@thomasmaughan47989 ай бұрын
Interesting. Start by factoring the numerator sqrt(2)*sqrt(4) over sqrt(3). Thats 2 * sqrt(2) over sqrt(3). Multiply top and bottom by sqrt(3) so you get 2 * sqrt(6) over 3. Some of these steps are duplicated in a similar problem.
@danluzurriaga60356 ай бұрын
Not creators' fault but please give feedback to stop these Filipino adds with cross-eyed children sipping straws etc... It gets attention I suppose but it is really child abuse as the child will later see how his/her cross-eyed appearance was used to make money. Stop the child abuse in Filipino ads.
@MerryDrums7 ай бұрын
Oops, in my haste forgot to deal with √24 which = √4 x √6 = 2 √6 therefore correct answer is 2 √6 all divided by 3
@rogergriffiths33458 ай бұрын
Glad this guy didn’t teach in my department. Answer is achievable by mental arithmetic for goodness sake!
@smokert55559 ай бұрын
Cool, but my calculator says 1.63. I though we were shooting for actual numbers and not another equation.
@richardjohnston30317 ай бұрын
All of you complaining about the length of the class should get extra homework! LOL
@davidg428811 ай бұрын
OK, TLDR is rationalize the denominator and simplify. Thanks for reminding me though!
@johnbell11846 ай бұрын
I always wonder what is the practical use of a specific math problem, Eg: where would we use this radical square root problem ?
@leightonscycles99157 ай бұрын
So what's the point? After all that work where does it get you? To me you still have a number that doesn't mean anything!
@larrydickenson89228 ай бұрын
The answer is the square root of 2.6666666 ad infinitum. Get out you calculator or log tables.
@jeromesassani953711 ай бұрын
You should memoprize the Sqrt of 2,3, and 8. sqrt 0f 2 = 1.414. sqrt of 8 is twice the sqrt of 2 or 2.828. sqrt 0f 3 = 1.732.
@williamdelmar396410 ай бұрын
As an engineer We can get the answer for all practical purposes. So, what you said, to however significant figures you need.
@jeromesassani953710 ай бұрын
@@williamdelmar3964 For classroom situations. I am from pre-calculator times and wasn't a math or physics major.
@williamdelmar396410 ай бұрын
Similar here, precalculator educated. Memorizing a few key results and numbers, makes it easier to check your slide rule answer.@@jeromesassani9537
@apopisso63027 ай бұрын
The exam supervisor,” times up” .But I haven t finished the first question yet!
@brocksprogramming6 ай бұрын
Radicals have never been my strong point as I'm quite mild.😅
@larryhomann8 ай бұрын
Long winded , drifts off the point . and please don't underline stuff , not a 6 yr old kid ; why not point to every letter with your finger
@mathmandrsam9 ай бұрын
The answer is 1.63... type sqrt(8) / sqrt (3) = and you're there.
@jeffreyschmiedeck42546 ай бұрын
This guy just rambles on . The guy on Science and Math is a better teacher!
@Peterseng248 ай бұрын
Start at 9:20. Way too long a video for such a simple problem. 🇦🇺
@stevewthespider7 ай бұрын
I hate irrational numbers as they are impossible to measure with tape measures or yard/meter sticks.
@johnplong36449 ай бұрын
Well you can’t have a radical in the denominator That is a clue
@syedmdabid71919 ай бұрын
Eheu!!! Id est 4√6/3vel √(8/3) responsimus.
@christopherellis26637 ай бұрын
¾ thre quarters. Nobody came fourth
@kimchee941129 ай бұрын
Square root of 3 is allowed everywhere.
@MartinHermans-dw3is10 ай бұрын
This is way too long an answer to this problem.
@tpobrienjr8 ай бұрын
2x1.4142/1.7321 no radicals.
@batavuskoga11 ай бұрын
Why isn't it allowed to have a square root in de denominator ? I know perfectly how to get rid of the square root in the denominator
@thomasmaughan47989 ай бұрын
Many of these problem examples are part of a much larger formula or equation. Simplifying as you go along *usually* helps in the long run. Very complex formulas can gradually build up errors if you do everything numerically (calculator, decimal approximations).
@michaelkeffer5048 ай бұрын
(2√6)/3 is the answer.
@MerryDrums7 ай бұрын
Answer equals √24/3
@C-man55310 ай бұрын
Mr. Roberts does irrationals.
@albertmoore44458 ай бұрын
1.633 or roughly .015 more than the Golden Ratio, close to the same as 5/3, (Fibonacci #5 over #4)
@krisswegemer116310 ай бұрын
No irrational numbers in the denominator is a weird preference, not a rule. It has no mathematical significance and is not practiced with any consistency. The same people who would not put the square root of 3 in the denominator would put pi in the denominator.
@innocentodenigbo72846 ай бұрын
That's interesting.
@tomtke735111 ай бұрын
(+/-2×sqrt(6))/3 like proper manners at the dinner table you're not supposed to have a radical (sqrt sign) in the denominator of a fraction. So multiply numerator and denominator by [sqrt(3)]. The backbone of algebra is do the same to both parts: (-1-) equation: same on left and right side. (-2-) fraction: same on numerator and denominator.
@gavindeane367011 ай бұрын
What's the reason for disallowing an irrational number in the denominator? Obviously there's no problem with that mathematically. Is it just a requirement of the syllabus that the kids you're aiming this at are taught?
@G0LGS10 ай бұрын
I don't see how the answer with a Square root is any better than the question you started with - I pretty sure if I had been asked the question at school in the 70's I would have been expected to write and answer to a few decimal places and not just as another expression.
@harrymatabal84488 ай бұрын
Just loves his voice
@aryusure194311 ай бұрын
Just to be clear: radical 100 divided by radical 4 = 5. right? In other words, it's only because we can't divide by an irrational number that we have to go through all that gymnastic. But we would still have to fix this problem if it was for example: radical 8 divided by radical 4. And if I got that method right I would then come up with this answer: 2 times radical 2 / 2. So, at the end of the day if the equation contains radicals that equal irrational numbers we have to use factoring to find the solution.
@mariaolaciregui212810 ай бұрын
2/3 square root of 6
@mikechappell415611 ай бұрын
I thought this was just simplifying and normalizing. There is no rule against dividing by irrationals.
@russelllomando846011 ай бұрын
good one, thanks
@googolian10 ай бұрын
Cos 45degrees is expressed as1/sqrt2 by the all other teachers except himtan
@markprange24309 ай бұрын
Tan 30° = ?
@markprange24309 ай бұрын
Diameter of a circle ≡ ?
@mrjesabi9 ай бұрын
Get to it already
@larrydickenson892210 ай бұрын
Any math problem (or physics, geometry, engineering, chemistry, etc) needs to come with a set of instructions such as decimals to 3 places, fractions in the lowest terms, no radicals in the denominator, no fractions under the radical, and on and on and on. Otherwise don’t judge the form of the solution.
@mariaolaciregui212811 ай бұрын
I did not place because y could not place de square roof, but I got it. Thank you
@stevenfisher53209 ай бұрын
“Prahhms”?.?
@kendavis804610 ай бұрын
A spreadsheet yields a very reasonable approximation at each stage of the process.
@drdentin321511 ай бұрын
sq rt 3 as denominator goofed me. I stopped there. Walk of shame.
@CyubahiroKeviniel9 ай бұрын
i like these
@ananiatsadik49346 ай бұрын
Boring .
@mariaolaciregui212811 ай бұрын
👍👍
@C-man55310 ай бұрын
Agonizing.
@danielmadden96916 ай бұрын
Thanks
@mattseclecticreviews361410 ай бұрын
If you are going for the lowest number of factors, the “answer” is 4 / sqrt(6). As others have commented, the idea that “you can’t divide by an irrational number” seems to be a matter of preference. I know of no mathematical rule that makes any answer “invalid”. This problem has many “answers”. No matter how you express the “answer”, the answer will still have an irrational number somewhere. And all answers “resolve” to an irrational number in itself. Just like “you can’t divide by the sqrt(3) because you don’t know it’s value precisely”, try multiplying 2/3 ~= 0.6666… by the sqrt(6). You still can’t get a precise value, only an approximation. If there is a definitive mathematical rule, I’d like to know it. BTW, ChatGPT, although not perfect, does not know of any mathematical rule regarding this subject.
@williamBryan-k2e9 ай бұрын
I went to eng school. Your numbers have to be in the form of a real number. and it is known that it is an approx - you just have to figure out the error level of observation and put that in - to give you number of digits to the right of the decimal. when you have to calculate flow through a pipe, or get the stresses on a beam - you have to use real number. Bottom line.
@afre339811 ай бұрын
The real reason is more about preforming a long division with a irrational number in the denominator is not doable. At least before the electronic calculator days. It is not wrong by any mathematical rule. But your answer will always be an approximation when calculating to get a value. NO matter if you write SQR(8)/SQR(3) or (SQR(8)*SQR(3))/3 It is more a relic from the old days with only using a slide rule. I come from a science/engineering background. And we see radicals in the denominator all the time. But in the modern days of calculators we do not care
@utha266511 ай бұрын
Not sure it was a typo, but I saw you cut and paste the same response in another thread. It's perform not preform, I'm leaning towards a typo, the rest of your sentence makes perfect sense. 😊
@moshes21811 ай бұрын
עעע
@lylegelbach13857 ай бұрын
WAY TOO MANY WORDS ... YOU MAKE IT HARDER THAN IT NEEDS TO BE... I WOULD GUESS THAT MOST OF YOUR STUDEBTS EYES GLASS OVER... GET TO THE POINT EARLIER.
@kennethwright8707 ай бұрын
2✔️6/3
@danielmadden96916 ай бұрын
2√6/3
@SteveSearle11 ай бұрын
So you still have not given an answer, you have only simplified the equation.
@thomasmaughan47989 ай бұрын
"you have only simplified the equation." Congratulations. That was the task.
@oyesolaayobami62387 ай бұрын
2/3√6
@martinfiedler431711 ай бұрын
Approximately 5/3...
@harrymatabal84488 ай бұрын
2√2/√3
@ernestcook42857 ай бұрын
7.111
@shakirhamoodi50097 ай бұрын
1.63
@aday16377 ай бұрын
1.63
@kk6aw10 ай бұрын
1.63...
@rudbeckia88511 ай бұрын
1.64
@Stylux-z1p11 ай бұрын
more words problem , por favor
@keithschipiour468411 ай бұрын
I dont know never seen a square root .What kind of plant or tree has a square root ?
@thomasmaughan47989 ай бұрын
"What kind of plant or tree has a square root ?" Koa wood. That's why it is so expensive.
@MichaelRodrigue-v5t11 ай бұрын
Would 2sqrt(2/3) be acceptable?
@danluzurriaga60358 ай бұрын
no
@HelenMontgomery11 ай бұрын
You lost me in the middle
@mollymam715311 ай бұрын
2radical6 divided by 3
@dnarna899411 ай бұрын
At the end, why not take the (+ve) and (-ve) root of 6???
@gavindeane367011 ай бұрын
The √ symbol means "principal square root of" not "both square roots of".
@drawfark8 ай бұрын
Wonderful!
@glenwardgross36611 ай бұрын
(out of the classroom many years) John why can't you take the radical sign out of the problem since you have one on top and bottom? Does dividing a radical symbol by a radical symbol just gives you one which you used to great your one with super powers? JAT Love math
@afre339811 ай бұрын
The real reason is more about preforming a long division with a irrational number in the denominator is not doable. At least before the electronic calculator days. It is not wrong by any mathematical rule. But your answer will always be an approximation when calculating to get a value. NO matter if you write SQR(8)/SQR(3) or (SQR(8)*SQR(3))/3 It is more a relic from the old days with only using a slide rule. I come from a science/engineering background. And we see radicals in the denominator all the time. But in the modern days of calculators we do not care
@jennifergrebner699410 ай бұрын
You have to be able to divide the top and bottom of the fraction by the same number. A radical sign is not a number. Taking the square root of a number is the opposite of raising the number to the 2nd power. What integer times itself will give you the number underneath the square root sign? It's no the same number for 8 & 3.
@thomasmaughan47989 ай бұрын
@@jennifergrebner6994 Square roots of non-integers (positive real numbers) exist and are relatively easy but actually calculating one usually involves logarithms. You can raise any positive real number to any real number power, even negative exponents. In this example, you multiply the top and bottom by the same number, in this case the square root of 3, to "rationalize" the denominator and make it simply 3. The top now has an extra square root of 3 times the square root of 2, they combine to become the square root of 6.