The Wittig Reaction

[@DaBaaaang]

You remind me of Joey from Friends, just smarter. Thanks for your work bro.

[@Tina-xw8mb]

This! 👆

[@mitcho5452]

I WAS JUST THINKING THIS AHH😂

[@jeremyharrison9265]

you are awesome, just came across your channel and these are one of the best explanations I have seen. Thanks!!

[@jOeCHEM]

Jeremy, thanks a ton, man! I've since made a second video on this topic kzbin.info/www/bejne/hpqpoYdoj92qntk (I go a bit more in depth because you can get a different double bond if you have a ylide thats attached next door to an aromatic system). Make sure to check out joechem.io/videos/38 where I have a worksheet + solutions linked (literally for free). And if you subscribe that would be H U G E L Y appreciated :)

[@kenhagiya565]

JoeChem saving my ass once again. Thank you for the videos!

[@mohammadsaifullahkhan53]

This channel is awesome!!!

[@tharushimunasinghe1716]

Thank you soomuch ❤

[@meryammaryam4348]

Thank you my friend🤗

[@Sophia-rl5ph]

Thank you so much, I really appreciate you!

[@irem9955]

would be better if you also solve questions which wittig is involved as a step. more complex questions pls

[@jOeCHEM]

Check out kzbin.info/www/bejne/hpqpoYdoj92qntk

[@stormydoctor9009]

hi you know for the lda how it deprotonates less sterically hindered alpha hydrogens why did it deprotonate the sterically hindered alpha H's

[@stormydoctor9009]

why not just use NaOme if you deprotonated the least sterically hindered H's

[@jOeCHEM]

It does because LDA is VERY large, so it is hard to reach more "crowded" alpha H's. So it is lazy and opts for alpha H's that are less sterically hindered, aka more accessible. Something like NaOMe is MUCH smaller, so it can access more "crowded" alpha H's.

[@francoislaflammeawono317]

Je ne suis pas d’accord avec ta réaction mon type