The work done on a particle of mass m by a force K[ (x 2 +y 2 ) 3/2 x​ i^ + (x 2 +y 2 ) 3/2 y​ j^

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Fun with Physics

Fun with Physics

Күн бұрын

The work done on a particle of mass m by a force K[ (x2+y 23/2xi^+ (x2+y 2 3/2yj^] (K being the constant of appropriate dimensions, when the particle is taken from the point (a, 0) to the point (0, a) along a circular path of radius a about the origin in the x-y
The work done on a particle of mass m by a force K[ (x2+y 23/2xi^+ (x2+y 2 3/2yj^] (K being the constant of appropriate dimensions, when the particle is taken from the point (a, 0) to the point (0, a) along a circular path of radius a about the origin in the x-y
The work done on a particle of mass m by a force K[ (x2+y 23/2xi^+ (x2+y 2 3/2yj^] (K being the constant of appropriate dimensions, when the particle is taken from the point (a, 0) to the point (0, a) along a circular path of radius a about the origin in the x-y
The work done on a particle of mass m by a force K[ (x2+y 23/2xi^+ (x2+y 2 3/2yj^] (K being the constant of appropriate dimensions, when the particle is taken from the point (a, 0) to the point (0, a) along a circular path of radius a about the origin in the x-y
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About D G Sir:-
Deepak Gupta Sir (D.G Sir) is a renowned faculty of physics. He holds a Master's degree from N.I.T. Jalandhar. He is guiding the students of IIT-JEE and NEET for more than 5 years. Under his guidance, several students have achieved their dreams of going into different IITs, NITs, IISERs, and in, different medical colleges.
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About This Channel:-
Dear students,
As you all know that IIT JEE Mains / Advance & NEET are one of the most prestigious and competitive exams of the country, for which lakhs of the students appear every year. These exams are known to be one of the toughest exams for which the students work very hard. A lot of coaching institutes provide good quality coaching and materials to the students so that their efforts and hard work can be reduced a bit. But as we all know that these coachings charge very big fees and a lot of students are not able to pay these big amounts.
That's why this channel Fun with Physics is created where you will find all the quality material for IIT JEE Mains / Advance & NEET explained by our expert faculty in a very simple manner, which is being taught at any coaching in India. You can ask your doubts in the comment box, which will be solved by our expert team very soon.
JAI HIND!
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Пікірлер: 18
@pepperoni101.
@pepperoni101. 5 ай бұрын
Sir, you have an amazing uplifting energy. Watched this with a smile on my face, thanks sir💗
@spenzr6920
@spenzr6920 4 ай бұрын
Maine faltu me partial differentiation krke ise conservative prove kiya taki ∆U=0 aye. Ye zyada simple tha. 👍
@deveshchaudhary7676
@deveshchaudhary7676 7 ай бұрын
Brilliant sir ....ek baar me hi smjh gyaa ❤
@Sanvi-0705
@Sanvi-0705 2 ай бұрын
Really thankful to you sir 🙏🏻🙏🏻 the way you explain is awesome and the way of speaking is really commendable, ie in accordance with the name Fun with physics 👍🏻 Please Keep uploading for us 🙏🏻🙏🏻
@DebanganChaki-zi6lo
@DebanganChaki-zi6lo 3 ай бұрын
Thank you so much sir...Your explanation is just amazing...please continue making such very very helpful videos for us ❤️
@aayush_1708
@aayush_1708 8 күн бұрын
Thanks sir itna sahi explanation wow !! Sir jee advanced ke aise hi short viedeo vanaya kre ye bahut hi acche aur time bounded hote hai
@artisharma....
@artisharma.... Жыл бұрын
Converted advanced problem to mains level
@shobhav.niceshobhitsingh9566
@shobhav.niceshobhitsingh9566 27 күн бұрын
THANK YOU SIR ❤
@YuvrajSingh-pf4fz
@YuvrajSingh-pf4fz Жыл бұрын
Amazing explanation 👏
@AbcdEfgh-i4n
@AbcdEfgh-i4n 4 ай бұрын
Thanks
@ishantgoyal8695
@ishantgoyal8695 3 ай бұрын
What an explanation thank u sir
@arunparashar1385
@arunparashar1385 5 ай бұрын
Amazing explanation❤❤❤❤
@physiqalguy302
@physiqalguy302 5 ай бұрын
love sir ki energy
@nsparmy2.o559
@nsparmy2.o559 Ай бұрын
Nv sir real id se aaiye😁, kya explain kiya h🎉
@raogouravyaduvanshi2951
@raogouravyaduvanshi2951 Жыл бұрын
🙏🙏🙏
@vaibhavchaurasiya4419
@vaibhavchaurasiya4419 Жыл бұрын
Sir ab ap circular cover karenge naa
@FunwithPhysics
@FunwithPhysics Жыл бұрын
Haan beta, vahi shuru krni hai abb
@Godkiller8524
@Godkiller8524 11 ай бұрын
It's jee advanced 🎉🎉
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