A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constan

A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constant). If U(0)=0, the graph of U(x) versus X will be, (where, U is the potential energy function) :
A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constant). If U(0)=0, the graph of U(x) versus X will be, (where, U is the potential energy function) :
A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constant). If U(0)=0, the graph of U(x) versus X will be, (where, U is the potential energy function) :
A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constant). If U(0)=0, the graph of U(x) versus X will be, (where, U is the potential energy function) :
A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constant). If U(0)=0, the graph of U(x) versus X will be, (where, U is the potential energy function) :
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About D G Sir:-
Deepak Gupta Sir (D.G Sir) is a renowned faculty of physics. He holds a Master's degree from N.I.T. Jalandhar. He is guiding the students of IIT-JEE and NEET for more than 5 years. Under his guidance, several students have achieved their dreams of going into different IITs, NITs, IISERs, and in, different medical colleges.
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[@utkarshkorhale6558]

Very Good Explanation Sir I Am Very Fortunate to Have U 🙏🙏🙃

[@subedaryadav6027]

Thank you sir 😇😇

[@studirony3809]

Sir every process of the question was crystal clear but if fxn is maxima then why it would tend towards -infinity it should be +infinite so ans would be opt. C

[@kesariyt5696]

sir mai class notes ke graph ratleta tha par abse try krunga aise hi nikalne ka