How To Solve Diode Circuit Problems In Series and Parallel Using Ohm's Law and KVL

[@TheOrganicChemistryTutor]

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[@AdhambekAbdumannonov-mi8bm]

You are legendary :)

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From my basic calculus course to physics -- and now, even in electronics. If I ever become an electrical engineer someday, please do know that you played a HUGE part why. Thank you for saving lives.

[@khalidsaifullah1321]

Happy Electrical Engineering Same here.......He is an Amazing teacher!!

[@mohamedbangura7329]

He is really a good tutor

[@kalpeshkumar3878]

Have you become an electrical engineer?

[@eren_yeager9927]

Omg EEE from UP?

[@rizz10-n3x]

R u an engineer now? Or housewife

[@davidc.7305]

Moments like 3:43 where he takes the time to explain milliamps is why this guy is king. He's always looking out for those who might be rusty/lost with the basics and doesn't assume. Thank you, Mr. OCT

[@hemgreen9984]

how do people not know milli by now? just move decimal over 3 places

[@gordonhuynh4294]

@@hemgreen9984 fr

[@omniyambot9876]

youre taking engineering not knowing milli😅

[@blazer7731]

@@hemgreen9984 Yeah but this could apply to other basics that someone may have forgotten. I'd rather someone over-explain than under-explain, which is what most uni lecturers do, hence why these channels are so popular

[@qualityff3458]

This is like 5th grade stuff

[@yazan774]

I do not understand why can't college professors explain this way. Thank you.

[@sandeepreddydevarapally5316]

Reason behind it Doing in parts

[@georgeaziz1846]

@@sandeepreddydevarapally5316 not correct professors are making small videos but it is not good also the duration of the video is not a reason for quality of it

[@IBasilisvirus]

lazy fuckers

[@mit4539]

"College profs", Man I am studying this for high school.

[@disenfranchisedrealist4433]

Not everyone in the education field is an educator. Just because someone is brilliant doesn't mean they can relate their knowledge to someone else. It's very much the same in coaching sports. The star quarter-back may have had an incredible career on the field but that doesn't mean there is any coaching potential there. Knowing something and knowing how to convey that knowledge to someone else are two very different things and possession of one is not an indicator of possessing the other.

[@beepsntones]

You guys are sooo lucky to have these examples explained so well on you tube, think of learning this stuff 20 years ago when we had very little help from the internet.

[@shivankitss8396]

Thats exactly what my father tells me

[@narayanaswamyprakash7147]

40 years ago in my case lol

[@fgbbhhfgjnbvbn4959]

Dont worry uncle

[@DavincisMind]

@@shivankitss8396 or 40 years ago....no internet at all 🙂

[@XJ290]

I was just thinking that today

[@claireyandel]

this man is the love of my life omg

[@captainamerica9568]

We would be lucky to have a professor like you.👍

[@LordJesus1447]

"Electricity will always flow in the path of least resistance" that's what we need to remember folks.

[@pagodax2599]

i wish you always happy ,healthy and successful in everything. I’ve been watching your video for so long . THANK YOU VERY MUCH!! 🙏❤️

[@RandyH524]

Dude you're literally the best tutor on youtube. Not only that, you're probably a genius in real life. Love you man. Thank you for everything that you do.

[@ishaanj8023]

He basically is, cause he literally teaches EVERYTHING

[@Peter_1986]

One _major_ reason why this guy is so good at teaching things is because he gives _several_ example problems. A lot of teachers are content with just showing one example and then they move on to something else, and that always annoyed me a lot, so it's great that these videos show a large number of examples.

[@olaoluwaomopariola4867]

He doesn't have to be a genius to do this though. He doesn't even have to be brilliant. He just learns it and teaches it after. Probably even forgets what it's about when a series is over. It's not hard at all. For all anyone knows he's looking at already written out and explained examples by someone else he got to do it for him or something. Surely you don't really believe that he knows everything he's teaching.

[@The_count_of_Monte__Cristo]

@@olaoluwaomopariola4867 womp womp ....

[@cyberlando]

DUDE YOU are AMAZING!!!!! you should do a video of PN junctions and how N-P type silicon works

[@pranavgupta8115]

i need

[@rockspoon6528]

Thanks man. I know you hear it a lot, but you summed up days of rambling lectures in

[@erickademe]

Same thing here, So grateful indeed

[@seringmodoujaw7048]

It took a whole year to understand just this. 10 mins into your video, I got it all in. African students are proud of you mein

[@Anonymous____________A721]

Y only Africa mein

[@michaelalleyne1403]

This guy knows everything I swear.

[@badgalirri]

You are just brilliant! You helped me get a 9/10 in calculus. Hope you will now again make me pass my electronics course haha. I don't understand why can't my professor explain it like this so we can actually understand...

[@NoOne0223]

Opps😂

[@umairishuman]

This channel is the best teaching channel out there. I love this channel.

[@Ocean_dott]

As long as I see the topic I want to learn on this channel I am safe. I owe my good grades to you sir❤

[@Peter_1986]

The method at 8:00 was actually much easier and more straightforward than the "quick and easy" method. =P

[@reaganhambrick8149]

idk why chemistry man is doing electronics but thank you

[@johnnoemartinez8712]

SUPER HELPFUL! GRATEFUL TO THE CREATOR OF THIS VIDEO!

[@katsuxrlj]

I used Voltage Divide in 6:26. Same process, I subtract the Vd to the Vs. Then voltage divide the 3k resistor (with the 9.3V) to get the Vo, and used Vo in Ohm's Law. Same result!

[@SuperCarmen57]

Thank you from the bottom of my heart for this lesson, very useful through the clarity of the explanations and multiple examples!

[@AdhambekAbdumannonov-mi8bm]

Such a wonderful tutor

[@ammarabaker1463]

Oh my God! I can't imagine this smartest way thanks so much! 💙💙🙏 Here in our country we teach ourselves so it was so difficult to understand, but you made it easy for us.

[@DarkSide-iw8qo]

hi ammar Im with you in sudan collage 😊😊

[@r.alhilal4495]

you are incredible ! if i ever become a computer engineer it's thanks to you and the rest of the youtube teachers

[@firdyan5394]

i don't too good in english but i understand your explanation. good

[@davidmakgopa1165]

was very helpful , i watched it x3 on different days and these diodes were made simple❤....

[@julialandauer9057]

just watched this because i realized my prof didn't do any examples and it's on my final.... god bless dude im in a "high speed" intro to circuits class thats designed for mechanical engineering students and its a nightmare lol

[@scyther0194]

Thank you , i love all your lectures!

[@artisticnoob5003]

This is wayyyy better than any of the videos!! I understood everything, THANKS DUDEE

[@kartikmehta17]

AKTU ke lagte ho tum :joy:

[@artisticnoob5003]

I didn't get you?

[@kartikmehta17]

@@artisticnoob5003 nothing just looking that you are from AKTU University because this is the ongoing topic which we r studying!

[@artisticnoob5003]

@@kartikmehta17 nahh, I am in 12th

[@kartikmehta17]

@@artisticnoob5003 wow! Congratz this topic was not covered in CBSE when i was in class 12th. Have a great future! 👍

[@camelliasamara252]

this video helps me a lot for my study. before seeing this video ,i had no idea about diode math

[@dtm7743]

With all due respect you are my life saver but please make another tutorial on how to solve diode circuit problems when the source feeding the circuit is Ac rather than a DC

[@kabandajamir9844]

The world's best teacher

[@successthruknowledge]

I liked especially the problem with diodes in parallel to highlight the concept that the germanium diode with the lower voltage threshold will be the one through which all the current flows! Also the example with the parallel diodes where the one with the greater voltage difference shows which diode will be the one through which current flows.

[@tykealy]

at 11:00 why is V0 = 0.7v ?

[@austin0207]

Did you ever figure this out ?

[@leonardomichael513]

@@austin0207 No :( I need an explanation

[@s0ber912]

@@leonardomichael513 @austin0207 the potential across the diode should be 0.7 the point B has to be 0.7, since the other end is grounded i.e. 0 volts

[@leonardomichael513]

@@s0ber912 Thanks man! I didn't know about the ground thing

[@omartusson]

Thank you very much.

[@zulfikarhidayat2663]

11:32 Why voltage at B point is 0,7? It's not passing the any diode yet?

[@dtm7743]

Because since point C is taken as a ground node i mean a reference node all our potentials are measured with respect to it and a silicon diode has a typical voltage drop across it of 0.7 volts one of the terminals is at 0 volts that is the ground terminal so the other has to be at +0.7 volts

[@praveensharrma465]

@@dtm7743 shouldn't the voltage at point B be 8 minus the voltage drop of the 3k resistor???

[@dtm7743]

@@praveensharrma465 Yes it is right you are harry but why would you take this way ? whenever you have a diode that is in the forward biased mode you can say mearly that the voltage drop across is 0.7 and sice and just like i said before point C in taken as ground ,potential at B is 0.7 with respect to C if C was not a ground node i would not have been able to say that

[@AI-kr7mj]

@@dtm7743 If we did not take C as a ground then ?

[@dtm7743]

@@AI-kr7mj what else node would you take as ground? when talking about voltage in circuit theory the node's voltage has to be measured with respect to a reference node because there is no such a term "voltage" instead we say potential difference the well-known reference point in circuit theory is the ground what is a a potential of 0 so you are not required to take your reference as the ground you can take it else where but i suggest you do not over complicate it you just take the bottom node as ground and all other node voltages will be measured with respect to it

[@Md.MiltonHossen-u5o]

The Supreme methods. I will request to viewers pls see this lecture at least 3 times. Then all confusion will be clear Love from Bangladesh

[@lime3023]

Can someone explain why in 10:19 the v output is 0.7v shouldn't it be 7.30v?

[@hyperionisalwaystaken]

You know, I hope 11 months late this problem isn't haunting your nightmares, but the reasoning is as follows: Point C (Node in proper jargon) is connected to ground. That means it MUST be at 0V. ...and BECAUSE a Si diode has a voltage DROP of 0.7 when they're on... ...If you ASSUME them to be on, therefore the voltage at node B (lets call it Vb) should be: one such that when Vb experiences a DROP of 0.7, it equals the voltage at node C (call that Vc) Vb - 0.7 = Vc Vb - 0.7 = 0 Vb = 0.7. QED.

[@lime3023]

@@hyperionisalwaystaken thank you☆

[@minjoon316]

Your lectures are amazing Understood the problems

[@leroycasterline1122]

At 5:10, you state that the Si diode is off because 'the Ge diode needs less energy to activate.' But it seems to me the reason must be that the forward voltage across the Si diode is only 0.3 volts (as the Ge diode has pulled it up), thus it can't turn/remain on.

[@SNoCappidona]

Yea, i am wondering whats going on in that circuit. 2 ideal voltages sources in parallel have the same voltage; these are diodes so i guess that doesn't apply. If it is true that only the Ge diode turns on, then i suspect there is no real practical application of this circuit and the silicon diode is redundant.

[@Rafiul2006]

You deserve millions of subs❤

[@mikebalbes6631]

the last problem will be much more comfortable to solve using nodal, but thank you sir for this.

[@TonyDaExpert]

Refreshing myself on electronics but man this way easier than I remembered in lecture lol

[@deko3140]

20:15 , isn’t it should to be Vo=14.3 ? Because we have a voltage in the ground and the multiplication of ( i * 6000 ) = 14.3 as well

[@larrybud]

15:30, if you're going to measure the output voltage, you would need to specify relative to what, since there is no ground denoted here.

[@boganza5140]

great man...looking forward to see more stuff like this..thumbs up!!!

[@holyfieldjr.5619]

Amazing! Requesting for a video on how a circuit works point to point

[@TheMotivationalSpideyGoku]

Thank you so muchh OC for your teachings. thanks be to God!!

[@한진영-o5q]

Are you sure 5:18 that is right ? It’s proved that electricity takes all paths. As we were taught current takes all the paths with inverse proportion to the resistance ? Please correct me if I’m wrong

[@moonsky008]

brooooooo awesome u cleared alllll my doubts dude chears

[@deepfake1647]

I think the guy is doctor of all sciences

[@Vishal-lw6hn]

Thanks mate , made my day a lot easier

[@kamleshnehra407]

Sir I think you are wrong at 22:33 , current choose low resistance that's why the current will go through only 2K ohm resistor ,hope if I'm wrong then you will correct me . But you are amazing teacher

[@jayantirakshit7859]

at 19:22, why does the higher potential win out the lower potential? Earlier in the video you mentioned that if the potential is lower, then it is favored due to its lower resistance? Could you please elaborate the difference in that part of the video vs this one? When do we know when to favor a high or lower voltage??

[@PhillJennings]

You are the best teacher ever

[@vbacz]

On circuit of 15:55 would the negative 8v point be drawn as a source that goes against (up the circuit) 16v or a source that goes down the circuit.

[@Festus2022]

Great Video. One question: At 17:50 Why does the 12V "win out" over the 5V leg of the upper 2 diodes, and why is the 5V diode OFF?

[@kirankumar.b.r7811]

Awesome explanation Sir🔥🔥🔥

[@tomaszgasecki]

You have a great talent. Thank you for your time.

[@jaysonromasanta7544]

BIG "THANK YOU" TO YOU SIR! :))

[@nathanielgarcia-vasquez4735]

mad respect saving our lives

[@sanchezjoaquinbrandonariel3756]

La verdad no entendí lo que decías, pero en la pizarra explicaste muy bien, gracias

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thanks for saving my life again

[@beytulk]

​@@rf4605 how can I help u ?

[@mikericardo9294]

Omg this guy is my Hero.

[@GOODvibesYT100]

Thanks from India 🇮🇳

[@fazimalik5599]

thanks sir Your explanation method is so good I understand it very easily

[@crazyworldtech4536]

At 22:50 min if in parallel one diode works, why did you take the equivalent of resistance in parallel. We should neglect the lower resistance (4)

[@deko3140]

I think because the voltages are equals in D1 and D2 so it’s like a parallel resistors

[@stewardderby3259]

Your course is very good Thank you so much for sharing your video

[@louco2]

Exelent! Thank you so much for taking the time to do these videos!

[@johnricolopez7856]

Thank you so much Goodluck for my exam tomorrow 😇

[@MaliaRojas21]

@1:05 , cant you just draw current the other direction for the circuit to be on? Or are we assuming vo -0 is the polarity across the resistor ?

[@jamineakariz4902]

in 12:06, why is the voltage output at 0.7? would that be 7.3?

[@deko3140]

Because it’s already in parallel with two Si diodes and each one has 0.7v as Si diode

[@SonicCloud7]

Thanks!

[@MrJimaras777]

in the example starting at 20:30 why didnt the current take the path of least of resistance and it split into two?

[@djkivler1916]

both are silicons

[@hanaabuhindy3466]

this was very very helpful!!!

[@TrionityIr]

I wish you were my teacher cause my current professor sucks.

[@mehraz8063]

I think this homie is trynna make me pass the course. ain't no way

[@paulos1466]

Actually, I learned lots of things using Internet channels more than my entire year of education, and I realised how much our education system is worth nothing and waste of money.

[@ryandeguzman6624]

Just want to makesure. Is it 9.33 ohms for the total resistance or 9.33 mili ohms. Love your videos!

[@premuhendis5419]

understandable explanations. Great!

[@aachannel258]

You're so Helpful!🥰🥰

[@gielomarbandoy9871]

TBH. I mostly understand this, than the lectures from school :)

[@stellaroubazany794]

you're a great teacher

[@davidmacfarlane4761]

For the problem at the 22 mark, the The parallel combination of the 2k and 4k resistor is 1.33 KILO-ohms, and NOT 1.33 ohms. Also the total resistance is 9.33 KILO-ohms, NOT 9.33 ohms!

[@lasithaamarasinghe9251]

Thank you sir. Great video ❤

[@sirisaksirisak6981]

I=V/R,V=IR we can use amp meter measure current value. If the outcome less than normal value show that diode broken.Kirchoff law.in put minus out put=zero.

[@martinbenitez3107]

23:20 Why not use Ohm's law directly? like i=11.3v/2k or i=11.3v/4k?

[@ChrisKuo-rs8fk]

i love this channel... fking love!!!

[@zikermu]

Thanks a lot for these Excellent explanations .

[@custodioarmindogungulo8465]

No words... Congrats.

[@belleluze]

12:34 I'm getting the same current but not the same voltage at the out put? What I did since it's a voltage devider was this: 16-(-8)=24-0.3-0.7=23v 23x(5000÷7000)=16.428v at 5k resistor and 6.571 at 2k resistor. I@(5k)= 16.428/5000=3.285mA I@(2k)=6.571/2000=3.285mA

[@victorkuan801]

For the last question, what happens if one of the Si diode is replaced with a Ge diode?

[@studymail4800]

it becomes a series circuit and the other si diode is ignored too

[@josefkornal4691]

thank you . you are a great teacher.

[@mrminecraft987456]

You are the best! You literally saved my ass :D

[@traumaone9117]

Really informative and nice! Keep up the good work! Thanks.

[@ageribalkissoon2426]

ain't no way my teacher used these exact questions in class 😭

[@sri9649]

Thank you so much i got all answers

[@MRRED-bk5hb]

YOU ARE LIFE SAVER

[@vishnugitte7940]

7:05 can u explain why the 2 resistors are in series ?I think both have 9.3 V across them ,hence parallel?😅😅HELP By the way I understood the method 2. MY BOOKMARK 5:00 (nice question)