Enthalpy of Formation Reaction & Heat of Combustion, Enthalpy Change Problems Chemistry

[@TheOrganicChemistryTutor]

Thermochemistry - Free Formula Sheet: bit.ly/3TP4U4u Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections

[@zacharyh5419]

I was stuck for hours on combining equations of formation to make a regular equation and the first 10 seconds of your video enlightened me. God bless you

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Omg same

[@grantwiesehan9515]

literally same

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Same here

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Bruv if this is the level of physical chem people have in the west every asian would top the test.... its way hard over here!

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When you have to learn Chemistry else where because you're under lock down and your teacher won't answer your emails .... btw. you just taught me something is less than 20 mins, which i've been trying to understand for the past 6 days so thanks

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I stopped listening during Chemistry lessons cause I literally don't understand my teacher's teaching..I just can't wait to come home and listen to your explanation on this topic...Thank you...I'm now the highest scorer in Term 1 ..Just scored (98/100)...Everyone was shocked..I'm just sad that I discovered your channel late...I'm now in my last year of high school...Should have started watching you from Junior level 😢😢....

[@awaisahmed5489]

Best luck all of you for exam tomorrow 🤣🤣

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Exam today 😂😂😂

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My exam is today too

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Test tomorrow 😒

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Thank him...but then he IS god

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I learn here more than in my class

[@GSU_Panther_Nation]

Thank you. You are a blessing when it comes to straight to the point lectures. In fact, better than Khan Academy, and teaches way better than my chemistry professor. Just have to search the textbook for a certain topic and then search it on KZbin

[@georgesadler7830]

Professor Organic Chemistry Tutor, thank you for a step by step explanation of How to Calculate the Enthalpy Change of a reaction using Enthalpy of Formations in AP/General Chemistry. The problem selection for this material are excellent. Every problem in this video also reviews the concept of balancing Chemical Equations in Modern Chemistry. This is an error free video/lecture on KZbin TV with the Organic Chemistry Tutor.

[@caitygart]

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[@RambunctiousVA]

woah I didn't know a 1/2 coefficient was allowed

[@feitan8033]

The coefficient of the product has to be 1 unless stated otherwise, so a 1/2 is required for the reactants

[@feitan8033]

@Megan choo To form water you need one oxygen and 2 hydrogen atoms

[@yabombo8145]

Do you like black people?

[@Abcsefghijklmnopqrstuvwxy]

The reason being is that the atoms of oxygen always exist in pairs; that’s why there’s a subscript of 2 in front of O. All diatomic elements are this way (H2, N2, F2, etc). If diatomic elements are always in pairs, how do we get just one atom of it? You would have to multiply the subscript 2 with something to give you one. The only way you would get one atom is by multiplying it by 1/2. Does this make sense? The 1/2 doesn’t mean half of one atom; it is half of 2 which we know is 1. It is another way of writing one atom of Oxygen in this equation.

[@someoneelse361]

@@yabombo8145 what does this have to do with anything?

[@niche5006]

The enthalpy changes are measured kJ instead of kJ/mol since you multiply everything by moles. Love all your videos btw.

[@kinghassy334]

Thanks

[@nicolasaq523]

Organic Chemistry Tutor The GOAT

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Better than my chemistry professor by a mile

[@minsungkim6792]

Thank you for this! Not many textbooks explain this concept properly.

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@@tahaprince6978 hi

[@laithahssan8253]

1:31 you have to put graphite because its the main form of carbon (solid) and thanks alot great video

[@Mejustme74]

3:31 for making this more understandable we can say whenever 1mole compound is form then enthalpy of reaction becomes eq to enthalpy of formation and when 2 or 3 etc moles of compounds are form then we have to divide the moles from enthalpy of reaction to get enthalpy of formation.

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this guy is a gem

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THIS VIDEO IS GOLD 🥺🥺

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Your tutorials have saved me once again, thank you

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You should be my professor!

[@ronncarlfaminialan7525]

We have an exam in thermo chemistry today. thank you for making this video. Wish me luck!

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Ronn Carl Faminialan how’d u go?

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@@milindbordia he probably died

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[@fynngreen00]

I have an exam tomorrow and I still don’t understand Heat of Combustion 😀 wish me luck before I head to my certain doom!

[@Jessicaah1]

Great video, I'm wondering though why you don't use reactants minus products in the combustion reaction of c2h5oh, since it's a combustion reaction that includes oxygen. I've learned that combustion reactions are always exothermic, so in this case it brings a negative sign which means exothermic, so I'm good with that, but HOW do I know when to use products minus reactants or reactants minus products? Do I just switch signs if I get a positive value when I know it's a combustion reaction? Little confused here. Thankful for answers.

[@aadarsha1487]

ikr shouldve dlne Reactants - Products in that one its the rule isn't it

[@sasmitpandey4980]

Is there a balanced synthesis equation for ethanol, or does ethanol only form through combustion?

[@sasmitpandey4980]

Never mind, I found it.

[@titusmwape2938]

Well explain and easy to understand

[@lorenzdequina2306]

Thanks alot bro, it make's easy to understand thermochem

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You are the best man🙏king

[@Swetha-ii]

A PRODUCTIVE VIDEO....KUDOS TO THE TEAM

[@MohammedHimedah]

Thank you very much man you're AMAZING

[@bumxrr]

welcome

[@hussnainshakeel2372]

who's studying for finals with me 🥴

[@davidgn40]

Lmao right here

[@andrewhill1570]

Right here 🥴

[@hussnainshakeel2372]

Good luck to both of y’all

[@davidgn40]

@@hussnainshakeel2372 had mine. This video saved me on the Enthalpy questions haha. Thanks. Hope your finals go/went well too.

[@sansamman4619]

I am studying for the finals that I will have one year from now xd, this Thermochemistry stuff is one hell of a challenge I am studying on a text book, I also have a few other "note book" things that should help with the text book, I have 50 practice problems, I have like 30 tabs opened, I will watch the mit open course ware lectures on thermochemistry and then I will be done. I don't know why I told you this, but after writing it down I feel a little better :')

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You simply the best

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I wish I could know which grade this lesson is for, bc I am taking it in high school second grade in Saudi Arabia, and thanks man for this video ❤❤

[@akazozo99]

Thank you so much sr.You save me from failing the exam.😞

[@kuzon2132]

Learned a lot

[@iconicahlly9377]

you've saved me for tomorrow

[@islamwasel2023]

Please strongly explain to me what is the relationship that connects the heat of combustion with the heat of the formation

[@janieli]

thank you. thank you. god bless you.

[@myax4500]

Thank youuuu this is so helpful

[@amrithabhat5019]

you are the best dude!

[@giridharansankar5735]

Yato gang?✌️

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Thanks you soo much brooo made my life easier

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Absolutely Brilliant 👏 👌 Thank you so much 😊

[@adycerriteno3230]

THANK YOU SO MUCH! CAN you make for heat of combustion please...

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You explain things so well. Are you a TA or prof or something?

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how can this piece of flesh can teach that amazing !!

[@namballalakshmanarao3831]

thanku sir.....awesome lecturing

[@jiminpark3865]

This is so easy.

[@saeedmohamed7008]

Thank u so much good job keep going.

[@karroten]

Another great video. Thank you!

[@shaisaroussi5324]

Question: Enthalpy of formation of H2O is 0 or -286? What do I miss? Thank you!

[@noraax]

This is probably a bit late but it’s -286 because H2O (L) is not a “standard state”, it’s created from the formation of H2(g) and O2(g). So the H2 and O2 are 0 not the H2O

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ohh man you are awesome

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Beautiful video. Nice job

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my goal is to fulfill my purpouse in life to the same degree you have fulfilled yours

[@CuriousAndCuriouser1865]

9:19 why is the result in kJ per mol? It looks like it should be for the entire reaction.

[@fezii9043]

What about calculating the enthalpy change of formation if given the enthalpy change of combustion?

[@hectorokereke9268]

Enthalpy change of combustion is enthalpy change of reaction And to solve for that is ∆Hproducts - ∆H reactants you can use algebra and finish up

[@fezii9043]

@@hectorokereke9268 thank you

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Thankyou so much for the awesome videos!

[@chiamakanwazue6237]

It’s second period and my test is fifth period, wish me luck 🥴

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How did your test go?

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Thank you. This is great!

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Thank you for such a great video :)

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my goat 🐐

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thankyou so much.........

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How do i know if the product is gas liquid or solid?

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This guy sounds like Mark Whalberg

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yess thats what i thought too

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Good one sir.

[@vkrs3315]

Thanks

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life saver !

[@arinzeanthony7447]

I thought that the Heat heat of combustion (being an exothermic reaction), the heat of reactants> the heat of products. Therefore it Should be heat of reactants - products in this case..

[@ES-qe1nh]

Wrong. If it is exothermic, the enthalpy change sign is *negative* since the reactants have lost energy

[@liamnotlast4571]

Why am I watching this? It's 2 minutes to midnight and I don't even go to school anymore!

[@sasmitpandey4980]

What is the balanced synthesis equation for ethanol?

[@sasmitpandey4980]

Never mind, I found it.

[@aidenwolf3558]

will the carbon dioxide and water formation enthalpy always be the same for problems or does it rely on the textbook

[@AmaKwakyewaa-y7r]

Thanks 🎉

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Thank you.

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Helpful,

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Thank you🇳🇬🇳🇬🇳🇬

[@shanuruppi2051]

thanks for this video

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333K views. 3 years ago Nice ❤️

[@Ashraf0304]

Its 8:36 and my test is at 9:20 wish me luck 🥲

[@christopherloughran9029]

What would happen if Aluminium had a value (hypothetically)? How would you isolate X ?

[@Arxxa]

Whats the point of listening in class for 45 minutes and not understanding when I can listen to your 15 minute videos and understand everything.

[@rosyskysong8590]

Could you explain why dH(rxn) is -1396kJ PER MOL at play time 9:25. I thought dH(rxn) is -1396kJ for 4mol-NH3 and 7mol-O2.

[@cam.r.7052]

For anyone else who wonders, I believe he made a mistake writing /mol and it should just be kJ. If you follow the units of each number on your head, the moles cancel.

[@silver9204]

Ily bro

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The goat

[@arrow1123]

hes so goated

[@nshimyumukizaonesime2525]

Do you only put elements on the reactants side?

[@toxicgamer5723]

Why is the enthalpy change of the reaction is equal to the enthalpy change of the copustion of 1 mole

[@neetuneetu373]

Sir how to find the value of reactants and products ??

[@andyoohhh2061]

Why wouldn't your units "mole" cancel out when solving for the heat of reaction? I think it should.

[@averyredonnett]

If I am not given the KJ/mol of the compound how and I supposed to figure out the heat formation of a compound?

[@BlessedAkue-yy8hg]

Test tomorrow

[@royal2566]

this really nice video thanks for it....

[@hayin2041]

May I ask how is it possible if we undergo combustion raction while still staying at standard condition (1 atm, 298 K)?