How To Calculate Theoretical Yield and Percent Yield

This video shows you how to calculate the theoretical and percent yield in chemistry. The theoretical yield is the maximum amount of product that can be produced in a reaction. The percent yield is equal to the actual yield divided by the theoretical yield times 100%.
Full-Length Math & Science Videos:
/ collections
Stoichiometry Formula Sheet:
bit.ly/3Z7uMw8
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Introduction to Moles:
• Introduction to Moles
How To Calculate The Molar Mass:
• How To Calculate The M...
How To Convert Grams to Moles:
• How To Convert Grams T...
How To Convert Moles to Grams:
• How To Convert Moles t...
Moles to Atoms Conversion:
• Moles To Atoms Convers...
Grams to Molecules Conversion:
• Grams to Molecules and...
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Grams to Atoms:
• How To Convert Grams t...
Moles, Atoms, & Grams Conversions:
• How To Convert Between...
How To Balance Chemical Equations:
• How To Balance Chemica...
Stoichiometry - Basic Introduction:
• Stoichiometry Basic In...
Avogadro's Number:
• Avogadro's Number, The...
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Limiting Reactant Problems:
• Limiting Reactant Prac...
Excess Reactant Problems:
• How To Find The Amount...
Theoretical & Percent Yield:
• How To Calculate Theor...
Percent Yield - More Examples:
• How To Calculate The P...
Percent Error:
• Percent Error Made Easy!
_________________________________
Percent Composition By Mass:
• Percent Composition By...
Empirical Formula Problems:
• Empirical Formula & Mo...
Empirical Formula - Hydrated Compounds:
• How To Find The Empiri...
Combustion Analysis:
• Introduction to Combus...
Stoichiometry Practice Test:
• How To Solve Stoichiom...
_______________________________________
Final Exams and Video Playlists:
www.video-tuto...

[@TheOrganicChemistryTutor]

Stoichiometry Formula Sheet: bit.ly/3Z7uMw8 Final Exams and Video Playlists: www.video-tutor.net/ General Chemistry 1 Review: bit.ly/3DNmZqb PDF Worksheet - 160 Questions: bit.ly/37SVLn6

[@me-om1zg]

Thanks😊

[@-clipz-]

Prayers turn to God may everyone everywhere be blessed and healed and protected in Jesus name amen.

[@gj7184]

Good luck on your test tomorrow

[@omranamin2636]

My exam is actually tomorrow

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how did you know? XD

[@nidhishsharma9471]

@Jaiden Boren mine is today and tomorrow

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Wtf

[@imakecomments]

Nah just confused on a lab report

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[@h4nood.]

i failed 😊.

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[@spaidory874]

my method: 1.) balance the reaction 2.) find the ratio (how many moles of this make how many moles of that) 3.) find the mr(s) of the substances you want to work with 4.) just put the mass given into the ratio after converting mass into moles brief version: 57 kg of aluminum oxide gave 17 kg of aluminum via electrolysis: 1.) 2Al²O³ ---> 4Al + 3O2 (balanced equation 2.)2 moles of Al²O³ give 4moles of Al so the ratio is 2:4 or 1:2 3.)Al²O³ Mr = 102 Al Mr = 27 4.) 57kg = 57000g 57000g ÷ 102(Al²O³ Mr) = 500 so 500 moles of Al²O³ were used ratio = 1:2 (1mole of Al²O³ gives 2 moles of Al) so 500moles of Al²O³ gives 1000 moles of Al this mass of Al= 1000 moles × 27(Mr of Al) mass = 27kg actual mass / theoretical mass so: 17kg/27kg ×100% = 62.9 % long explanation: (sorry the numbers appear as powers) 57kg of aluminum oxide gave 17kg of aluminum via electrolysis step1.) balance the reaction 2Al²O³ ---> 4Al + 3O² step2.) find the ratio of the elements we want to work with 2 moles of aluminum oxide make 4 moles of aluminum so the ratio is 2:4 or 1:2 (look before the element/comound in the balanced reaction and use the numbers to figure this out) step3.) find the Mr(s) Al²O³ has an Mr of 102 Al has an Mr of 27 (technically this is aluminums Ar since it is not a compound) step 4.) it says 57 kg of Al²O³ was used in electrolysis so we wanna convert this into moles: 57kg is the same as 57000g so 57000/ 102 (the Mr of Al²O³) gives us 500moles. so we now know that 500 moles of aluminum was used. lets put this into our ratio that we found out in step 2. ratio is 1:2 (for moles of aluminum oxide vs moles of the aluminum produced) now just use this ratio to find how many moles of just aluminum were produced. 1:2 -----------> 500:1000 since the ratio states that 1 mole of aluminum oxide gives 2 moles of aluminum. so 500 moles of aluminum oxide should theoretically give 1000 moles of alumimun. now we now that 57kg of aluminum oxide was used and that this equates to 500 moles of it so now lets just find out how much aluminim was produced in mass convert moles into mass ----> 1000×27(mr of just aluminum) gives 27kg (theoretical mass) we were told that 17kg of aluminum was produced so niw what we do to find %yield is divide 17kg(actual mass given) by 27kg and we turn that into a percent to get the percebt yield which should be 62.9 percent.

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[@natnaelsolomon4227]

What time did u finish writing this all huh

[@sebastian7494]

Thank you for the free help!

[@blakecos5467]

I use this it’s much simpler one u know it

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Absolute life saver, my chem lab professor works multiple chapters ahead of lecture and did not want to read more than necessary for my upcoming lab. Thank you! I should ace this quiz now.

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Thank you so much, as a maths lover it irritated me that I could not work out complex percentage yield and now, a day before my GCSEs, your video has saved me. Much appreciated.

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wow you have taught me in 6 mins more than any teacher in history of the whole world

[@jodycsinexjr8874]

Great video! My lab instructor is a new TA and he just gave us one example and turned us loose on solving a ton of unknowns. No one understood. Unfortunately, having a Dr. teach us in the lecture and his TA do our lab causes a huge disconnect. The TA does things differently than the Dr. who breaks things down in a great way. It is killing my grade! I am struggling to keep an A and that is not me! I have never made below 97% in a college course. Until now, I have pulled the grade up to 93% and that took more work than I am used to. Thanks for the great video, the theoretical yield is pretty simple, only he could make it hard! He NEVER mention the limiting reactant once! Pretty important information!

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I've deadass learned more from this than my chemistry teacher could teach in the last month

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this video saved me lmao. my first AP chem test is tm and this finally made sense to me

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Thank you for the step by step. it was so very helpful.

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[@infinitedelete]

Appreciate the quick video as review for my AP Chem clsss

[@zkillerwolfz3308]

You fucking made it way more complicated than needed, guys all you have to do is multiply the masses by the molar ratio that's IT

[@Liv_Rose02]

Thank you so much! My chem teacher is an idiot and only glossed over this topic without actually teaching anything

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Thanks

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MTV teacher skipped this part ,you are the best

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[@dilfheeseung]

Doing a quick cram for a chem test. Praying I pass it.

[@esmyyt3061]

How did you do

[@dilfheeseung]

@esmyyt3061 got a 38/50 [my fault for waiting like 2 days before the test to actually study for it] but it's way better than my original score of like 20 😅

[@daniellaportal2021]

You're doing god's work

[@Chickennuggetandfries]

u made this so easy!!!!! thank u

[@omarmm797]

Thanx, this is realy helpful

[@StevenGSamuel]

Thanks This video really helped me understand the concept But I have a qns. Is there a formula to calculate theoretical yield?

[@renatalmg]

This helped me so much thank you lots! I wish my chem teacher taught like this.

[@mouthofawhore4867]

Thanks for the video 🙂

[@puki4067]

istg this is easy but also so hard at the same time,, it's easily confusing... but your explanation is extremely clear! hopefully i'll be able to actually do my assignments on my own from now on TT

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[@nihilira6944]

Now if only I knew what solid precipitate was

[@somebody1026]

Bro simpliy we can calculate the theoretical yield like this : 44g of C3H8 = 132g of CO2 30g of C3H8 = X X = 30 × 132 / 44 = 90g of CO2 T.Y = 90g of CO2 If you don't understand this i just assumed that CO2 gram isn't given😊

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Thank you so much. I'm currently failing chemistry and have studied for 2-3 hours every night. This subject is super hard for me. I spent 5 hours studying this tonight, watching videos and reading guides and doing problems. Whatever you did differently, it helped. Something in my head clicked and I understand this now! Again, thank you SO much!

[@TheOrganicChemistryTutor]

You're welcome

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Did you pass?

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I wasn't at school for 2 days I missed the entire lesson like a dumbass

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Because schools don't check if the teachers are able to competently teach their students

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How come professors cannot explain these concepts this simply?

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Because they understand the material so easily and so they perform shortcuts to look smart meanwhile half of the class is failing due to their pride and arrogance. They need to show full examples of how to do the material but they dont bother and expect you to learn it by your self. Some teachers were never meant to teach and they know it and i cant understand why they are there to begin with in the first place. Not ALL teachers can teach. BUT TOCT is my Hero and i respect his craft it all make so much sense.

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Honestly, youtube has taught me more than school. Im in the 7th grade and i like learning about science for fun but school is just stressful. Thankfully, i have a good teacher this year and last year but my grade four teacher sucked ass. He was to arrogant to actually explain how multiplation worked and was trying to win an imaginary game of who can teach the fastest instead. I wish school focused more on teaching than grades and scores.

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i love it when mark wahlberg teaches chemistry

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i heard it too but after reading your comment i cant stop laughing during the video for some reason

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[@bailey125]

Kinda complicated method... simply put; [[Mol = Mass(g) ÷ Molar Mass]] ∴ 30 / 44 = (30/44) [= Moles of C3H8] 3(30/44) = 90/44 [= Moles of CO2 since there is a 1:3 ratio] 90/44 * 44 = 90g [Theoretical yield since molar mass of CO2 = 44] It was just coincidence that the molar mass of Both C3H8 and CO2 are the same

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bruhh i still dont understand a thing i suckkk at chemistry

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this is what i do everytime

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That's what I was thinking

[@khansaboo2030]

what if the ratio was 4:3 then??

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I know I'm like 4 years overdue but THANK YOU! Isn't it weird that KZbin videos are MUCH better than our actual teachers in school? Like all of the lessons I learned was from KZbin😅

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5 years overdue lmao

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his voice is such a comfort

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"you know". Nah but out of all honesty you're teaching me better then my chem teacher can/has since the start of the semester

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I'm in college right now and I have a Chem test tomorrow. This whole day I have had people pulling up to me asking me if I made chemistry videos because this guy sounds like me. 😂

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i’m a freshman in highschool and i have to learn this not even capping

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@@gerardohernandez5572 what on earth has you being a freshman got to do with people thinking this guy is the guy making the videos because they have a similar voice

[@plutoniumin]

@@gerardohernandez5572 same

[@strongfurygamer4484]

yeah i’m done w chemistry i still don’t know what i’m doing💀🙏

[@m.bilawalkhan7789]

another simpler method guys C3H8:3CO2 44 : 132 30 : x 132×30/44= x 90=x

[@Josama0214]

This is wrong and definitely isn't a simpler method

[@blackcat738]

to all of those wondering. here's a quicker way to do this. Actual Mass of C3H8 / molar mass (relative formula mass) of C3H8 using your answer times that by the Molar ratio difference (Example. H20 and 2H20 = 1:2) then time by that by the molar mass (relative formula mass) by the one you are comparing your molar mass to. as if it had a molar mass of 1. Here's how you do it. 1C3H8 = 30g compared to 3CO2 30 (g)/ 44 (relative mass of C3H8 12x3=36 + 1x8=44)= 0.681 (continuous) molar ratio = 1:3 (1C3H8 3CO2) 0.681 (continuous) x 3 = 2.045 (continuous) time that by the relative mass of the product (in this case 3C02 if it was 1CO2 which coincidently has the same relative mass as 1C3H8) CO2 = 44 (12 + 16x2= 44) 2.045 x 44 =90g 90% theoretical yield. the actual that we got is 70g/70% so its 70/90 (the smaller number is first.) x100% = 77.7% percentage yeild. there you go. hope this helps. (also I am not a teacher, I am a college student who just grasped this.)

[@scarlet5621]

Thank you so much!

[@blackcat738]

@@scarlet5621 even though its a year later. Your very welcome

[@jabary3596]

You explain it so well and your voice is very pleasent unlike my proffessor :)

[@ayaanlasheen2903]

It's a great explanation but you could get the theoretical yield by just using the molar ratio in grams. 30g of C3H8 and the molar ratio is 1, x grams of CO2 and the molar ratio is 3. Cross multiply and you'll get 90. it's way more simple

[@haaey1197]

3 years ago: watching for tomorrow’s quiz 2020: watching for quiz currently taking now

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It's something else isn't it?

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It’s cute

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His voice gives me anxiety. He sounds like he's either nervous or right about to go into a panic attack.

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Noelly Abreu the breathiingg

[@HMistry100]

Thank you! btw you sound soo much like Mark Wahlberg! lol

[@ferny198]

Don't mind me, just taking notes because I slept in for my Ap Chem class and wasn't able to know what everyone was doing

[@kittymowmow12]

My professor with a PhD in chemistry cannot explain any mathematical processes in laymen's terms. He makes everything SO difficult and hard to understand. Thank you, stranger on the internet, for doing this for all struggling chemistry students.

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I am sooo uncooked

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You've been my teacher for my whole chem course lol, my chem teacher can't teach.

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First time i didn't get his video🥺idm but really thankful that he uploads:)

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I understood from his other video and now i can do this question and all other yeild questions he is a REAL GOAT 🐐

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Thanks so much man.. you taught me more than my chem teacher did this whole year.. thanks bro keep it up

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i’m still so screwed

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Ai...He deserves a noble prize in chemistry man!!!

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Good luck on your tests everyone!!!!❤

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This dude works wonders. My prof teaches for 3 hours every lecture, and somehow makes the topic more confusing then it needs to be. Thank you for making things clear and organized.

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who come here looking for yield calculation in finance? its like you entering a wrong class

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Who else is here doing A levels💀

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What would’ve we done without your videos 😭😭😭 thank you so much ❤️❤️❤️

[@piczohun]

I've watched so many videos on this and yours is the only one that makes sense. Thank you!!

[@evaluna3979]

this video helped me review percent yeild but I feel like multiplying and dividing by 44 makes the equation longer and is kind of unnecessary. that's just my preference tho.

[@tayyabiqbal2143]

Literally 2 mins into the video and I get it already...Hope you hit 1 million .

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Im here because we have test later HAHAHHA i hope i won't get zero Heheh absolutely not cause you taught so good and on point.

[@Dr-zaam]

thank you it was very helpful .....thank you thousand times

[@rileymccue3641]

You explain these concepts so simply and smoothly much better than my current teacher, also your voice is really calming and its making me less anxious for my final, thank you so much!

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@LEARN WITH SHIREEN for the basic English concept Join 💯

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This helped me more than my chem teacher, really good stuff man.

[@lp6636]

I missed a day and I have no idea what the fuck this is

[@jansonbento4124]

Mark Wahlberg knows his chemistry.