Question 7 The displacement in meter of a particle moving along the X-axis is given by x=18t+5t^2.

[@dhanyabhat.k.r3574]

How do we get the acceleration as 10m/s2 at the end ?? Should we have to use differentiation?

[@noorarshiya1981]

Thank u mam 👍🏻

[@priyanishad4045]

How do get 10t in 18+10t

[@actiongaming8157]

v=d/dt(18t+5t2) =d/dt×18t+d5t2/dx =18dt/dt+d5t2/dx (diffreretiation rule 3 constant) and rule 1 =18+ 5dt2/dx =18×1+5×2t =18+10t

[@jayajoshi6953]

18=0_Constant

[@ThePhysicscatalyst]

we get 10t after differentiation of 5t^2 because d/dt(x^n)=nx^(n-1) when x is a function of t. So here d/dt(5t^2) = 5*2t^(2-1)= 10t

[@tiddisharma3931]

@@ThePhysicscatalyst can't understand

[@dishagujar7411]

Very good explanation mam, Thank you so much mam

[@ThePhysicscatalyst]

Most welcome 😊

[@dishagujar7411]

😊😊

[@nilutpalkashyap-sd5kp]

Don't say whole square...... Its t square

[@yashrajtiwari4701]

Good explanation!

[@ThePhysicscatalyst]

Thanks!

[@jayajoshi6953]

Mam why there is 10m/s sq

[@ThePhysicscatalyst]

because unit of acceleration is m/s^2

[@Mastershifu108]

@@ThePhysicscatalyst from which book this question is from

[@nilutpalkashyap-sd5kp]

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[@ap_singh650]

❣️❣️

[@shabanapardhan8034]

💕💕𝑵𝒊𝒄𝒆 𝒆𝒙𝒑𝒍𝒂𝒏𝒂𝒕𝒊𝒐𝒏 𝒎𝒂𝒂𝒎 😄😄.𝒌𝒆𝒆𝒑 𝒊𝒕 𝒖𝒑👏👏👏😜😜💕💕