There is more than one way to skin a Sudoku

[@JohnRandomness105]

18:40 Here's an interesting deduction about block 9. If the green part in the block has only one low digit, it must be R8C8 and can't be 1. On the other hand, the green section may have two low digits. In either case, the renban can't have 2. It's either 3-7 or 4-8. 20:10 Here's a version of you and your friend's deduction that follows from above. Once 2 is barred from the renban, we get a 19 pair in column 9, block 6. The right peach cell is the only cell in column 9 for 7, and the left peach cell contains 5. This forces 5 to join 3 on the line in block 2, and 6 in R3C9 as placed.

[@anaayoung9142]

What a cute thumbnail 😍 Did in 21:57 with some help. The 5 in row 8 was beautiful indeed! Interesting way to see the 5 in row 8 looking at the column 9, thanks for showing us that! =)

[@missingdeck9999]

Fantastic puzzle and loved your solve!

[@kana2112]

What a cool puzzle! And yeah, show the different bits of logic!

[@JohanWilt]

Disadvantage of that is I tend to judge if I can ( and want to ) solve a puzzle by myself first, just by video length. Which gets reckt by all the interrupting, getting stuck and getting help, and solving puzzles that he already knows. Showing different logic _is_ interesting, but it means I can't use video length to judge puzzle difficulty. But most puzzles I can do anyway; Bremster doesn't do the nuclear three hour solves of CtC anyway.

[@jeffreyturner2493]

The corollary to not having a 1 or a 9 on the five square Renban line is that it has to have 4 and 6 on it (either 23456 or 45678 in the extreme).

[@JohanWilt]

At the breakpoint I reasoned that the bottom right renban has to have 4, 5 and 6 on it, exactly one of them has to be on the vertical part ( because R3C9 can't be actually a 3 and forms a triple with R2C9 and one of R789C9 ), so R9C78 both have to be 456, and take it from there.

[@pastapete83]

This took me 30 minutes just to get the first digit, because I was so fixated on boxes 7, 8 and 9, I missed the breakin in box 1. But, after that break in, I found an easier way to resolve the 5s. Once you have placed the 7 and 1 in box 3, the 7 in box 9 gets forced. That then forces the 5 in box 9, and then you can roll 5s around the grid. 42:10 in the end.

[@praematura]

Gah, I had a very sloppy solve, and I think I made an errant deduction that just happened to be correct at one point, but did make it through in 31:31 (conflict checker off). Many thanks to randall for an amazing puzzle, and to BremSter for presenting it! Edit: Oh, should have waited until the end of the video. 😅 Yes, seeing the different types of logic was very cool, certainly do like the idea of doing this more!

[@林老師-i5d]

35:33 for me nice puzzle

[@ganimede17]

00:59:06