Your students are very lucky. When I was in the university, we had to deal with much harder problems in the thermodynamics exams, including double interpolations and complex systems.
@turk25893 жыл бұрын
By the way, your lectures are excellent, too.
@burakemreevrenos83852 жыл бұрын
Hangi üniversitedeydiniz hocam
@mdlass41244 жыл бұрын
Hey. shouldn't we also be using 0.0014 for v in the first part?
@engineeringdeciphered4 жыл бұрын
Yes, it looks like I accidentally used the volume of 0.014, but should have been using the specific volume of 0.0014.
@engineeringdeciphered4 жыл бұрын
But I think all the other numbers (the x and everything else) are still correct. I just miswrote it wrong there.
@mdlass41244 жыл бұрын
@@engineeringdeciphered oh okay👌🏽
@jasperaj24875 ай бұрын
@@engineeringdeciphered came to comments to also as that thanks sir!!
@asf_x13022 жыл бұрын
I think the Volume is 0.014 m^3 , which means the 14L/1000m^3 = 0.014m^3 the quality X will be 0.19 for state1 and 0.393 for state 2 .. Am I right?
@nourdarwish42772 жыл бұрын
I think the same; because in state 2 (vf & vg) changed, so the quality (x) must change to be equal to 0.394😅 And H = 1527.846 kJ
@ramiljr.donina40074 ай бұрын
specific volume was used, meaning 0.0014m^3/kg.
@sacrificemylifeforjuraku2279Ай бұрын
for the second part if volume and mass didnt change how come the specific volume has changed?
@mkhairulirwantarmedi73562 жыл бұрын
how do u find t
@DiyaPatel-v9r Жыл бұрын
This is a great playlist!! Do u have one for thermo 2 as well? i m taking it next semester after this course.
@ibraheemmuslih43892 жыл бұрын
How would I know if the 'x' value makes sense or not?
@engineeringdeciphered2 жыл бұрын
X is zero if it’s a sat liquid and x is 1 if it’s a sat vapor. And x = 0.5 if it’s halfway between. So if your value is closer to the sat vapor value then your x should be above 0.5. If your value is very close to the sat vapor value then your x should be closer to 1.
@ibraheemmuslih43892 жыл бұрын
@@engineeringdeciphered Thank you very much
@yigitcan824 Жыл бұрын
Professor where's the question 10 .Before this video its Q9 and in this video Q11
@nourdarwish42772 жыл бұрын
I think in state2 x isn't the same value as in state1; because in state 2 (vf & vg) changed, so the quality (x) must change to be equal to 0.394😅 And H = 1527.846 kJ, am I wrong teacher?
@victorcasillas80574 жыл бұрын
why didnt the equation for X, mass of vapor over total mass work ?
@engineeringdeciphered4 жыл бұрын
Because we don’t know the mass of the vapor. So the way I did it is easiest. There is probably a way to find the mass of the vapor but it would be a lot more work than the way I did it.
@victorcasillas80574 жыл бұрын
@@engineeringdeciphered Thank you.
@mothug9782 жыл бұрын
Professor, how did you find T= 0.61 C? Thank you in advance!
@mothug9782 жыл бұрын
I got it... through interpolation of the Tsat between 280 and 320 Kpa.
@abdallahhamdan45052 жыл бұрын
@@mothug978 can you explain it please
@mothug9782 жыл бұрын
@@abdallahhamdan4505 Your pressure = 300 Kpa, and need to find Tsat. By using Table A-12, you have to interpolate between pressure 280 Kpa and 320 Kpa to find your Tsat. Hope that helps