Thermodynamics - 3-5 Pure Substances using property tables - saturated liquid and saturated vapor

Download these fill-in-the-blank notes here: drive.google.c...
And now you can purchase my Thermodynamics notes completely filled in (184 pages of notes and problems) for $50 here: sowl.co/ksG5e

[@mishkamakani5847]

your youtube videos are sooooooooo helpful! omg! really sad to see this was three years ago. amazing content- really clear explinations and you are a great teacher

[@molemomoroke5974]

Thank you so so much. This lesson helped me for the test I am writing tomorrow .

[@tarikcil02]

Thank you dear mister greating from Turkey

[@melisaalfonso471]

Thank you for posting this. It really helped me, I was so lost before this video

[@franciscoluigi5519]

you are a life savior

[@ronniesilingwani8426]

soo helpful thank you professor

[@DC-yf5rb]

Thank you for the video, extremely helpful. However, what if we aren't explicitly given that the substance is a "saturated, superheated, or compressed" liquid? And we are only given pressure, temp, volume, etc. Would we need to use a vapor dome?

[@dilbarkhan4158]

saturated liquid glass vapour at 27 degree celsius is contained in a rigid steel tank of volume 0.1 metre cube it is used in an experiment where it should pass through the critical point when the system is heated the mass of water liquid inside the tank is

[@kennydalid9438]

thanks to this i hope you post more examples

[@alperenkurt2892]

you are a good man, thank you.

[@francismanlavi4849]

Love you bro

[@marcbrandonpoligrates7079]

just a question, it says 'Rigid tank' so it should have constant volume right? I'm confused

[@mobolajifasasi9428]

Please where can I get the steam table?

[@jrambo0617]

These are great.

[@sunmichoi6888]

thank you so much!

[@luisguevara4113]

I AM LOST... can anyone share why it is not p*delta V? the problem does not mention anything about adding heat... Q-W=deltaU + KE+PE--> there is no PE no KE... so how do you know when to use all the previous equations he used for all the different processes vs. Q=m(h2-h1) ????? Thank you in advance for any light you can shed.

[@firstlegend5105]

Because we there is no flow work, there is no change in flow work but there is a transfer of energy due to latent heat of valorisation. - There is constant pressure so there is no flow work. Since the question asks for the amount of energy transferred to the water, we are not talking about kinetic energy. Kinetic energy only refers to the movement of the particles per unit time.

[@hyperhero8345]

What are these table labelling standards called? They're the same in my thermodynamics textbook as they are in yours, so I'm wondering where that standardization comes from.

[@d7oom373]

when do we use internal energy because in question 3 I thought we have to use internal energy because of change in energy

[@engineeringdeciphered]

If it just says "energy" you need to include all energy change. Only calculating the internal energy change would be leaving out the energy change due to the constant pressure volume change. Enthalpy combines both internal energy and this energy needed to expand. (I may explain enthalpy better in later videos).

[@d7oom373]

@@engineeringdeciphered thx

[@kennydalid9438]

pls post also the pdf format for property table with the convertion table

[@kylevebar3909]

Different book different table different value

[@gerielombi-on1539]

Is 30°C can be a superheated water?

[@engineeringdeciphered]

Sure. At a low enough pressure

[@user-cd2eb6lo3s]

السلام عليكم عادي سوال استاذ