Software Testing Tutorial #34 - Equivalence Partitioning in Testing

Get all my courses for USD 5.99/Month - bit.ly/all-cou...
In this Software Testing Tutorial, we will learn about equivalence partitioning in software testing. Equivalence partitioning (EP) is a very important black box test design technique which is very widely used in software testing.
In this tutorial we will learn about equivalence partitioning with examples and how you can use equivalence class partitioning effectively in software testing and also explain this question in any software testing interview.
🔸FREE Training's at training.rcvac... 🔔SUBSCRIBE to CHANNEL: bit.ly/2YGU6JM
Help me in spreading the knowledge, please hit LIKE, SHARE, and SUBSCRIBE for the latest tutorials. More tutorial playlists below:
✅ ALL PLAYLISTS (Software Testing Mentor)🔸 / softwaretestingmentor
✅ ALL PLAYLISTS (RCV Academy)🔸 / @rcvacademy
✅ JIRA BEGINNER TUTORIAL🔸 bit.ly/jira-beg...
✅ JIRA WORKFLOW TUTORIAL🔸 bit.ly/2EzKOEB
✅ JIRA ADMINISTRATION TUTORIAL🔸 bit.ly/36MPPFR
✅ JIRA TUTORIAL INTERMEDIATE🔸 bit.ly/Atlassia...
✅ JIRA TUTORIALS🔸 bit.ly/jira-tut...
✅ ZEPHYR TUTORIAL🔸 bit.ly/zephyr-f...
✅ SOAPUI TUTORIAL🔸 bit.ly/Sopui-tu...
✅ JSONPath TUTORIAL🔸 bit.ly/2sIZIFG
✅ POSTMAN TUTORIAL🔸 bit.ly/2PBbhI7
✅ ISTQB AGILE TESTER CERTIFICATION TUTORIAL🔸 bit.ly/istqb-ag...
✅ ISTQB FOUNDATION LEVEL CERTIFICATION TUTORIAL🔸 bit.ly/istqb-fo...
✅ CUCUMBER SELENIUM TUTORIAL🔸 bit.ly/cucumber...
✅ TESTRAIL TUTORIAL🔸 bit.ly/testrail...
✅ AGILE TUTORIALS🔸 bit.ly/agile-tu...
✅ PYTHON TUTORIALS🔸 bit.ly/python-p...
✅ PYTHON BEHAVE TUTORIALS🔸 bit.ly/python-b...
✅ PRACTITEST TUTORIAL🔸 bit.ly/practite...
✅ JAVA TUTORIAL🔸 bit.ly/2F1iL1B
✅ ZEPHYR TUTORIAL🔸 bit.ly/zephyr-f...
🔶 ENROL IN MANY FREE TRAININGS ON RCV ACADEMY PORTAL 🔶
training.rcvaca...
🔶 FOLLOW US ON TWITTER 🔶
/ rcvacademy
/ swtmentor
/ mrmverma
🔶 LIKE US ON FACEBOOK 🔶
/ softwaretestingmentor
/ rcvacademy47
🔶 OUR TUTORIAL WEBSITES 🔶
www.softwarete...
www.rcvacademy...
🔶 GET MY TRAININGS ON UDEMY 🔶
www.udemy.com/...
#SoftwareTestingTraining #SoftwareTestingTutorial #SoftwareTestingBootcamp #SoftwareTesting #QA #QATraining #QATutorials #RcvAcademy #SoftwareTestingMentor

[@ammygill9769]

I am practicing for ISTQB from syllabus but couldn’t understand properly and through your video i got it,wow very nicely explained. Thank you sir.

[@sanchitrahate5803]

Watch it in 2x

[@amalacherukuri8103]

Wow.. what an explanation.. just one time for the clear picture.i have been watching your videos since two months. It's been really helpful. Every topic explanation.. u nailed it.. u r a really mentor..Thanks Manish.

[@Ane-genius]

I watched many videos to understand … but u don’t until I watch you’re video thank you so much you are the best 🙏🏻🙏🏻🙏🏻

[@tolentinoaramrhamyrc.6244]

Thank you Sir! I can easily understand the EQ!

[@SineQuaNon1]

Great video, as always.

[@hadiquafazal5653]

You make the content very easy . Good job

[@barzilaizio5833]

well said SIR. thanks a lot

[@softwaretestingmentor]

Thanks and welcome! Keep watching and sharing.

[@zahramahdavi9448]

Im so grateful, you explain sooooooo good

[@softwaretestingmentor]

Thank you. Keep watching for more videos and tutorials.

[@oxanajarkova7351]

Amazing explanation! I am a fan of your channel! Thank you!

[@karmelahrenovic8613]

Its amazing, thank you so much. Could you please do some more examples about black box testing techniques. :)

[@hiimanengineer9668]

Thank you so much for explaining this

[@softwaretestingmentor]

You're very welcome! Keep watching for more videos and tutorials.

[@Scarletteunjilee]

Great explanation, thanks!

[@softwaretestingmentor]

Thank you very much. Keep watching and sharing.

[@leonardoescudero8350]

What if you add 0, would that be considered invalid even though the problem says you can add whole numbers? It passes the 1 - 100 but 0 is still a whole number but I’m guessing 0 would still be invalid because it passes the input from 1 - 100. But I’m not sure, what do you think?

[@govindasharma8619]

Sir, regarding Equivalence partition 'example', wouldn't decision table technique more suitable for testing this example?

[@user-rw9xq3sf5d]

very well explained, thank you

[@softwaretestingmentor]

Glad you liked it. Keep watching and sharing.

[@mohanadadel6749]

Thank you sir , very helpful❤

[@softwaretestingmentor]

You're welcome 😊 Keep watching and sharing.

[@jennybeko1604]

Thank you so much...your tutorials are so well explained and easy to understand. Your son is so cute. He will probably be 6yrs old now. Halo Frands ..Lol... Hello Friends.....Hello cutie.

[@churafltet1215]

Thank u sir it's interesting

[@softwaretestingmentor]

Always welcome. Keep watching!

[@sameerkumarvishnoi1327]

Thank you

[@coolpix807]

Excellent explanation.

[@softwaretestingmentor]

Thanks. Keep watching for more videos!

[@P.D.V.Prabhashana]

Thank you sir

[@softwaretestingmentor]

Welcome keep watching and sharing.

[@shivbhaktamy]

Thank you so much. It means a lot really.

[@shubhamprasad8352]

Beautifully explained !!!

[@nigarsultana1739]

Awesome sir.

[@softwaretestingmentor]

Thanks a ton! Keep watching and sharing.

[@tashikasingh3664]

Hi sir, You have explained the concept very well. thank you so much for this. Regarding this concept i have a question which i'm unable to understand it properly Q. Postal rates for "light letters" are 25p up to 10g, 35p upto 50g plus an extra 10p for each additional 25g up to 100g. Which test inputs (in grams) would be selcted using equivalence partitioning? A. 8, 42, 82, 102 B. 4, 15, 65, 92, 159 C. 10, 50, 75, 100 D. 5, 20, 40, 60, 80 how to find equivalence partitions in this?

[@repackgamers5191]

option c would be appropriate

[@vishal3288]

Thank you sir ❤️

[@user-ly8jb7ex2q]

good.

[@reginachife5353]

Thank you. Please can you please help me solve some questions?

[@anastheticss]

loved it

[@atiyawarsi111]

Best one

[@softwaretestingmentor]

Thank you so much. 😊 Keep watching for more videos and tutorials.

[@krishnak6100]

Thankyou Sir but,if there is code in discount does that means we have to have seperate test case?

[@uchennaezeh5456]

Good

[@jordanfernandes4384]

How to check for decimal value above 1 and below 100

[@vidyapnair6516]

Hi I have one doubt is it possible or is it a right way to divide the valid value 1-100 divided in to 1-50 and 51-100

[@sachinbs984]

🔥

[@yuktasreddy8984]

what about 1.1? will that also be considered as a valid partition?

[@meetsaurabhtiwari]

What is the exact purpose of equivalence partition ?

[@gauravrajpurohit882]

actually I have doubt that if in an question been ask that a person can drive when his or her age is atleast 18 or no more than 60 then what is the equivalence partition in this case .... should we take 18 as valid or invalid ?? please give answer

[@leandrawoods8568]

atleast 18 would mean 18 is valid, I guess...

[@anamikatanwar1954]

👏👏

[@PRADEEPKASARE-bb2me]

👌👌

[@atiyawarsi111]

Hi How could I contact you for taking tuition

[@jeancarlo912]

A fitness app measures the number of steps that are walked each day and provides feedback to encourage the user to keep fit. The feedback for different numbers of steps should be: Up to 1000 - Couch Potato! Above 1000, up to 2000 - Lazy Bones! Above 2000, up to 4000 - Getting There! Above 4000, up to 6000 - Not Bad! Above 6000 - Way to Go! Which of the following sets of test inputs would achieve the highest equivalence partition coverage? a) 0, 1000, 2000, 3000, 4000 b) 1000, 2001, 4000, 4001, 6000 c) 123, 2345, 3456, 4567, 5678 d) 666, 999, 2222, 5555, 6666 can somebody answer that question? I know the answer as is part of the ISTQB exam, however, I dont understand the actual way to get to the answer, thank you

[@anghelutadragos1898]

@Jean Carlo Feoli We will start first by creating the partitions: The first partition is from min to 1000 ( I added min because we don't know the exact value it can be 1 or 0) The second partition is from 1001 to 2000 The third partition is from 2001 to 4000 The forth partition is from 4001 to 6000 The fifth partition is from 6001 to Max ( I added max because we don't know the exact value where the application will stop counting the steps) Conclusion: We have identified 5 partitions After this let's look at the answer provied and wich partition do they cover: a) 0 (covers partition 1), 1000 (covers partiton 1), 2000 (covers partion 2), 3000 ( covers partion 3), 4000 (covers partition 3) - in total this set of input values covers 3 partitions b) 1000(covers partition 1), 2001(covers partion 3), 4000 (covers partion 3), 4001(covers partion 4) , 6000 (covers partion 4) - in total this set of input values covers 3 partitions c) 123(covers partion 1), 2345(covers partion 3), 3456(covers partion 3), 4567(covers partion 4), 5678 (covers partion 4) - in total this set of input values covers 3 partitions d) 666(covers partition 1), 999(covers partion 1), 2222(covers partion 3), 5555(covers partiton 4), 6666 (covers partion 5) - in total this set of input values covers 4 partitions The correct answer in this case is d because it covers the most partitions. I hope this helps you, if something is not clear, tell me and I will try to explain it to you.

[@pradipvaghela3179]

​@@anghelutadragos1898 thanks dear, your example will help to other for more clearance about EP too.

[@shakyak.gurusinghe5821]

@@anghelutadragos1898 you explained so good🤝👌

[@Gaurisutar-vw2ly]

Are yar thoda to fast bolo sir

[@mrm-69-f6o]

Did you know that KZbin has playback speed option?

[@mindblow3029]

Not covered the topic thoroughly Not a good lecture just one example and topic is finished nothing else

[@elnino61]

Thank you