Three forces acting on a body are shown in the figure. To have the resultant force only along the

Three forces acting on a body are shown in the figure. To have the resultant force only along the y- direction, the magnitude of the minimum additional force needed is
#JEEMains
#JEEAdvanced
#NEET
#IITJEEPhysicsLectures
#JEE
#JEEMainsPreparation
#IITJEE
#JEEExam
#IITJEEMains
#JEEMainsExam
#IITPhysics
#JEEPhysics
#IITJEEPhysics
#JEEPreparation
#IITExam
#IITMains
#IITPreparation
#PhysicsJEEMains
#IITJEEPreparation
#JEEMainPhysics
#IITJEEExam
#IITLectures
#BestCoachingForIIT
#OnlineCoachingForIITJEE
#LearnLiveOnline
#OnlineJEECoaching
#OnlineClasses
#howtocrackJEE
#strategy
#NEETpreparation
#NEETPhysics
#NEETExam
#NEETLectures
#NEETPhysicsLectures
/ riteshdahiya

[@ourlifestyle9421]

Anyone for NEET 2025? 👀👀

[@insta4722]

😂

[@madhoni9838]

2026 bro

[@SujatSirsat]

Sir solving whole Aakash module 🤌😎

[@CODE....]

Effortless

[@mdmotiurrahaman5735]

Dc Pandey is better

[@SujatSirsat]

@@mdmotiurrahaman5735 for neet aakash modules are enough 🗿

[@waibhav_keshri]

Who is best aakash module ya allen module physics ke liye btaoa koee

[@HarshSingh-pl8xs]

​@@waibhav_keshri Allen

[@ParnaMukherjee-m7z]

This question is from ..Allen +akash+errorless+DC Pandey+Arora(i checked from my errorless and my school friend's books)...almost same questions hai sab book mein ... so no argument about Books and module ... difference is in the type of summary about the topic ..

[@ankitabiswal7852]

Thank You Actually this question I have tiered so many times and also with help of so many sources but I was unable to understand but here I understood ...!!!

[@Manumanu-ee9ws]

Me Also

[@BoomBoom-sc7ek]

So you both is dumb😅😅 only for fun

[@priyanshu9109]

Good explanation sir 🔥

[@saklin4439]

Amazing sir.

[@mohammadkhan-f7o]

thnx a lot sir you are the best keep continuing.

[@ncheepataiah8548]

Thanks sir

[@sanskrutichavan13]

Thankyou sir✌️🙌

[@mdmotiurrahaman5735]

3:14 that should be -1/2(icap) Isn't it 😢😢

[@kidsverse-moralstoriesandl2262]

Thank you sirr jii 👀

[@rohitpadwal1811]

Smile at end he gives 😎

[@Saturo_gaming_001]

° ° • ✓

[@Adi-qs7cq]

Smile dekhne aata hai ya solution

[@sar-cast-icbabaa2349]

the net force of f1 f2 and f3 comes out -1/2i directly so ans comes out 0.5N as sir ans is 1/2 then he takes -1/2??? 🙂

[@ism8299]

mujhe toh sir nervous lgre sb kuch glt boleee jaa rahe the isliye

[@narmakim139]

Can you please tell me in English, Why we are taking 4 sin in x direction instead of 4 cos. Please

[@toonami324]

To cancel the x component u have to take the opposite vector which means negative that's why it is taken as negative

[@_.saurav23]

Brilliant explanation!! Thankyou 🍁✨

[@ttglub2985]

Thank you so much sir

[@mohammadkausar9836]

Awesome explanation sir

[@sangamgayen6291]

Nice explanation

[@pritibhatripathi8762]

Thank you so much sir 🙏🙏😌

[@Wanderblogs4209]

Best explanation i got ❤

[@anubrata.876]

Thankyou sir

[@pranjaliingole8547]

Thank youuu sir

[@vedashtikar4546]

Thank you sir

[@naieemresearches]

Amazing

[@ShivaniBhusare-p5e]

Sir usme F3 ka angle Diya nahi hai to kaise liya o aapne

[@antrarana7131]

Vertically opposite angle hai..F1 k opposite ;)

[@Sadtimefriendo]

Last meh kuch garbar laga mujhe

[@rinasingh4298]

- 4 kyu aaya 😢samaj nhi aaya

[@Fcgaming-wv5fo]

Siuuu

[@brilliantmind1401]

Itna time nahi hota haii neet mai 😅😅😅😅

[@SidXD-md1dg]

why is there negative sign in front of x component of F1, i.e -4 sin 30 i ?? please help me out someone !!

[@Sachin_Tiwari572]

BCS vo negative axis me h bhai west me negative hota h (-i cap) ☺

[@islamicworld-s3t]

Negative coordinate mai hai

[@TukaramBiradar-lf2zp]

Because that force is present in 2nd quadrant so it's x-axis is negative so its component is in negative x axis and another component in positive y axis