To determine heat of neutralization of strong acid HCL and strong base NaoH

‪@a2zpractical991‬
Maharashtra Board practical
to determine the heat of enthalpy of strong acid HCL and strong base
heat of neutralization reaction
acid base reaction
12th class board
12th class heat of neutralization reaction
11 12th class heat of neutralization reaction
strong acid and strong base practical
to determine the heat of enthalpy of strong acid and strong base practical of Maharashtra Board

[@sadanandgurav5525]

2024 batch, tomorrow is my board practical exam thanku you for the wonderful explanation ❤🎉

[@a2zpractical991]

Plz share

[@nofear2875]

Which college ?

[@pruthvirajkshirsagar2607]

Same 😀

[@goreprathamesh9603]

Same

[@GauravWarkhandkarA]

Same 😂

[@BadRevengeIwasgood]

Neet aspirant now come there 😂😂😂😂😂😂😂😂😂😂 i am first one

[@a2zpractical991]

😅😅😅🙏🙏🙏

[@tahiramushtaq9522]

I m second

[@a2zpractical991]

@@tahiramushtaq9522 ohh

[@sahil4358]

Me also 😂

[@BadRevengeIwasgood]

Competitors from jammu kashmir 😄😄😄

[@kaifmansuri9078]

Tomorrow is my chemistry practical and I am watching at night 1:30 am 😂😥

[@a2zpractical991]

Best of luck 😁😁😁😁 Plz share also

[@user-yi4kr5nk8z]

I'm also

[@sadiamanzoor3949]

Helpful Watching from Pakistan🇵🇰

[@a2zpractical991]

Can u share in your study group

[@riya9050]

Awesome!

[@Drawwithmaddyy]

Thank you so much sir😊😊 aap jaise sir ke vajah se aaj hum jaise students jee rahe hai❤❤

[@gaushikkannaujiya5878]

Thankyou Sir ...Everything is OK... There is a calculation error...Q=100×4.184×2.5=1046 J...and onwards..

[@harshitkushwaha9923]

you are right

[@A.K.-zl1yo]

Sir you are great I didn't attend many practicals in my college and now tommorow was my practical so i was very nervous but after watching your videos now i am pretty confident to attend my board practcal. So Thankyou for this great help of yours and yes i have subscribed your channel ❤❤

[@rajugavhane098]

Nice explanation sir 😊😊❤❤❤

[@shravani_shelar_7660]

Thank you sir tomorrow is my board practical.... Well explained😊

[@Nessdmello-ox2ej]

Same bhai

[@spsarkargaming0065]

After 3 hour mera chem ka practical hai aur me abhi sikhne aya hu 😂

[@shrvan01]

Same brooo

[@ayezas4639]

love this, thanks! ❤😂😊

[@a2zpractical991]

Thanku..

[@sagarkumbhar3663]

Bhaut hi badiya sir thank you so much ❤❤

[@a2zpractical991]

Plz share

[@AhmadRaza-sx4xw]

THANK YOU SIR BCOZ OF YOU MY PHY PRACTICAL WENT GOOD

[@a2zpractical991]

Ohh plz share

[@a2zpractical991]

Kha se ho

[@anuragdubey540]

Nice 👍

[@akshaya5123]

Thank you sir this lecture help me a lot 🙌 ❤ tomorrow is my practical exam

[@a2zpractical991]

Wlc plz share

[@LordGaming9211]

Tomorrow is my chemistry practical and watching at 9:52 pm 😂

[@a2zpractical991]

Kal to holiday hai

[@LordGaming9211]

@@a2zpractical991 aaj hai Sunday

[@LordGaming9211]

@@a2zpractical991 and kal mere practical bhi hai hai 22 ko 😥😥

[@Pranjal_Mohare]

​@@LordGaming9211Ruia college me he kya ?

[@ShreyaShetty-cq4fi]

Tomorrow is my chemistry practical and watching at 11:52 pm😢

[@gregorythomas2826]

thanks Sir❤❤

[@airtel0974]

Thank ypu so much . Today is my board practical exam after 2 hours

[@a2zpractical991]

Best of luck plz share

[@airtel0974]

@@a2zpractical991 ok

[@visualjouneywithmanoj]

That is very well explained. Thank you !

[@a2zpractical991]

Kha se ho aap

[@Rohit123bhai]

Wow

[@Akshay109]

Wonderful teaching thank you very much sir 😊😊

[@a2zpractical991]

Plx share

[@a2zpractical991]

Plz share

[@apurvadesai7035]

Thanks sir today's my board practical exam 🙏

[@a2zpractical991]

Best of luck

[@shrikrishnavishwakarma3155]

Ab ase teacher ho to baccho ko sab ayega

[@a2zpractical991]

Thanku

[@vishalchauhan6768]

Nice sir

[@aashishsinha2306]

Sir if the value comes out to be -58.07 is it correct pls sir reply

[@KshitijK2]

Sir At 3:40 after noting t2 from NaOH solution do we need to wash the thermometer for finding t4?

[@a2zpractical991]

No directly do it ok.. If it's helpfull plz share ok

[@jahanman2khail102]

Thanks

[@MemeBrother_27]

Very helpful today is my chem practical i am watching before it 2 hour of my practical 😂

[@a2zpractical991]

Plz share

[@goreprathamesh9603]

2024 present ❤❤❤

[@ushajha8973]

Thankyou sir

[@a2zpractical991]

Thanku to..

[@NiluTalware-ps5cc]

Thanks for you sir

[@a2zpractical991]

Wlc

[@YuvrajSingh-es5er]

Thank you Sir

[@a2zpractical991]

Plz share if u r like

[@sunainapatil3361]

Bohot hard hai sir ye neutralization aur sublimation 😭😭 apne bataya nai mercury ka reading kaise lena hai

[@AANAYAK_BROTHERZ_04]

Calculation Should be corrected... Q=100×4.184×2.5 Q=1046 So, final Ans will be ∆H= -41.84 Hope it may useful...❤

[@a2zpractical991]

Aap kr lo

[@kumargautam-wy9qk]

0 5 mole hai kaise pta kar rahe hai sir??

[@jagrutipaste6369]

sir please make video on aksking question during board practical exam

[@a2zpractical991]

Already I uploaded

[@Quick.Recipee]

12th physics activity no. 5" Diffraction pattern using a laser beam " yeh practical" karwa do sir plz

[@a2zpractical991]

Ok

[@mohammedsaifi1646]

Thanks sir

[@a2zpractical991]

Share with your friend..

[@Jaykarn123]

Sir Please all practical ke video upload Karo na

[@a2zpractical991]

Ok

[@diptiranjanbeura5576]

But it should be 13.57kj for hcl vs naoh neutralisation

[@gaming1tap25]

Hii

[@user-mt5jo3rq7n]

1 doubt. when u multiplied 100x4.184x2.5 howd u get ans as 104.5 the ans is coming 1046 right

[@a2zpractical991]

Do it calculation its own ok

[@sumanmasanta7593]

thanks sir

[@a2zpractical991]

Wlc

[@lahanugaikwad8786]

Sir please experiment 4 chemistry vedio upload karo

[@a2zpractical991]

Ok

[@ramusheety6469]

Sir kay main appke channel main invest kar saktha hoo

[@sonisharma1697]

Very very nice explanation

[@a2zpractical991]

Thanku

[@sanskritichitral1742]

Sir my different of t4 and t3 was 2.25 it is correct or need to be 3

[@a2zpractical991]

U r right what u will get is right

[@a2zpractical991]

If u r like my video plz share in group college

[@sanskritichitral1742]

Actually initially I got the difference 1 but the teacher said it's wrong

[@a2zpractical991]

@@sanskritichitral1742 2 ya 2 se jayda aata hai

[@sanskritichitral1742]

Ohkk thank you so much sir

[@ADITYAKUMAR-pr2ms]

Sir practical book name बता दीजीए जिसमे का data video me show हो रहा है,,प्लीज fast reply very important

[@a2zpractical991]

Maharashtra practical book 12th chemistry

[@ADITYAKUMAR-pr2ms]

@@a2zpractical991 aap sir kaha se hai

[@a2zpractical991]

@@ADITYAKUMAR-pr2ms mai Mumbai se hu belong krta hu Uttar Pradesh

[@StudyAir-sv3sy]

Sir experiment number bhi likh ke dalo na samajme nahi aata konsa practical hai 😢

[@a2zpractical991]

Aim se pta kr lo plz ...

[@jasenmarndi4723]

Tomorrow is practical exam & watching at 11: 30 pm😅😅😅😅

[@a2zpractical991]

Best of luck

[@priyankamondkar1064]

Thank you sir 🤗♥️

[@a2zpractical991]

Plz share this video to other thanku..

[@Jaykarn123]

Please sir

[@a2zpractical991]

Ok

[@vishalchauhan6768]

Voice is not clear sir.

[@a2zpractical991]

Pehle ke video hai

[@michaelavishay8172]

why you do not use glaves

[@a2zpractical991]

I do.. Ok

[@sonalishukla6150]

Today my practical😢😢

[@user-pw5cu9lx4z]

Those who come before one day practical exam😂😂 are legend

[@vishalsharmaji4749]

Legend are watching 1 day before practical

[@a2zpractical991]

Kha se ho

[@asrarr2234]

5:24 104.6 kaise aya

[@gegeuiiu]

Error

[@anilpanmand8057]

Tommorow my board practical

[@_ansha_12]

Same

[@irfankhan-dn9rx]

Today is my chem practical and I am watching at 10:32 am..😅

[@a2zpractical991]

Ohh

[@hirahile5947]

Today is my practical 2:00 😂

[@xx_itachi_7703]

Calculation wrong hai 1046 ayega bich mein point nhi ayega

[@shaikhahad6447]

Hamer pr.exam Sa Sahara 😅😢

[@icawx12nikhils87]

It ll be 1046 not 104.5

[@icawx12nikhils87]

Even it ll be 41840 joules

[@sharmiladhamal30]

Q=1046 aa raha hai 104.5 nahi ata hai

[@saishtalekar9965]

sir values are wrong!

[@a2zpractical991]

Just a process u can slove it.. Easly ok

[@a2zpractical991]

Share with your friends

[@harekrishnakundu2700]

Q 's value will be 1200 joule . Calculation is wrong & enthalpy of neutralisation value actually -57 kj /mole ....... So, doubtful value .

[@a2zpractical991]

U r may bi right do it calculation with your self.. Ok if u have any dought ask me.. Ok chack out all videoo ok..

[@MRSHESSHHHHH]

Tvm walo Attendance lgao😂👇🏽

[@a2zpractical991]

Aap log TVM se ho

[@madhuripatil9405]

Thanks sir

[@a2zpractical991]

Oo

[@a2zpractical991]

Plz share with other