Transistor - 2 - MOS Capacitor Threshold Voltage

Transistor - 2 - MOS Capacitor Threshold Voltage

[@nomadshubham3907]

Best IIT prof Ive come across

[@vikky3905]

Where could I get the assignment questions and interconnect lectures?

[@ajiths1689]

Greetings sir, Firstly thanks for the lecture series !!... I have one doubt at 21:13 as, why you have written a Negative sign to the charge ... could you please explain ... waiting for response, thank you

[@bhatwaqar66]

As there is minority charge carrier that is electron in this case and immobile Acceptor ions, both having negative charge. That's why

[@anjalianand9359]

because....oxide inteface has become n type ....negativity charged.

[@HakunaMatata0707]

Professor has also incorporated the nature of the charge in the equation. As you will see further in the video, you will find that while finding the expression of Qi', he has only mentioned the magnitude and not the nature of the charge. That's why it wasn't apparent. If you drop the nature of the charge from your derivation, the process becomes very evident. But then you have to take care that you are using only the magnitude of the charges in the second case.

[@rishabvyas2812]

where can I find the lecture slides?

[@balajimg382]

drive.google.com/drive/folders/1UxrZOyjCY5fJz5O7xyAC3M8FwaoenUBp

[@_mixsingh_]

@@balajimg382 bro plz add remaining lectures slide too

[@ursblogger3410]

prev video recap 3:05

[@anjalianand9359]

how did u get Qi expression??? at 27:00 last step is really confusing 😏😑

[@amalenduaman7239]

The last Vth equation I am getting different

[@vikky3905]

@@amalenduaman7239 yeah

[@GauravKumar-oy3rj]

@@amalenduaman7239 yes....W/L should also be there...then the equation satisfies

[@GauravKumar-oy3rj]

its a qualitative analysis....inversion charge is only created when Vgb>Vth.....forming a capacitor so charge =capacitance * potential difference....ie....-Cox(Vgb-Vth)...and the negative sign is due to nature of charge