Tricks for Constraint Motion || Laws Of Motion 07 for IIT JEE MAINS / JEE ADVANCE / NEET

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Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test.

[@debasishpattnaik8454]

sure sir

[@riyamehra23]

Last question : 80 N

[@anujkumar-go9cz]

Sir modern physics chapter per video upload kare please

[@VishalKumar-zh1cq]

@@riyamehra23 kya tum explain kar sakte ho kaise hua 80N please😇

[@luminamathavan8894]

Nahi 200N answer hai

[@sanikadeodhar7205]

I was scared of all these type of questions...i am so glad i came across this video! Thank you!❤

[@sparkfacts5493]

❤❤❤❤❤❤❤❤❤❤❤❤

[@harkiratchadha]

Tru yaad

[@glitched_matrix44]

Same :)

[@arnavsinha834]

yeah man

[@PriyanshuKumar-lh7pr]

@@arnavsinha834 11th me gaye ho

[@xyz-qs8sr]

For last question N cos53=ma(acceleration of wedge horizontally ) Since acceleration of wedge=12, mass of wedge=10,and cos 53=3/5 => N3/5=10*12 => N=120*5/3 => N=200

[@yenusatyan9858]

Correct

[@being_aiimsonian]

👍

[@insiderswithpraveen6918]

Its wrong corrrct ans is 120 N

[@yenusatyan9858]

@@insiderswithpraveen6918 How?

[@yenusatyan9858]

@@devtripathi7317 😁😁

[@mrcharm767]

Behind every Sol of a tough ques there is a physics wallah who is making it a halwa ques

[@amanagarwal1382]

Shi kaha bhai

[@WizardVX]

Sahi hai

[@kunal6014]

Ekdum sahi bhaai

[@aadil579]

I like it👌👌👌

[@jugalkishore619]

Sahi pakde hi...😂

[@Gzrigel]

The answer of last question is 200N Solution: As the wedge moves in the shown direction with 12m/s2, the only force acting in that direction is Ncos53. So, NCos53=mass*acceleration => N *3/5=10*12 => N = 200N Thanks U SIR.

[@Mem_s67]

Thank you so much

[@shivareddy108]

It should be cos37 right?

[@abhisekdalai1225]

@@shivareddy108 No

[@sourthakjackmcober29]

N= 3/5*120= 72 newtons

[@rknif781]

wait that was the normal reaction you found. there's no need to use Ncos53 f = ma => f = 10 kg x 12m/s => f = 120N

[@shantaramchavan506]

Till date of 44 years of AGE ,THIS ONE IS MOST EASY WAY OF LEARNING , STUDENTS GRAB IT YAAR. IM PROUD OF YOU. SHANTARAM CHAVAN , KALYAN. GOD BLESS U.

[@kuriouskid1285]

@Damian Patriot time paas hoga. 🤣

[@alwinjoseph4682]

Must be a teacher?

[@hemalatha8351]

@@alwinjoseph4682 DEATH NOTE FAN!!!!!!!!

[@alwinjoseph4682]

@@hemalatha8351 lololol

[@alwinjoseph4682]

@@hemalatha8351 army as well lmao I saw your comment

[@arpitadesai5028]

There are many teachers who are expert but they dont know how to connect to a students mind...Anddd hereee comes you... Sir how nicely you explain such complex concepts very clearly and simply... You can feel a students mind.. 💙💙 Sir you are blessed from millions everyday.. And we are truely lucky that we all got privilege to learn from you... Sir simplicity level infinity... 💯💯💯

[@somya8839]

can you pls tell me that how we will come to know that in which direction the tension is acting???

[@sayansarkar9803]

@@somya8839 You can check sir's first video on NLM. There he clears the concept of tension and its direction

[@somya8839]

@@sayansarkar9803 yes i check for it...now my doubt is clear ..thx

[@sayansarkar9803]

@@somya8839 welcome

[@AbhijitDas-tt4os]

@@somya8839 opposite to the point of contact between mass and string

[@satyaneshibyomkeshbakshi2166]

Last ans will be 200N...the block is moving due to component of Normal (N)along horizontal...so Fnet=ma Ncos53=10*12 N=(120*5)/3=200N Note: Normal due to block =normal due to inclined plane(Newton's 3rd law)..so N in both the cases will be 200N...and that is the force which is causing the inclined block to move

[@shivapandey7018]

Thnx bro. I was not getting it

[@satyaneshibyomkeshbakshi2166]

@@shivapandey7018 you're welcome

[@jeekayvines1568]

Mera bhi 200 N aya

[@baba017bora4]

👍🏼😁

[@samitr3110]

But vertical equillibrium ki wajah se Ncos37=mg N=125 AARA H

[@nishtha8414]

Force of alakh sir's video subtratcts tension of students which is equal to awesome results ✨✨🤞🏻🤞🏻

[@iTz_Harsh127]

💙

[@harshitverma6550]

F=St-T=Ar

[@itz._IZUMI3940]

true

[@romanemperor9488]

🙂

[@jixpuzzle]

Nice one!

[@djm2187]

Force by wedge on rod is the NORMAL REACTION on it , Mass of wedge = 10kg Accleration = 12m/s^2 F=120N Also Ncos53 provides accleration 12m/s^2 So the F must be equal to Ncos53 N×3/5 = 120 N = 200N

[@shashivardhan6541]

Same answer here🙂

[@deepasaha4365]

Yep it's 200N

[@Sachin_Meena.]

Correct 👍👍

[@minaladhia3793]

Ncos53= ma(a=acceleration of wedge =12) N=ma/cos53 By solving N=200N

[@ridhigowri2521]

Thanks a lot😄

[@chanduudarapu7906]

Last question answer is 200N✌🏻, Process: Ncos53 = Mass of wedge x acc of wedge N= 120 /cos 53 =120 x 5/3 = 200N

[@shreyahaldar6911]

Many many thanks bhai🙂

[@kodurisl3696]

Yes for me also the same..

[@shakyaratnawahane6209]

Sorry brother but you are wrong ans is 80 N Bcs N=Mgcos37⁰ N = 10*10*4/5 N=80N

[@rudrakshkaila8435]

Same bruh

[@mayanksrivastava7540]

Sahi hai bhai 200 aayega

[@sourabgajurel4062]

Sir ,you became an inspiration for all the students. We are glad enough to have a teacher like you, thankyou sir for your sacrifice. We are with you ❤❤❤❤ .

[@thekidmagician7920]

Homework Answer - 200N Force is applied on Rod by the Wedge. Thank You so much Sir for teaching in such an Amazing Way. Lots Of Respect & Love to you Sir.

[@preetirawat7701]

Please elaborate

[@paridhibhardwaj]

I got 80 newton

[@अक्षतकुमारसिंह]

​@@paridhibhardwajyes it should be 80N

[@leandrawoods8568]

In case anyone wanted to check out the song in the beginning... It's called "Present Moment --- Eldar Kedem."

[@uzmakhan3853]

thnq...i was actually looking for it😅😅

[@abhijeetmachaveproductions755]

thanks bro

[@varishazafar4791]

Thanks.....I really wanted to know.

[@shruti4725]

Well in this case you don't know it's 'You and me' from same singer

[@leandrawoods8568]

@@shruti4725 oooh I didn't notice that... It was written in small letters on the front... But thanks

[@npsingh31]

13:50 yahi to mera aim hai..God bless you sir..We all with you no matter what's situation...

[@AmaanKhan-wo1ww]

Answer is 200N In order to find the force make components of normal reaction of rod on wedge then take horizontal component ( because it is responsible for acceleration in forward direction ) now make equation N.sin37°= (mass of wedge ) × ( acceleration ) Put values and you'll have the value of N.

[@rajaramgupta6554]

Tysm for your valuable reply

[@kiranshah5348]

Best way of explanation of ans Thank you

[@prajnaparida1880]

Thq for explaination in better way

[@herosoftheworld7]

But he asked force on rod by wedge right

[@lamishajoshi7480]

No,it's wrong we have to find force on rod by wedge ,so we will have to make N by wedge on rod N=mgcos¢ N=80newton

[@sudhakeraelugu8169]

I am taking coaching for jee in the institution but the teaching of alakh sir is so good as compared to our institution teachers. The way of solving the questions is so awesome and this is so helpful for us

[@ashokkothari9121]

Sahi kaha

[@ashokkothari9121]

You talk right

[@virendersingh-gz5cw]

Ques halwa ho gya.......👏😛😂😂best dialogue by alakh sir.....

[@shivampathak6167]

Sir answer of last question According to newton's law F = ma N cos 53 = 10 a N cos 53 = 10 × 12 N × 3/5 = 10 ×12 N = 5 × 10 × 4 N = 200 newtons😊😊 Sir many new teachers are there on KZbin but you make the studies like fun to us I am your great devotee and student 😍😍 Thank you Alakh sir ☺☺

[@yogipatel8531]

Thanks bhai mera bhi vahi answer aya or me sabka comments dekh rah tha ki kishine apna ans dekha to mila hi nathi sirf apka hi mila thank you....

[@shivampathak6167]

@@yogipatel8531 it's OK bro keep studying...👍👍

[@ig_kunala]

overall force will be 120 ....normal reaction will be 200

[@shivampathak6167]

@@ig_kunala ya i wrote the same thing N=200..

[@subhasmitapanigrahi4984]

​@@ig_kunalahow 120 N

[@mayankkulkarni3600]

Sir vapas piche kaise?? Plz ek heart sir Hit like if u think sir is best ever 👍👍👌👌

[@rajatpaul3784]

The final question given by Alakh sir was nothing but an IRODOV question. That's why Alakh sir was smiling

[@phijiks]

Answer bhi dedo

[@rudrakshrai.11]

​@@phijiks200N

[@phijiks]

@@rudrakshrai.11 hi can you please share the question no. So I can search solution from the internet or best if you know the link to solution can you please provide

[@rudrakshrai.11]

@@phijiks actually it is not the same which alakh sir gave, it is very similar to it. Irodov Q.77

[@darksungaming2524]

how bro can u pls explain@@rudrakshrai.11

[@yashdokania]

Sir you made such a difficult topic a "HALWA TOPIC" Thankyou Sir #PhysicsWallahIsGreat

[@somya8839]

can you pls tell me that how will come to know that in which direction the tension is acting???

[@uttkarshranjan8321]

@@somya8839 as tension is a pull force it will act always in opposite direction to any mass

[@somya8839]

@@uttkarshranjan8321 Ohh thx

[@prakharprakhar7693]

opposite to the points (Here,point : mass,pulley,m.pulley e.t.c)

[@Greem877]

What was ur rank and percentile bhaiya

[@himanshubaghel6288]

Sir plzz redox reactions We are not forcing but please sir Vote if anyone else wants

[@ayushjain8781]

Yes, sir please take next chapter as redox reactions......

[@khushiSharma-tl1qe]

U known redox hamre school me phele hi ho gya h 2 months phele

[@shantonughosh1388]

Yes sir plz start redox reactions

[@mymanindia]

@@ayushjain8781 organic

[@himanshubaghel6288]

@@mymanindia bro organic bhut bada hai usse pahle agar redox ho jAega to maja ayega varna organic hi chalta rahega bhut din aur hamare school me reaa raha hai so plzz

[@aesthetehere7316]

13:50 That line.. YAHI TO MERA AIM HAI 🙂💖

[@TheSaneInternational-SNI]

lyrics of the song which was played at the beginning: "i got time, its clear to see from up here the world seems small" it was so relaxing 👌👌😊

[@Tanishqkanojia1163]

Award do koi bhai ko

[@kitchenqueen4589]

Yes ,u r true

[@quateadfarid7100]

Gane likh le video kyu dekhta hai

[@ManishKumarmks_10]

1.Two best teacher alakh sir and 2. kzbin.info/www/bejne/jZvYoGSbfJZspdE .. ONLYJEE ASPIRANT MUST WATCH

[@harshsuthar2992]

It's not from up here .....it's from a pin😂😂it's from a pin the world seems small....but although great song!!

[@dhimansekharnath4143]

Sir , the answer of H.W question is 200 N . This is the force that applied on the wedge by the rod .

[@aryanshah1698]

CAN YOU PLZ EXPLAIN HOW

[@swayam7079]

@@aryanshah1698 bhai sun Acc to hamara 12 N Aara hai Aur mass of wedge 10 hai To net force = 120 N Aur N sin 37 bhi vahi hai so

[@swayam7079]

@@aryanshah1698 equate karke dekho 200 N as jayega

[@soumodeepchatterjee3248]

I also got the same

[@shakyaratnawahane6209]

Ans 80 N

[@UJJWALCSE-in1tf]

sir joh topics rhe gaye jee ke liye ab tak ke chapters me vo please january me pure kara do ge sir please please like if any one wants this

[@rachnabhatnagar3006]

Earlier I use to wonder what is so special about Alakh Pandey sir's teaching after seeing this video i think i have my answer . Superb lecture

[@scienceamateur5058]

Bhai thodi si padhai bhi kar le

[@AbhishekYadav-zj2jm]

Congratulation for 500k in very less time .sir you are awesome

[@sahiljain2524]

Congratulations to physics wall ah family

[@anjali8254]

Abhishek yadav can i ask from where u r

[@AbhishekYadav-zj2jm]

@@anjali8254 i am from varanasi

[@Harsh0401-t7h]

Me too

[@anjali8254]

@@AbhishekYadav-zj2jm is it chakiyan in varanasi

[@r.murali5945]

Actually I am south Indian, I don't know Hindi, but his lecture made me to understand this concept very clearly. His way of teaching is really appreciable.

[@BLG120]

Same here

[@unknownera241]

Naanumdhan

[@iameswar4482]

Same

[@41keerthanaa66]

Naanumdhaan

[@swadeshpramanik7038]

Aao ma

[@shikhachauhan7748]

*Starting song* Song name - Present moment Singer - Elder kedem

[@u_nknown4O4]

tnq 😐

[@takshdeadkiller2499]

Sir me 10 class me NTSE ke liye preparation kr raha hoon sachi sab kuch samajh aata he or aapse to JEE and NEET wale बच्चे padhte he unko to sabh 100 % samajh aata hoga fir bhi pta nhi baar baar aap ye kui poochte ho ki samajh aa raha he ?? Salut you sir...

[@mimonsk2874]

Who else is watching Alakh sir' s old videos for revision leaving pace batch classes?

[@baklol.0_0]

Last question answer:- Force on block by wedge = Ncos37° => 80N

[@kaiwalyabarde6604]

That's why work done in mind set of TENSION is always zero

[@adityashelke2662]

I love the you explain the concepts. Everything becomes clear more than crystal. You are the best physics teacher I have ever seen in my life.

[@dakshkaushik7]

"I love the you explain the concepts" I think you meant "I love that you explain the concepts"

[@versharawat2851]

Sir ,great trick, even my coaching teacher don't know ...... Thank you very much.

[@ruchikaarora4597]

Hn

[@secretagentrandybeans5846]

Coaching badlo bhai

[@secretagentrandybeans5846]

Ego hurt hogayi😅 And Don't worry I know how to manage my studies ..thq😌

[@ruchikaarora4597]

😂

[@ruchikaarora4597]

Vese common sense ab kya hi coaching badlenge..

[@MohitSharma-um8gj]

Is 200 N the answer for the last question bcuz in wedge the component of N in diretion of a should be equal to 120N , therefore Ncos 53=120 , ==>N=200N

[@motivationwithzabir7010]

Bhai T kaise kat ja rha hai

[@mitesh2k3]

👍 correct answer

[@tanishprabhavat7212]

No bro....N=500/3

[@tejasshetty519]

@@tanishprabhavat7212 he is right, how the hell did u get 500/3 XD

[@kunal6014]

Tanish it's totally wrong answer is 200N only

[@edugyangurukul7357]

The answer to the last question ... 200N For wedge ... a=12m/s2 Force(F) in the direction of acceleration=Ncos53 mass=10kg F=ma Ncos53=10x12 Nx3=5x10x12 N=200N ...... Force on rod exerted by the wedge ... Correct me if I am wrong ...

[@edugyangurukul7357]

@@nightbot487 Kaise.... Please explain ... 🧐

[@nightbot487]

@@edugyangurukul7357 ha Bhai mere se glti ho gyi thi 200N ki hoga

[@edugyangurukul7357]

@@nightbot487 Aacha Aacha ... Thik hai 😁

[@ayushijha9634]

Controversy is in your personal space ..as a teacher you are always my role model what you did may be wrong ...but it doesn't mean you can't be you are human and everybody makes mistake ...your motive is not wrong , what you did is for a good reason...those 42 lakhs Students of your ..who see you as teacher will be still be there for you..don't worry sir, you are here for a reason and that reason will be fulfilled great people don't get into controversies but they are included and that's totally fine..! We still love you sir ❤️ I want you to sleep with complete satisfaction today , becoz you are able to make change in life's of millions of student . You are gem with complete genuinty

[@Shreyash7807]

Last Homework Question Ans- Ncos53= 10×12 = N× 3/5=10×12 So, N= 200N

[@ShaunakKhare-qu5vx]

👍

[@KrishnaKher25]

thnks

[@accio_meatballs]

Can't we use acc component instead

[@gametech693]

Sir, you are really one in 'A LAKH', You are just GREAT!

[@chaitralipethkar2734]

ham to ye diagram dekh kar hi dar jaate the but now we are confident enough to solve these questions...... all thanks to ALAKH SIR

[@Windy5369]

The sound effects are amazing it really refreshes mind😁 and make the study more fun 💚

[@rajeshdash2922]

Wah sir what a explanation of all these concepts...... Really u r a great teacher

[@sekharraja8305]

When I started to seee ur lectures I love to develop good theroy

[@Chinnu-je7hr]

Whenever we have a movable pulley use the concept. Work done by torque is zero Therefore summation of T•x=0 diff wrt time 25:54 T•v=0 T•a=0 Points to be noted in the above expression it is dot product 17:06. Be careful about the sign of van x 10:23

[@pritamdutta9383]

Questions dekhne mein jitne bhayankar hai, solutions utne hi easy hai.... All credit goes to our all time favorite Alakh Sir..... Thanks a Lot sir....

[@rajveermandloi2316]

A very good morning sir , i m Rajveer Mandloi from Ahmedabad. I saw all of ur videos nd absolutely loved them all ur way of teaching is fabulous. I understood everything that u taught us through ur videos nd i was able to solve all the questions which u did in ur videos , but sir when i tried to solve ncert i wasnt able to solve it!! Like i cant relater with that nd i m not able to crack those questions. Can u please me out with this!?!? It would be a grt help sir if u could help me out with this with ur suggestion!! Plsssss do reply sir!! I hope u’ll help me in this! Regards Rajveer

[@arpitapaul6353]

Don't see sirs videos directly without knowing anything about the chapter.. Though sir teaches in a awesome way still u need to first know what u r going to learn rather than getting fully dependent on sir. So first have a quick overlook over the material that u r following, read it try to understand it of Ur own first . That will help u in getting Ur concepts clear and will help u to solve ncert questions which r mostly conceptual ones.If u don't know which book is a good book then take alakh sirs Pdf notes ,read them and then see the lectures . Probably this technique will be more effective. It's because I too faced the same problem that u r facing and I did the same and this technique helped me to improve

[@Rickdeb707]

নূরুল

[@joginaidugandi4677]

When i started to see ur videos then i started to love physics

[@anubhavtalus3890]

ok

[@carryminatimix10m51]

You are best teacher in the world

[@carryminatimix10m51]

Thnk sir

[@nh5043]

Last question ans: N=200 Newton Imagine wedge as a normal mass of 10kg, F (ie N) is applying on it downwards at an angle of 53° with the horizontal, So take components of F(ie N). Its component along the horizontal is Ncos53, no movement in vertical, so mass is moving due to Ncos53, no use of Nsin53. a is given as 12m/s²,m=10 kg F=ma Ncos53=10×12 N×3/5=120 N=120×5/3=200 Newton

[@krishnaverma4673]

Thanks😃

[@MIexperiment078]

I was having zero interest in physics but now i love physics just bcz of u sir .thxx a lot

[@epikherolol8189]

I was having -100 interest in 11th physics now I have 0 interest slowly it will go to +100 interest

[@real_name_hidden3782]

25:55 This one can be done using application of derivatives as well

[@anubhavtalus3890]

ok

[@phijiks]

How ? Can you show ?

[@Ani-nz6bw]

35:32 Sir : Kr paye the ye question khud se Me : sir 2❌ ki speed me pause krne ka muaka nhi mila toh chap liya sir: boht bdiya

[@omkarbansode7417]

Everyone watch in X2 😂😂

[@aayushithakre1632]

😂

[@Hiii-p5w]

23:00 as block a moves forward block b moves upward in y drctn

[@gagangagan6997]

Kya baat hai 🖋🖋 Wahhh 📖📖 Mashalla 🔭🔭 Superb 🔰🔰 Great 👋👋 Owsom💁💁

[@draculagaming1101]

Answer-200 Newton F cost 53 degree is equal to mass and acceleration 3/5=10×12 =120×5/3 =200 N

[@Lavanyayadav8118]

How is force Fcos 53°

[@Lavanyayadav8118]

@IITBOMBAY_CSE2024 okyy

[@ashishkumarmishra3000]

Homework question done......Answer is 200N...PROCESS:- NCos53=MASS of wedge x Acc^n of wedge 3N/5=10 x 12 N=40 X 5 N=200N THANK YOU SIR

[@shivamkamra8807]

Can we make components of component of a vector? I m just confused. If yes then there can be a component of mg along acceleration. I hope u understood

[@CheapPhysics]

N = mass of the wedge * (acc. of the wedge through the line of the normal force == 12 cos53)..... My ans. comes 72 N...... Can you explain my fault? ....

[@ashishkumarmishra3000]

@@shivamkamra8807 yes, you have studied THIS in NLM

[@ashishkumarmishra3000]

@@CheapPhysics You should take component of N,then try.. you will definitely get your answer.

[@joysplay.]

@@shivamkamra8807 Yes bro there will be a component

[@realitytouch3468]

Amazing sir . Ekdm achhe se smjh aa gaya😊😊. Thank you sir.😊😊😊

[@Varnika.]

Hw ques Ans is 152 N 100cos37 + 10×12cos53 Gravitational force mg is also acting whose cos component will be taken. Am I correctm? Little bit doubtfull since others are saying 200N

[@vivekpatel7452]

Sis. ans 200 N hoga In the diagram from Ncos53⁰=m.a2 By the way I am also not actually sure that it is the right ans .

[@Varnika.]

@@vivekpatel7452 ohh no problem still thankyou very much 😄 I'm glad at least you tried the ques😊

[@ayyajay]

Okay so, if we go by the basics, normal force is the constraint here, the wedge starts to accelerate with 12m/s² due to the normal force. When the wedge was at rest, it still had mg acting vertically downwards, but it didn't produce any acceleration in the horizontal direction, therefore we don't have to consider gravitational force component along N. Secondly, again N is the force causing acceleration, 12m/s² is the component of N acting along the x axis, therefore the component of N along x will be equal to 12•m, in your soln, you're taking the component of 12 along the direction of N which is incorrect. Having that explained, Ncos53°= 12•10 N= 12•10•5\3 N= 200N Hope this helps :)

[@Varnika.]

@@ayyajay thankyou very much this cleared a lot😃

[@hallamacchadunga7702]

Hit like who want sir upload tricks in physics for neet and jee

[@yenusatyan9858]

Me

[@arnavnegi6099]

Mee

[@bhavyasri8668]

yes sir please upload

[@Tanish-sr3sq]

5 years later... still very useful

[@toofanibaccha2364]

Force on rod by wedge = Normal reaction Since the Second block is always in contact with the ground during the whole motion , we can apply the equation - Ncos(37)= mg N × 4/5 = 10×g N = (25g)/2 (If we take g=10m/s²) then N = 125N

[@PriyanshuKumar-lh7pr]

Correct ans

[@PriyanshuKumar-lh7pr]

Correct answer bro

[@srinuchandaka3959]

Massive respect to you sir.. because of you we are aceing every difficult concepts with less efforts.. Thank you sir🙏🙏

[@arjantiwari3529]

Ans of last ques is 200 N

[@tanishabijwe1502]

I got 80N ... Can you please tell me how did you?

[@dhannukumar2504]

@@closednotebook thanks bro 🙏

[@bhupendrayadav527]

Pseudoforce 120N...... 80N normal rexn

[@user-ki6pt2zg1h]

Kindly see this motivational video examination in life never give up-kzbin.info/www/bejne/oWXaZaOXoJtpjJI

[@jyotiswaroopsingh6333]

@@tanishabijwe1502 normal reaction on wegde component form N cos 53=120

[@bitupannath3794]

As its acc. is due to the horizontal component of Normal force on + x direction! So, Fnet = m*a Nsin37=10*12 N=120*5/3

[@dreampcsofficer1228]

N.cos37=mg N.4/5=10*10 N=100*5/4 N=25*5 N=125N(ANS)

[@tadaranung1391]

its 120 due to conservation of momentum

[@natureclub3825]

200 N ?

[@sheikhsheheemrizwan]

mgcos37°=N 10×10×4/5=N 100×4/5=N 4×20=N 80N=Normal Reaction

[@shauryavardhan8481]

29:19 I solved that in 2 seconds using a different method. If we consider the acceleration a1 to be the perpendicular, and the 3 root 3 acceleratioin to be the base, we can say tan 30 = a1/3root3 or a1 equals 3 m/s2

[@googleuser8030]

Yaa

[@daisyrose8392]

Yeah...Is this method is correct ?? For all these types of questions 🤔🤔🤔 reply me shaurya vardhan bro

[@swatisaoji7124]

@@daisyrose8392 @Daisy rose because the block 2 is moving as well as block 1 is moving..... Therfore the lengh we take in tan will change and our ans will be wrong Hope u understand Regards.. Atharva Saoji Physics teacher Kota..

[@nuclearff8601]

3:30 8:15 10:04 12:15 14:30 17:00 21:20 23:50 25:50 28:18(important) 33:15(important) 36:20

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when i start watching his videos..i just can't stop watching .. you're very great sir😇😇

[@dr.praveenshinde5588]

Ok

[@elementary1204]

Best haircut I have ever seen.😊. Thanks Sir for Such clarity of concept.

[@NEETASPIRENT-kr8qd]

Yhh

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[@Neo34014]

39:15 in that question, I think there’s an easier method inspired by a question of physics galaxy, a1 is perpendicular to a2. So a1/a2=tan theta and hence a1=a2 tan theta. Putting values we get same answer. I saw this method application in physics galaxy and found it easier and useful.

[@grandlegendfootball]

I don't saw the previous video of this topic but I understand how to solve this types of questions because of this LEGENDARY teacher

[@yajanttripathi6571]

80N is the answer of the last question given by Sir. The direction of N is along the x axis for the inclined plane(wedge) and that component is mgcos theta so, N = F = mgcos theta = 10×10×4/5= 80N. I am in 10th right now. I am preparing with the help of his videos!! Great explanation Sir. Fan ho gya mai to!!!!!

[@debasritaprusty6470]

Mera bhi same aya hai.. Best of luck....

[@yajanttripathi6571]

@@debasritaprusty6470 Tum kis class mein ho??? All the best to you too!!

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This video is really very helpful for me thank you very much sir, ❤️ From Arjuna 2024

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Best teacher of my life

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Sir thank you for this awesome methods and tricks. previously I was afraid of the complex pulley problems but I now I'm easily solving them. 🔥

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Congratulations,, sir ..for 500k subscribers,,, in. Short time,, it's ur hardwork and our love for u.. 😍😍😍🙏🙏🙏🙏🙏🙏

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Best*

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[@premranjan-vb2sr]

Is this for neet also?

[@AdityaKumar-gv4dj]

@@premranjan-vb2sr of course

[@krishdabhoya3801]

well explained sir and I wish that you become our compass in the journey of JEE/NEET till the end so that even storm strikes we would capable to handle our boat

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It is verygood sir ❤ thank you

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I loved that intro! It was comforting and felt like it implied 'no worries....you're gonna solve them' coz i got freaked out seeing the thumbnail of this video. Hats off to u sir,....you knowingly or unknowingly provide us what exactly we need. ♥

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We are proud of you, sir. U made me understand everything, cleared every concept, thank you sir. Can't ever thank u enough.❤️

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[@kirtimishra258]

The force on rod by wedge is normal rxn After that there is a vertical mg downwards on wedge and a horizontal towards right ma whose vector addition gives normal (N) and as ma and mg are inclined at 90° normal comes out to be √[(mg)2+(ma)2] which is 156.2 isn it that way and not than whyyyyyy

[@shikhamaninath3578]

You are the bestest teacher ever Sir 🙏🙏🙏🙏❤️❤️❤️

[@dr.shubhamkumar6185]

LAST QUESTION ANSWER IS 200N SOLUTION:- N cos53 = ma -) N x 3/5=10x12 -) N=200N [ANSWER]

[@shreyamondal4861]

I got 150N becz I done Ncos37=ma

[@nitin1914]

For the first time, I solved maximum of answers correct. Thank you alakh sir.🙏🙏🙏🙏🙏🙏🙏😢😢

[@iitbombaychalle]

If you can't solve Pulley problem Please visit my chennal

[@rajuprasadkeshari1230]

Guru bina gyan nhi gyan bina aatma nhi Dhyan, gyan, dhairya aur karma sb guru ki hi den hai Ar hm sb ki physics aapki den hai You are such a great teacher.. Guru purnima ki hardik shubhkaamnayen sir 💐🙏🙏

[@sanjeevkare7580]

your interaction is like friends and ur explanation is like movie which cannot be forget . sir , ur are best physics teacher

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[@nandiniagarwal7942]

8:41 I think acceleration of 1 kg will be 2a and 2 kg will be a... Am I right?

[@SaifKhan-yg3jh]

acc of 2 kg is double of acc of 1 kg

[@zohaibansari9261]

Mujhe in question se bohut dar lagta tha aur feel bhi nahi hota tha agar sir padha bhi de toh but jabse alakh sir ye lecture dekha hu toh pura feel aa gyi

[@karishmasah2580]

Alakh sir you don't know how much you are helping me and my type of students thankyou so much I promise you sir after achieving something in my life will definitely come to you for giving my thanks

[@iconic-clicks]

mee too

[@karishmasah2580]

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[@iconic-clicks]

@@karishmasah2580 yaa sure..