Class 11 chap 5 | Friction Force 03 | Block on Block Problems Friction | IIT JEE / NEET

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Class 11 chap 5 || Friction Force 01 ||Static and Kinetic Friction || Friction IIT JEE / NEET ||
• Class 11 chap 5 || Fri...
Class 11 chap 5 | Friction Force 02 | Angle Of Repose | Friction on Inclined Plane | IIT JEE / NEET
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Class 11 chap 5 | Friction Force 03 | Block on Block Problems Friction | IIT JEE / NEET
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Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chap 5 || Friction Force 01 ||Static and Kinetic Friction || Friction IIT JEE / NEET || kzbin.info/www/bejne/i4Slc2qqqcySkNk Class 11 chap 5 | Friction Force 02 | Angle Of Repose | Friction on Inclined Plane | IIT JEE / NEET kzbin.info/www/bejne/fqKblaKhediql6s Class 11 chap 5 | Friction Force 03 | Block on Block Problems Friction | IIT JEE / NEET kzbin.info/www/bejne/fnXLmZxsbdunrdU Class 11 Chap 5 || Laws Of Motion 01 || Newton's First Law Of Motion || NLM IIT JEE NEET NCERT kzbin.info/www/bejne/j6vbho2wgtefnLM Class 11 Chap 5 || Laws Of Motion 02 || Newton's Second Law Of Motion || NLM IIT JEE NEET NCERT kzbin.info/www/bejne/Y5eln3dmm9CMoLs 11 Chap 5 || Laws Of Motion 03 ||Pulley Tricks For IIT JEE Mains || How To Solve Pulley Problems kzbin.info/www/bejne/j3_HqaCEg8asZtU 11 Chap 5 || Laws Of Motion 04 || Newton's Third Law Of Motion ||Conservation Of Momentum kzbin.info/www/bejne/rICXg2CvaLGiY7M 11 Chap 5 || Laws Of Motion 05 || Spring Force || Spring Numericals|| JEE mains NEET All concepts kzbin.info/www/bejne/pabEdWSpd9mAebs 11 Chap 5 || Laws Of Motion 06 || Pseudo Force | Inertial and Non-Inertial Frame of Refrence IIT JEE kzbin.info/www/bejne/hZfdk2Vpf5megKc 11 chap 4 || Circular Motion 06 || Motion in a Vertical Circle IIT JEE / NEET || Critical Velocity|| kzbin.info/www/bejne/m2G3paxmi5akaLc Motion Under Constraint || IIT JEE MAINS and NEET Physics || KINEMATICS Class 11 / JEE /NEET || kzbin.info/www/bejne/faKaeXuVm92Ld9k

[@kashishagrahari2019]

Physics Wallah - Alakh Pandey sir 29:54 glt h u didn't take the value of fiction ie 0.1

[@choudharyofficals100]

sir stress ch ka baneye class 11

[@LoveLove-nb5ti]

👌👌🙏

[@nalandabasu8641]

Sir my mother is a school teacher but she admires how u make the students understand each topic so easily.....ur lessons helps me to manage my time for self-study without going to tuition

[@santoshkumarsoni3668]

Sir circular wala lecture nlm mai play list mai kyu h plz bataoo na

[@nupur8804]

My one advice to everyone please watch this lecture once again after sometime then, you will surely understand the concepts clearly, as this is among one of the complex topics so many can't understand it at first

[@GauravSingh-gk4sv]

1st time I can't understand anything

[@GauravSingh-gk4sv]

@@nupur8804 ok

[@afrozmustafa4952]

system of particles aur tough hoga kya bhai?

[@ShivaniSingh-gs9qf]

Yes u r right

[@jessicamarinagajpati2965]

I watched it twice then only got some clearity

[@rajshah8143]

at 29:54 I think you need to take the friction coefficient between 10kg block and ground as 0 instead of 0.1 as you havent considered that in the question. Anyways awesome explanation sir, I love watching your videos👍

[@ShubhamSingh-ri4ul]

Raj shah yes same doubt the max force will become 2.5N

[@srishhty_]

Shubham Singh i think the value of f(max) between the 10kg block and the ground is 15 N and that between 5kg and 10kg block is 10N so the 10kg block is not going to move anyway.. correct me if I'm wrong

[@AiimsFlyer]

Raj shah Yes i also agree i think that was 0 like previos question... That was mistake

[@AiimsFlyer]

Srishty Priya But relative motion is there and sir also calculate the accln of both block then how can any of one block is in rest?

[@prakhargupta2864]

yup

[@gametech693]

Sir, you are really one in 'A LAKH', You are just GREAT!

[@dmnxexotic0p55]

Good one bruva!

[@Beast56_z]

Exactly 🤏

[@audisuresgameplay5686]

Waah Waah What Wordplay!

[@khushipatel886]

Sahi baat

[@KartikGarg-s6f]

Wrong

[@flypheonix7835]

I have watched this lecture 1 time and understood almost 60% and I will come again to understand more..

[@swityyadav8333]

Happy teachers day to one of the most amazing teacher

[@athulkrishnapv4364]

The only teacher telling acceleration as asceleration lol

[@delusionalplatonist6077]

@@athulkrishnapv4364 Toh kya hua, pdhate toh acha hai na

[@ssubhashini6121]

@@athulkrishnapv4364 So what? Did you come here to learn the pronunciation of acceleration? Sorry but it is not an English class. This is a physics class where the best physics teacher teaches. It is unbelievable how one can be so ungrateful to say such mean things.

[@ssubhashini6121]

@@delusionalplatonist6077 Exactly!

[@athulkrishnapv4364]

@@ssubhashini6121 get lost

[@shashiraj695]

28:38 Fmax changes ,because now in this question lower block also has Friction coefficient, but in previous question lower block don't have any friction coefficient ,so Fmax changes

[@noname-jl8sp]

But 10block shouldn't move because sir didn't considered coefficient friction bottom

[@fantasyplays425]

@@noname-jl8sp yes

[@BushraKhan-ek2jc]

I was looking for this comment. I think sir forget that he has taken a value of co efficient btw lover surface and block

[@shashiraj695]

@@BushraKhan-ek2jc yes ,may be

[@BushraKhan-ek2jc]

@@shashiraj695 have you solved with taking the value 0.1 can you tell me what did you find the value of a max and Fmax Please

[@aryanverma8344]

For everyone who got confused in 28:08 question Sir made a mistake instead of writing 0 sir wrote 0.1 so fmax wouldn't change as when he made the 10kg fbd he considered friction of 10kg be 0 So don't get confused

[@supreeth6315]

Or it could be the either way around? Probably sir forgot to use the 0.1 mew value in the 10kg blocks FBD...

[@v.i.pgamers7275]

right

[@teacher.student-7525]

Right

[@AdarshKumar-ks4dx]

Mai 0.1 leke solve kr rha tha aur ans nhi aa rha tha

[@SamudraFlavorsYT]

@@AdarshKumar-ks4dx ikr me bhi

[@wrickbasak8666]

28:08 In this case if we take 2nd μ=0.1 The 10kg mass does not move because it kinetic friction of above is less than limiting friction of 10kg mass. So the accn of 10kg is 0 And of 5kg relative to 10kg is 8ms-².

[@niranjanshastri7816]

Yes you are right

[@PradeepKumarThottathil]

Yes

[@narensinha8578]

shouldnt 2nd move backwwards

[@simranbahal1968]

​@@narensinha8578static friction can change it's value to make relative motion zero

[@vikaschandraf1231]

Yes thats why he had Fmax = 15 of previous question. Floor is frictionless.

[@Diiacreahsi]

28:00 mint waale sawaal mein galat hai sir , 15 N not max force for that because their is friction0.1 between lower block and surface where as in previous questions there was 0 friction between lower block and surface..

[@himanshushekhar2734]

sahi bola

[@bhikalalkag8415]

Yes it's ❌❌wrong

[@mukultiwari2339]

Ha bhai sahi keh raha hai 🛠️❌❌❌❌❌

[@narasimhareddy1234]

Fmax is 12.5 N not 15 N in the sum 28 min

[@virtuous3188]

@@narasimhareddy1234 Fmax will be 10N

[@vercotiseredemption5342]

Alakh sir exactly knows the mindset of the students. I have never come across someone with teaching experience as good as alakh sir . You really have raised every bar of teaching any teacher could possibly have set.

[@ankushroy3577]

amazing hai yaar yeh video kya video hai bhai maan gaye alakh sir is the best

[@saurabhchaudhary2110]

Do you alakh sir?

[@sankalpsahasrabudhe3003]

@@saurabhchaudhary2110 yes I do alakh sir 😁😁😂

[@History-Geopolitics47]

Sir rolling friction

[@vishveshmokariya4227]

Coolboy Sankalp lol I also do alakh sir...I do alakh sir every day😂😂😂😂🤣

[@fanclub3199]

Kuch samaj nahi aaya

[@amadelfarooq]

At 29:54 if lower block haa u =o.1 than fmax changes and it comes out to be 12.5 ,and still f>fmax therefore both blocks move with different acclerations of 8 and 1m/S2 .and friction =kinetic friction .at last f' limiting on lower block when force is on the upper block will act in opposite to the direction of f'limiting on 2nd means here 10kg block .thnku

[@vidhurraina6207]

Sir ne galti se niche friction likh di lekin sir ne 0 mana h

[@cppandey3377]

Physics wallah : like Unacademy : comment

[@rohitprasad4740]

😁

[@kalyanidas412]

@@rohitprasad4740 physics wallah!!!!!! 😃always..... ✌✌

[@rohitprasad4740]

@@kalyanidas412 math ka best teacher KZbin par kon hai

[@kalyanidas412]

@@rohitprasad4740 qki mei maths nai krti mujhe koi idea nai h maths k teacher ka but pandey sir physics n chemistry k liye best h..... Mere liye.... 😊

[@rohitprasad4740]

@@kalyanidas412 your are preparing for neet

[@akashP998]

Sir apke videos dekh dekh k mene class test top Kia chemistry ka Kisi ne b expect nhi Kia tha (kyonki m koi tution b nhi jata) Thank you sir 😍

[@manthanpathania1789]

Optimistic 007 same here bro. . ...a very big thnks to sir.....🙏🙏

[@cricketspeed6655]

Yr mai bhi 2nd topper Huge thanks to sir

[@manthanpathania1789]

Hey...everyone...should we make a whatsapp group for better discussion on class 11 topics ??

[@sahilsayani1505]

MANTHAN PATHANIA yes

[@sahilsayani1505]

MANTHAN PATHANIA sir ko bhi add karte hai

[@sakshamsharma7751]

I love sir's accent while sayin *"aksleration"*

[@AshwaniVerma-w2u]

Bro sir say ascelaration

[@UV.475]

Acceleration*😶

[@Unitainment00]

Askelleration!!!*

[@helloharsh08]

​@@Unitainment00yeah😅😊

[@zaviyar9585]

Yessss

[@gauravahirwar4083]

The Man behind our success in the exams ❤️❤️

[@sakshim.3156]

Sir not only this one..but all of your lectures are BEST among other on youtube..😃

[@krishnaprasad5391]

i am too a big fan of alakh sir but physics galaxy lectures are at next level not in explanation in explaining no one can beat alakh sir but questions

[@pracs6520]

​@@krishnaprasad5391 are all his free lectures enough for jee mains pls help buddy?

[@simplinnocent7180]

@@pracs6520 yes

[@deepakpradeep3820]

@@pracs6520 It depends on you.If you think you can then you can.Just work hard.

[@Rishabhkumar-ue2uc]

Wpqeoiwiwrqiowqiwoz will point uiziqw wupAqpw

[@yashjoon3889]

Let me clear the confusion at 28:00 problem just to help people as I was also confused at the starting Look value of limiting friction on 10 kg block due to 5 kg block is given by u N = 0.2 * 5 * 10 = 10 N. Now limiting friction on 10 kg block due to ground is : u N = 0.1 * (10+5) * 10 = 15 N Now closely analyse the system and see that friction due to ground is higher than friction due to 5 kg block . thus the 10 kg block wouldn't move at all, at any force applied on 5 kg block. Hence 10 kg would remain at rest and acceleration of 10 kg block would be 0. Now to find acceleration of 5 kg block make FBD. On making FBD we get friction force backward as 10 N and applied force forward as 50 N Thus net force in forward direction becomes 40N and a=f/m thus a=40/5 = 8m/s^2

[@sandhyavinu492]

Yes 10kg block will not move at all

[@sumitkumar4670]

Thanks man it helped me a lot....

[@drdriver9064]

Right bro

[@ashishkikaksha8534]

47:23 if the weight of upper block(let it is 20 kg) is more than lower block(=10 kg block) then is it move together at the condition 15≤F≤45 Sir plz 🙏

[@moonwalkers2005]

This comment 💬 should be pinned

[@jashansidhu086]

I am really luck that i born in that generation where physics wallah is there 😍😍 thanku sir

[@geet8890]

kzbin.info/www/bejne/hX6bdmCGoJ2BZ7s

[@bipinmishra3477]

RIP English!!!

[@HarshYadav2004]

@@bipinmishra3477 lucky mein bas y lgana hi toh bhool gya hai wo aur kya

[@reflexop8584]

kuch jyadha nahi ho gaya

[@artisticnoob5003]

50 rs kaat overacting ke

[@Professorgamer7780]

When sir u say that "dont worry y'r concept will crystal clear" I really forgot my stress 😝 I ❤️ u

[@headoverclouds]

At 50:35 , friction between 10 kg block and ground will be kinetic friction and not limiting friction as the 10 kg block is in relative motion with the ground.

[@studybro__]

I was just looking for a comment about that thanks

[@Hottbabe-qu2nz]

Kaneki in ur dp nice💜💜

[@ritulranjan7754]

Amazing sir i regret that i found ur channel very late

[@shang_chi4651]

Same here bhai

[@047-lakshaybhugra3]

Same yaar

[@aneeshaprasannan4130]

same here

[@ajaysinghnaruka2000]

Same here

[@afzalimam09]

Same here

[@anirudh_444_]

31:44 sir u didnt consider the friction b/w the block and the surface which is .1, if considered the acceleration will become .5

[@iminvinsible]

No bro the block would have been at rest cause static friction is self adjusting.

[@sarojupadhyay-pi9yz]

​@@iminvinsibleplz clear mine also coming -.5 in negative direction acceleration

[@goodwillcreations4097]

Sir in 3rd question, u=0 should be considered for surface ....only then a of 10kg block will be 1m/s^2 ...if not a=0

[@manojSingh-vx5mx]

At 32:35 there is friction between the block and the ground also ..so the net force on the 10kg block is 15-10=5 and the acceleration =.5 Yr explanation is so awesome that some small mistakes can be ignored

[@jaihind2798]

Same I am just searching in comments for this

[@jojo46674]

But 15;Newton which is limiting friction greater than 10N external forces so block will not move😢

[@sauravsangwan9358]

Success in not clearing iit jee ,neet or other competitive exam ,the real meaning of success what i have learnt from alakh sir is devoting your life for making other's life successful

[@Rajvardhantiwari1103]

Yes same thinking here bro

[@aryamasingh8706]

point to be noted

[@kavitarodge8171]

@@aryamasingh8706 lol

[@sananaz2940]

Well I don't know about jee but in neet you devote your life for other people and their lives So kind of like the same thing that sir is doing. Obviously every profession has its pro's and cons but please don't disregard all those who prepare for these competitive exams

[@epikherolol8189]

U are partially correct. Success is not defined. It varies from person to person. For one person success might be getting good marks in exams, while for another might be getting into a relationship, while for another one might be to start a business... It's relative

[@stillalive2359]

31:05 sir there is friction between 10kg block and the surface! Why u didn't use that (u=0.1)?

[@madhavsharma6643]

yaaaaaa

[@madhavsharma6643]

so i think 10-10/10 = 0m/s2 for ground se attached wala block right?

[@theimaginer6661]

Same question

[@theimaginer6661]

10 kg block will not even move

[@BrijeshKumar-vo3un]

This will be given or decided in a question

[@harshvardhan5484]

Sir I don't have words to explain my feelings towards you and your way teaching. That's why I don't comment on your every video but I pray for your long , healthy and lovely life. Thank you sir for everything. 😊

[@DRaghunatharaoPH]

I learnt not only physics but also Hindi by his classes... Love from AP

[@AbhiKovella]

Yeah brother Mee too

[@alok-IIt_aspirant]

​@@AbhiKovelladistrict??

[@seemaban1675]

No matter how much we use technology in education, these videos are just evergreens. ❤️

[@jyotsanapatel8230]

you made me fall in love with PHYSICS.....thank u sir ! ❤

[@blackcharge4700]

I s this jee level video??

[@sanjoydasfansoffical8885]

@@blackcharge4700 yes

[@erenyeager2815]

37:00 here for finding acc we can also consider the blocks as a system and apply f net by total mass. it will also give the same answer

[@tiyaagrawal6905]

How can I thank you ? You’re the best physics teacher - every other teacher should consider you as their teacher 👨‍🏫

[@vedaantkurmi5483]

very correct

[@JesssEEe9]

One dought ?

[@carguy7480]

Timestamps: 3:10 block on block 6:20 steps for b on b 12:46 q 17:40 q 23:40 q 27:40 q

[@snakeuhatessprite8288]

Thank you

[@manavbhadoriyaxiithb4928]

Ye kse kr te h bhai

[@oumgupta1640]

@@manavbhadoriyaxiithb4928 just write that time example write this during commenting ( 01:00 ).

[@Confused_dreamer]

Thanks bruh

[@AKFCANIME_BACKUP]

Thanks

[@khubaibakrami1739]

Duniya jo bhi kahe... Par.. Aap ka duster..😂 Aap ka marker..😂 Aap ka teaching style...😍 Sub kuch BEST..... 🤷🤷🤷🤷🤷

[@subhammondal7850]

Sir sir sir mai bol raha tha ki ye 30:41 wale samai mai wo 10 kg k block ke upar friction kam karega ya nahi matlab waha pe aapne MYU Ki value di hai 0.1

[@coderYT1]

SIR! Teachers like you on KZbin has made concept clear FROM EACH CORNER OF INDIA.

[@gaurinandurkar]

hi

[@studystudy7034]

Indeed the best lecture on block on block problems on the internet!!!!!!!!!! Such a headache topic but so beautifully and smoothly explained by our alakh sir😘😘😘😘

[@zubiyanoori924]

We have all witness alakh sir journey from a simple white board to a smart board...He really is the best..The board,of course doesn't matter his way of teaching...He work as hard as he does earlier...lots of respect..

[@Gotouchsomegrass-bs9nu]

At 28:30 , the F(max) = 7.5N The Acceleration of Upper Block will be 8 and the Acceleration of Lower Block will be 0 Sir forgot that the coefficient of friction between lower block and ground was 0.1. He solved the question thinking that it was 0.

[@gojoahahaha]

yes

[@burnt_toastt]

What will be the direction of f limit on lower block with u 0.1

[@satyamprajapat309]

Yes

[@sahilakhtar_07]

Bro ! My Fmax is 12.5 ! 😢

[@sarojupadhyay-pi9yz]

Sir forget f kinetic of lower 10 kg block I also caught

[@mukharjeeujjal]

THE REASON BEHIND MY CONCEPTS IN PHYSICS IS ALAKH PANDEY SIR...HUGE RESPECT FOR THIS MAN🙏🙏🙏

[@abhisheksilverrrrr]

In this whole video m1=10 kg, m2=5kg, Acceleration,a=2/3ms-² μ=0.2 Limiting friction,f=10 N Sir ek example pura concept clear karwa diya...♥️♥️

[@janhvi6589]

Good evening sir At 28:35 F(max) will be changed na Because in previous cases value of coefficient of friction of 10kg is 0

[@arindam3276]

Yes u r right. It will be at rest.

[@on60]

at 31:46 I think you need to take the friction coefficient between 10kg block and ground as 0 instead of 0.1 as you havent considered that in the question.

[@divyamahesh1200]

S

[@navindrayadav8277]

Sir,in question no.3,to move 5 kg mass,it must have to overcome the limiting friction on it due to10 kg mass and the value of it is =10N .since ,force applied (10N) on 5 kg = limiting friction on 5 kg.so, it will remain at equilibrium and it's acceleration= 0m/s2,,,,,,,,

[@milindpatel6633]

Yes bro ....

[@janhvisingh9179]

Hmmm same doubt??

[@riyathakur5515]

Thank God u commented this otherwise I was almost about to cry due to frustration 🙂🙂🙂🙂

[@sadhukrish3344]

31:18 Sir isme Ground and 10 Kg block ke bich me friction lagega to a=0 ho jayega. Sir loved your all videos.

[@namangupta4791]

Ya

[@ChiranjeebRoutray]

Yes 10kg move nehi karega

[@vinaydeshpande2754]

bhai 10N nhi 15N hoga, kyuki Normal reaction nikalne mai dono blocks ka mass conside kiya jata h, issliye 15N ho jayega, aur 10 kg block ka acceleration 0.5 m/s2 hoga in left direction

[@Ziyaulan]

@@vinaydeshpande2754 absolutely correct bro

[@riyathakur5515]

Thank God u commented this otherwise I was almost about to cry due to frustration 🙂🙂🙂🙂

[@smitasmita8951]

I didn't like physics but watching your lecture sir I feel that physics is a interesting subject ...very good explanation sir

[@drkomalpaul1864]

Yes same here

[@abdusabdud8218]

You can read physics by resnik Holliday

[@utkarshthakur5430]

@@abdusabdud8218 pehle NCERT sambhal le ...

[@mahendramishra1074]

Of course 😊

[@abdusabdud8218]

@@utkarshthakur5430 yes, firstly we should focus on ncert

[@ScribbleDraws]

This video shot under low light will make our future bright!

[@Diebnsjsj]

28:28 I think sir there you should calculate the f max as there is u-0.1 and precious was 0 anyway....I think a max should be 8mupons2 if am I right?

[@meenakshinagar9056]

Mhuja bhi asa hi lg rha h , ki sir sa mistake hui h yha pr

[@delta1_2_3]

Correct✔

[@Honeycomb_123]

Yes..I m also confused here

[@MuskanSharma-mt5bn]

Yes I thought I was wrong

[@ketanroy6663]

ya bro tb se vhi soch rha hu

[@preetisharma2782]

I wonder how can someone dislike his efforts

[@asutoshmishra9024]

PREETI SHARMA Coaching wale

[@kamranmdkamran7542]

Haa

[@manojbashist1220]

The jealous coaching teachers

[@sanjaykandpal1]

I am hod of Allen maths Kota I have dislike it

[@sambhavmishra5423]

@@sanjaykandpal1 Jhute..

[@Aupscaspirant7637]

At29:54 the answer will change accln of 10 kg block will come 0 ( rest) and accln of 5 kg block will become 8

[@RaviSingh-vv7tm]

Yaa

[@RaviSingh-vv7tm]

Yaa

[@tanveerraj9536]

Wrong sir is write 💯

[@real_selvan]

Yes

[@ms_smokey2055]

No dude...i thnk @ of 10kg block comes out to be O.5m/s²

[@nikenell9777]

In 32.05, acceleration of 10 kg block will be less than 1 m/s^2 since there is another Friction force which act on floor as well.

[@abhinav1052]

correct i got the acceleration as 0.5 m/s^2

[@daksharora1440]

SIR I WANT TO THANK YOU NOT ONLY FOR THAT YOU PROVIDE FREE LECTURES FOR PHYSICS BUT ALSO YOU INCREASE MY CONFIDENCE TOTALLY!!! MAY YOUR CHANNEL REACH 100M ONE DAY!!!

[@iamharshraj10]

Sir at 28:00 min as you have taken coefficient of friction between 10 kg and ground 0.1 but while solving question you missed it. I think that the 10 kg mass will not move as 10 N is being applied by 5 kg and 15 N is limiting friction value so the 10 Kg box will not move.

[@artwithuma5752]

Right bro...it won't move

[@NurulIslam-hj9om]

Right

[@niturajan310]

Right

[@sudhanshuchaubey3245]

At 29:54 You didn't consider the friction between 10 kg and ground... But then also wonderfully explained.Thank You sir 😊

[@inistheonlywayout4620]

Last question mai 10kg mass wale ko bottom se kinetic friction Nahi act karega kya? Why sir take limiting friction Please help me

[@rohannani4994]

@@inistheonlywayout4620Radder because it is not moving..... if a body is in motion then we will consider kinetic but in the previous question, the body is in rest as Flimiting is greater so sir consider static friction.

[@nishantsharma8690]

Yaar mujhe physics mei kya non medical ka koi bhi subject coaching mei nhi samaj aata mai keval toppers Ka face dekhta hu Lekin alak sir ko shayad hi bhagvan ne hum bachcho ke liye banaye hai taki hum bhi toppers ban sake ❤❤❤❤❤❤

[@anonymousforever1677]

I always regret that I didn't study physics from Sir in class 10th. Had I done it, my phyiscs would have been improved.

[@stethophillic1248]

me too

[@YuvrajSingh-hn2uu]

Sir, question no 3 ka acc max wrong h

[@madhusmitadas390]

I also😫😭😭

[@siddharthncv3960]

@@aarushgupta2309 its good, i dont see anything wrong in her sentence.

[@starman3533]

@@aarushgupta2309 bhai tereko zaroorat hai english classes ki

[@anveshasrivastava3096]

Sir you are the best teacher I have ever seen. Even my physics teacher also sees your video and recommend us to do the same. My physics teacher also teaches very well but your teaching is magical sir. Sir aapme jadu hai jadu :-)

[@Radhasahu975]

Sach me sir jesa koi nhi pdhta.

[@dipeshawasthi3131]

I watched this video earlier few weeks ago and I thought I can't understand 😭 and now I came up with new energy and finally I got it. Salute to you Alakh sir. Love from Nepal🇳🇵🇳🇵🇳🇵❤️❤️❤️❤️❤️

[@dipeshawasthi3131]

@ Completed Class 12 without giving exam😄😂😂😂😂😄😄

[@sharshavardhan4469]

In which class bro

[@hemanandadas1010]

fxgcbvhjkhgfdfcnvbghkhcvbghjnkl;kjhgfdcgvbhnjmk,.

[@rajendrakumarsharma9920]

Don't mine

[@farhanalam9611]

You are One in " A LAKH " ❌ You are one in " A billion " ✅

[@shaileshkumar104]

Sinh the best, you are very passionate about teaching physics. I respect two teachers late pradeep kshetrapal and now You. You are carrying lagacy of pradeep sir.

[@VISHAL-df8py]

Before 32:00 in the qn it should be mew as 0 on 10 kg block if this is correct then please hit like guys

[@anushkanath8741]

This is success... Physics wallah ads on Physics wallah videos

[@notaname8333]

I am still studying by your old videos ❤️

[@ajayrana8885]

me too

[@Daily_Dose.for_indians]

Mèe to

[@krishdubey4691]

❤️❤️❤️

[@subratapal806]

2:29 Sir you are best, so the video as compared to others is best 😊 "Love you Sir" from Kolkata

[@ctendstoinfinity]

I doesn't understand the block on block concept through New pace video, so I camed here, And I think I learned new new things, Btw I love RG sir too😊 no offense here.

[@oumgupta1640]

ohh bhai what a coincidence me too 😂😂

[@ctendstoinfinity]

@@oumgupta1640 Padhai kro broo December aa gya 1saal baad competition samne a kr kda ho jayega all the best 👌👍

[@anikasaini4237]

same here bro

[@shalendrasharma651]

Thanku so much Sir You cleared my each and every doubt. .. BEST TEACHER OF THIS WHOLE WORLD. . GOD BLESS YOU SIR.

[@see3945]

Not of this hold world idiot whole universe idiot

[@prithwirajroy3915]

sir, in 27:01 , by calculation the value of f comes 6.6 N (when we substitute the value of a). But you said that static friction is equal to the applied force until it reaches limiting friction. In this case limiting friction is 10 N, also the applied force is 10 N, then why f is not equal to 10 N, which is the applied force ? Also if we assume that f is smaller than 10 N, then there must be another force in the opposite direction of 10 N, which will decrease the net applied force and make it equal to f. Then which is this hidden force ? I think the hidden force is the pseudo force 5a in the opposite direction of 10 N, is this correct ?

[@EditsUniverse22]

Yahh me too got stuck there

[@prithwirajroy3915]

I even forgot that I had a doubt on Friction .. Still no replies 😔

[@AJ-oj7ze]

aur haa..idhr pseudo ka koi sambandh nhi banta...q ki hum jo kuch observe kr rahe h wo inertial frame se kar rahe h..mtlb ground pr se 🤟

[@AJ-oj7ze]

tumne friction ko turant "meuN" samjha wo mat kro pehele check kro ki Fs h ya Fk...Fs ka koi formula nhi h...'meuN' Flimit ka formula h

[@jikkymind114]

@@AJ-oj7ze YES BRO , LAGTA HAI TUMNE ACHHI TAYYARI KI HUI HAI. BY THE WAY , I LIKE THE WAY YOU DEFINE PSEUDO FORCE BY INERTIAL AND NON INERTIAL FRAME.👍💪

[@varshithakaja5043]

Very Thank full to you sir....All your conceptual videos made me confident on my Phy JEE examination.. Thank you very much sir

[@rajeshshukla1731]

Sir you had made me love!!!!!!! physics. I am glad I am at this where I don't have to wait for your next video.

[@gurigurm5801]

Samee

[@shishirkumar5981]

Konse clss m h??

[@geet8890]

kzbin.info/www/bejne/hX6bdmCGoJ2BZ7s

[@geet8890]

kzbin.info/www/bejne/hX6bdmCGoJ2BZ7s

[@hemantsaini4781]

29:05. sir 2nd surface par BHI friction force h to BHI Fmax. 15 hi Hoga kya ??

[@AryanLadani-cc1ou]

In 28:00 Question sir has written frition between 10 kg block as 0.1 but has solved whole questions by considering as friction 0. So its just writing mistakr

[@vimalvermaofcl6933]

@Physics Wallah - Alakh Pandey at 28:51 you take u=0.1 I think it should be 0

[@paritoshtiwari276]

28:38 galat kiya hai sir ne kyuki agr meu ki value 0.1 loge too amax negative Aa jayega. Jo hoo nahi sakta kyuki blocks applied force ki direction me move kar rahe hai.

[@kapildevkaran511]

Yes same here sahi bola

[@dazzlingbeauty9006]

Sir pl upload videos of work power and energy(IIT jee) And also upload the videos related to the questions of HC Verma

[@saradameher8788]

yes it will be great help

[@Sambit-l4w]

5 years still this lecture is so much relevant even today

[@adarshsingh7690]

I watch three times this video then I clearly understand this topic💯

[@satishkasana931]

Sir i think u are wrong at 31:09 because 10kg block also has their own coefficient of force of friction i.e., 0.1 so the acceleration of 10kg block should be 0 as the friction force applied by 5kg block on 10kg is equal to its own friction force so , they will cancel each other . Sir please reply it's my doubt. Aapne phele doubt ka bhi abhi tk reply nhi kiya hai.!

[@rachitjhunjhunwala5780]

Yes same here

[@bhoomika.ramchandani]

Tbh I never saw sir telling to like or subscribe or anything bcz he is just focused on teaching us 😌..you are great sir ...really appreciate it 😄

[@geet8890]

kzbin.info/www/bejne/hX6bdmCGoJ2BZ7s

[@sunitaranaware4479]

Sirji , pranam ho aapko 🙏🏻 .itna accha to koi bhagvan hi padha sakta he..aapke vaje se hi main physics main zero se hero ho gai hu. Thank you so much.😊🙏🏻💯

[@triangle2591]

Thank u brother for making clear every topic in an easy way.Though our curriculum is not same but it helped me a lot.Love from Bangladesh❤️❤️❤️

[@sanatan.inspirations]

If you are from Bangladesh than do you understand Hindi?

[@triangle2591]

@@sanatan.inspirationsYa I understand Hindi(Just common words🙂) but dont understand Hindi wiriting😅.

[@sr8489]

This will never get old ,, no matter how new teacher teach😄😄😄

[@siddhi_sb7607]

No one literally no online teacher is as good as you even byjus teachers.. ♥️#YOU ARE THE BEST TEACHER♥️ OF INDIA♥️ Hit like if anybody agree...

[@tanaypatel7192]

Don't compare sir with byju's

[@siddhi_sb7607]

@@tanaypatel7192 why?? Byjus teachers have high quality animations for teaching but Alakh sir makes us to imagine that animations in our mind so...he is better than byjus...

[@tanaypatel7192]

@@siddhi_sb7607 ya!! Absolutely true

[@tanaypatel7192]

@@siddhi_sb7607 are you from gujarat?

[@siddhi_sb7607]

@@tanaypatel7192 no...maharashtra

[@AyanSamanta-px8oz]

Myself AYAN sir..... Big fan.... Ap sa mujhe motivation milta hai..... ❤ u sir

[@Androgamer757]

30:48 a1 = 8m/s^2 a2 = 0m/s^2 F1=F2=10N Correct me if I'm wrong

[@radhasingh7761]

On 50:45 , i think there may be kinetic friction working on 10 kg block. Because they are in motion ????????????

[@preetithapa7301]

Yes i also think it should be kinetic..

[@shreyapandey4950]

Fk=Fs hoga cause mu ka value for both same hai

[@cricketthoughts4062]

Hnn bhai hit sir ko kinetic bolna tha agar meww ka value different dia hota to prblm hota

[@namechain-l9j]

No there will be static friction Because they are moving together

[@shreyakesarwani343]

thank u so much sir for this 🙂 Best video ever on KZbin regarding this concept 🤩

[@rishi6587]

31:10 the block will not move bcoz it's F limiting = 15N and applied force is 10N ( by the above block ) since Flimiting > F applied therefore the block will remain at rest

[@SwapnilshelkeInfinety]

I love you sir You are god of physics and chemistry Aap akale hi kitni mehanat karte ho Thanks you so much

[@yoddha-bereadytofight2366]

@@siamaniyar7941 right

[@shubhampadghan5652]

@@siamaniyar7941 yes sia

[@lavanyalab2455]

I am confused with block on block when my teàcher explained it but now when I listened physics wallah l am interested in block on block . Thank you so much 👍👍👍

[@AJAYSINGH-wt9hj]

sir not only this video u r every video in comparison to other is best … well im preparing for aiats from u r lectures only … so u can understand how much good is lecture covered thnk u ….

[@theultimatecoder3433]

same-

[@Itz_krishi_12]

@AJAYSINGH-wt9hj thumara IIT YA NEET MAI SELECTION HOO GYA KYA

[@itsabhi123]

Who one watch this from 11 ov.\2022.👍 Thanku so much sir. Complete this revision lecture.🔥🔥🔥

[@freeman8757]

Sir 50:31 me 10 kg block or surface ke beech limiting friction kaise lagega kyunki 10 kg wala block to surface ke respect me chal raha hai to friction to kinetic hona chahiye agar 10 kg wale block par 15N ki force lag rahi hogi to peeche ki taraf limiting lagega 🧐 lekin answer ek hi aya kyunki "u" Ki value same thi agar friction limiting lagega to please reply karke explain kar dena

[@ok-kb7yz]

U are absolutely correct, sir ne galthi se bola hoga , actually kinetic friction hei lekin yaha par kinetic friction ki value nahi di hei isliye limiting friction ka hi 'mue' lena hei.

[@ravindersangha6146]

I see many teachers which teach like you even much better than you but only with fees. But I does not see any teacher like you who give this type of logical education for free

[@vaidikjhawar3475]

He is earning way high than any teacher due to his all monetized videos....Anyway he is good

[@mahadeoparulekar3509]

He is the best teacher

[@tiredcat6653]

Nobody can teach better than him. I had the same opinion about my faculty at aakash but PW sir proved me wrong. The faculty is still amazing but he doesn't go in depth he assumes student already know each little things..

[@smgaltair]

tysm sir. i always skipped this part because i never really got an idea how it worked. The more I tried to clear this section the more confused I got. Keep making videos like this. You're a life saver. ❤️

[@geet8890]

kzbin.info/www/bejne/hX6bdmCGoJ2BZ7s

[@littleleaf4499]

Me toooo

[@salonishukla3320]

Its the best lecture ever on block on block systems Ekdum clear......

[@brainlybadges]

Me at coaching nd school - i am not getting anything 😢 Alakh sir - mai hoon na ....🙂 Your methods are great sir you made me fall in love with physics 🙏

[@ishikasrivastava7719]

Thanks a lot sir . Before watching this video l was afraid of these questions but now my all fear has gone .u r the best❣️

[@arin_p]

Same here!

[@clashsquadranked7694]

Love you

[@sagarrathod8321]

Sir, u had made a mistake at 31:00 that , u forget to consider the coefficient of friction between surface and 10kg Block i.e u=0.1 and ans come acceleration= 1m/s² but If consider then ans will come 10 - 15 / 10 i.e -0.5 m/s²

[@RashmiKumari-qo3ot]

Yes me to noticed the same thing sir mistakely took meu2= 0.1 but took it as 0 so it will also make a difference. In Fmax. Hope you noticed the new f max. Is 15/2

[@sirishasiri5930]

is this the last lecture of the chapter ? and did chapter completed ?

[@RashmiKumari-qo3ot]

@@sirishasiri5930 have you watched both constraints lect. Then it's last otherwise watch those 2 also

[@pratyush_singh_somvanshi]

@@RashmiKumari-qo3ot Sir ne impulse ke baare me nhi padhaya

[@RashmiKumari-qo3ot]

@@pratyush_singh_somvanshi nai