Triple Integrals in Spherical Coordinates

[@soccerboss7924]

Finally a spherical integral video that actually explains the boundaries. Integrating should be the thing that comes easily but the bounds have been tripping me up. Thank you sir I probably won’t do well on my test tomorrow but I’ll definitely do bettter now thanks!

[@joaquinmattecamus3639]

Absolute goat, as the level In calculus increases, the harder it is to find videos and this one explained how to find the boundaries perfectly

[@seniorshimhanda5690]

This video incredibly enabled me to understand parametrization, a crucial step towards comprehending the electromagnetic theory. Now I can compute electric fields, electric potential and electrostatic energy with ease. HMP is basically the best math tutor online. Thank you for helping me overcome this hurdle: electromagnetism is the basis of my career!!!

[@HoustonMathPrep]

This is outstanding to hear! Best of luck with EM theory! \o/

[@syahfA1]

Finally I know why I need to learn this thing. Before this, I just calculate it without knowing the purpose. Thank youu sir. Good and clear explanation.

[@menaceecho6790]

prepping for calc 3 final, huge help

[@mukhtarabdi4443]

Thank you so much. I go to through all your videos about double and triple integrals I really appreciate the simple and understandable way that you explained. Thanks again

[@user-kb7xw2zo4c]

Luckily I found your video before the exam... I totally can't understand what's Rho and everything before watching your video... thanks!!!

[@HoustonMathPrep]

You got this!

[@isisyasmim639]

I really like the progression of the lesson. Very helpful!

[@HoustonMathPrep]

Glad to hear that!

[@jordanfreidel1751]

Just one question, when setting the integral limits for dfi why do you only go half way around(pi) the sphere and not all the way around(2pi)?

[@HoustonMathPrep]

Remember that phi is measured from the positive axis downward. So if phi is from 0 to pi, that will give us a slice that is a semicircle in shape (in the xz-plane). If we take that semicircle and revolve it about the z-axis (which is the theta from 0 to 2pi part), we get the entire sphere. If we used phi from 0 to 2pi, our slice would be an entire circle. This means we have two of the slices mentioned above both revolving about the z-axis to generate a sphere, and each of those slices would generate a sphere by itself which would give us double the sphere we want.

[@jordanfreidel1751]

@@HoustonMathPrep thank you so much!

[@aSoulJourner]

Thanks, very clear explanations and good exemples.

[@aarthiarulabi3331]

Thank you very much, sir. Awesome video.

[@HoustonMathPrep]

You are welcome! Thank you for your kind words.

[@harshanasenevirathna6677]

You saved my day ❤❤ semester credits goes to you☝

[@HoustonMathPrep]

The credit is all yours! We just provided a little help 😁

[@zanelemdhluli9548]

These videos reaaally help 😁✨

[@krishanbhalsod4750]

Question, when you were setting the triple integral for the last problem, why couldn't we solve for p and make that the upper bound, when we were given z=3 and phi=pi/3? Might be a dumb question.

[@coralch1]

Thanks man! It helped me a lot!

[@HoustonMathPrep]

Glad to hear it!

[@thetwogoats6851]

This is amazing!!, thanks alot.

[@HoustonMathPrep]

You're very welcome!

[@Hadii127]

A lot of thanks ❤

[@aashwinsharma1859]

Thnx 🙏

[@HoustonMathPrep]

Welcome 😊

[@Tangebul_Murtoza]

Its amazing ❤️

[@hago8924]

well done :)