Two forces are such that the sum of their magnitudes is 18N and their resultant is

Two forces are such that the sum of their magnitudes is 18N and their resultant is 12 N which is perpendicular to the smaller force. Then the magnitude of the forces are

[@viswasbhatt3840]

Tum logo ye sab band kardo tum logo se kuch samajh nhi aata

[@birkishorsahu1508]

Eqn 4 is not required

[@RitikaDotaragavi]

Then what should be done?

[@birkishorsahu1508]

​@@RitikaDotaragaviArey (f1)^2-(f2)^2 =(f1+f2)(f1-f2) Ismein f1+f2=18 ka value daldo Then you will get f1-f2= 8 f1+f2=18 and f1-f2=8, iss dono eqn ko add karne se you will get f1=13 and f2=5

[@RitikaDotaragavi]

@@birkishorsahu1508 tq

[@DikshaRani-sl2fz]

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[@kalpakkamble3942]

Find the angle between two forces of magnitude 300N each if their resultant is 150N. Please solving answer

[@aadityakiran07]

Cos inverse -7/8

[@aadityakiran07]

Or 151 degrees

[@Lucifer_23]

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[@tithighosh2027]

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[@sandeepsinghkatoch8335]

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[@BirendraKumar-cm9nz]

Boring

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[@shivu7544]

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