Understanding the formula for the Mode of Grouped Data

This video is for those students of statistics who are looking for an intuitive understanding of the formula used to find the mode of a set of grouped data.
If you still have any doubt or question, please feel free to ask in the comments.

[@dhruvsoni2270]

It is THE best derivation I ever saw on youtube. Really happy to see such a logical person in the world. otherwise, everyone just cares about memorizing. Thank you so much, bro.

[@nitinkumarsingh134]

Teacher like you are worthy to receive best teacher award

[@makeki7756]

Any kid would fall in love with mathematics after watching this. Just beautiful derivation❤️

[@rohanshah6178]

Sir it is just an ingenious derivation for the formula for mode. And your explanation was even more beautiful. You clearly showed the assumptions we make before deriving the formula(that F≠R and and R,F ≠ 0), the central idea behind the derivation and then the wonderful geometric derivation along with your helpful comments and lucid explanation in the process. Loved it so much. It is really the clearest and best explanation I have come to find for the formula. Thank you so much.

[@thephysicistin]

Thank You for your kind words. 😊

[@CrypticalGaming]

Thank you so much sir .It's been extremely helpful and informative to me. You're an amazing teacher.

[@chillhouse4685]

Simplicity level 100. Thank u sir

[@Kripalu_das]

Sir, your method really gave me a wonderful insight into what Mode really is. Because of your help and kindness I came up with a way to calculate mode mentally. All thanks to you. For mental calculation Mode (Z) = l + [h/R+F] R Where l = lower limit of modal class h = modal class width R is rise F is fall I CAN'T THANK YOU ENOUGH 🙃🙃

[@pkmmotivationalfactory6984]

Thanks sir 🙏🙏

[@sophiagodfrey-n3r]

thank u sir

[@ranjanakushwaha2534]

Outstanding explanation sir

[@Kamalika04]

Wonderfully explained!! Thank you so much

[@thephysicistin]

You're welcome.

[@rakibulhassan3041]

you took a great initiative for us and better understanding

[@shamanthchandra9100]

Great explanation. Thank you.

[@jawaharyadavyadav9337]

Please make a video on formula for finding median of grouped data ...

[@thephysicistin]

Ok. I will make a video on it soon. Stay subscribed to the notifications and you'll know when the video is published.

[@pratapchandramohanty9434]

Great explanation thank you

[@gayatrichanda6003]

Hats off to you.🙏🙏🙏🙏🙏🙏🙏

[@poojaandprajwal7041]

Very well explained ☺️

[@beinghimself]

That moment u find someone who know what he is saying 🎉❤

[@harshitsherawat1869]

Thanks sir I was in great need of this

[@professorcalculus7885]

The mode doesnt necessarily have to be in the modal class, it may happend that if the modal class has frequence 4 it is cong from 4 differen numbers lying in that class while some other class might have frequency 3 but all are just contributed by 1 number?

[@priyanka11d33]

Thank you so much for this video sir 😊

[@anirudhkapatia2299]

Point that why x/y has to be equal to r/f is not very clear please explain again I do not want to rote it And thank you for making such videos they are of great help

[@thephysicistin]

Since there is no individual frequency given in the data, the modal point inside the modal class is defined to be l+x, where, x/y=R/F. You can take it as the convention we use to assign a modal point, if needed, to the dataset.

[@voyageintostars]

Hey! I just had 1 question. x/y has to be R/F... I understood that. But then why are you calculating R/R+F? Why is there that extra R in the denominator?

[@AmanSingh-mg4mm]

loved it sir

[@DeepakGupta-uv1oh]

Gjb ka explanation sirji❤️❤️ rock 🥌

[@hemantthakur9010]

Sir, what is the interpretation of pt E, why it should denote modal value, and how it's additional factor to lower class will take to real modal value, and in what sense?

[@thephysicistin]

The point E is a representation of the modal point in grouped data. There is no real modal point. But if we have to assign one, this is how we do it.

[@tanushkapla2245]

maybe we can even skip on the similarity part in the manner as follows: x/y=R/F (the core idea) 》y/x=F/R 》(y/x) +1=(F/R)+1 》(y+x)/x=(F+R)/R 》h/x=(F+R)/R 》x/h=R/(F+R) Rise and Fall can be attained by basic arithmetic and hence will obtain x. Btw..AMAZING VIDEO SIR

[@everytopic2076]

Brother he is proving the core idea

[@Nazia87_]

Sir why we are taking the ratio of the x/y and the Rise /Fall ? Can you explain it by taking real life examples? Or we are assuming it to be equal while deriving the formula .Why we are assuming it can you explain with a real life example? Please sir I am confused.

[@KNarasimhaSwamy1]

Sir, can please explain (in another video) why graphically mode is calculated in that way I.e. why should we join AC, and BD...

[@thephysicistin]

This is a very simple thing. We join AC and BD just so that we can verify and deduce the proportionality using similarity of triangles.

[@jawaharyadavyadav9337]

Sir deriveration kaun sa book mein milega

[@thephysicistin]

I have not followed any book for the derivation I did but there are a few good books on Statistics where you may find the derivation. 1. Statistics by Robert and John Witte 2. Statistics by Freeman, Pisani and Purves

[@Nazia87_]

Why z(mode) is l +x... If we add these we find the distance between 0 to the point z in the x axis How it's equal to mode?

[@Nazia87_]

I found this answer

[@ttwwoo22]

@@Nazia87_ pls say

[@jasonsolano2935]

Nice, I always want to undersant why something is like it is

[@kaushikkr.sarmah82]

Sir what happen if dotted line is not passed through the point E ?

[@thephysicistin]

The modal line (dotted) will always pass through E (the point of intersection of BD and AC). To verify, you can draw a normal from E to CD and name the foot as G. Now you can deduce that the triangles AEF and CEG are similar. Thus AE/EC = FE/EG. The triangles BEF and DEG are also similar. Thus BE/ED = FE/EG. This proves that E has to be the point of proportionality.

[@ranjanakushwaha2534]

One more thing, without doing all the geometry we can still get by intuition that: R/R+F is the ratio which will be equal to the ratio x/h and hence substitute the values and get the formula.

[@thephysicistin]

Absolutely.

[@yasirsonic5835]

Thank you sir..it was clear cut!!

[@MrSatan-ji8kj]

Great sir

[@thephysicistin]

Thanks

[@JatinKumar-ol2py]

Why mode is at intersection of line AC and BD .Please clear it.

[@thephysicistin]

For grouped data, we have to assume that the modal line divides the modal class into the two subclasses with the same ratio as that of rise/fall. The modal line (dotted) will always pass through E (the point of intersection of BD and AC). To verify, you can draw a normal from E to CD and name the foot as G. Now you can deduce that the triangles AEF and CEG are similar. Thus AE/EC = FE/EG. The triangles BEF and DEG are also similar. Thus BE/ED = FE/EG. This proves that E has to be the point of proportionality.

[@pramodydw1912]

Sir median ka bhi derivation ka ek vidoe bna skte hai kya ??? Grouped method

[@thephysicistin]

Sure. Will make a video soon.

[@pramodydw1912]

@@thephysicistin waiting for that

[@kartikr5995]

Median too sir please

[@thephysicistin]

I have already made the lecture on the median. kzbin.info/www/bejne/o6u6cqFjjJJloc0

[@everytopic2076]

Just nailed it

[@beinghimself]

I remember deducing this last month. But i think you could’ve explained it faster and easier

[@ranjitgupta1136]

Thanks sir

[@garimasinghal4977]

Why x/y = R/F? I didn't understand?.

[@thephysicistin]

That's the definition of the modal point of a modal class.

[@garimasinghal4977]

@@thephysicistin sir, Please could you Explain the definition??

[@Zindagishow]

Derivation of mean formula

[@everytopic2076]

Epic

[@Spotdot123]

Pls ye video bhi hindi me bana do

[@veeravasanthi6338]

Sir i am not understand

[@thephysicistin]

Which part did you not understand. Let me know.

[@Ankushkumar16108]

Please explain in hindi

[@thephysicistin]

If I explain in Hindi, those students who don't understand Hindi won't get any benefit. But most students, even those from the Hindi belt, can understand English. In India there are more people who understand English than those who don't.

[@guru_bro]

Isse phetela mic nahi mila apko ?

[@Nazia87_]

😂

[@sarikatandulkar8563]

Try to speak in Hindi as well as clear for more subscriber

[@thephysicistin]

I want to make my content intelligible internationally. Also, any serious student understands the importance of English as a language, no disrespect for any native language.

[@Spotdot123]

Hindi me hota toh ache se samajh aata mere Eng jara jamti nahi hai

[@sarikatandulkar8563]

Looking very confused 🙄

[@thephysicistin]

What is?

[@mukeshyadav-kp3dw]

thank u sir