Uniform Circular Motion - IB Physics

[@clarizeesmeralda3765]

This guy is so underrated , the way he teach is so direct to the point hands down

[@mauriceapollo8688]

instablaster

[@mohamedabdibarre7094]

Learn to comment than learn to competition

[@philomenangoh6365]

This man speaks the language of my brain cells

[@AndyMasley]

Aw that's so nice

[@runeknight2842]

This guy teaches better than my teacher

[@iwayandikadarmaputra3755]

its all correct 🤭

[@cristobalcaviedes9671]

Fr

[@aycb8805]

It is so great that i finally found a lesson video that is JUST PERFECT !

[@Learning_with_Musti]

Best video I have seen on this topic.Well done Sir. You inspire me to be a better teacher

[@danieljatombliansky3515]

SUPER HELPFULL, really, there aren´t a lot of videos explaining this stuff, thanks a lot

[@larsityosmarsilyet5933]

dude really, . In just 14 minutes, you really taught better than anyone. I liked and subs to your channel. Keep going like that.

[@jfrkhrfn]

bro literally i cant thank you enough. keep it up man.

[@johnnyboy3390]

Absolutely phenomenal job teaching this content, and $2,000 cheaper than my uni physics classes...

[@user-fl7iq7lo8j]

Absolutely nailed it. Have my exams tomorrow and your videos are the best one I can find on youtube, in terms of quality and going straight to the point ✨

[@Twlghtsvd]

I’m in 12th grade and this channel is helping me so much this channel is underrated amazing video

[@yeetmeat1356]

Are you going to cover the HL topics as well? That would be a big help, and thanks for giving us this type of quality content!

[@AndyMasley]

I'd like to! I'm still working through the SL topics. Unfortunately each video takes a while so I'm not sure when I'll be done with the HL material.

[@highschoolphysics9459]

Very cool animations and timing for your teaching content. My students appreciate your work.

[@11392ash]

HOLY SMOKES, you broke that down SO WELL!!! Thank you so much

[@sinan1322]

This video was pure miracle 😁 helped me a lot to understand this topic ! Thank you !!

[@kelvinthehuman]

Waooo....amazing explanation, without a waste. Hats off to you, Mr. Masley. Greetings from the Dominican Republic.

[@vandal3603]

Hey man, thanks for making this video, physics is alot harder than I anticipated, so vids like yours helps me out a lot.

[@juliette0523]

You made it so much easier for me to understand this stuff, thank you so much!

[@AndyMasley]

So happy to hear that!

[@Mrvicoloco666]

Hey ANDY, greetings from Ecuador, you just saved some my first classes. I was struggling a lot about how to introduce the important concepts of UCM. Master!!!

[@AndyMasley]

So glad to hear this was helpful!

[@altonmiles4027]

Amazing video! Very concise and easy to understand. You saved me hours of studying so thank you

[@natrs2335]

Thank you so much, I understood in 15 minutes what I didn’t understand in class in 2 hours

[@jenniferbello-ld3rp]

I have an exam on this unit and this video was really helpful. So glad I found this video

[@yabool2001]

Man. It's awesome! Not overdone like many other movies.

[@bautistabaiocchi-lora1339]

Exactly what I was looking for, thank you sir.

[@md_rifat_chawdhury]

LOVE FROM BANGLADESH. PLEASE MAKE MORE VIDEOS ON PHYSICS . YOUR TECHNIQUE IS REALLY GREAT.

[@mandysgainedmomentum9555]

I am an IB physics teacher and I like this video. He is an experienced IB teacher although he looks young.

[@AndyMasley]

Skincare routine is key. Thank you!

[@simsambros]

This was the perfect video I could find for circular motion

[@Opticsport]

my fav so far, thanks alot Mr. Masley

[@nig786]

Thank you so much for explaining this topic, you teach very well FR👍

[@RinaNewhouse]

Hi Andy! Your level of teaching is superb! I, in all honesty, learn the most from YOU! One thing, though: I believe the answer to a_c (time stamp: 13:48), is supposed to be 5.94E-1 m/s^2, or 0.594 m/s^2, assuming all previous answers to be correct, would it not? I calculated it twice, once on my calculator, and once again on Desmos, and both gave me the answer of 0.593609625668. Would you wanna quickly double check? Other than that super minor thing, I cannot thank you enough for posting these lessons for all of us to learn from. You are single-handedly getting us through our physics classes. Best, Rina

[@AndyMasley]

Yes you're correct! I made a mistake in that section

[@AndyMasley]

And thanks so much for the kind words, so happy the videos are helping!

[@RinaNewhouse]

@@AndyMasley It did help! I did well on my first exam because of you!

[@Mouse-qm8wn]

You are a great Teacher please continue making videos 😊❤

[@peter3900]

Thanks so much really found this helpful even though im not an IB student

[@Palestine194]

very interesting lecture sir.....From Pakistan....well explained.

[@danhnguyenthanh7178]

this guy answer my biggest doubt. why acceleration point toward the center? what is the role? why not in the same direction as the velocity? timestamp: 3:48

[@Archie1981]

Very well explained❤

[@MonSonBro]

You explained this better than my teacher did in 2hours, thanks!

[@amtulsyed5402]

Very helpful and concise! Thank you!

[@levychipapa190]

wow i just cant believe i just understood 70% of circular motion in jxt a few minutes wooow you dope man

[@arindomchakrabarty2254]

Concepts, explained in a simple way.

[@sabaalameer100]

you made so easy to understand it

[@MikeStallings2023]

Outstanding teacher. What is "IB"? These lessons are valuable to people like me who have no clue what IB is. And this is very hard to google.

[@AndyMasley]

Thanks so much! IB stands for "International Baccalaureate" it's a specific physics curriculum that I was teaching at my school

[@jamesluc6506]

Your video is so great. I am in the middle of my May Physics Sl exam. I am sad for finding your channel late but also happy for finding it before my final exam. You explain it so well (much better than my teacher). I am pretty sure all your student get a level 7. Just wonder do you have some IA topic recommandation material that could be shared if you still have it (I know you have left teaching). Thank you for the great content.

[@AndyMasley]

My advice for the IA: 1: A good IA is often a middle school-level experiment with high school-level analysis. You don't need to do something crazy, just a simple experiment with a clear independent and dependent variable and a pattern that's either linear or that you can linearize. 2: It's often helpful to look through the IB physics equations and find one that has two variables that you can test. As a very simple example, you could look at F = ma and measure how the acceleration changes when the same force is applied to different masses and rearrange the equation to be a = F(1/m) where a is the dependent and m is the independent variable. Working backwards like this from an equation to an experiment can make it easier to find something you can linearize and analyze in the data analysis section.

[@jamesluc6506]

@@AndyMasley Thank you so much for your helpful suggestion. I have another quick question, who will mark our IA? I have heard two statement where one says that the teacher marks your IA and one or two IA of your class will be sent to IB to be reviewed and they will decide to increase/decrease the mark of the IA marked by your teacher. And another one states that the teacher only gives you the predicted mark, the IB will review and gives you the final mark. The reason I asked it is because our teacher clearly tells us if we choose a SL topic, is it at most about level 5 and he always suggest us to choose hl topic ot outside the syllabus of IB, so I am concerned if he will be the person to give us the final mark for IA. Thank you very much!

[@cloudy7817]

my physics teacher cant teach for shit. thanks to u I (probably) wont fail my test lol.

[@zh-vu7zc]

Best Explanation. Appreciate it ❤️💐

[@DingusSquatfordJr.]

His explanation is nice and clear compared to my professor.

[@hoanggiabaotran9025]

Great video, but I have a question regarding the Example Problem 1! The formula booklet stated that a = v^2/r = (4 x π^2 x r)/T^2, and in the video you used v^2/r to get a = 4.641. But technically, in the given variables, you already have r and T, so would it not be easier if you just substitute everything inside (4 x π^2 x r)/T^2? That is what I did, however I ended up having a = 4.626 instead. Could you help me verify what went wrong? Because essentially they should be giving the same answer.

[@AndyMasley]

You're correct that those formulas are equivalent to each other. Ultimately physics has many formulas that can be rewritten based on convenience. F = ma could also be F = m(Vf -Vi/t) if the variables called for it. Our answers are so close that it's possible that I just rounded incorrectly!

[@AndyMasley]

I might have used a slightly less exact number for pi, like 3.14 instead of 3.1415926 etc.

[@hoanggiabaotran9025]

@@AndyMasley I see. Thanks for replying!

[@budderrrr4855]

you deserve my real teachers salary

[@gloryeruka2501]

What a great video 😲 thank you so much sir!

[@cartoonic6039]

I have a very simple but question. Why doesnt the object collapse into the point. Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre. For example: The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy. But objects in the real world dont have fixed energy level so what keeps them in circular path? Another example is that if we change the mechanics occurring on the body interms of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still move circular

[@nadirenuryasar2729]

example 1 should be 4626N since you shouldn't round up 11.7809... to 11.8

[@vd4538]

Hi Andy, thanks for all your efforts in helping us all. I just had a small doubt for the second example problem... By using the formula I was getting 2 π x 149,600,000 x 10^3/ 365 x 24 x 60 x 60. Which was giving me the answer of 29,806 m/s. However you got the answer of 2.98 x 10^5 which is 298,000 m/s. I just wanted to ask if I went wrong in the calculations anywhere or was the displayed answer a typo? Thanks again.

[@neotiwari3772]

It is 2.98 x 10^4 m/s, he probably made a typo

[@Mrabosaleh4ever]

Thank you

[@nikolasolakov1232]

@@AndyMasley no he's actually right, after staring at it for a good 30 minutes and solving i saw that it is actually correct and its not 10^5 but 10^4

[@JenniferRokks]

@@nikolasolakov1232 how?

[@amznani2023]

@@nikolasolakov1232 how???

[@nsfw9087]

I'm a little confused in example 2, isn't the earth's orbit around the sun not in uniform motion? (Kepler's law) orbit's shape is an ellipse, not a perfect circle.

[@AndyMasley]

Correct! It's actually an almost-perfect circle, the ellipse is usually exaggerated in diagrams, but it's technically not uniform circular motion. I find it has enough of the same properties as uniform circular motion (centripetal force and tangential velocity) that it's a useful example to explain UCM, but it's technically not perfectly uniform.

[@amznani2023]

ok but how did you get the 2.98 x 10^5 m/s in example 2?

[@charleskoripamo7488]

Is it wrong to say the direction of the force on the object changes, therefore the direction of acceleration changes?

[@abel_kidus]

Thanks for making me understand the concept.

[@giancarriedo715]

I WISH I FOUND THIS BEFORE MY PHYSICS EXAM AAAAAAH

[@shamelsinha1626]

Ur the reason I ditched my textbook and no longer attend online class!!!

[@Booooscared]

u absolute madlad

[@alirazanasir5992]

Thank you

[@nadirenuryasar2729]

example 2 is also wrong vt=2.98x10^4m/s

[@akankshabhatt3357]

Thankyou so much for this video, was trying to make sense of this fromone of my mcat books and it just wasn't clicking.

[@karlalerma4231]

I need help :( so I have a problem " a 2.0 kg object is attached to a 1.5m long string and swung in a horizontal circle at a constant speed using a centripetal force of 192N. What is the speed of the object?" I'm very confused I looked up vids but can't find one for my scenario:(

[@jabbedcrab]

Correct me if im wrong, but when calculating Vt in the last example problem, the answer is actually 2.98x10^4, i kept getting the wrong final answer with 10^-5!!

[@zh-vu7zc]

Sir , Do you have any videos on banking angles of road?

[@AndyMasley]

Yes! Here: kzbin.info/www/bejne/b2XOo4CJmd10apo

[@maggiiuwu3022]

ur a king

[@harunosakura9798]

sorry I only have a question that why delta 0 = 2.pi ( 8:58) ? and thank you so much, I have learned this lesson for at least 15 times ( included learning from my teacher and internet ) and I still don't understand till I find yours. Its just too easy to understand, and the way you put all of the base-knowledge in just 14:01 video is just so amazing, it really helps me a lot. I have subscribed your channel after only 5 minutes watching yours, and hope that you will make more great video, especially 10 grade physics cause I'm at grade 10 now ^^ hope you will answer my question soon. have a nice day !

[@AndyMasley]

So happy it's helpful! Delta theta is 2 pi because that's how many radians one complete circle is. If you need help reviewing radians use this: www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:trig/x2ec2f6f830c9fb89:radians/e/degrees_to_radians

[@harunosakura9798]

@@AndyMasley omg thank you so muchhhhh

[@berserkjr6154]

👍 ty for good videos

[@wrentay2306]

for example problem 2, the velocity should be 2.98 * 10^4 not 10^5 when you calculate it, and even for the acceleration, 5.9 * 10^-3 is yielded when we use 2.98 * 10^-4

[@genocydical135]

Yea, my thoughts exactly. Am I missing something?

[@carlygorgal4514]

Came to check the comments to see if I wasn't the only one

[@wrentay2306]

@@genocydical135 no its just a mistake worry, it happens

[@rogeliocampos4593]

nice work

[@teguhgumilar6868]

Hi , I am a physics teacher, can you tell us what application/software to make animation on your slides? Thanks

[@AndyMasley]

Apple Keynote! Explained here kzbin.info/www/bejne/noiap6VuicemqMk

[@teguhgumilar6868]

@@AndyMasley would you like to share your slide to use ? thanks

[@yanyaZhao]

May I ask why the time is 16 seconds.

[@OscarSL]

You had Vt's order of magnitude as 5, even though it should have been 4. (In example problem 2)

[@yinkak3921]

Doesn’t the formula for tangential velocity assume that there is no tangential acceleration?

[@yinkak3921]

Nvm just realized the title says uniform circular motion

[@iqrajabbar5287]

V v v v v v nice....❤

[@suraphelendalu4070]

Thank you so much

[@lanapark6099]

thank you so much

[@basesixty6739]

tangential velocity for last question should be 2.98*10^4

[@zahraaalhadi4451]

You channel is a real treasure (: but I wish you could download the slides you are explaining as pdfs

[@islamdowidar1930]

Amazing

[@mahlanesophonia3080]

THANK YOU SO MUCH

[@jamesmatheson9624]

We need to investigate adding multiple rings aounrd the first ring and using smaller and bigger balls. In the rings to change the force to fully understand how the forces are changing

[@isabeldevalenzuela7892]

thank you so much!

[@dullahanan4371]

I have a question in uniform c.m net force should constant

[@AndyMasley]

Yeah usually we assume the net force is constant. If the net force changes but the radius and mass stay the same, that implies that the velocity changed, so the circular motion is no longer uniform (at one speed).

[@chijinduegbo5640]

velocity is not consant speed is constant because velocity is speed with respect to direction and in circular motion direction is not constant

[@user-vq5uc4lm2t]

erika and candace

[@imnotmark3053]

My teacher took 2 class period to explain what looks like a very simple topic 💀

[@AndyMasley]

In defense of your teacher this is hard to explain on a board without animations

[@imnotmark3053]

@@AndyMasley You do have a point. I feel like seeing it visually help me understand it faster and better.

[@edinsonorlandodoradodorado9101]

Man, you are awesome, congratulations

[@madhyapradesh8841]

Wow thank you so much sir

[@isoheilhsni]

This video was awesome Super helpful 👍👍👍👍

[@joshuankrumah3532]

that what i was looking for

[@blackhand441]

Why is tangential velocity 2πr/T ? I thought it would be zero since there is no displacement 😢

[@AndyMasley]

It's a poorly named term that the IB uses, tangential speed would make more sense! You're exactly right and the IB is just a little lazy with this variable

[@blackhand441]

@@AndyMasley Thank you for your reply

[@sarahkim9546]

You are really good.

[@NgengRual]

I can't understand this circular motion sir😢

[@Mutabaruka-8]

This is really helpful.

[@paulduggar5888]

Mr. Masley thank you so much i think i can get an A tmrw bc of u i didnt know UCM until just now

[@AndyMasley]

Hope it works out!

[@leylay1447]

Thank you this was very helpful!

[@Scientists_dont_lie]

If accelration and deceleration can be felt or sensed, how come then, we dont feel or detect the earth spinning 1600+ km? Or dont feel it as it makes a decelration and acceleration while making its eliptical orbit around the sun at nearly 70,000mph nor feel or sence anything as it orbits the center of the milkyway galaxy at one half million miles an hour? Earth is spinning on its axis at high speeds while obiting the sun at high speeds while its also orbiting the galaxy at even more fantastic speeds and we as individuals standing(sitting lying down) on earth cant detect any of these things Despite the fact that spinning in a circle is acceleration with is detectable and "felt" while earth is also accelerating and decelerating in the eliptical orbit (deceleration is also detectable and/or felt) arpund the sun and in addition to that orbiting the milkyway at a half million miles per hour? There are numerous spinning motions and orbiting motions happening (both of which we are told are " felt" and or detecatble at fantasitc speeds). Yet according to a einstein who was quoted Saying that he has "come to the conclusion that the motion of the earth cannot be detected".

[@AndyMasley]

Acceleration can only be detected when we experience some resistance to it. Astronauts on the International Space Station float freely, but they're constantly accelerating toward the Earth. They don't feel it because everything around them is accelerating at the same rate. Similarly, we don't experience Earth's rotation because everything around us is rotating with it. This video goes into the details of how the experience of acceleration is related to Einstein's theory kzbin.info/www/bejne/joPVYp6XjbB1qbc

[@NatnaelDaw-cv9bt]

I am not a teacher.and I can't hear what are the words that you were said so please slow down or I don't know just balance your speed.the other thing is nice I liked those pictures thank you.

[@kaeberii]

my teacher said that centripetal force was a type of force 🧍🏼‍♀️

[@AndyMasley]

Your teacher's WRONG

[@kaeberii]

@@AndyMasley you're absolutely right !!

[@lawalolamide7770]

Pls can u write that radius for me in full digit. 149.6million km. I don't really know how u got 1.496×10^11. I know that a million has 6 zeros