Uniform Circular Motion Formulas and Equations - College Physics

[@TheOrganicChemistryTutor]

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How is the displacement equal to the circumference of the circle should it not be zero as it ends up at the same point?

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[@hyperz_pro8970]

How is the displacement equal to the circumference of the circle should it not be zero as it ends up at the same point?

[@aileenjackson7145]

This video on uniform circular motion formulas is a game-changer for anyone trying to make sense of physics problems. The step-by-step breakdown of equations and real-life examples provided a straightforward approach, helping me navigate through the complexities of circular motion with confidence.

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How is the displacement equal to the circumference of the circle should it not be zero as it ends up at the same point?

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How is the displacement equal to the circumference of the circle should it not be zero as it ends up at the same point?

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Simply: T = Fc + mg cos θ (Measuring θ from point D)

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we need more physics videos, can you upload one for uniform circular motion for dynamics side and not kinematics side?

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i think he times these videos because we just started to learn about circular motion in my college physics class and its kinda scary how he just made this video 6 days ago

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How is the displacement equal to the circumference of the circle should it not be zero as it ends up at the same point?

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[@AirTrend05]

In 4:21 it should be 4pi^2R^2 right why you have written R there it should be squared right??

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[@rinrin192]

5:37 - tension

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This is for a levels?

[@Interestinggirl-in2ne]

4:17 hello i am very stupid so could someone please explain why the 2 and the pi get squared but not the R?

[@carterhonsinger6360]

it does, the square just gets canceled out by the other R on the denominator coming from the Ac equation. leaving only one R in the numerator.

[@ayabongampungose8030]

at 17:15 why we subtract mg,

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[@user-px5oy5zw3q]

The formula in 4:18 is wrong. The correct answer is actually (4pi²R²) / (T²)

[@Yusenindabackrooms]

Wait what is Ac measured in

[@99ish91]

M/s^2

[@kanyeeast420lol]

IF V=2(PI)(R) THEN V^2 SHOULD BE = 4(PI)^2(R)^2 RIGHT. BUT U HAVE MENTIONED IT AS V^2=4(PI)^2(R) MAY I KNOW THE REASON

[@crookedqq]

he put the formula for accelaration which is v^2/R not just v^2 which cancels out square

[@kanyeeast420lol]

@@crookedqq ohh ok thanks

[@gianramos7766]

4:34 why is the R not squared?

[@tomassilva9860]

you do square the R since every element in the Velocity equation has to be squared, but when you divide ((4*pi^2*R^2) / T^2) over the already existent R from the Centripetal acceleration formula , the R^2 cancels the R in the denominator, leaving the T^2 in the denominator by itself and an R in the numerator.

[@gianramos7766]

@@tomassilva9860 Ohh thanks for pointing that out:)

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