Uniform Continuity|Uniform Continuity csir net|Uniform continuity Results|Rahul Mapari real analysis

[@rashmirajput2850]

real itna easy ho sakta h ye bs aapki 3 videos dekh k samjh aa gya...u r amazing sir

[@rajendarnagabathula1929]

Thank you sir,u r the great person to help so many people like me.

[@nafeeskhan4187]

👌👌👌👌

[@justiceforsidhumoosewala6225]

Thanks sir , u.c Ko itna achey se explain krney k lea

[@tripling2266]

Amazing sir, the explanation is amazing, I dont have words to say how much I glad to meet u bcz me humesha se ye topic padna chahati thi but mujhe kabhi samjh hi nahi aaya ya yun kahun kisi ne aap jesa samjhaya hi nahi . You are wonderful at this topic. Thanks for clearing my doubts. just one request plz make another video with full explanation of connected and compact set with example🙏🙏🙏🙏🙏🙏🙏🙏

[@raazkaladhillonuboke4689]

Sir aap jis b language mein teach kr te o wo buat acha teach kr te o I am from Punjab you are the best teacher 👨‍🏫

[@esswarid6223]

Superb video sir , looking for more conceptual and csir net related questions discussion

[@shalinisl8920]

Excellent sir 👌 Now I am watching all the lectures on real analysis. Thank you Sir

[@yashpandey1428]

thanks sir bahut zayada aacha aap samjha diye again thanks sir

[@mathslearner8251]

Thank u sooo much sir for all your videos. Its very help me to preparing net exam.

[@Divyakant2341991]

you Outstanding and mind blowing superb teaching and I have no words for your teaching method

[@RahulMapariBasicMaths]

Thank u so much.

[@biswajitlenka2730]

Thank You sir. You're doing such a great work but your channel is so underrated

[@mathematicsmind8648]

UC clear in 3 amazing videos.. & We r eagerly waiting more from you Sir...

[@sudhalakshmi7315]

Thank you so much sir very clear explanation..I don't know hindi but I understood ur way of teach 🙏

[@Mathematics-0kset]

Thank you. Sir. It is very helpful for csir net exam..

[@umashankarsahu8649]

Thank You so much Sir for all the three videos. It will really be helpful in my preparation.

[@irshadyatoo3294]

God bless you sir I'm from kashmir if can Qualify NET it s only because of teachers like you as u know we don't have facilities in kashmir but still at 2g speed I am watching ur vedios till late nights 👍👍👍👍👍

[@priyasaharan2787]

Thanku so much sir, hope so ke ab question attempt ho jaye ache se

[@rashmirajput2850]

thanks alot sir,clr hua concept sir bcoz of u,plz make a video on R.I. also

[@ummeammara113]

Thank u very much sir...u explained uniform continuity concept very well

[@sahilsethi4644]

Thank you so much sir for make me understand the concept of UC

[@jagadishchandradehury6249]

This is very helpful, thank you so much Sir.

[@mizanurrahaman8687]

Very Nice Expatiation. Thank You Sir .

[@aditimaurya3935]

Thank you sir ... You explained very well. Also please make a video on REIMANN INTEGRAL for IIT JAM🙏🙏🙏

[@suhailawm]

sir language not a problem. easy to understand in your explanation method

[@manojkumardandapat2037]

Thank u Sir...Nice explanation

[@MathByManoj-he2iw]

Thanks sir ji 🙏🙏 🙏 for this types of lectures...😊

[@sourenduacharjya9528]

thank you lot sir. concept clear ho raha hai

[@jalaluddinmondal990]

Thank you sir.plz make more videos on Abstract algebra for CSIR NET and SET.

[@sherifkaja2333]

Thank you so much sir. Very nice explanation. 👍

[@dr.vinodchandra5926]

thankyu so much sir.. for helpful vdos.

[@liveyourlife9232]

Great job with great effort

[@soumenpati4133]

Thank you so much sir... really you are a great 🙏❤️... this is very helpful for us

[@thiloshkumarc4153]

Beautiful explanation sir..

[@AB_K96]

Thanks U sir providing Teaching ✌️

[@Takhelleii]

Very 2 helpful nice explanation

[@nehapandey5845]

Thnku sir ,it's very helpful

[@risingmathematics2864]

Very helpful sir. Thank you.

[@usmanaziz7087]

Most authenic knowledge u have sir love from pakistan ♥️♥️♥️♥️♥️♥️♥️💕💕💕

[@RahulMapariBasicMaths]

Thank u very much.. I think, it's a beauty, power and respect of Mathematics that, u send me love from Pakistan.. I salute to Mathematics...

[@dr.harisankars6433]

Thank you very much sir

[@rainalaha6150]

Thank you sir. Sir , pls make video about metric space pls.🙏

[@sasikala8048]

Nice explanation sir

[@Vikas_85]

l am very thankful to u sir, The concept of uc was well explained. Please make videos on connectedness and problems occurred on connectedness in csir exam🙏

[@RahulMapariBasicMaths]

Ok. Thank you

[@shalu4839]

Sir thanku so mch

[@sangitasaha4228]

Thank you soo much sir!

[@akankshajangid6335]

Sir plz function of bounded variation..

[@mathematicsmind8648]

UC clear ho gaya Sirji.. 😍😍🙏🙏🙏

[@selvarajsabitha3122]

Good job sir

[@shalinisl8920]

Excellent sir 👌 Thank you Sir

[@devakibadekkila7164]

Thank you very much sir:)

[@rubinasahoo8238]

Tq so much sir it is very helpful

[@Mmmmm-m8r]

Great Sir 🙏🙏🙏

[@rashmihr1074]

Tq so much sir🙏🙏🙏

[@sajhijana2211]

Thank you sir thank you soo much

[@komalkumar5073]

Thanks u sir, it is very helpful for me. Plz make more videos on ode n pde

[@RahulMapariBasicMaths]

Uploaded

[@amandeepkaur6997]

very well explained

[@omkar1070]

Well explained sir ❤❤❤❤

[@ashtaniprajapati]

Thank you sir

[@ritikashrivastava8773]

Thankyou so much sir..🙏🙏

[@inkuydv6549]

Sir plz make videos on function of bounded variation with previous yr questions 🙏

[@tapasnaskar52]

Sir I think your definition of connected set is the definition of convex set. For convex set joining line must be straight line,for connected set joining line may be curved line ie there must be a connection between these two points....

[@RahulMapariBasicMaths]

U r right. That's why I have not given technical or bookish definition. It is just to understand the concept.

[@periyanayaki6999]

Thank u so much sir

[@pradeepdholpuria986]

Pls sir make videos on linear algebra..🙏🙏

[@RahulMapariBasicMaths]

Ok. But when I make on linear algebra some students tell me real Analysis

[@pradeepdholpuria986]

@@RahulMapariBasicMaths No problem sir As your wishhh.

[@RahulMapariBasicMaths]

Ok. I will definitely try for my best

[@pradeepdholpuria986]

@@RahulMapariBasicMaths Thank you sir ..🤟

[@liveyourlife9232]

Thank you

[@sripad72]

Rahul ji, u said since lim sin(1/x) does not exist as x tends to 0, it is not UC, but limsinx as x tends to infinity doesn't exist, however it is UC. Can u please clarify

[@himani8965]

Thank you toh hum bolenge Sir. Thank you

[@rajkaram4026]

Tq so much sir

[@kanimozhi2268]

Pls make vedios on uniform convergent like this..

[@RahulMapariBasicMaths]

Uploaded

[@NOORALAM-kz4nb]

Please Sir bounder variation k question banao

[@nilanjana1346]

When interval is zero to infinity then what happen? In this case at infinity limit exists is important?

[@pankajkajal9622]

Thnku sir🥰

[@gulshanjoshila3756]

Thank u sir

[@NeelamYadav-cq4bd]

Thanks sir

[@sanjaypaul4869]

Limit does not exist . Not UC Is it an iff condition?

[@niketachoudhary247]

Hello...sir If we do second question with interval (0,1) by using theorem that f is u.c. if it's derivative is bounded on (0,1) then it is not true for x.sin1/x

[@Kiran-vd7gf]

Sir , how we can say that if limit does not exist at end points then function is not uniformly continuous eg. f(x)=x is uniformly continuous on(1,infinity ) but limit at infinity do not exist.

[@charudattashinde4732]

sir kya aapka whatsapp group he net or nbhm ke exams ka..

[@dr.ramswroopswami8101]

Nice sir

[@AbhaySingh-wk3vg]

Sir tan πx/2 ko jab 1- krke chk ki h limit so x ko 1 Kyu rkh Diya,smjh Ni aaya mujhe

[@pakvlog379]

Dense set If A cluser is equal to R then A is called dense not limit point On the other hand If A'=R then A is called perfact set .

[@subratagorai6612]

Sir f(x) = exp(x) cos(1/x) is uniformly continuous on (0,1) ???? Please give reasons......

[@sanjithar2355]

Sir, results except Cauchy test is not necessary right?

[@HarpreetSingh-bt5vb]

I think closure of A must be R for dense

[@aliusmansahib9379]

Sir g agr 1/x ko open interval (1 infinity)mei ly to yh b uc nai hona chye same jis trha (0 1)mei Lya hai q k (1 infinity)mei b 1 include to nai hai hm es k kreeb jitni cahay CHOTI value ly skty hai bsss dusry wlai trick sy to yh uc hogaaa kindly plzzz sir clear kr dy reply kr k yh bht concfuse kr rwha hai point

[@aliusmansahib9379]

Q k xy to 1 k kreeb jitni CHOTI value dy gy 1xy itniii Badi value dy gaaa to phr yh uc nai honaa chye per dsury wlay method Sy yh uc bn jataa hai

[@lovelypari373]

Sir if we can prove that the function is Lipschitz function then it will be uniform continuous??? Can we prove by this method? Is there any limitations of Lipschitz function?

[@RahulMapariBasicMaths]

Yes, this is one of the method

[@stevenabakash919]

U said the definition of convex set

[@vineethsasi1985]

Sir please explain the definitions in English

[@RahulMapariBasicMaths]

Already explained

[@soundharyadevik9694]

Sir I need english language...I cant able to understand....

[@murthymechi4296]

🙏🙏🙏

[@SRMaths-sr7mg]

👍👍👍👍❤️❤️❤️❤️❤️

[@nareshwagh751]

Sir u told that if limit comes infinity then it is existing infinitely in singularity topic but here u r saying it doesn't exist 🤔

[@AjayGupta-ps8mt]

function e^x is U.C. in R or not

[@RahulMapariBasicMaths]

No

[@simmann2032]

@@RahulMapariBasicMaths but e^x is u.c on (-inf a) where a is finite. Right sir

[@RahulMapariBasicMaths]

Right

[@AjayGupta-ps8mt]

@@RahulMapariBasicMaths but sir Aapne iss vidoeo ke 4.32 pr Bola h ki. e^x is u.c. on the set of real number😫😫😫

[@RahulMapariBasicMaths]

Achha. By mistake hua hoga. Because we have check on (0,1).

[@mantashawani7959]

Sir e^x (0,1) py U.C hai ya nahi? Plz reply

[@wasubhat4163]

Yes

[@akash105a]

Sir if a function f is closed and bounded on an interval then also it said to be a uniform continuous. Isn't it? If it's true then why f = x^2 is u.c when x €R

[@RahulMapariBasicMaths]

x^2 is not UC on R

[@akash105a]

@@RahulMapariBasicMaths sorry sir the function is f = x

[@RahulMapariBasicMaths]

@@akash105a ok. Now, stat: if function is continuous on closed and bdd interval is UC. It's a sufficient condition and not necessary.

[@akash105a]

That means on intervals which aren't closed and bounded there are some functions which are uniformly continuous while others are not.

[@rimaauliarahayu]

for f(x)=e^x if xn= ln (n) and yn= ln (n+1) then |xn-yn| -> 0 but |f(xn) -f(yn)| =1 > epsilon. so e^x non uniform continu. am i wrong?

[@akash105a]

Mod of substitution of the function of those points has to be less than epsilon for mod of substitution of the points less then delta

[@rozil2763]

Lim tends to 0 of Sinx/x is 1 by rule But cosx/x is not how please explain sir

[@Vikas_85]

Because it is not a indeterminate form L hospital's rule

[@bishnu3170]

Sin(x) is UC on (0,1)

[@RahulMapariBasicMaths]

Yes

[@rachnayadav612]

It's wrong this statement is not vice-versa... Only U.C can be proved ...we cannt claim that function is not U.C by this result

[@jishanalam007]

Sir R closed set hota h

[@RahulMapariBasicMaths]

Yes

[@Sachin-is5oc]

Speak hindi

[@RahulMapariBasicMaths]

Ok