How to use Newton's Method to solve an equation on an interval. Calculus 1 tutorial

[@bprpcalculusbasics]

👉 How to get the newton's method formula: kzbin.info/www/bejne/n4eypIhqqdOiq80

[@maximeclere9902]

4:58 XD the answer has 2.7 and 3.14 in it

[@WerewolfLord]

4:55 The answer is approximately 2.7.....[suspenseful music plays*] *it doesn't but it should

[@owoLight]

*audible gasp*

[@tejarex]

Newton's method works great when it works, but it fails when the initial guess is not good enough, which is pretty easy in general. Given a continuous function f and 2 points where f has opposite signs, finding an intermediate root by bisection, always keeping two points with opposite signs, is guaranteed to work. For this example, assuming that the 2.63 root is unique, one would check 2.5, 2.75, 2.625, 2.6875, 2.65625, etc.

[@andikusnadi1979]

12x^3 not 12x^2

[@boldspider6923]

very straightforward, thanks Bro

[@robertveith6383]

@ blackpenredpen -- I don't see your rationale for picking x_1 to be 3. I would have averaged the endpoint values and used 2.5 instead.

[@NattyPi]

my profesor didnt really explain it either and what sucks is we have an exam coming up and all the examples have been to 6 decimal places which means if you don't pick a really good starting point you will end up spending 30 minutes on this. In class we ended up on xsub11

[@T-zm6ft]

Excellent video👍

[@kepler4192]

now do it with euler's method now

[@bradley9856]

So the answer was closer to 3 anyway? That's interesting. Good video ty

[@kiit8337]

Where is the full lecture for newton method?? Help plz

[@MyBroSux24]

check on 3 blue 1 browns brilliant video where he not only shows how newtons method works but how its applied to resemble a fun pattern.

[@AviPars]

Thanks

[@Tiwey]

Isnt this the differentiating quotient of the normal?

[@woofy2000]

π'th

[@diniaadil6154]

fancy way to just say you're third

[@moskthinks9801]

@@diniaadil6154 nah, according to the comments, π = 5

[@riendmuskus4050]

@@moskthinks9801 look at timestamps looks like he was after 3 but before 4 so it checks out Should've been 2.63rd though

[@mathiasschembri5207]

he means π in radians

[@francocosta1]

Wolfram rules!

[@hanantoaditya4139]

Is this numerical methods?

[@bprpcalculusbasics]

Yes

[@gatocomcirrose]

i mean, if you have to do this by hand it's just better to use wolfram alpha

[@TristanANain]

Thank you sir for the lesson but the sad face tho😂

[@robertveith6383]

*@blackpenredpen* -- Here is a way without calculus: Set 3x^4 = 8x^3 - 2. Divide each term by 3x^3: x = 8/3 - 2/(3x^3). If you let x_1 = 3, then x_2 ~ 2.6419753, x_3 ~ 2.6305154, ... , x_6 ~ 2.6300203

[@josevidal354]

Though its correct that You approach the answer,, it doesnt always work. For example, lets Say You want to calculate another root of the same polynomial that is about 0.696889... Using the same method, lets start with a close one: x_0=0.6968, then x_1=0.6961, x_2=0.69044, x_3 = 0.6412, x_4 = 0.1378, x_5 = -251.83, x_6 = 2.66... if You continue You eventually aproach the other root 2.63002... but not the one we wanted. How can You know When is it ok to do this? The answer lies In calculus:: You have to make sure that the root You want to get has an absolute value of it's derivative at the function f(x) = 8/3-2/3x³ less than one.

[@priyanshrawat442]

That pokemon ball mic is cool

[@robinson5923]

Ωth

[@marmot1434]

sixth

[@Ashmit_1729]

Make a video on golden ratio Please*10^100000000000

[@henrybeenh7076]

Nothing 's wrong with you

[@lukopro3655]

Fourth

[@umarfayziev5235]

Third

[@gamerpool9000]

First

[@dublindark7945]

Second