Using kirchhoff's rules find the current in each resistor shown in figure

[@anthonyrodrigues9506]

In 11 minutes you were able to cover more than my teacher did in 3 days...thanks so much!

[@indiaclo]

I agree!!!!!!! I understand it soooo much better now. I will be using his videos the rest of the semester.

[@siwelalulwandle5407]

loooool you finished me

[@SuleMustafa-y1b]

😮 ehh please how did the man get magnitude ?

[@abiramaeswaranganesan3878]

😢​@@indiaclo

[@DapaChrons]

Finally a video that actually went through each step properly, thank you!!!

[@Mitrell]

You're one of the best tutor alive. Thank you so much.

[@jadbuilder]

I swear I owe you a kidney for this one. You have singlehandedly saved me at least three days worth of mindsplitting trial and error. Earned a sub for sure.

[@letsgobunnies8399]

Thank you sooo much for the videos , you have really helped me out for the exams . May God continue t bless you sir

[@demon1c462]

Absolutely perfect. Couldn't have explained it any better, THANKS A LOT!

[@audreyd5996]

Thanks for this video! I couldn't completely understand the topic until I saw and listened your explanation

[@natalielane3561]

Thank you so much for your videos, been watching all the circuit ones and they are so helpful (I feel confident enough to complete them now with your help!)

[@faisal7736]

Thank you from the bottom of my heart. You are a savior.

[@sanjanasrinivasan13]

After watching many videos....I understood it finally Thank you so much sir!!

[@guggystyle]

You're welcome!

[@electricalengineerriazul]

Thank you so much 😍 ... your class is very helpful for me ... Now I can solve this math ... 😊😊😍😍

[@tanvirbadsha1629]

The best 11 min before i go to exam xD thanks a lot. Take love

[@finhasnebiyou987]

This workout question literally was in my physics final exam yesterday what I'm regretting now is that I didn't watch it :(

[@seangvibol923]

Hello teacher I’m from Cambodia Thanks for sharing this Video teacher 😘🥰

[@guggystyle]

Hello from Buffalo, New York!

[@paulcarty9278]

When adding the two equations 5 -1.5 i2 + 5 - 0.75 i2 = i2 how did the 1.5 and 0.75 become 3.25 I'm getting 2.25 have I missed a step? Many Thanks

[@nasthehustler2539]

Same thing 😢

[@Mark-en8hj]

I think he got a mistake but it's fine I mean.. we all do make it sometimes but, yours is just the right answer.

[@꺄호-u4t]

There is I2 on the right side and -2.25*I2 on the left side. Maybe you forgot I2 on the right side😂

[@davidmwansa1187]

Not really he made a mistake

[@trentrogalski3254]

Thank you, this was explained well. you give a perfect amount of time for me to follow along and work out the problem with you.

[@basilkhan1998]

I owe it to you man. My professor sucked at explaining this

[@uchihalite-nd9vb]

Not me watching than before my exam 🎉

[@Waxmancan13]

Thank you so much i struggled with a similar problem for weeks! this really helps!!

[@ernesto456100]

Amazing video like always. I had been struggling with my homework and thanks to your video, I was able to finish it on time. This topic was very confusing for me, but after watching this video, I can now say I have a much better understanding on this topic.

[@crnchi]

For anyone confused about how to find out if the currents need any kind of prefix after calculating, look at the final step of the first substitution 3.25*I2 = 10 Check your resistances in V = IR format here, V = 3.25*I2 so the R is 3.25 and whatever the mentioned prefix is (in this case kiloohms) You can multiply by that prefix to make the answer more clear: 10 = 3250*I2 which gives 10/3250 = about 0.003077A (amps) then you can convert back to a more convenient prefix 3.077mA (milliamps) Alternatively (and likely more easily), you can constantly keep track of your prefixes by writing them through every step of solving Example: writing 3.25kΩ*I2 instead of just 3.25*I2. This way you shouldn't forget what scale your answer should be on

[@yohanneskefale7032]

Your video realy helps me.....thank you so much!!!

[@aks9144]

where did u calculated current in each resistor?

[@arshu916]

Very good approach.. i went through many lectures on kirchhoff's law problems.. they were all incomplete

[@Charlie-lp4qx]

OMG you're awesome i've learn so much in 11min

Very useful. You earned a new sub

[@faheem1216]

For part a how did u get 3.25?? Skipped a step and I've been over it many times where does the extra 1 come from?

[@꺄호-u4t]

There is I2 on the right side and -2.25*I2 on the left side. Maybe you forgot I2 on the right side. (-2.25)I2+10=I2 => 10=I2+(2.25)I2=(3.25)I2

[@DyingWillofTheUchiha]

This made so much sense. thank you very much!

[@charlesbromberick4247]

Very nice presentation.

[@ИльясШамшиден-р8п]

absolutely perfect teaching

[@UBEnergy1872]

Brilliant, well done! Thanks so much.

[@SuleMustafa-y1b]

Please I don't understood how you got the magnitude after the potential difference?

[@danielkhalandovskiy5838]

Can you finding the power delivered to each resistor in this problem?

[@Salamanca-joro]

I got i1 as 0.38 mA and i2 3.08 mA as well but when i added them to find i3 and i got 3.46 for i3?? I made i1 and i2 to go the junction and i3 to leave the junction, does this make my answer wrong?

[@Salamanca-joro]

I made a mistake here for i1 I got negative 0.38 so I forgot to use it And indeed I got 2.7 for i3😢🎉🎉🎉🎉🎉 let's go!!!

[@operationsusfoods1354]

at 9:01 you did 10\3.25 . You said 2.25 at first. so instead of 3.08 its 4.44.

[@kaizer8813]

Saw from another comment and I just noticed that the video isn't wrong, also I think he never said 2.25. Anyways, the video's right because there's still an I2 on the other side which is just 1. So 1 + 2.25 = 3.25. Though this is years ago, just wanted to share haha.

[@rhudinaormasa1962]

Sir when I add what you got on I1 to 13, it didn't match the answer you got on I2

[@ebunoluwaojo9356]

why did you change the direction of loop 2,

[@mackss9468]

Absolutely fantastic! Thank you!

[@JfC_HipHop]

This clears up a lot of issues that I had. Thanks!

[@carylingridc.manalo5518]

how about if there is only one battery and three resistors and I need the current of each branch of the circuit? pleasee answerrr

[@SRINIVAS_99]

I2 value is 4.4444

[@Subzi_]

I like your voltage value. ;)

[@untitledmusic7986]

im also confused where did 3.25 came from?

[@꺄호-u4t]

There is I2 on the right side and -2.25*I2 on the left side. Maybe you forgot I2 on the right side. (-2.25)I2+10=I2 => 10=I2+(2.25)I2=(3.25)I2

[@junlinwu7577]

How do you find total current after finding I1, I2, and I3?

[@GershomChabala]

Amazing❤❤❤❤

[@ahmeda.mahmood9333]

Thank you very much you have very good explaining method

[@Camillelele69]

im confused. i have similar question for my physics class but we just need to find the potential at a specific point . for example in this problem, how can i find the potential at point c

[@praveenmittal2150]

Shut up

[@collateralkiller959]

Multiply current and resistance

[@odhiambojohn9695]

it should be 2.25 not 3.35

[@kurowashi3268]

yea he didnt notice but still a great help tho..

[@꺄호-u4t]

Loop1) I1=5.0mA-1.50*I2, Loop2) I3=5.0mA-0.75*I2, I2=I1+I3=(5.0mA-1.50*I2)+(5.0mA-0.75*I2)=10mA-2.25*I2 I2=10mA-2.25*I2, ∴3.25*I2=10mA, I2=10mA/3.25

[@faheem1216]

@@꺄호-u4t how do u get 3.25???

[@꺄호-u4t]

@@faheem1216 Check the equation in the last row. There is I2 on the left side and -2.25*I2 on the right side. Maybe you forgot I2 on the left side.🙂

[@triplea1998]

i think even the like is not enough to thank you ❤️❤️❤️

[@sea5205]

Thankyou, such a good example question and walkthrough!

[@crislozada1031]

thank you man. from colombia.

[@olivertsaldivia4927]

You are the best thank yoh is very easy to understand the lecture

[@amadubah241]

Please can you make a video of 3 loops with multiple voltage switches

[@maliksalisu5255]

u r de best thanks a lot

[@sean_tristan31]

do you always have to move in a different loop the 2nd time?

[@DevaKumar-uy6mf]

Nice explanation

[@JoeMcLutz]

Thank You! 👍

[@larryg2320]

So, you are using conventional current flow

[@einsteingonzalez4336]

Thank you, but matrices to solve it is overkill, I’d use that rather than going the long way.

[@Hannah-lr1uc]

this is so helpful thank you thank you thank youuu

[@maxi0613]

i loved the video and how you taught but that yellow light is killing my eyes

[@olivertopa]

If only potential difference at f what is the answer

[@jyothi1723]

thank you!!!

[@Skunkfish16]

The true goat

[@guggystyle]

Moo . . .

[@anikaisom557]

Thank you sooooo much

[@Violetvixen789]

THANK YOU SOOO MUCH

[@Nia-pv5ix]

How to determine which current for each resistance??

[@evam4588]

Bless you. I finally understand this.

[@reubenwilliammpembe667]

Thank you - you are the best!!!

[@kelvinscott1517]

hey i have a circuit problem like this can i get some help?

[@davidmwansa1187]

Have seen you’ve written your answer is wrong sir on 3.25 instead of 2.25

[@akhilvs8593]

oh god atlast now i understand kirchhoff law

[@ayom6354]

God bless you sir!

[@neroflame13]

you're a life saver

[@neroflame13]

you're a light saber*

[@biridun9999]

nice

[@JuniorPalioSikipa]

❤❤❤

[@MoniSmiles]

If you chose different directions, how would you know if the current is positive or negative? I chose a different direction and got a negative answer for I2, and it took me over an hour to redo it, because i thought it was completely wrong, until I did it your way and realized I just had the sign wrong!! what a waste of time, please tell me so I dont make the same mistake!

[@mel_pastel]

MoniSmiles you did it right. Your negative sign was just indicating that your current is actually going in the opposite direction.

[@NoorNoor-pf5id]

I wish the background wasn’t yellow😢

[@whiteeagle4647]

It's 2.25 when you add

[@meta-1123]

KING

[@awakenfesco5303]

THE ANSWER IS WRONG, YOU MADE A MISTAKE IN YOUR CALCULATIONS,

[@josephguida5432]

He made a huge mistake. This was a classic node voltage analysis problem that could have been done in 3 minutes. (b) was positive 69.23

[@_zerofox]

#Legend

[@roham1981]

life saver

[@eleven9743]

Thank you so much

[@WaqarAhmed-uk7tc]

I2 is 4.44 since 0.75 and 1.25 is 2.25 not 3.25

[@WaqarAhmed-uk7tc]

1.5*

[@frankup209]

(1)I2 + (0.75)I2 + (1.5)I2 = 3.25 I2. you're forgetting to add the 1 that already exists on the right side of the equation.

[@priyayadavyadav8502]

I think Its 2.25 not 3.25

[@askwang]

yes yes

[@w_3007]

thank you so much....

[@theinsultingfrenchman5052]

Lol I wish you were my teacher!!!

[@ashtonsibanda1844]

😊

[@DavidLee-b9k]

Miller Helen Thomas Karen Clark David

[@biltonjohn6109]

Llak Il

[@soothingaf8701]

can we take I2=I1+I3..

[@praveenmittal2150]

Yup

[@whiteeagle4647]

i2 answer is wrong

[@꺄호-u4t]

I2 is not wrong. (-2.25)I2+10=I2 => 10=I2+(2.25)I2=(3.25)I2 => I2=10/3.25 Yessss

[@gabrielmakoi3905]

Thank you so much