Using the Wave Equation (Wavelength, Speed and Frequency)

[@connordziadul6048]

Even now, does this video prove significant for scholar education. You saved my overall physics percentage. I can’t thank you enough

[@akiraleva5496]

This video is pure gold, thank you so much for the simplicity and being straight forward -- you rock man !!!

[@joneshilburn126]

Thank you so much, you just made physics better. Very useful

[@erwinbauernschmitt4104]

This helped so much! Thanks for the explanation. I really liked the question you used because it allowed you to manipulate the data/values to solve different parts of the problem.

[@faithlee8925]

This video saved my life. Thank you! Hopefully I can pass physics now

[@MadhavNumeroUno]

Well well i would have passed but now i am ded

[@wiktoriaklimczak7775]

Even 6 years later this video is helpful for many. Thank you for the very good and short explanation

[@zenqxq]

Bro tysm I'm having a hard time understanding this at school but this just help me understand it now

[@TheScienceClassroom]

😀 I'm so glad you understand it now! Nice work!

[@davidnathanielnaicker2351]

Just started physics and this is helping me so much ,thank you 🤙

[@TheScienceClassroom]

You're welcome!😃 Good luck studying physics!

[@PotegoLekoadi]

I need you to be my physical science teacher ❤

[@TheScienceClassroom]

🤗

[@caleahparis]

this was so concise much appreciated

[@TheScienceClassroom]

I'm glad it helped! 😃

[@MohammedNuralamMollah]

Thank you so much this video helped me a lot

[@velo9361]

as childish as this is, 100th comment. still, tysm for the video, it has HUGELY helped my understanding hope u do more vids like this TYSMMM

[@TheScienceClassroom]

100th comment! Awesome! Glad this video helped you out!

[@mwendwakirimi336]

Really helped a lot .... Feel appreciated

[@praveenapradeeshkumar2521]

Thank u your class is so good❤

[@TheScienceClassroom]

I'm glad you like it!

[@keituu.M]

this was really helpful thank you

[@egitamakloe388]

Beautiful video

[@connorisbored3834]

I have a classwork due in like 15 minutes and this saved my grade so thank you

[@zooMonalicom]

Thank so much for making video . I am very happy ☺️👍. You are so good

[@yulissacontreras9958]

If a weather station emits an electromagnetic wave of frequency 300 MHz or 300 X 10^6 Hz and it takes 0.0002 seconds to receive its echo from the rain cloud and the returning frequency is 310 MHz. What is the speed of all electromagnetic waves ?

[@jessicaike7919]

it makes my equations easier and understood

[@Dym2828]

Thanks again

[@TheScienceClassroom]

Always welcome

[@swiss4ever93]

thank you this video was a big help

[@Mowee3644]

Thank you very much 💜

[@krishamarieserenadoavenido771]

Omyghaaad thank you so much!! This video save meee and my gradess!! Again thank you so much❤❤

[@Legends_1729]

Thanks

[@insanebandi8585]

Thank you

[@Hacker-yb9wz]

thank you!

[@TheScienceClassroom]

👍😀

[@Isabel-qf2fm]

where did u get sa 10^-3 on the 1.85x 10^-3s?

[@Crypt2349]

Thanks a lot

[@user-ze8fr9wq1t]

Dumb question, but if you were given the frequency, distance and speed would you use t = d/v or t = 1/f?

[@ssolveig]

How do I get the wave speed with only the frequency and wavelength?

[@Trippzyy]

wave speed = frequency x wavelength

[@luthandokeswa7198]

And just like this guy saved my ass Thank you so much we really appreciate it 🙏🏾

[@TheScienceClassroom]

No problem! 👍

[@yoo3644]

is speed and velocity the same thing?

[@squirtlett7369]

They are the same number, velocity just includes direction. For example the speed of a car could be 60 mph while the velocity of that same car is 60 mph South

[@jjche3480]

NO THEY ARE NOTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

[@plutovvv]

yes

[@Maryam-uw3xx]

I love PHYSICS

[@tamarimazara5536]

How do you calculate it on the calculator

[@mdnaimur4948]

Is there anyone who could solve this for me? if mass transport is 1 cm per wave period, calculate in meters the total mass transport over 10 hours, assuming the wave has 10second period

[@APersonOpinionWithoutThought]

I would have do this on a piece of paper. If you would just replace those...the parts or information into the layout in the video, you might work it out.

[@wasanalakmini1227]

it was great.

[@mudgalclass9472]

154÷0.467=329.76 not 330

[@diy-projects]

close enuff

[@Runic_]

he rounded it to the closest whole number

[@SiphokaziGqola]

Do you always multiple by 10 exponent negative three

[@TheScienceClassroom]

No, I wrote the solution to 1/540 in scientific notation. 1.85 x 10^-3 is the same as 0.00185

[@amarbat4794]

thank you for making it easier

[@verydry137]

got a physics test tomorrow less see IF I MANAGE TO REMEMBER THIS

[@pierrebringmans4274]

why its 10 to power-3???

[@arescaim3142]

Please help me because I dont get how to get period of wave

[@Ash-luvsZ]

1 divided by the frequency

[@CHIPEPO-lf9qx]

How did u find 10^-3

[@TheScienceClassroom]

The answer my calculator gave for part c was 0.00185, so I changed that to scientific notation.

[@pubggamersgamers7570]

A sound wave has a frequency of 2KHz and wave length is 15 cm . How long wave it takes to travel 1.5km

[@carsonleischner5884]

Hemanti Kumari 2000x15 = 30000cm/s or 300m/s -- 1.5km x 1000 = 1500m -- 1500/300 = 5 seconds not sure if I’m right but that is my answer

[@gabrielm4907]

Does anyone know how to find a wavelength without knowing the velocity?

[@paranoid-v3q]

The velocity is given. You can't find a wavelength without velocity.

[@paranoid-v3q]

I calculated the velocity and got 329.7. Is it not necessary to write down the exact answer? But it's still cool anyway.

[@TheScienceClassroom]

I rounded my answer to 3 significant figures to match the given data

[@YuriLawrenceCORATE]

whats the formula?

[@moonmoondas]

Calculate the wavelength and time period of a sound wave of frequency 480 Hz (Velocity of sound in air = 330 m/s) . Please let me know the answer

[@XxBugzzyXx]

What if it only completed 4 instead of 5

[@scribble_demon2505]

I'm hearing and I have captions on and the last equation you cant see if you do

[@fenixamorebey5595]

How did you end you up with your last answer on "C"? With the tenth to the negative 3rd power

[@fenixamorebey5595]

Im am barely studying this on my own & want to be able to understand it. Please elaborate

[@terry-fb9il]

search standard form in google, it is just a different expression of the answer. it is just more convenient to show in this form.

[@dawesazor651]

look for the SCI on your calculator and press it and add the numbers above

[@joshffa3855]

Bani solorzano -3 power is a decimal so 5.67 x 10-3 would be 0.00567 -3 is the number of zeroes. So 3 zeroes before the number starts.

[@mvrd3431]

@@joshffa3855 thank you.

[@caia1869]

omg thanks! i can now go to 8th grade

[@nicobasima9370]

Wait I’m in the 9th and doing this shi- how the hell are managing?!?

[@aaravsingh541]

I’m in 6th :) 😅

[@nicobasima9370]

@@aaravsingh541 bro. I respect you. I bet you’ll do great

[@aaravsingh541]

Thanks

[@atharvapote755]

Nice

[@MalfoySimps]

I think the 1st question a) is supposed to be 329. Idk

[@TheScienceClassroom]

I rounded it to 3 significant figures so that's where I got the 330.

[@opianomattyobloggergameran5075]

how did you get 330 as you speed?

[@Chadrawss]

OpianoMattyo Blogger Gamer and more 154 divided by 0.467 =329.76 then round it off =330 m/s

[@caizelynshaine5072]

@@Chadrawss but i thought that if you wanna get the speed you multiply wavelength and frequency

[@solfaie]

Im doing my homework while crying rn

[@justmesnappy5536]

Bruh if I can rate ur teaching out of (10 ) I would have gave u 10/10 💵🔥✅✊💸

[@Clouddey]

1:50 the reason he got 330 instead of 329 is becaue he rounded it to the nearest 10

[@TheScienceClassroom]

Yes, to keep the precision of the answer consistent with the given values.

[@samstudy6229]

Thanku re

[@thatonehomelesslady9482]

How do u get 330 meters per sec

[@imaneamaziane2601]

he rounded it ul

[@l75rd83]

iv just got a picture

[@rosemariebalingit6808]

I think this is wrong calculation because if you are going to find the speed of the wave the formula must be v = w(lamda) × F

[@rodinamendoza6886]

this is Y E S

[@DarkMatterr]

I wonder how long it will take me to answer a simple question like "C"... A calculator isn't permissible in the Physics S.A.T test.

[@SushiPoke]

Ultra Instinct Goku if a calculator is not allowed on this portion then just leave the answer in it’s equation form. they can give you the point because technically it is the right answer

[@meepbeep2464]

@@SushiPoke thats not how MY SAT works :'(

[@SushiPoke]

meep beep really? Well I doubt that anyone can solve 1/540 hz without a calculator. I’m pretty sure if an equation like that was on the non calculator portion of the exam, then it’d be fine to just put 1/540 hz. Although, if there was clearly a way to simplify it without a calculator, you may lose a point because it wasn’t simplified

[@meepbeep2464]

@@SushiPoke my teachers told me I have too simplify it :( (Dont worry the questions were not that hard)

[@aayaneditz945]

Isn't the answer for part a is 329.764

[@TheScienceClassroom]

I rounded this to 3 significant figures to match the given data.

[@caizelynshaine5072]

Wait....so you divide the wavelenght to the time to have Speed? Our teacher taught us to multiply it lol XD...

[@caizelynshaine5072]

Wavelength*

[@real-gn7fn]

me too

[@Villascout]

No, if you notice he is dividing the distance the wave travelled (154m) not the wavelength (0.611m)

[@ProGaming-nc9bo]

I AM THE FIRST COMMENT👍🏻👍🏻👍🏻👍🏻👌🏻🎶🎶🎶👻👽

[@meepbeep2464]

I see this, and be like, NO ONE GIVES A -

[@caizelynshaine5072]

@@meepbeep2464 lol AHHAHAHA

[@youssufibrahim2335]

Green

[@vicheakeng6894]

5.5mm

[@Hansenes]

I love the internet.

[@TheScienceClassroom]

😀

[@sin3224]

hehe where the x 10 -3 came from

[@kelvindennis9557]

nice

[@jjche3480]

ar

[@trudymerritt8149]

What

[@baconcgm9869]

Physics Bye Bye

[@Landon.0utlaw]

God i hate science

[@zuliatameen3286]

thank you

[@cycyrus6993]

Thanks

[@niharikasaikia5276]

Nice

[@czechdisout7923]

Thanks

[@sulfashaji8305]

thank you

[@marlonhardemanjr.6959]

Thank you