When you solve for the two equations at the very end, you had the acceleration at a = (6i - 8j), but when making the two separate equations, you made 8 positive. If that was not a mistake, why did you end up doing that? Otherwise, seriously great video. This filled me in on two weeks worth of material. Hopefully I do good enough on this test (:
@CPPMechEngTutorials7 жыл бұрын
Nice catch. At 8:58, the left side of the second equation (containing the y terms) should be -8 instead of 8. The answers for alpha_AB and alpha_BC are correct though. I just placed a note about this error in the comments.
@dr.engineering2016 жыл бұрын
CPPMechEngTutorials please do mor examples on general plane motion and explain where you be these formula from.
@premkc65828 жыл бұрын
pls add some more videos related to kinamatics of rigid bodies
@bigmoneymiller71743 жыл бұрын
What an incredible and clear-cut video. Thank you.
@KooKKoZ6 жыл бұрын
how did you get omega AO to become 10 k? was that given?
@CPPMechEngTutorials6 жыл бұрын
Yes. That is a given.
@Chan-ux7ej4 жыл бұрын
Thank you for this video. I was able to follow through the entirety of the video, however, I had trouble with one concept. I could understand why the angular acceleration of AO is zero (due to its angular velocity being constant), but I was wondering why we didn't assume the same for angular acceleration of BC. Would love clarification
@adharshsrinivasan69427 жыл бұрын
At 8:17 when substituting the fomula u have menationed a(c) to be 0 but still u have still taken the value Can u explain why?
@CPPMechEngTutorials7 жыл бұрын
a_c = 0 because it is a fixed point. Can you please explain what you mean by "but still u have still taken the value"?
@adharshsrinivasan69427 жыл бұрын
Why havent you considered alpha(BC) value as 0?
@CPPMechEngTutorials7 жыл бұрын
Why should it be 0?
@antonioworrell55247 жыл бұрын
I'm having a little trouble with that as well. If you considered alpha (ao) as zero because it had a constant angular velocity wouldn't alpha (ac) be considered as having such as well?
@TomFisherEng7 жыл бұрын
9:04 you say 2 equations and 2 unknowns but I see 3 unkowns. Please could you explain? I followed everything up until here.
@CPPMechEngTutorials7 жыл бұрын
What are the 3 unknowns?
@andriuszapasnikas51846 жыл бұрын
Hi, are you sure your answer for alfa ab (min. 9:03) is correct? I am getting -56.25 Rad/Sec. : because if Wab=2.5 and Wbc=5.833 then 8=-6.124+0.625-0.24 alfa ab
@andriuszapasnikas51846 жыл бұрын
sorry ignore my previous comment. I have just read pinned comment. Thanks for great video
@ensaiosmecanicos35626 жыл бұрын
sorry, but i can't see where the values for W^2(BC) and W^2(AB) came from... are they equal to zero or are they unknowns?
@havalothman37837 жыл бұрын
In which book can I find that exercise plz ? can you recommend some books whchs have solutions for the exercises Thank you!
@hassanhassani29127 жыл бұрын
i need info on collision for linkage systems. can anybody help?
@vredekhoo39448 жыл бұрын
8.52 , should term 'aA' be 6j-8i rather than 6i-8j? Since aA=wAO x rAO=10k(-0.06i+0.08j)= 6j-8i?
@CPPMechEngTutorials7 жыл бұрын
Yes. Nice catch. At 8:58, the left side of the second equation (containing the y terms) should be -8 instead of 8. The answers for alpha_AB and alpha_BC are correct.
@chandramoulidharmana8 жыл бұрын
thank u sir i hope it can helps me in my tomorrow examination.
@CPPMechEngTutorials8 жыл бұрын
Let us know how it goes.
@mehmetalivat4 жыл бұрын
Pure amazing solution step by step.
@ensaiosmecanicos35626 жыл бұрын
shouldan't normal acceleration component (W^2 x r) be negative?
@sayanjitb3 жыл бұрын
For which arm?
@Kadoc06 жыл бұрын
I am extremely grateful for this video! Thank you!
@CPPMechEngTutorials6 жыл бұрын
Our pleasure.
@mrdod91627 жыл бұрын
Why is the velocity at Va=0?? Doesn't it have a velocity?
@CPPMechEngTutorials7 жыл бұрын
Can you provide a time stamp where the velocity at A is said to be zero?
@JordanAXJ6 жыл бұрын
Why alpha BC is not zero since omega BC is a constant of 5.833 rad/s ?