Chemical Equilibrium (Part-2) | Class 11 Chemistry | JEE 2022 | Flash | Vedantu JEE Enthuse English

[@Vedantu_JEE_English]

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[@liyanakp8197]

Where is the part one?

[@varunk.s3899]

session starts at 5:23

[@Mr_wolf162]

3 years later still watching ❤ as a dropper

[@ballusartandcrafts6291]

?Part 1???

[@dattatari]

Amazing....crystal clear ...now I am going follow all your lectures

[@DeekshaR-j4w]

Part -1

[@babydances5399]

hello sir here what is k to the power of x and at the time of 21:21 at the video time

[@harshavardhini3641]

Sir session is awesome, answer for h.w question is 0.1,0.2,0.2 sir

[@poojithapatel3480]

I too got same but aishwarya ans looking differ ..

[@jyothivb3212]

Session is amazing....following all your videos...

[@aishwaryagandhi1878]

Sir the session was awesome 👍. 2HI ➡ H2 (g) + I2 (g) t (eq) 0.2 0.8 0.8

[@poojithapatel3480]

Concentration or moles at eq u posted. ...i got 0.1,0 .2,0.2 as concentration of each term at eq

[@indiantalent3407]

0.05,0.46,0.46 sir is it correct

[@haria272]

Where is part 1 Sir ple upload 🙏🏽🙏🏽🙏🏽🙏🏽🙏🏽🙏🏽🙏🏽🙏🏽🙏🏽

[@Sunil-if6gj]

Sir, is partial pressure and normal pressure the same?

[@varsithvarshu5958]

0.05 , 0.2,0.2 ... The x value is coming as 8/9....correct me if am wrong... ☺

[@hariprasathmadhavan3496]

Crct

[@sskk5539]

Respected sir please clarify my doubt 52:40 you had written the no of moles of a,b and c Instead of writing the no of moles,can i write a moles like in previous questions ? please clarify my doubt sir Thank you 🙏

[@sanjitp9576]

First part is private?

[@sarikajadhav3329]

What's mean by partio pressure

[@aairashakeel8120]

Sir can you please tell me best book for physical for practice questions

[@Vedantu_JEE_English]

N avashthi

[@aairashakeel8120]

@@Vedantu_JEE_English thank sir The lecture is absolutely assom .👍😄😄

[@khushiaslam5259]

Amazing session sir🧡🧡🧡🧡

[@TheodorerooseveltTheFourTH]

Starts by 6:15

[@Blacklinebyjatin]

thankyou so much sir

[@idreesgulxar349]

hiiii sir

[@mitulmalani9921]

answer: 0.05,0.22,0.22

[@dharshinis8166]

0.1,0.2,0.2

[@chandugoudbolagam7724]

Could you explain

[@dharshinis8166]

U will get 16=x^2/4(1-x^2) U should take square root on both sides..then u will get the and If u dont take square root it will b very tough to solve!!!!!! Hope u understood😊

[@chessclouds5100]

0.05,0.4,0.4

[@swapnilverma3612]

Sir session and ur teaching was awesome but plzz teach in hindi too