Triangles L2 | CBSE Class 10 Maths Chapter 6 | NCERT Solutions | Sprint X Pre Board 2020 | Vedantu

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[@abhinavpanwar3383]

Me : (turning pages of NCERT)Maths is so easy Also me : (turning pages of RD SHARMA) R.I.P my marks

[@anusreekarottel6029]

Same!!!

[@designersparzival2352]

RD .SHARMA hah never saw any book easy than RD.Sharma , I am solving RD.SHARMA from 6th class ! its easy pal ! try a little practice and U will also gona LIKE IT!

[@aiswaryapriyadarshin3779]

Yah same 2 same.

[@urvii.diaryy]

@@designersparzival2352 you are genius if you find Rd Sharma easy😂😂

[@runupanda246]

As we know that median divides the line segment into two equal half (mid point) and angle formed is 90°. So, in triangle ABD and triangle ADC AD=AD(common) BD=DC (D is the mid point) Angle ADB = Angle ADC (90°) Triangle ABD =~ Triangle ADC ----- (1) In triangle PQM and triangle PMR PM=PM(common) QM = MR (M is the midpoint) Angle PQM = angle PMR ( 90° ) Triangle PQM =~ Triangle PMR ---------(2) So, from (1) and (2) Triangle ABC =~ triangle PQR (By SAS Criterion) By CPCT Thank you for effort for us and this session is good.

[@mathematicianadi7662]

medians work as altitudes only in equilateral triangles so you can't say that here they will make an angle of 90°

[@dishasonowal5555]

Wonderful and superb explanation. The best teacher of mathematics, always I wanted to learn from Sir and because of sir only I am becoming more confident. Thank you sir once again. The hw ans is as follows- Given- AD is the median of triangle ABC and PM is the median of triangle PQR. To prove- triangle(ABC) congruent triangle(PQM) Explanation- Here we need to extend AD to AR and PM to PS Then, AD=DR and PM=MS ABRC and PQSR are llgm AB/PQ= AC/PR= AD/PM AB/PQ= BR/QS=AR/2/PS/2 AB/PQ=BR/QS=AR/PS Angle BAR= Angle QPS Angle CAR=AngleRPS therefore Triangle ABC=Triangle PQR hence proved.

[@savitagarje4479]

Most questions are similar to those of the questions from NCERT EXEMPLAR 😊😊😊😊

[@riyaojal6609]

4:04 session starts

[@ishan9002]

session starts 4:04

[@ajay-ib1wh]

The fabulous teacher whose each word motivates me

[@shizu3331]

Hw Question is from...NCERT exercise 6.3 Question no. 14 .... Ans : ABC ~ PQR (By SAS similarity Criterion) Session Was Amazing....Thank u Sir..❤❤

[@Raushankumar-dc7ug]

Dear sir your teaching style is diffrent for other teacher Sir you have clear my all doubt Thank you sir You are a really great

[@MRSVDGAMER.]

Today's session was better amazing than previous one Amazing From Drimy Jain 🤗🤗🤗 Lalalala

[@bhadranair5302]

HW answer Triangle ABC ~ triangle PQR by SAS

[@guptad2010]

Waiting for yet another video of triangles.....☺️ ♥️ 😃 😇 🤗 superrrr duperrrrr✌️✌️✌️✌️

[@anamika331]

This session is gonna be super duper amazing as always sir 🙂🙂🙂

[@funnycreator7151]

I like Vedantu a lot.😍😍😍

[@sharviarora969]

sss similarity

[@divyanshughosh8663]

Answer => ABC~PQR (SSS Similarity Criterion)

[@mayurigupta9475]

When median and sides are in ratio so we can say that the two triangles are similar now in ΔABC and ΔPQR Ab=pq(given) Angle b=Angle q Ac=pr Hence by SAS these are similar Nice session sir Sir please tell the name of students who gave right and fast answer in sessions also please sir

[@ankuranant1655]

HW Traingle ABC similar to Traingle PQR by SSS similarity.

[@ankuranant1655]

The session was amazing ❤️

[@TubeEducations]

Hello Ankur. I'm Bilkiyas. If you want please support my Tube education.

[@CAStudent-w3x]

Sir, 3rd question me Hume pata kaise chalega ki trigonometry Ka question hai ya triangle?

[@parthback2u]

GOT TO LEARN A LOT VEDANTU THANK U ALL THE MASTER TEACHERS OF VEDANTU :) :)

[@urvii.diaryy]

Best teacher of mathematics 💜💜you are helping me alot during these days! Whenever I watch your any lecture I feel very relaxed 😌 because after your session it feels like that I know everything now thank you so much sirrr🥺🥺💜💜💜

[@5-minuteanimationwithharsh724]

It is similar by sss

[@surendrasinghchoudhary8819]

session was amazing nd ...................thnk u for this lovely session thnk u sir

[@rajivpandey7438]

Triangle ABC is similar to triangle PQR by SSS similarity criterion. Sir was amazing sir ☺️😊

[@VedantuClass9_10_11]

Thanks a lot!

[@harshkardha7634]

Session starts at 4:05

[@varishthraj9913]

ThnX

[@singhadityaadityasingh031]

Sir I like your way of teaching very much

[@sonuchaudhary3038]

Answer by SAS

[@arpitasen5525]

Harsh sir's explaination is short , easy and crisp! this is an amazing session ....just loved it💜

[@VedantuClass9_10_11]

Thanks a lot!

[@pallaviprasadpallu3339]

R u an ARMY...?!

[@serouniclips6801]

Sir maths ka vip series bhi karao please ❤️❤️❤️❤️❤️

[@pratiksourav7695]

Hii Sir, I have prooven triangle ABC similar to triangle PQR by SAS similarity. But how can I send in comment section??

[@UshaDevi-kw7fj]

Awating for this session eagerly

[@kailashjat4209]

This Sprint series is helping us a lot🙈🙈✌✌

[@devpriya7385]

Sir , can u plzz explain the home work question ?

[@sdeep8894]

7:54 sir ye question Book me kaha h..

[@golurajpoot006]

Today's quote is amazing

[@VedantuClass9_10_11]

Thanks a lot!

[@Zeba-vt9vl]

Doubt Sir in 7th question part 2 you said RHS is not a similarity criteria but in ncert it is given

[@suhani_aryan1088]

triangle Abc ~triangle pqr.. by sas...

[@ayushyadav06]

Waiting for the session!😊😊🙈

[@surajgupta9971]

Looking cool in the blazour 😉

[@letsmakejobseasy228]

H.w question s are similar by SAS criteria of similarity

[@AbhinavSingh-tg6sv]

Sir uu are great

[@sussyuchiha5780]

Sir, any idea of coming live? Pls do reply sir..

[@vikas0783]

Sir don't know about this class 😮😮😮😮😮

[@TavSvagtm]

Same

[@renubansal2244]

HW Answer Triangle ABC ~Triangle PQR by SAS Session was amazing

[@VedantuClass9_10_11]

Thanks a lot!

[@mahirastogi379]

triangles are similar by AA similarity..

[@dineshtyagi9271]

Waiting for the amazing session as always ❤❤

[@abhimanyusingh7579]

Very amazing and helpful session sir

[@prajwallakra]

hw answer in ∆ ABC and ∆ PQR given AB proportional to PQ AC proportional to PR so AB/PQ = AC/ PR cross multipling AB/AC = PQ/ PR so ∆ ABC Similar ∆ PQR sir lekin aaj ke session main chamat wala part sabse best aur op tha 😂😂😂😂👍👍

[@mathematicianadi7662]

yeh konse new criteria ki khoj krdi bhai tune🤣🤣

[@prajwallakra]

@@mathematicianadi7662 aare bhai dekh na dono main ratio wala property use hua hai na tho isliye ye converse of BPT jisa hua 😓😓 aisa shayad maine kahi pe dekha tha

[@shanmukhmanojp]

Sir what I did is correct

[@adityamenon3887]

hw answer - proved

[@chemistrywallah9760]

Great explanation

[@nishantsingh1379]

What a wonderful session 😊😁😉😁

[@tilakraj284]

Ans:- Triangle ABC ~triangle PQR by SAS similarity criteria

[@AmitNaykodi123]

Waiting for the session...

[@virajbhati4427]

SESSION WAS AMAZING 👍👍👍 ∆ABC~∆PQR{SAS}

[@pradeepsinghfromsgs7481]

Waiting for this sessions

[@selenophile_335]

Thank-you so much really ur session helps us a lot because these types question comes in our exams 💜🧡...

[@gauravsingh9498]

😉😉😉 Loved your session sir ☺️😉😉 Sir you are the best maths 🤠 teacher ☺️😅

[@VedantuClass9_10_11]

Thanks a lot!

[@gauravsingh9498]

Thank you sir Big fan of yours

[@sakshipandey957]

Wating for the session !! ☺☺

[@lalitavinod7313]

Wonderful session 🙂👌🏻

[@sonurathee7030]

Waiting for the session

[@romajha5066]

Amazing

[@kaustubhchakrabarti2400]

Sir, Superb Session. Thanks a lot

[@VedantuClass9_10_11]

Thanks a lot!

[@ishitasingh555]

Sir, homework done

[@Rohitpatil-qe7in]

Waiting for the session😊😊.

[@nsairaman8633]

HOMEWORK ANSWER. CONSTRUCT DE. BD=DC AND QM=QR ( MEDIAN BISECT) AD=DE (BY CONSRUCTION) PM=ML(BY CONSTRUCTION) SINCE DIAGONALS BISECT EACH OTHER IT IS A PARALLELOGRAM. AC=BE AND AB=EC (OPP SIDES ARE EQUAL) SIMILARLY, PQ=RL AND PR=QL. AB/PQ=AC/PR=AD/PM (GIVEN) AB/PQ=BE/QL AB/PQ=AE/2/PL/2=AE/PL T(ABE) SIMILAR TO T(PQL) (BY SSS) ANGLE A= ANGLE Q (CPCT)--------------------------->1 SIMILARLY T(AEC) SIMILAR TO T(PLR) (BY SSS) ANGLE CAE= ANGLE BPL (CPCT)-------------------------------->2 ADDING EQN 1 AND 2, ANGLE CAB= ANGLE RPQ IN T(ABC) AND T(PQR), AB/PQ= AC/PR (GIVEN) ANGLE CAB= ANGLE BPL (PROVED) T(ABC) SIMILAR TO T(PQR). THUS PROVED.

[@vinodpatidar8027]

Thank you so much sir you make this chapter so easy for me 🙂🙏🙏❤️

[@villaincutz688]

I made it 1.5k 🥳🥳🥳🤩🤩

[@pallaviprasadpallu3339]

Session starts at 4:05 Advertisement starts at 14:40 and ends at 18:45

[@bhadranair5302]

Super session 😁😁😁👌👌👌

[@VedantuClass9_10_11]

Thanks a lot!

[@dishitatiwari2603]

Session was amazing!!

[@karanpandey_mr.perfect3704]

SR plz can uu tell the sprint time of question ur vdo makes it invisible

[@bhavyasingh2285]

Sir what about Apollinius theorem.

[@nidhishshetty7337]

not there in cbse

[@bhavyasingh2285]

@@nidhishshetty7337 ok thnk u

[@perabathinisruthisruthi3169]

Hw is by sss criteria Amazing session

[@VedantuClass9_10_11]

Thanks a lot!

[@Vibhasingh0406]

First we will prove ∆ABE~∆PQL by SSS similarity then we will prove ∆ABC~∆PQR by SAS similarity criteria

[@suhani_aryan1088]

amazing session..❤️

[@VedantuClass9_10_11]

Thanks a lot!

[@architadas_13]

Waiting for the session..

[@akshatsrivastava4863]

Can't wait 😍🥰😍🤩

[@priyanshupatel7050]

Amazing session

[@ratneshmaurya4]

The sessions were so damn amazing sir I really enjoyed...sir your face just like chocolate milk and gorgeous you're awesome...!!! by the way sir please make one more extra session for menti.

[@mayurigupta9475]

Sir please take a menti please sir because preboards are coming

[@Soniasharma-rg9lf]

HARSH SIR IN ONE WORD MATHS MAN 😎🔥, GUY who can teach trigo without looking at the board 😂😂

[@abhijithpk9510]

Sir why was yesterday 2 sessions

[@surendrasahay4225]

can someone please explain me the homework question ? im not able to solve it

[@Vikas_pal563]

❤️❤️❤️❤️❤️❤️❤️❤️

[@varunchandar5673]

session starts at 4:02 thank me later

[@shivampandey2607]

Thanks 🙂

[@nigarchandali9488]

Sir ye sab toh bohot easy the....tough as gaye toh...???

[@Srishu01]

23:49 ye piche se awaj kesi bhai ???😂😂😂😂😂listen carefully then ☝️

[@anchitbagde7706]

7th question hamare pre boards me aaya tha

[@seetupandey4479]

2 tan90°/ 1- tan^2 90° sir ye question ka solution bta dijiye

[@seetupandey4479]

Plzz sir

[@anshikagupta1114]

I know the solution but how can I write it in comment

[@swapnilkulkarni5479]

sir pl uploa the pdf of this session a humble request

[@VedantuClass9_10_11]

Please check YT description

[@rudrakshtiwari1074]

h=6

[@mahakkumari1412]

Waiting for it.. The session is going to be amazing as always...🙂

[@dalisapopat7606]

Plzzzzzzz sir upload the pdf of this chapter

[@novideos...822]

Sir I am studying last night before pre board , and this moment : 26:10 made me laugh 😂😂😂

[@shauryasharma5171]

Since all the sides are proportional { GIVEN IN QUESTION} Therefore AB/PQ=AC/PR=BC/QR Therefore Triangle ABC & Triangle PQR are similar...

[@priyanshusrivastava4332]

Sir In AP i can't understand questions no 7 .

[@prateektiwari8514]

👍👍❤️❤️❤️👍👍

[@starstudio143]

👍👍👍👍👍👍