Velocity - Time Graphs | Graphs | Maths | FuseSchool

[@emilynowrang7729]

Teachers should teach like this more often! This was a really great explanation

[@fuseschool]

Glad you think so!

[@miwie]

Hello tae

[@andersondomingosgomescassu6818]

Some hard trap playing in the background Everyone liked that

[@yamanyardmc5699]

ikr

[@balang8009]

kinda sounded like ear rape

[@MrRuelTuition]

I really admire your animations. I wish I could replicate that to some extent for my students. Keep up the excellent work!

[@fuseschool]

Thank you very much!

[@shootingstars2127]

I have two questions: 1. In a displacement-time graph, an increasing gradient or a curved line upwards means the velocity is increasing rapidly and we would use the tangent line to calculate the gradient at any given point, right? 2. How would you calculate, in a velocity-time graph the area(displacement) under a curved line?

[@physicsnama]

Ans.1- Yes. An increasing gradient or a curved line upwards means the velocity is increasing rapidly . The slope of tangent line at a point on the curve, tells the instantaneous velocity at that point. If slope makes angle θ with the time axis, tanθ will be instantaneous velocity. Ans.2.- To calculate area which is equal to displacement, in a velocity-time graph under a curved line, we will take help of integrals calculus. We will divide the whole area into infinite numbers of strips i.e. No. of Strips N→∞.If there is expression which shows relation between v and t, Area A= ∫ v(t)dt. For details keep watching physicsnama next coming video.

[@raheebr2438]

Great explanation!

[@fuseschool]

Thank you!

[@GamerDS76]

this channel should have more viewers.

[@fuseschool]

Thanks! Appreciate it!

[@rumesaharoon8471]

THANK YOU SO MUCH THIS HELPED ME AT THE VERGE OF MENTAL BREAKDOWN

[@fuseschool]

Glad we could help. Take care of yourself!

[@Mouaz111]

understood perfectly great explanation

[@fuseschool]

Great to hear!

[@thegchannel7528]

I really love Fuse school its very education keep up the good work

[@fuseschool]

Thank you :) much appreciated!

[@thegchannel7528]

@@fuseschool is one good educational

[@sardar602]

It is very helpful video

[@fuseschool]

Glad it was helpful!

[@arshadulhaqueahnaf1942]

Nice🤯😊

[@fuseschool]

Thanks 😋

[@rashimahajan8596]

Amazing video... Thanks for your help..

[@fuseschool]

Thanks! Glad you liked it 🙂

[@valexizhexa1786]

@0:16 Street fighter "Perfect!" Sound effect

[@zubiali4862]

Thanks so much Really great

[@fuseschool]

Most welcome!

[@hsingh8408]

Please provide me link of distance time graph video.

[@fuseschool]

kzbin.info/www/bejne/oqOrcqGobsiMmrM

[@ladygchannel314]

Very clear. More pls

[@fuseschool]

Thank you 😉

[@jinitbafna8312]

They are stunning videos. Thank You so much

[@fuseschool]

Thank you too! Glad you like them!

[@saikarthik8551]

Thanks dale for you keen narrative skills which go smoothly into my mind and joe the script was was amazing and beautiful with simple and good vocabulary, well that is what peopl6are searching for . Keep it up 😀😀

[@fuseschool]

Wow, thank you so much! 💜

[@ja_goddess4573]

Great video really helpful

[@fuseschool]

Glad you think so!

[@asioleridinedomingosramos1557]

Beautiful!

[@fuseschool]

Thank you!

[@suhridshourjarahman9631]

point be is constant velocity and therefore no acceleration

[@mramod6307]

FuseSchool can you clarify as I agree with the comment, a flat line indicates 0m/s2 due to no change in velocity = 0m/s divided by time = 0m/s2

[@fuseschool]

@@mramod6307 That's right, no change in velocity means acceleration is zero. Your calculation is correct.

[@blaze7521]

i just found out about this channel and i think u guys are really cool (the animations are great and really help to us to understand the concept more practically) but it would be better if the speaker (the one explaining the concept) had a bit more enthusiasm and energy in his voice

[@fuseschool]

Thank you! And thanks for your feedback!

[@vinodka8288]

Can u explain this more detailed in another video. I didn't understand anything.

[@urwatulwsq4793]

Lol same

[@dregwu8904]

Song name?

[@fuseschool]

Please, check the end credits 😉

[@dregwu8904]

@@fuseschool I cant find the song

[@fuseschool]

If you have access to KZbin Audio Library, search for "CxDy - Turbo"

[@dregwu8904]

@@fuseschool thanks

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[@mkgaming3598]

Lol teacher

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Ti teg tnod I

[@xavierarokiyasami1436]

Simply waste