Venn Diagrams - 4 || Logical Reasoning & Data Interpretation || CAT Exam Preparation 2024

[@hirensoni7636]

I had read comments many are having doubts in alternate chocolate distribution method let me explain Consider 120 cars as a person And 244 accessories as chocolate Firsrty divide 1 chocolate to all 120 cars as its given in question 120 cars were decoratted so no car should without decoration after this we can maximize I.e all 120 cars are having 1 accessory by now, 124 accessory (choco) left Then we have to maximize cars decirated with 3 accessories 124 should be 124/2 = 62 means max 62 cars will have this 2 accesories and previous 1 i.e 2+1=3 accessory For minimum after distributing 120 chcoco as none left without decoration We are left with 124 choco Again divide 120 choco to 120 cars so 120 cars would be having 2 accesories (choco) each i.e 240 So finally we will left with 4 choco I.e 4 cars with 3 qccessories minimum

[@satyampasi6669]

this example helps me in maximization & minimization also. thank u

[@pranjalsrivastava1191]

i feel if we go through this way then it won't come out as correct. lets say the three accessories were not 80,84 and 80 but change it to 60, 94, 90(the total being the same = 244)....now if we go through the same chocolate method then we will say that 120 are given , rest 124 are divided by 124/2 and hence the same answer = 62...But here is a simple catch ...when i said in the the beginning that one of the accessories is only 60 in count then it is not at all possible to have 62 cars getting 3 types of accessories. "NOTE": the purpose of the question was to find the num cars which got all the 3 "types" of accessories and not 3 accessories(as in count). So in this question the answer came out to be true by coincidence because we had ample amount of all types of accessories. If any accessory is less than 62 then that becomes a problem. Please do let me know if my understanding is wrong!

[@mauryajain6922]

Thanks 🙏

[@sneha6652]

Thanks Hiren!

[@shashankgupta4671]

not all heroes wear cape some have good internet connectivity and solve doubts thank you

[@rikky6769]

Keeping chocolate distribution method simple: Consider, cars = person Accessories = chocos (1) We have to distribute 244 chocos among 120 people and then find how many maximum person can get 3 chocos after distribution. => We have, chocos = 244 Person = 120 First, Distribute 120 chocos among 120 ppl. So, each 120 person would get 1 choco and we are left with 124 chocos...... (i) Next, 124 has to be again distributed among 120 people. We give " 2 " chocolates one by one to everyone until 124 chocos end. 124 chocos can be be equally given to 62 person each getting " 2 ". Remember, these 62 person also got " 1 " choco during previous distribution phase. ( see i ) So total 62 person will be getting 3 chocos each. (2) We have to distribute 244 chocos among 120 people and then find how many minimum person can get 3 chocos after distribution. => 120 has to be distributed among 120 people. After (i), In second phase, again 120 chocos distributed among 120 people. So now each person has got 2 chocos and we have 4 chocos left. These 4 chocos are again distributed to first 4 persons in the third phase. So, minimum 4 person will get 3 chocos each.

[@RajeshKumar-mq1ic]

Ricky bhai sirf aapka explanation smj aya

[@abhinavabhinav5795]

Nice explanation bro. Thank you

[@imaaduddinansari1635]

thanks nice explanation

[@GUNJAN-os4bh]

thanks bro

[@Kitcatt_tv]

Thanks bro

[@sumitmehra-xt5zi]

This is my understanding of the alternate chocolate distribution method : In the question it is given , there are 120 cars and each were decorated with 3 different accessories . The total no of accessories that were used were 80(power windows) + 84(AC) + 80(music system) = 244 accessories. Now , we need to find the maximum no of cars which were decorated with all the 3 accessories : For that we have to make sure that every car has been decorated with 1 accessory . In doing so , we are left with 124 accessories . So now every car has 1 accessory . So in order to make that 1 accessory to 3 , we need to distribute 2 more accessories . But we are left with 124 accessories which can be only distributed to 124/2 = 62 cars . So it can be concluded that only 62 cars got 3 accessories.

[@HelloWorld-g5b]

❤🎉

[@ayushikumrawat3099]

It feels so good when we learn some new concept which once seemed too tough to crack.. sir you've constantly been giving us this good feeling.. thankyou so much sir❤

[@Rahulbajaj561]

For the last part: We have 120 cars and 244 accesories. If you guys have seen the previous video then you'll come to know that we need to divide the chocolates among all the person equally at the initial stage. So in this question, Consider cars as persons. And Accesories as chocloates. So if we divide 244 equally among 120 cars we will be able to give 2 chocolates to each car but we will be left with 4 chocolates as 244 is not completely divisible by 120. (I.e remainder will be 4) so the 4 accesories will be distributed among 4 cars.

[@khushboodixit4893]

But in his maximization and minimisation master set -2 video. He didn't divide equally at the initial stage and direct division method. Please clarify

[@nitinparashar8977]

Waah .. your chocolate distribution is amazing method Sir .. I am able to apply in TIME book questions .. thankyou

[@Rodha]

Thank you. If you like the channel please share among the friends who are preparing for CAT exam

[@VishalSingh-zb8vw]

@@Rodha great work sir hats off

[@ashishakatsuki137]

How to do this pls explain? In a college each of 200 students in class is a member of at least one of the three clubs A,B,C .80 students are member of A , 90 students of B, and 100 students are member of C. Q. If 25 students are members of only A then maximum no of persons who are members of all three clubs?

[@AmanKhan-pb9me]

@@ashishakatsuki137 55

[@rajatharry]

@@ashishakatsuki137 Is it 35?

[@wasifkhan1710]

Can you please explain the last part where you used the distribution method for the Car problem?.

[@mansisharma767]

Thanks a lot for teaching by this chocolate method sir, its amazingg!!! Now I can solve the questions in an easier way while getting a clear picture of what this maximum minimum concept actually is.

[@Devil-tr3qk]

Chocolate distribution clarification: We have 120 cars and 244 accessories >one accessory is given to each car=120 accessories >Remaining number of accessory= 244-120=124 accessory. For getting maximum number of cars with three accessory, we have to find how many number of cars we can provide more accessories with limited number 0f 124.(Since each have one accessory we only have give two more.) >that is,124/2=62 For getting minimum no. of cars with 3 acsry,we distribute one accessory to this 120 cars >remaining no of accessory=4 This 4 can be given to anyone. So min with 3 accesy=4

[@Devil-tr3qk]

For getting minimum no. of cars with 3 acsry, >we distribute one accessory to this 120 cars That is ,120 out of 244 is given. Remaining 124 choclates >We distribute one accessory to 120 cars again >remaining no of accessory=4 This 4 can be given to anyone. So min with 3 accesy=4

[@musicalapoorv2387]

thanks for explaining 😉

[@pranjalsrivastava1191]

@@Devil-tr3qk I feel if we go through this way then it won't come out as correct. lets say the three accessories were not 80,84 and 80 but change it to 60, 94, 90(the total being the same = 244)....now if we go through the same chocolate method then we will say that 120 are given , rest 124 are divided by 124/2 and hence the same answer = 62...But here is a simple catch ...when i said in the the beginning that one of the accessories is only 60 in count then it is not at all possible to have 62 cars getting 3 types of accessories. "NOTE": the purpose of the question was to find the num cars which got all the 3 "types" of accessories and not 3 accessories(as in count). So in this question the answer came out to be true by coincidence because we had ample amount of all types of accessories. If any accessory is less than 62 then that becomes a problem. Please do let me know if my understanding is wrong!

[@amishamaheshwari2107]

explained in the easiest way possible. Amazing sir!

[@legendaryquotes964]

Hey ! What was your score in last cat ??

[@vishalkumar-sc4hj]

HONOURABLE Sir, you are simply great! AWESOME TEACHER.

[@karanwattamwar6395]

For the last question if we use the deduced equation of (II) + 2(III) = 124. We will get answer as 2. But according to the chocolate distribution method the answer is 4. Anyone wanna explain the paradox?

[@hirensoni7636]

I am also havimg similar confusion

[@nandakumar116]

The answer has to satisfy both the equations (1) and (2) If III is 2 then II has to be 120 Let's sub in (2) I+II+III=120 then I will be -2 negative numbers are not possible Let's take 3 you will get I as -1, not possible Let's take 4 as the answer then II will be 116 Sub 4 and 116 in (2) then I will be zero I can be zero So min possible answer has to be 4

[@pranjalsrivastava1191]

I feel if we go through the mentioned chocolate then it won't come out as correct. lets say the three accessories were not 80,84 and 80 but change it to 60, 94, 90(the total being the same = 244)....now if we go through the same chocolate method then we will say that 120 are given , rest 124 are divided by 124/2 and hence the same answer = 62...But here is a simple catch ...when i said in the the beginning that one of the accessories is only 60 in count then it is not at all possible to have 62 cars getting 3 types of accessories. "NOTE": the purpose of the question was to find the num cars which got all the 3 "types" of accessories and not 3 accessories(as in count). So in this question the answer came out to be true by coincidence because we had ample amount of all types of accessories. If any accessory is less than 62 then that becomes a problem. Please do let me know if my understanding is wrong!

[@spacetalk9011]

​@@pranjalsrivastava1191it was a very interesting thing that you mentioned here I will try and figure out how that will work so thanks for this comment hope your doing well 😄

[@satyathota2488]

Anyone pls solve minimum number also by equation method as sir did for max

[@dikshakumari1332]

Sir ur video has helped me a lot to attempt 50% of lrdi.thanku sir u

[@PrakritiPrakash10]

Amazing explanation of both methods. Thank you, sir!

[@OurIntrospection]

Still can't understand how A+B+C = I + 2II + 3III

[@Ashish-yq2lt]

In the last part with chocolate distribution one accessory is assumed as one chocolate so total we have 244 accesories. How can u give 120 chocolates to 120 cars and say that one type of accesory(say AC) is hence given to each of the 120 car, since the number of accessories of each type is limited, like 84 for AC ? Please clarify.

[@abhishekmahur2662]

For every accessory the car gets a chocolate. So 120 cars were decorated means they all need to be given a chocolate each. watch max and min vdos no. in 213...in this order and then watch venn diagram vdos your doubts will be cleared

[@karanwattamwar6395]

@Sim Sidhanti no no dude. I respect how you thought! Even after watching max and min videos by sir, i still wasn't able to completely grasp until the moment you explained it in this way. Thank you !

[@pranjalsrivastava1191]

I feel if we go through the mentioned chocolate way then it won't come out as correct. lets say the three accessories were not 80,84 and 80 but change it to 60, 94, 90(the total being the same = 244)....now if we go through the same chocolate method then we will say that 120 are given , rest 124 are divided by 124/2 and hence the same answer = 62...But here is a simple catch ...when i said in the the beginning that one of the accessories is only 60 in count then it is not at all possible to have 62 cars getting 3 types of accessories. "NOTE": the purpose of the question was to find the num cars which got all the 3 "types" of accessories and not 3 accessories(as in count). So in this question the answer came out to be true by coincidence because we had ample amount of all types of accessories. If any accessory is less than 62 then that becomes a problem. Please do let me know if my understanding is wrong!

[@machetebhai8688]

don't think too much over the last question (I) + (II)+ (III)=120 ------- eq1 (I) + 2(II) + 3(III)=244 ------eq2 when you do distribution for the deduced equation of (II) + 2(III) = 124 consider eq1 and eq2 constraints while assuming. For finding maximum value of (III) : assume (II) as minimum to get maximum value of (III) [ (II)---(0 can be given) + 2(III) = 124( eq1 will follow (I) + (III) = 120 and eq2 will follow (I) + 3(III) = 244)] thus, (I) =58 (II) = 0 (III) = 62. satisfying above constraints cross-check. For finding minimum value of (III): assume (I) as 0 so that we can maximize (II) to get minimum value of (III) (eq1 will follow (II)+ (III)=120 and eq2 will follow 2(II) + 3(III)=244 ) (II) + 2(III) = 124 can be written as {(II) + (III)}+ (III) = 124( (II) + (III) = 120 from above ) thus,(I) =0 (II) = 116 (III) = 4. satisfying above constraints cross-check.

[@ashutoshyadav4758]

In last question they have not mentioned how many people won't get and accessories done, or they should have given atleast 1 car has to done with any of accessory So technically answer should be CBD right?

[@bhaskarmaniraj]

Read carefully. 120 cars were decorated. ( means evey car gets a chocolate)

[@memegenerator4910]

Nice concept just outstanding🎉

[@harshitasharma2423]

Make more videos on 3 set Venn diagrams please sir

[@achyutawasthi18]

Thank You So Much Sir for this fruitful session ❤️

[@govardhanlucky2442]

can anyone answer this question through chocolate distribution method, q) each student in a class plays at least one of three games - badminton, basket ball, and tennis. 65 play in each game. exactly 20 play in all three games. find the largest and smallest possible total number of students respectively in the class

[@kamleshdarshan1064]

Can anyone clarify my doubt.... 20:34 In last question remaining 124 chocolates are divided by 2 via CHOCOLATE method.. how and why?

[@moodyme6716]

coz earlier when we distributed 120 chocolates to 120 cars, each car got 1 chocolate already. now our goal is to give 3 chocolates to max no. of cars, so we'll give 2 more chocolates and since they already have 1 , now they'll have: 1+2=3 but since we had only 124 chocs left, when divided by 2= 62, so we can provide 2 more chocs to 62 cars only, so only those 62 cars will now have 3 chocs others will still have 1 choc only HOPE THIS HELPS

[@chiragsardana1881]

Chocolate distribution method is great!!!! Thanks

[@shubhamjaiswal1031]

sir shouldn't we look for constraints for solving minimum number via choclate distribution? For example we have 80,84 and 80 and we are assuming all 120 cars to have been decorated with two accesories.If we take 80 and 80 from power windows and music systems only 84 cars be decorated with they cant be clubbed with any others ?

[@princesuryvanshi9685]

Here chocolate Distribution method ...acts as time saver

[@janatarora3998]

sir not getting tht chocolate distribution method plz elaborate

[@abhishekmahur2662]

watch Max and min vdo 2 then 1 then 3 4 ...after that watch venn diagram vdos. you will get it

[@roshqsarrosh4225]

The first method is more easier to understand

[@TejasAcharyaa79]

To find maximum we must consider II as 0, what about minimum?

[@tejpratapsingh5480]

Please clear my doubt: in the last question, what if we want find the maximum numbers of cars which were decorated with 2 accessories only?

[@moodyme6716]

then after giving 120 chocs to 120 cars, each got 1 choc now since the goal is to give 2 acc. only, we'll divide 124 by 1 only= 124= 124, but the total no. of cars is 120 so we can give 120 chocs to these 120 cars, each getting 1, when added to the previous 1 choc they got it becomes 2. now we're left with 4 more chocs, which we've to give to 4 cars, 1 choc each, so 4 cars will get this 1+2 (earlier) =3 but since you specified 2 accessories only and these got 3 we'll subtract remaining 4 from 120 so 120-4=116 cars can get 2 accessories only HOPE THIS HELPS

[@janvis2504]

@@moodyme6716 Hi, can you please explain the last line? Want to know why 4 was subtracted from 120 in the end

[@mbagirl03]

I can't appreciate your the way of study sir hats off Sir ✨✨

[@nehatibrewal182]

Kota Factory ki Chocolate theory sai lekai yaha ki chocolate theory tak ham bare ho gye :/

[@himeshpandey57pandey55]

Since roman 2 represents no of intersection point of 2 circles and if you assume it to be 0, then how can you get the no of intersection point of 3 circles as more than 0 as 2 intersection had zero value how can 3 intersection have more than that

[@nirmalrawal7494]

It is not possible to draw but possible otherwise. None of the cars got 2 accessories, that is all of them either got 1 or 3 accessories.

[@sanidhyanaik8434]

The chocolate distribution part is not explained properly.

[@piyueshkalamkar8420]

Watch last vedio of vein diagram 2

[@Shikha001]

Great explanation sir😇

[@ratneshtiwari7634]

Great job sir jii

[@satishchodisetti7896]

Sir for max in car question ,we have do divide 244 by 3 then answer is 81,,we think in this way sir,but i am getting doubt thas 81 is not answ, because 80 is limited to 2 accessories,so cross checking it is wrong , But when we have maximize you done by giving 1 to all ,but where as in question not asked to atleast 1???? Please clarify my doubt sir:))

[@ishwarthegod7]

make me correct if i am wrong but , 62 cars are the cars which is the maximum car which has got maximum chocolate and 4 is minimum cars which has got maximum chocolate .

[@001youtubee]

Yes, that's correct and the same is explained in the video

[@gurmeharkalra3938]

Thank you sir😇

[@VikashKumar-sl4wg]

great teaching sir

[@manjuuppar2952]

For last question , chocolate distribution method is not convinced ,,plzz explain that again sir with good quality questions for 2020 cat aspirants ,,plzzz gurujii

[@lornemalvo2171]

convinced? What are you trying to make a METHOD convince about? As far as the fact that you didn't understand it is concerned, watch maximization/minimization videos first

[@pranjalsrivastava1191]

Hello Sir, I feel if we go through this way then it won't come out as correct. lets say the three accessories were not 80,84 and 80 but change it to 60, 94, 90(the total being the same = 244)....now if we go through the same chocolate method then we will say that 120 are given , rest 124 are divided by 124/2 and hence the same answer = 62...But here is a simple catch ...when i said in the the beginning that one of the accessories is only 60 in count then it is not at all possible to have 62 cars getting 3 types of accessories. "NOTE": the purpose of the question was to find the num cars which got all the 3 "types" of accessories and not 3 accessories(as in count). So in this question the answer came out to be true by coincidence because we had ample amount of all types of accessories. If any accessory is less than 62 then that becomes a problem. Please do let me know if my understanding is wrong!

[@pranjalsrivastava1191]

i would say this limitation will come in both the methods...it is because even from the equations we will get 62 as the answer, but the funda will have limitation if the number of any accessory is less than 62. then we will have to treat it specifically and that lowest number will be the answer. Lets say for eg in this question itself if the numbers were 50, 99, 95 = 244(again) .....By calculation we get the ans as 62 but since 62 is greater than the lowest number out of 50,95 and 99 then we will have to choose the lowest number as ans since we can have only maximum 55 cars which have all of the 3 accessories.

[@ayushbajaj8328]

Sir chocolate distribution method also have some limitations the answers for the movies question in this video does not matches by venn diagram and by chocolate distribution.

[@abhishekpatil6563]

By solving the first question by chocolate distribution Answer I got was 12 Can someone help please?

[@cachexxcookies]

1:55 It should be Both Cricket and Hockey: p+d

[@utgaming21]

Sir is there any batch of yours which completes the full course for CAT 2023 on unacademy

[@Rodha]

Yes. Going on. Last year batch recordings also available

[@abhishekr.]

Waah! ❤

[@cumulusmusic100]

Thank you Sir🙏.

[@shubhambhatt9902]

Why we took value of 2 as 0 in car question for it's max value??

[@muskaandatta9233]

To maximize 3, we will have to minimize 2

[@tonymartial1211]

infinite thanks to ravi sir

[@adritasaha5089]

In the maxima minima question, how am I left with 2 cars after distributing 3 cars each?

[@medihelaxmusic3344]

Thank You Sir!!

[@qwertykumr6848]

thankyou sir for this class

[@harshitachawla3234]

Hey, can anyone explain, the last part. In chocolate distribution, we can get 82,81,81 chocolates. I am little confused.

[@shubhamalok631]

In the last question how can we find minimum number for ||| using first approach?

[@aladinn2659]

Same...question from me too..

[@pranavchaulkar2082]

Eqn: (II)+2(III)=124 Here minimize (III) also means maximize (II), Thus, put III=0. This gives (II)max = 124 but 124>120 (cars available for distribution) so we can still distribute 124 in one more round. This gives 124-120= 4. Hope this helps.

[@harshverma9512]

Please put captions also

[@gunsandroses7867]

at the start wouldn't people playing cricket and hockey be: only cricket + only cricket and hockey + only hockey?

[@aayushshah858]

choclte distribution in last i messed up it all.

[@belawalmumtaz618]

Which is the first video of venn diagram? I am unable to find, please help

[@Rise_with_Shivam]

Thanku sir

[@dhruv5774]

I don't understand twice of two there is 3 circle and nd there is thrice

[@Shivendra-c7p]

Love you ravi sir

[@riadas8434]

I am not able to get the last chocolate distribution in relation to cars. Could any body please elaborate

[@piyueshkalamkar8420]

Watch last vedio vein daigram 2

[@abhinavsharma341]

Same here

[@vikashsingh-lv2rx]

will they not be providing diagram in the exam?

[@Rodha]

No

[@ishpreet18]

Sir chocolate method is quite difficult to understand.

[@aspiringminds8475]

yy can't maximum possible value of all three be 80

[@muditd9866]

Sir I applied chocolate distribution in the first question But I am getting the ans 12 Could u plzz help me out

[@harshitpant6871]

There are 100 students and (41+35+60)= 136 chocolates. 3 students get no chocolates. So we have 97 stu and 136 ch. Give 27 st gets 2 ch each so 27 students-54 chocolates. We are left with 70 students and 82 chocolates. Now giving each student 1 chocolate we have 70st-70ch and we are left with 12 chocolates. Now we will distribute 2 chocolate to each student so we get 12/2=6 which means 6 students get 2 more chocolates in addition to 1 therefore 6 students get 3 chocolates each

[@muditd9866]

@@harshitpant6871 Thanks man🙂

[@ashishakatsuki137]

@@harshitpant6871 bhai can u explain this ? Can someone explain this question using chocolate distribution strategy ? In a college each of 200 students in class is a member of at least one of the three clubs A,B,C .80 students are member of A , 90 students of B, and 100 students are member of C. Q. If 25 students are members of only A then maximum no of persons who are members of all three clubs?

[@harshitpant6871]

@@ashishakatsuki137 35 hai kya

[@ashishakatsuki137]

@@harshitpant6871 15 hai

[@Abhijat23]

why II is zero for maximum?

[@001youtubee]

So that III can be maximized

[@pankajsuryawanshi960]

can i get some ques in pdf???

[@samyakjain720]

Love you too sir

[@anirudhdalvi3569]

Sir this 3 set explaination was not very clear.

[@pranavkottappurath6806]

[@muskanchaudhary242]

sir how this II + 2 (III) came

[@TejasAcharyaa79]

Subtract the 2 equation

[@chiragsardana1881]

1 hr ago same sets and same order ---i watched in ELITES GRID October 2016 videos!!

[@brilliantminds8355]

Aree bhaii...Sir is teaching like he himself is solving mock...Barely is he concern about whether video watchers are getting the concept or not 😅

[@Rodha]

It's a recorded video. Not a LIVE session. So I will explain each point on depth. U can repeat the video n number of times

[@anirudhdalvi3569]

Why 100 x 2? Tsk 😢😢

[@amisha1304]

Can anyone pls tell me chocolate distribution method..I can’t get it🙏

[@subhamgupta4445]

right😅😂

[@samyakjain720]

In the last question how can we find minimum number for ||| using first approach?