Radius of Gyration summary

[@virtually_passed]

CLARIFICATION: The terms k_x and k_y does NOT mean k*x and k*y. The x and y terms here are subscripts. Sorry for the confusion.

[@Firethunder7]

Thanks, I don't anyone came to watch this video can miss that :)

[@MohaMMeDiN55]

This is the best explanation about what radius of gyration really is exactly! Thank you for sharing.

[@SomeRandomCanuck]

Big warning to the people watching this, it's (ky)^2, not k(y^2). His calligraphy is messing things up because he's putting characters and using the same font size and not using subscripts in the video. Misleading if you have no prior idea what the radius of gyration is. You'll think it's k(y^2) at first glance.

[@virtually_passed]

You're exactly right! Sorry, I didn't realize my subscripts looked so large that they were mistaken as variables! Thanks for pointing this out.

[@ernestjesly]

what is the previous video of this?

[@ygs6450]

what is related videos to understand this whole concepts?

[@daisydo7669]

What did you find, yg s 😭

[@stephenwilson6927]

So how would I find the radius of gyration of a potato?

[@ksciencebuddy]

thanks I needed it today somehow you uploaded the best one

[@virtually_passed]

Thank you :)

[@ankitaaarya]

What's up bro, you got iit??

[@noonesperfect]

Dear sir i have question, Radius of gyration of a body about an axis at a distance 0.12 m from its center of mass is 0.13 m. Find the radius of gyration about parallel axis passing through the center of mass. this was solved using parallel axis theorem but i am bit confused suppose axis of rotation changes then point where moment of inertia value will be same (i.e. radius of gyration distance) will change also but in this case how you can graphically represent the statement. if you have any idea please care to explain. Thank you.

[@virtually_passed]

Hey mate, you're right to apply the parallel axis theorem! I suspect your units for 0.13 should be m^4 though? Or are you referring to mass moment of inertia? In which case it would be kg m^2. I'm a bit unsure what you mean by your second statement. Can you please clarify? The moment of inertia about the center of mass will be smaller than the moment of inertia of the same mass about a parallel axis.

[@noonesperfect]

Matthew James thanks for reply , im pretty much sure its distance not mass moment or area moment of inertia. here is the solution drive.google.com/file/d/0B37HsWrMUe1gdWZxcFh0eDVsOU0/view?usp=drivesdk you will get idea but what i really dont get it how many axis of rotation here considered , by sketching diagram how you can represent this statement as Radius of gyration from axis is 0.12m and from center of mass it was 0.13 m so i guess we are talking two different axis and last statement says take axis passing through center of mass which is parallel to one of the axis i guess, thats where i get confused as it seems radius of gyration is located from 0.12 m and 0.13 m from two different axes and then again we take another axis which will pass through center of mass so we can solve this using parallel axis taking any two axes. Kindly go through link it will clarify you more. thank you very much.

[@virtually_passed]

Hi mate, I can't access your Google Drive. Please email me on [e-mail] and send me an image. I'll get back to you ASAP :)

[@noonesperfect]

Matthew James mailed you,thx.

[@virtually_passed]

I just replied to your email :)

[@nehirovic7051]

Oh thank god I find someone who’s not indian

[@madalincalamanciuc6656]

ikr

[@alwaysconfuzd]

Nice and racist, are we?

[@SomeRandomCanuck]

@@alwaysconfuzd Shut up jew.

[@wezzzzzzzz]

Racist!

[@ravisha000]

Racist

[@EnjoimentProductions]

The strip of area is not infinitely long... The strip is thin. It's long too. It's length is long enough to be the same area of the area of the potato.

[@chisolanyala2996]

Thanks very much. You really doing great stuff.

[@virtually_passed]

Thanks :D glad you liked it.

[@chasiew8854]

thanks

[@Yamunch]

nice! this makes sense now! thanks

[@virtually_passed]

Glad to hear it :D

[@AK-lp5lv]

mechanical and materials ... tmichenko

[@markaan2705]

thanks man

[@virtually_passed]

You're welcome :)