Motivating the normalizer by quantifying the notion of normality through voting is a great pedagogical start.
@katyohsiek9153 жыл бұрын
this lecture series is SAVING me!!! thank you so much for uploading these!
@pu5epx Жыл бұрын
Greetings from Brazil. This series is my favorite soap opera! :)
@manassrivastava10483 жыл бұрын
You are awesome Professor! Even though my semester is over I am binge watching your videos instead of Netflix! Thanks a lot and looking forward to more amazing math! Is it possible for you to do a lecture series on representation theory, I am gonna take that course next sem and I am a final year undergrad student from India! Thanks a lot!
@nainamat68612 жыл бұрын
Voting idea for explaining is perfect, thank you professor 🙏😊😃
@ir6plans6011 ай бұрын
I love the opening question.
@atzuras3 жыл бұрын
In every math course there's a point in which my neuron snap. no wait... yeah it's gone.
@pawebielinski4903 Жыл бұрын
I have a problem with the proof of observation 1. Why is the last equality (i. e. Hg=Hb) true? We only assumed that gH=bH, in other words b \in gH. For this equality we would need b \in Hg.
@pawebielinski4903 Жыл бұрын
Ah I see, that's because gH=Hg so b\in gH is equivalent to b \in Hg. Ok
@wotanxiaozuo7 жыл бұрын
Very good explanation!
@maurocruz18242 жыл бұрын
13:10
@ijindela57227 жыл бұрын
1:30 Should be "at minimum ONE element (e) votes "yes""
@deepaksachan52406 жыл бұрын
No, this is correct. Notice every g in H will always satisfy gH=Hg because H is a subgroup.