Visual Group Theory, Lecture 3.6: Normalizers

[@shaisimonson3330]

Motivating the normalizer by quantifying the notion of normality through voting is a great pedagogical start.

[@katyohsiek915]

this lecture series is SAVING me!!! thank you so much for uploading these!

[@pu5epx]

Greetings from Brazil. This series is my favorite soap opera! :)

[@manassrivastava1048]

You are awesome Professor! Even though my semester is over I am binge watching your videos instead of Netflix! Thanks a lot and looking forward to more amazing math! Is it possible for you to do a lecture series on representation theory, I am gonna take that course next sem and I am a final year undergrad student from India! Thanks a lot!

[@ir6plans60]

I love the opening question.

[@nainamat6861]

Voting idea for explaining is perfect, thank you professor 🙏😊😃

[@pawebielinski4903]

I have a problem with the proof of observation 1. Why is the last equality (i. e. Hg=Hb) true? We only assumed that gH=bH, in other words b \in gH. For this equality we would need b \in Hg.

[@pawebielinski4903]

Ah I see, that's because gH=Hg so b\in gH is equivalent to b \in Hg. Ok

[@atzuras]

In every math course there's a point in which my neuron snap. no wait... yeah it's gone.

[@wotanxiaozuo]

Very good explanation!

[@smackronme]

I guess the color of x at 8:59 should be blue..

[@Mrpallekuling]

Yes, same error as in the previous lecture (3.5).

[@maurocruz1824]

13:10

[@ChuanChihChou]

Gerrymandering of group theory

[@ijindela5722]

1:30 Should be "at minimum ONE element (e) votes "yes""

[@deepaksachan5240]

No, this is correct. Notice every g in H will always satisfy gH=Hg because H is a subgroup.