Voltage Divider Bias (Solved Problem)

[@aryakrish4316]

really priceless content for someone like me as a electrical and electronic student .

[@pashamshyamsundharreddy4438]

thanks sir .you are doing awesome job for the society even there are less views you are continuing to upload. thank you very much

[@ankitg2023]

The best part is the design intuition that you provide in the summary of each lecture. Thanks for these tutorials.

[@shafinsarwar6448]

Best teacher on internet or maybe in the World. May Allah bless and help you all the time...

[@fernandohood5542]

It be nice to see this applied to a practical circuit using known transistors.

[@abdullahsalik7078]

Impressive and genius way to teach! My professor in university is a Ph.D. but can't teach with this efficiency :')

[@riyasanthosh7124]

Thank You for your videos,they are really useful.Could you please add a presentation on MOSFETs too?

[@shourayduggal9461]

sir can i say that potential drop across R2 = Vbe + pottential drop across 1.2 kohm, I can calculate the current through R2. Hence current through R1 will be 20uA + calculated current, hence apply kvl => Vcc - (I + 20uA)R1 = Vb.

[@innocentlombanya7356]

I like the lecture... I'm understanding clearly.

[@imminentfive5623]

Now I'm open thanks man kip it up nice and clear👍

[@arijit1204]

thank you Sir.. for this season..

[@incredibleindia-withsid]

Thankyou sir for this playlist. I had a question, in the last part (f), when we use KVL instead of V(BE), what will be the equation because I always had this doubt, when using point potentials what if in the branch if we have more than 1 point potential how do we decide it's polarity?.

[@RahulSingh-ey4wf]

U cleared the concept very well,Tysm sir

[@akibjawed5076]

The difference between "with approximation" and "without approximation" is nearly 1.2k-ohm which is very large I think, isn't it?

[@josephguida5432]

The approximation method is an excellent way to reduce your final exam score.

[@vilayathshaik8733]

Sir for calculating Vce when we apply kvl for output loop Vcc-Vc-Vce-Ve=0 Vce=Vcc-Vc-Ve Vce=16-10.6-2.4 Vce=3v But the answer is completely different from urs pls clarify my doubt sir if I am wrong pls correct me And can we find as Vb=IbRb Sir ur reply is much needed pls clarify this

[@AJ-et3vf]

Thank you very much sir! Lucid, insightful, and very understandable!

[@UECAshutoshKumar]

Thank you sir

[@atharvak5748]

If you don't approximate Vth = Vb, then R1 = 26.857 KOhm

[@kv5539]

How did you find R1 .please help me

[@electro-magnetik528]

@@kv5539 Vth - Vb = Ib * Rth ---> (6.8/(R1+6.8))16 - 3.12 = 20micro(R1*6.8k)/R1 + 6.8k ---> solving this you will get finally 3256R1=87584 --> R1= 26.89kohm.

[@8xtreme]

thanks bro

[@barathnatarajan8566]

You made my day sir

[@grandson_f_phixis9480]

Thank you very much sir🥳🥳🥳🥳

[@LuisMartinez-fj9vi]

you can also find the R1 using the value of IB

[@aasthasinha4979]

Really helpful

[@babumalik7564]

Thanks for the given information....

[@sayyad__md]

Helpful, thank you sir..!!

[@electronicsolutionindia3538]

Nicely explain

[@FaizanKhan-dp3sr]

You are great sir

[@rajkumarthakur7480]

Sir explain how you say that vth is equal to VB

[@Playzone481]

good one thnk u

[@newbie8051]

Difficult problem but cool thanks !

[@kshitishkumar5118]

Sir, can we obtain R1 with the help of ib formula ie :- ib=(Vth-Vbe)/(Rth+(beta+1)Re).......???

[@swethasri2276]

Thank U sir.. Please tell us which video you are uploading after transistor re model?

[@kamlakshimeena6042]

i think in the last part formula for voltage division is incorrect it should be VB= VTH= Vcc * R1/(R1+R2). Pls correct if i wrong??

[@onlystudy3294]

as it is value of R1 =26857.91411 Ω, Vth= 3.233

[@nickino211]

thank u, sir

[@ruthwik8772]

Vcc is greater than Vb so current has to flow from Vcc to Vb .In that case Ic will be negative and also the R1 will be different.Can you please explain?

[@ViralShortsOfDuniya]

Thank you very Much sir🙏

[@Followtheclass]

Without emitter resistance can solve thevenen voltage at base sir?

[@sandeepgouni2871]

sir if we solve with out considering thevenin circuit r1=(Vcc-Vb)/i b.which gives R1 as (16-3.1)/20micro amp=645 kilo ohm.why the answer is different?

[@Nilotpal_Chakravarty_]

It's wrong bcoz ib is not flowing through r1 it is ib+current flowing through 6.8kohm or r2 u need to use thevenin theorem

[@Cybernetic1]

Sir Please make videos on OP AMP please..

[@vinayaksood5677]

How was Vb=Vth ?

[@ekawakakonahi1174]

What’s the current thru R2 and isn’t the voltage across R2 =Vb?

[@lemuelcericos3395]

why do you consider Vth as voltage drop at vb ?

[@shubamsalaria9904]

sir , how did we get the value of vbe=0.7v???

[@lilianmaillot9449]

it's usual voltage for a "diode" to conduct, and a transistor could be seen as 2 diode back to back. So it 's not by calculation, it is only the conduction condition for a transistor to work.

[@nagabhooshanmesta9788]

Sir if vth=vb i think r1=5.16 ohms sir once it check otherwise say how r1=28ohms

[@themangoman5642]

how did you find R1 you didn't show the steps. please tell me.

[@ROHITKUMAR-lh3ps]

3.12=(16*6.8kohm)/(R¹+6.8kohm) 3.12(R¹+6.8kohm)=16*6.8kohm 3.12R¹+21.216kohm=108.8kohm R¹=(108.8kohm-21.216kohm)/3.12

[@jasonkimjabla1767]

R1 = (R2VCC-VBR2)/VB

[@themangoman5642]

@@jasonkimjabla1767 how soon you’ve replied to me

[@manishramesh9344]

How did you Use Kvl in the particular you have used vcc-IcRc=10.64 how can we make the loop Like that I am confused ? Can you help me in figure it out?

[@kv5539]

Go through the before lecture that discus about the point potential.👍

[@sav7978]

why is VBE equal to 0.7V?

[@nccnitin]

Silicon

[@saikumarhalyal8337]

R1 calculate in the which formula

[@annamraghuram3713]

Is self bias and voltage divider bias are same?

[@lawrencemayfield9669]

How do you do a voltage Bias that is eing driven into saturation?

[@lawrencemayfield9669]

Voltage divider Bias in Saturation condition how do find all terminals and beta?

[@surayakshsharma7883]

upload the amplifier part also please

[@naifalsefri1985]

Can u do an example where R1 and R2 are unknown ??

[@awaiskhan-yn8so]

Sir in our book capacitor is included Please help sir examanition is comming on head please sir

[@shriganeshayenamah3422]

Ha bhai HBTU mein bhi h

[@Ravi_Qant]

Sir, Ive been trying to make a single stage amplifier. By these calculations I'm getting confuse. I got whatever you taught. But when it comes to make an amplifier, I'm confuse in selection of base current. Even the law by which we free the collector current from beta is also getting miscalculate. Please help. And Thanks

[@fernandohood5542]

I have come to realize that many of these videos are not done for the real world. People forget there is a real world.

[@santhoshthota4778]

Excellent but how Vth =Vb at 8:42

[@Followtheclass]

Same procedure we follow?

[@ramnagaboina3339]

how can we consider ie=ic can u explain

[@AmitKumar-es1gp]

Sir, how did u consider vcc =16 v and vbe=0.7v...Pls tell??????

[@antoinebadimame]

Hi I am not an expert but from what I have already seen in the video: Vcc can be easily gotten from calculating the pd drop across the R1 resistance as I1 * R1 = Vcc - Vb And lastly Vbe is a property of the B-E junction which is acts as a diode. We consider that it is a Silicon diode. And given that the Silicon diode has a barrier potential of 0.7V We conclude that Vbe = 0.7V. I hope this helps.

[@MCSGproject]

ur up electrical eng ineering shit creek amit

[@ViralShortsOfDuniya]

Amit Kumar if Vbe is not mentioned take it as 0.7V

[@saicharan9655]

Milan Samanta for silicon diode Vbe is 0.7v

[@sinchanghosal4342]

if you don't know this then go to hell. trivial stuff

[@sunitparida6176]

How can I find out base current if asked

[@charlesenricosalinas5368]

Is it always that Ic is nearly equal to Ie?

[@vivinraj8821]

What if base current is not given... How to find it?

[@creative_ajit_]

How to come 0.7 = Vbe

[@janesalinamaris4321]

Can anyone pls explain how do we arrive at vth expression

[@manickamshanmugaraja7935]

Upload stability factor

[@kv5539]

How can i find R1 without approximation of Vth please anyone help me

[@thinker6655]

What if no beta value given?

[@KevinRodriguez-ip7wu]

i have a question is IC and ICQ similar? if you where to find ICQ....sorry i have lecturers that cannot explain at all if this question sound stupid.

[@ajithkumarthanakala3082]

wtf

[@sohalgate9668]

Icq is Ic at which our transistor is operating.

[@ShubhamNahar26]

Would you plz tell how did you get V(BE) = 0.7 ?

[@Ravi_Qant]

Shubham Nahar that's fixed for silicone transistor.

[@ShubhamNahar26]

Ravi Kant i figured it out. btw thanks :-)

[@d96yt4]

NIT Agartala

[@lifeandu3286]

what is the procedure if vth is not equal to vb?

[@shihabmahmood9135]

consider current through R1 is I1 and through R2 is I2. Applying KCL at Vb in the first circuit we have, I1=I2+Ib. Now, I2=Vb/R2. As we now know I2 and Ib we can calculate I1. Finally R1=(Vcc-Vb)/I1.

[@shihabmahmood9135]

This particular math can be solved without Thevenin equivalent circuit

[@94D33M]

@@shihabmahmood9135 Absolutely correct

[@bsbijoy]

joss.....

[@asadarshad8628]

How Vcc is 16 can anyone tell me?

[@elamparithiparithi3344]

Why Vbe is 0.7 volt?

[@shaikshamsheer7559]

How u ggot R1=28pls tell me

[@mrcastor9093]

Sir, when calculating R1, we have to multiply Ohms with Volts. But that's against Ohm's Law, where U = R * I. There's no U * R ! EDIT : I've figured out that by continuing the calculations for R1, if you keep the units of measurements multiplied with each other, KOhm * Volts will be on the denominator and Volts on the numerator. By making the common factor the Volt unit, it will cancel out between the denominator and the numerator, in which only KOhms remain for R1.

[@hamzafarid6153]

Mr Castor here he used voltage divider rule not ohms law... V*R/Req

[@ajithkumarthanakala3082]

can u tell me a good reference for solved problems for analog circuits..

[@asishswain1860]

Wow

[@chetanbhatt5153]

Why not you take Vbe as 0.7 and get solution like every question.. Here too Vbe doesnot came 0.7 is there any mistake you had done🙄

[@JustinVarghese]

I got r1=5.117

[@kiranilyas079]

why do we take r1 always greater than r2?

[@Thisious]

Based on the equation Ve = (R2/(R1+R2)) * (Vcc), you will see that if R1 is not greater than R2 Ve will be very large and most of the circuits voltage will drop over Re. At extremes this causes Ic to lower to minimum and Vce to increase to maximum - not a particularly efficient circuit and nowhere near an ideal q point

[@sajidmalik2596]

according to me it should beta +1 =ie/ib .because there is RE. so ie should be 2020

[@lemuelcericos3395]

you doing it wrong, if you did it in kvl you will come up with a different answer

[@a.vishnu3331]

Go and learn that how to teach , you are simply reading not explaining

[@ehsanahmedsiyam4584]

You guyz are teaching great but why don't you guyz improve your english.

[@mysteriousone_telugu]

Speak loud man

[@khalidsami5556]

thank you sir

[@bibhutibhusansahoo6019]

Thank u sir