We Finally Gave him the CONTRACT .. And He...?

[@FlyingBeast320]

twada kutta tommy, sadda kutta Kuttta... finally Kallu Ji is a Beast Family member now. Tax savings ke liye download ETMONEY app etmoney.onelink.me/unJQ/c7d77eb6 its really helpful

[@Abhishekkalravlogs]

Recently started to vlog my life in🇮🇳 and let me know ur feedback ,show some love ❤Thanku☺☺

[@sohashah2895]

😂😂😂😂😂

[@usmantvvlogs6852]

3

[@deepakpandey4042]

Hello 👋 sir

[@killchorfansclub52]

Subscribe SENGAR BROTHERS VLOGS

[@pratyushamishra3567]

Flying best has become the lawyer and his first client is elaichi powder 😂 Congratulations 👍

[@akashabbigeri]

Next one will be February 😂

[@pratyushamishra3567]

Yeah😂

[@Aditya-xy7mo]

@@akashabbigeri Mela bhi vlog channel hhhh.. Iska cinematic or editing check LA..lo..... kzbin.info/www/bejne/jJemgmiJbcRmftk Support pease. Last pleaze Comment bhi la...... Do plzzeeeee.

[@samkhalifa1171]

And his first victim is air asia😂

[@arjunojha4445]

🤣

[@XavierMemeWorld]

Fun fact: People read the whole comment when you write fun-fact.

[@Abhishekkalravlogs]

*My whole content(vlog) is shot on iphone 11 see yourself* do chckout u will definately love it

[@FlyingBeast320]

next contract for Xavier bhai,,,, he is Dank

[@air4947]

ohhh

[@dharmeshnahar7788]

@@FlyingBeast320 par ye wala asli h ya nakli. Sab yaha Xavier bane huwe hai bhaiya 🤣🤣.

[@jkdada78100k]

How many years will your mother live,, 1 (Ignore: 0 years × 2 (Subscribe : 7886 years ✓,,😭😭😭😭

[@youknowwhere6890]

2:34 FLYING BEAST - jaise march boht accha mahina hain. Students - Ajji Ghantaaa !!!!

[@veteranyoutuber2305]

*Gaurav taneja ki acche se leli* kzbin.info/www/bejne/aGGmfH-epN11p5I

[@gigihadid3488]

kzbin.info/www/bejne/i4ivYmyCoZt1n6s

[@shubhrandhawa4417]

@Ashwini Birla yeah same

[@ruchikasharma0510]

😆😆😅😅

[@smeltgamerz2344]

The only KZbiner i see how is searching content in dog's and justice for ilaychi powder and justice for february 🤣😂😂

[@samikshasingh3930]

Tanmay bhatt ka naam suna h😂😂

[@Kaioken0769]

Sir did youn listen about Chat @Tanmay Bhat

[@krishnashah6406]

Also side mirror 😂

[@Deepaksharma-sx8wd]

Ye tu nhi teri jaali gnd bol rahi h🤣🤣🤣

[@Mr.Potato23]

I never seen few adults so serious about something like this, lockdown seriously fucked us up.

[@parikshitmulik1064]

bhai ye comedy hai yar itne bhi pagal nahi hue log bas ekjan hogayi PAGAL ZONE

[@Foodieladke]

😂

[@shreekantvaidya4728]

When u r so lonely at home without wife and daughter that u sign a contract with a dog

[@veteranyoutuber2305]

*Gaurav taneja ki acche se leli* kzbin.info/www/bejne/aGGmfH-epN11p5I

[@quantummechanicc7125]

When calendar was being built ,Other months had filed a case against February for having a Valentine ,So international calendar organisation gave verdict in favour of other 11 months by reducing number of days February can spent with his/her Valentine 😬😬🤣🤣🤣🤣😎😎😎😎😎

[@heyyymal]

Chai without Biscuit is just like "VLOG" without "RASHI"😂

[@varidhisingh2912]

Correct

[@snehamurmu2600]

Yes

[@heyyymal]

@@varidhisingh2912 😬

[@heyyymal]

@@snehamurmu2600 😅

[@varidhisingh2912]

@@heyyymal it's true I miss rashi I watch vlogs only for her

[@kunalchoudhary1452]

This is the level of dedication of an IITian 👍

[@charviwagh8529]

Other dogs be like: mauka gawa diya humne...😂😂

[@Aditya-xy7mo]

kzbin.info/www/bejne/ZmW0k6Klm8arftE

[@Addu5221]

Sir your point is valid, it is possible that you start with some speed less than escape velocity and keep a constant thrust such that F(thrust)=mg. But this is lacking some practical consideration. If you might have studied in spring mass and similar system is F (force is applied gradually such) in a quasi static process such that at each point net force is zero we get F=kx or x=F/k But if this force is given suddenly then from energy conservation F.x=1/2kx^2 or x=2F/k So we see from same force elongation is twice. So overall consideration is that to escape out of gravity if all the thrust is provided initially at full potential then less thrust force will be needed as compared to keeping a constant velocity(less than escape velocity) and providing thrust force gradually to maintain equilibrium i.e. F=mg. And now you know that how much fuel saving it will do. Another aspect is that we are considering projection. Not every object has a motor, if you want to shot a bullet or a stone - you will not attach a thrust motor to it. Lastly you want to save us from hustle of changing the force as gravity changes with elevation, this will be a better idea. I hope it helped us all develop some understanding.

[@DhrutikantP]

Rashi not home to disturb.... Flying beast: let's print contract for dogs. 🙄😂😂😂❤️

[@Anubhav184]

Hi DAV student

[@AvantikaTales]

kzbin.info/www/bejne/gYDNaX2afaytY9U

[@manitigupta]

@@Anubhav184 hey!!! DAVian??

[@Anubhav184]

@@manitigupta You too?

[@manitigupta]

@@Anubhav184 yeahhh

[@rachitsingh5143]

Uncle be like: aap hatiye aap hatiye.... Aaj contract hokar rahega..😂 Uncle op

[@yuvrajmhatre7710]

Tomorrow's news ..elaichi ,and February filed case and there lawyer is flying beast 😛😂😂

[@avinashyadav06]

Really🤫

[@kitchenwithnimmi9772]

👍😁😁

[@aartiaggarwal2603]

Ohh god😭🤣

[@kangkeeboruah5609]

kzbin.info/www/bejne/oorXmHSIn7pkgM0🙏🙏

[@mohitahuja4201]

🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣

[@expelliarmus3377]

Nhi bhai ..agar escape velocity se dhite bhejoge to wo gravity ko overcome nhi kar payega aur beech se hi laut ayega ...matlab initaial speed to wohi dena padega jisse gravity overcome ho ...matlab initaial KE grater or equal hona padega final gravitaional PE se at that height where object doesn't fall anymore(1/2 Mv^2= GMm/(R+h)..eg . Ke taur pe ..agar aap ak stone ak building ke upar pauchana hai to aapko use ak minimum speed se through krna hota hai ...warna wo waha tak pahchega hi nhi ....😅😅aur agar aap use Ve se kam ke speed se bhejoge aur constant force dete rahoge tab v wo chala jaega lekin thurst same nhi hote alag alag height pe Btw I'm 12th student ..and used to watch ur vdo for refreshment ... Apka question sunke Aese hi bol dia jo man mai aya 🤣🤣

[@yusufahmed4964]

People after 4 years in the comment section be like Only og people remember the dogs who signed the contract 😁😘

[@MRPerFect-sy3mp]

Og ?

[@AyushSharmaOfficial55]

@flyingbeast @gauravtaneja @ritutaneja @everyone Pata nhi koi padhega bhi ki nhi, phir be Let's PUT this. Gaurav's Question to elon musk and possible answer should be. Agar hum escape velocity se thodi kam speed pr bheje toh toh woh kabhi na kabhi toh pahuchegi (GAURAV'S LOGIC) and delhi 100km ki speed se jana ya 50km ki speed se jaana pahuchna is different. Explaining Gaurav Example: Delhi jaane ke liye car ki speed 100km (escape velocity) itni hai ki woh road ke friction (earth gravitation) ko overcome krke chal paa rhi hai. Now, ab you decrease the speed of car from 100km to 50km/h it is still overcoming the road friction so it will definitely reach delhi is lesser time. But when rocket is going with constant velocity less than escape velocity it will not reach kyunki woh us speed se earth gravity ko nhi tod paayega chahe 10 hrs le ya 10 days, it will be repeled everytime. And, Gaurav's logic is right when the rocket goes with velocity double the required velocity that is 2 X Escape velocity and in Gaurav's assumption it is less than 2 X Escape velocity not Escape velocity so it will cross tthe atmosphere in more time. HOPE IT MAKES SENSE Thanks for reading Dislike if anything is wrong.

[@shaheenahussain4932]

@@AyushSharmaOfficial55 seriously i didn't knew einstien was and is alive 😮😮😮😮😮😮

[@yusufahmed4964]

@@MRPerFect-sy3mp original

[@ashishverma4078]

@@AyushSharmaOfficial55 👍🙏

[@brutalgaming1204]

without rashbari it looks like I am studying in a maths class 🤣😂😂🤣🤣😝

[@gigihadid3488]

kzbin.info/www/bejne/i4ivYmyCoZt1n6s

[@thenameisprateek3828]

kzbin.info/www/bejne/f6TSaHdofbOWbrs

[@in.meraki]

When he said about contract. I didn't know he was so serious. 😳

[@nishitbakiwala470]

Gourav bhai yeh planning sirf kree hai ( kutta contract ) Bcz wo wapis apni wife ko darange Phir wo gourav bhai ko nikal dengi ghar se. Then unko ghar dogs denge 🤣🤣🤣😂🤣😂😂😂😂🤣😂😂

[@GAURAVUPADHYAY4547]

Bhai title dkh k samajh nahi aya kya?

[@varshithsai1089]

Then your probably not a flying beast fan 😂

[@rishikhamkar27]

Naye aye ho kya 😂

[@sahilsahni6557]

Content ke liye seh lenge thoda😂

[@deepalinigam5434]

Without escape velocity, eventually the object flying upwards will come down under the influence of earth's gravitational field. Take the example of a ball. No matter with how much force you throw it towards the sky, even with external force, it will eventually come down because the earth's mass is way greater than the mass of the ball so the downward pull on the ball will be tremendously huge as compared to the upward force on the ball. So we need an escape velocity to equalise the momentum of the ball and earth then only will it be able to fly past the moon. Hence escape velocity 11km/sec is required and spacecrafts cannot fly below this velocity otherwise they will come crashing down soon after .

[@akshatavaidya8281]

You typed one sentence that downward pull on the ball is huge .. I agree it ... When we throw the ball with max force traveling in velocity opposite to the gravitational force , at one point velocity of ball becomes zero n as gravitational force is still constant , the ball comes down ... Then how come spacecraft of constant velocity can't reach to the space ?( as we'll give it constant velocity) ... I think to leave one atmosphere n enter to whole new atmosphere containing different type of particles in it ( frictional force will be different in those two comparing atmospheres ) so maybe giving a sudden change in velocity helps to enter the space (gives that kick to the spacecraft to bear with the frictional force of other atmosphere) ... Am I right ? 😅 ( I learnt this in 12th now I'm studying biotech , so I have no connection with Physics anymore .. I hate physics but I had to ask this )

[@deepalinigam5434]

@@akshatavaidya8281 somewhere down the line fluid friction is also crucial in the process of launching a rocket but the point here that I was trying to state that if that you launch any spacecraft below the escape velocity i.e. 11km /s the rocket will be able to leave the surface of the earth but not its gravitational field, so it will either keep on orbiting the earth or fall back to the surface. but if we employ escape velocity, the rocket would get sufficient centrifugal force to traject it into an open curve away from the planet. in concise you need a thrust greater than that of earth's gravity.

[@akshatavaidya8281]

@@deepalinigam5434 yeah right 😁 .. Thanks

[@ubaid5939]

Usko pata ha ye sab usne iit clear kari ha... Wo bas apni biwi ke sath masti kar rha tha👍🏻

[@deepalinigam5434]

@@ubaid5939 of course just wrote this for everyone else who might want to know more

[@amisharashminayak5788]

Who's still digesting the fact that he actually made a contract with the dog .

[@lightningth5545]

I

[@veteranyoutuber2305]

*Gaurav taneja ki acche se leli* kzbin.info/www/bejne/aGGmfH-epN11p5I

[@Sizzling_Mamata2111]

Bhaya took foot print of the dog as a signature...like seriously😂 he bhagwan 😆

[@shreyamishra3227]

Shitt man....you break the suspense 😂😂

[@mallumoto8986]

*or what he do give the dog a pen!*

[@vaidanshtanwar8310]

He bhagwan nhi hye ramm

[@kunjshah8180]

You want him to give a pen or what

[@kshirsagarpratyusha6726]

Woah finally contract mil hi gayi!!!🎉🎉😂

[@Students_onduty]

But Content nii Mila 😀

[@prabhat1973ful]

10:43 Sir formula for escape velocity i.e √(2gr ) is derived by the conservation of energy : Ki + Pi = Kf + Pf ½m(Ve)² - GMm÷r = ½m(0)² - GMm÷∞ ½m(Ve)² = GMm÷r Ve = √(2gr ) If we take velocity constant as you said then : Ki + Pi = Kf + Pf Ki = Kf ( as V was constant ) then : Pi = Pf -GMm÷r = -GMm÷∞ r = ∞ . Which is not possible . Please tell me if I am wrong .

[@abhinavbarve4352]

On TV: Tarak mehta ka ulta chasma On KZbin: Flying Beast😁😁😁

[@lordlightnin999]

Tmkoc is dead

[@payaln3168]

Yes same 😁😁

[@aishvaryatiwari5414]

Dono moorkhta justify karte rehte hain

[@payaln3168]

@@aishvaryatiwari5414 badi jalan ho rahi he tumhe 😂😂😂

[@Veshnabishere]

Uncle was so serious for the contract that he forced the dog to sign 😂😂😂

[@nishitbakiwala470]

Gourav bhai yeh planning sirf kree hai ( kutta contract ) Bcz wo wapis apni wife ko darange Phir wo gourav bhai ko nikal dengi ghar se. Then unko ghar dogs denge 🤣🤣🤣😂🤣😂😂😂😂🤣😂😂

[@dhruvverma6147]

The question about the escape velocity really intrigued me. So, for those who are curious, here is a good answer. Actually, the answer lies in the conditions assumed in the definition of E.V itself. While defining escape velocity of calculating it, we assume that after we have given it a certain velocity off the ground THE SOLE FORCE ACTING ON IT IS THE EARTH'S GRAVITATIONAL FIELD, even air resistance is not counted!(theoretically, of course). Now to the part, why we can't propel a spacecraft by applying force to maintain constant velocity? After launching, if we are able to maintain constant velocity, we will be able to take it to space. (If we applying a force in the air, then the concept of escape velocity can't be applied) I think, we already apply force to provide acceleration. If it weren't for a force, a rocket's speed would keep on decreasing, but it never does! This implies that the acceleration in the form propulsion that we are providing is not only cancelling the air resistance but is providing more than that! Interesting, isn't it? Lastly, I feel that the concept of escape velocity is not really applied like we study it initially (prep times!), cause I don't think we will ever be able spontaneously launch a heavy piece of metal at this high a speed, hence the propulsion system which keep on accelerating it till it is fairly out of the Gravitational field. THANKS FOR READING THIS. And, I am an JEE aspirant, in case you are wondering! Edit:Faltu main Jyada lamba likha hai, science walo ko explanation ka shauk hai😂

[@dhruvverma6147]

@@hetpatel2001 And the reply? XD

[@ashishgiri2373]

Can we have his comment pinned

[@ashishpratapsingh2629]

It is not important for you to escape earth only by attaining escape velocity until you are not providing constant acceleration...

[@Ravi-zi2ti]

bhai iit tu hi nikalega pakkkaaaaa.......

[@raviyadav-py6no]

So basically Gaurav is right in his approach that we don't need to achieve escape velocity , but only if some constant forced (even when the spacecraft Is in air ) has to be applied continuously in order to get into space . Also since this is not possible atleast not now so we use escape velocity . It's Like giving a very hard punch to the rocket 🚀 and the punches force is what gets it out in space .

[@purvanshnatani4896]

Sir ritu Ma'am was right As if you are going delhi to Jaipur and Delhi is pulling you with 60kn hr force and you have speed of only 50 So definately you will not be able to reach so you need high speed than 60👍👍❤️ Love you sir 💕 Purvansh

[@AryanSingh-ku8ry]

Me after watching him prepare the conract papers: Hayye Raam!

[@arrishbara]

Sameeee

[@DJD911]

Heyo ARMY

[@sushreeswagatika8742]

Actually

[@priyajr2240]

Nythng fo content

[@metheantilibrealdoge7202]

Bts is gay.

[@sabkabro2322]

3:56 The assignments we engineers submit 🤣

[@sabkabro2322]

Lol 😂

[@hemantshokeen1789]

This contract is void because he had signed in influence of others

[@meetdalal98]

Contract due to undue influence is voidable at the option of aggrieved party.

[@abhimitra5290]

Lagta hai business law jayada parh lea ho 😅🤣

[@aishvaryatiwari5414]

Under coercion

[@harryharry1129]

Oho Indian contract act 1872ghol ke pegye ho kya bhai😂

[@veteranyoutuber2305]

*Gaurav taneja ki acche se leli* kzbin.info/www/bejne/aGGmfH-epN11p5I

[@mokshaggarwal8744]

10:26 In this case,object will attain equilibrium after a point where Gravitational force of earth=Force exerted by the object. Hence it will be in a fixed equilibrium position till fuel finishes.

[@chahatbhatia2157]

Thank u. I also started wondering 😂😂

[@prashantsaini7669]

Yes.

[@harshitsrivastava2523]

Kallu Ji be like : ab hum vo kallu nahi rahe jo libir libir kiya karte the...ab humko chahiye phul ijjat 😂

[@aaliza992]

Gaurav ji flex on being an engineer more than being a pilot😂❤️

[@kangkeeboruah5609]

kzbin.info/www/bejne/oorXmHSIn7pkgM0👍🏽

[@SKYLINEBGMI]

kzbin.info/www/bejne/bmayiIWehd-Ig6s

[@NehaKumari-su1gg]

No one: Literally no one: Gaurav Taneja: Typed a contract letter and taken a print out of it 😂 finally taken signature of the dog (kallu)🐕 I mean seriously 😂🙏

[@TejanshSingh]

Sir aapkaa doubt clear krna h toh suno: Jab aap usse escape velocity se kam force pe bhejoge toh fuel zyaada lagega usse atmosphere se bahar nikalne mai, and agar zyaada fuel chahiye toh tank bada lagaenge rocket mai jisse uska mass bad jayegaa, and hame same distance cover karne mai aur zyaada time lagega, and hence we have to stick to the escape velocity.

[@ujjwalsingh8038]

Flying beast is someone whom I listen to with full concentration even if he's talking nonsense😂😂😂Feb me 28 days

[@funnymemos8434]

Same

[@sakshiarya6773]

Same here

[@sakshiarya6773]

Same here

[@nishitbakiwala470]

Gourav bhai yeh planning sirf kree hai ( kutta contract ) Bcz wo wapis apni wife ko darange Phir wo gourav bhai ko nikal dengi ghar se. Then unko ghar dogs denge 🤣🤣🤣😂🤣😂😂😂😂🤣😂😂

[@heyyymal]

"VLOGS" without "RASHI" :- Time Passes Slowly "VLOGS" with "RASHI" :- Time FLIES😂

[@mansisharma2355]

Serioisly!!😂😂

[@___Esther]

Right👍

[@heyyymal]

@@___Esther 😬

[@gauravkar4805]

10:42 Escape velocity is the speed required to escape gravity in the absence of any force being applied. To keep going up requires the continual application of force. So yes, of course it is possible to keep going upwards and further from the earth, but without reaching escape velocity you would eventually be pulled back to earth when the fuel runs out. Asli me we would need enormous amount of fuel if we go slower than escape velocity which is inefficient and not possible for any spacecraft to have that amount of fuel.

[@aakashmitra1114]

i was searching for this explanation. i also thought the same but was finding anyone else thought it or not.

[@litcode702]

He is saying he is providing force that will oppose earth's pull. So, the body will be at constant speed throughout its journey

[@dr.rahulgupta3227]

Not a single rocket achieved escape velocity till today. Basic behind the concept of escape velocity is that it only applies when we are just giving a push or thrust to any object on earth surface not a constant force throughout the flight, obviously rockets leave the earths gravitational field without achieving escape velocity because they have a constant force for propulsion and it is practically not possible to give escape velocity to any object today. Escape velocity =11.2km/sec means 40320 km/hour speed at once

[@Itsybitsyak]

@@hetpatel2001 but Newton’s law are wrong

[@venky2020]

@@hetpatel2001 this explanation is below basic level😂

[@sreetshresth9591]

During their physics argument ! Commerce and humanities batch be like 🙄🙄

[@smilewithmobile]

🙄

[@shaankapoor971]

This person has the ability to sign contract with any living being on this planet 😂😂 Edit: thanks for so much likes🙏

[@shekharkapoor9208]

multi talented hai na

[@alkasingh1354]

Marketing he can sell anything. Smelly socks too

[@shaankapoor971]

@@shekharkapoor9208 yup bhai Apne bhai lakho par bhari

[@shaankapoor971]

@@alkasingh1354 😂😂

[@PawanKumar-ed7hc]

Finally we see 4th member in the VLOG i.e..,"kallu"😂

[@SantoshSingh-oz5io]

Le That Dog: " Hath jod ke gujarish hai bnd krdo Contract krwana" 😂😂

[@neelimasingh4648]

Finally contract is signed. I was waiting for this since my would be husband has suggested your channel. Keep rocking 👍.

[@RX-GHOSTGAMING]

Normal people make tea : heaven Flying beast make tea : death

[@vikaskumar-oy7gi]

😂😂😂

[@koushikdas8411]

😂😂

[@tamannaagarwal6942]

Khatarnak soche ho bhai😂😂

[@RX-GHOSTGAMING]

@@vikaskumar-oy7gi 😂

[@RX-GHOSTGAMING]

@@koushikdas8411 😂😂

[@SAM-hu8wq]

3:40 LMFAO!!! He's actually making the contract !!🤣🤣

[@sanjumayank80]

In this vlog I feel like' soona Soona lage soona Soona lage' we miss you our Princes👸👸👸 Rashi love you

[@Abhishekkalravlogs]

Mela vii vlog channel hhhhh.....❤.. Iske editng and cinematic chck la..loooooo Comment b😘😘i la....loo........

[@pieceofmind6371]

Exactly

[@Rakesh-zg5lc]

fuudddu log is vlog ko dekte hain or time wasted krti hai

[@viditgangwar999]

Ritu ma'am is quite right kyuki agr particle ko escape velocity se km pr rkhenge to bo kbhi bhi gravitational pull mtlb grav. field se bahar ni jaa payega... Ritu ma'am OP 👍

[@abhijeet7629]

When Rashu is there although the vlog comes late thats more interesting

[@sovitranjanmishra6039]

Missing Rashu

[@jaspreetdhaliwal4839]

Don't feel like seeing blog without rashi😭😭😭😭

[@okajsy8]

IITians are talking about how to arrange spices😂😂😂❣

[@geetamehta9110]

You should learn the spelling of spices

[@nishitbakiwala470]

Gourav bhai yeh planning sirf kree hai ( kutta contract ) Bcz wo wapis apni wife ko darange Phir wo gourav bhai ko nikal dengi ghar se. Then unko ghar dogs denge 🤣🤣🤣😂🤣😂😂😂😂🤣😂😂

[@downtown910]

Talking*****spices****ye science me padh rhe ho 😂😂😂

[@okajsy8]

we are not here for any controversy about spelling for spices

[@okajsy8]

@@downtown910 lene ki himmat to rakhi baad mai bhale change ho jaye aur spelling humanities mai dekhi jaegi na ki science mai

[@sahilsarupria8832]

When you say that the force is constant, the gravitational pull is also constant and the force applied by propulsion is also constant but the fact that the gases are ejected from the rocket shows that the overall mass of the rocket is continuously decreasing and therefore, applying F=ma shows that if mass Is decreasing then acceleration has to increase at a constant force. So, even though force is constant, the rocket is still accelerating. Now, about the escape velocity, there are two reasons, firstly if you are sending the rocket at a constant velocity, the rocket will decelerate(velocity reduces) until its velocity becomes zero and eventually will fall. Also, moving the rocket at a constant acceleration against the forces of gravity and air resistance it is very difficult to maintain that and therefore fuel consumption is very high which is not feasible and good for the nature

[@harshsharma1182]

escape velocity is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a massive body. so if the object is propelled then the object will go out surely if constant thurst is provided.

[@mrdynamite0398]

@@harshsharma1182 not always ...only when acceleration is greater than gravitational pull...other wise at some point between the journey both acceleration will be equal and after moving further gravitational force will dominate ...

[@RakhiDeshwallearner]

@@mrdynamite0398 correct

[@sahilsarupria8832]

@ODA 595 no centripetal force is when it is already in orbit and moving in circular motion, when the object is trying to escape the earth's atmosphere it is not in circular motion so centripetal force does not play any role

[@aishaansari1866]

Hello I am Ramsha from Mumbai. rashi vlog mei nahi aati to maza nahi aata hai aaj vlog rashu ke bina adhura tha We love u rashu❤❤❤

[@shobhadevitaduri8916]

Ur vlogs so ADDICTIVE than STUDY CONCEPTS.

[@Abhishekkalravlogs]

*My whole content(vlog) is shot on iphone 11 see yourself* do chckout u will definately love it

[@Noname-jx3mr]

Mom: what are u watching. Me: Learning how to get a contract signed by a dog. Mom: Signed by a WHAT?

[@kangkeeboruah5609]

kzbin.info/www/bejne/oorXmHSIn7pkgM0👍🏽👍🏽

[@starcookingandcraft2859]

kzbin.info/www/bejne/qoSnmZ6qitN0pM0

[@sumitrawat3201]

If he combines his vlogs it will be better than starkid movies😂😂

[@hiravatiyadav8340]

This video is related to what are the reasons of allergy and it's precautions if you want to be safe from allergy pls do watch this video kzbin.info/www/bejne/eX6cnnaPepVjbck

[@hiravatiyadav8340]

He gives information about skin allergy pls like,share and subscribe kzbin.info/www/bejne/i2fIh5Wmdpege6s

[@HasanKhan-xj7sc]

Bhai aap ko escape velocity ka formula abhi tak yaad hey itne Salo badh bhi 👌👌👌👌👌👌 Aur ek taraf ham log hey jo gyarvi se barvi mey kya gy adhe chaptero ka hi nam bhula bethe😂😂😂🤣 Seriously Gaurav bhai plz bata dje ky ham JEE ki tyari kyse kare. Aap apni koi tips and strategies dje study ky lea🙏🙏🙏🙏🙏🙏🙏🙏

[@yashpokalwar8938]

10:43 TANEJA PHYSICS TUTION 100% IIT placement guarenteed

[@nishashukla_11]

Fun fact :- 14th February ko valentine's day hota hai uske correct 9 mahine baad 14th November ko children's day ...why🤣🤣😅

[@atyabarshad116]

😂

[@sunakshisharma6388]

😂😂😂 op

[@simpisingh8593]

@@atyabarshad116 o bhyiii 😂😂😂😂

[@bharatrockzz1841]

🤣🤣

[@labdhishah9857]

Good one

[@ImSandipRoy]

Fun fact: I'm in class 11 about to finish gravitation topic....and the discussion is relatable 😎

[@piyushtak6605]

So give me the formula of orbital speed..... i am too in class 11

[@mohammadayaankhan4694]

Me too

[@sukuna6081]

Mee too

[@dipanshu_not_nice]

I am about to end oscillation ch.. Which institute do u study??

[@dipanshu_not_nice]

@@piyushtak6605 √GM/R

[@noname50007]

Suppose mai aapko aak rassi se bandh deta hhun aur agar aap 100 km per hour ki speed se force lagao ge toh aap rassi torr doge but lakin ap agar uss se kam lagaoge toh kaise tute gi......i think that is the point of escape velocity............ hope you understand it.....if yesss then great success.....and also thanks for making our everyday better than yesterday...❤️❤️❤️🙏🙏

[@SumanKumar-jd3hu]

Flying beast started talking about escape velocity. Arts and Commerce students be like:- haa ye pehle kar lo

[@anantdahiya1756]

😂

[@naveensenapati9032]

Uncle be like : hum karte ha prabhandh...aap chinta na karo.

[@gigihadid3488]

kzbin.info/www/bejne/i4ivYmyCoZt1n6s

[@hemugandham]

When rashbari doesn't comes in vlog Me: khatam Tata bye bye

[@garviiii]

The escape velocity is the minimum velocity with which if u throw something then it will escape earth's gravitaional sphere.......Matlab escape velocity aapko bs ek baar deni hai...uske baad kuch ni karna ....uske baad vo cheej apne aap nikal jayegi. If u want to escape something with constant velocity then u will have to provide it constant power during its journey and that takes a lot of fuel ⛽ Both the situations are almost ideal That's why Interplanetary spacecrafts goes through a number of manoeuvres so that they will get that much velocity. (This also reduces fuel consumption because planet's gravitational force is also used in accelarating the craft).

[@gargigunjiyal98]

hahahahhahaha this vlog is on some different level of humour. February, elaichi powder and uncle helping him for the contract. 🤣

[@satwikkumar9410]

10:38 We all know that satellite moves in a elliptical orbit around the earth so if you apply an external velocity to it (other than its orbital velocity) then its orbit will become expaned but still it will keep rotating about the earth (expansion of orbit means the perigee and apogee will become higher with respect to earth surface as it was before applying the external vel.). Now if you keep applying that velocity (no matter weather it is constant or variable ) to that satellite then ultimately its orbital velocity will become its escape velocity and it will escape the earth's gravitational feild.

[@shuchitanayyar9507]

Kuch samjh nhi aaya bhai thodi easy language me smjhao

[@bhumikaananwani1361]

Flying beast is following rashi's calendar these days. 28 dec 2021😂😂

[@SachinSurti]

Bhai aapke video bohot sahi hote he. And agar pure din me kuch kharab bhi hua ho na to aapke video dekh kr stress relief hojata he. Thank you gaurav bhai for making this video.

[@koushikdasgupta572]

Without Rashu it's felling something is missing 🙁.

[@imboy8659]

It's like tea without milk

[@R69-u6q]

11:19 sir equilibrium ho jayenga earth ke force aur rocket ke force ke bich mtlb rocket bich main udta rahenga with zero displacement RITU mam ap sahi ho. car vala liner motion hain aur rocket 3D factors pai kam krta hain

[@fictionalgamers7827]

Waah bhai

[@R69-u6q]

@@fictionalgamers7827 yo

[@sameerwadhwani8318]

1:07 Flying beast making tea for his guest His guest be like : Aaj maut se direct appointment hai apun ka

[@maheshwarmrinal4976]

Simple and easy F=ma a=dv/dt ...... And mass is continuously decreasing (as fuel burns) Hence if m decreases we have to increase dv/dt (for equilibrium) 2nd point If v = constant a= dv/dt =0 hence force equilibrium can't achieved . Ultimately rocket will fall down due to gravity Ritu ma'am was right lame question tha😂😂😂😂😂😂

[@divyankbatham9173]

Fun Fact:: In rashi's absence his father is forgetting month and is putting 28th December 😂😂

[@kirtisharmasharma6168]

kzbin.info/www/bejne/fWWTdGV4nJephNU

[@hastulaegogoi7499]

11:00 Your velocity won't be same because of deaccleration caused by air resistance and atmosphereric hindrance.

[@sh1119a]

But he mentioned there is propeller there to provide constant velocity throughout ,but just taht it is going by lesser than escape velocity. So , I don't think drag forces is the possible answer.

[@ritikrautela234]

Wohi baat hai agar tum wall Pai constant force lagate rahoge to agee thodi na badh jaoge hindrance force se jyada hi to lagana padega

[@dhruvacharya2602]

Hypothetically yar

[@gauravkar4805]

Nope that's not how it works, there is no air resistance in space. We can go with slower speed than escape velocity but in order to do that a rocket would need enormous amount of fuel. It is not necessary to travel at 11km/s to escape the earth's gravity, any speed will do, as long as you keep going up. 11km/s is known as escape velocity because a body travelling up at this speed at the earth's surface will keep going up without any further force being applied so yes you can go at lower speed than escape velocity but you would need enormous amount of fuel and if you don't achieve escape velocity then the rocket would fell back to earth when the fuel vanishes due to Earth's gravitational pull.

[@alokrai4494]

0:14 everyone is in the month of January but gaurav bhaiya through wormhole is in 28 December 2021

[@aryasingh9974]

😂😂

[@sairushikesh7265]

Sahi bhai🤣🤣

[@divyaashishpatel5905]

Rashu ne date batai hogi..... papa today Is 28December 🤣🤣

[@aayushtailang7684]

Bhai gajab notice kiye be tum

[@aayushtailang7684]

@Flying Breast fake id

[@Praveen-uj7wz]

Escape velocity is that minimum velocity required by a body at earth's surface to escape out from the Earth's gravitational field. So, at that velocity kinetic energy of the body is equal to the total energy difference between g=9.8 and g=0. So if we give velocity lower than escape velocity the Kinetic energy wouldn't be equal to the above said energy difference and to compensate that we will have to do work, in simple words we have to apply force.

[@vandanaraturi1286]

0:12 When you're so done with the editing that you wind the whole year in the 1st month itself 😂 P.s - He wrote date as 28th December ' 2021

[@varshu027]

8:47 🌈Gaurav expression 😍

[@Abhishekkalravlogs]

Recently started to vlog my life in🇮🇳 and let me know ur feedback ,show some love ❤Thanku☺☺

[@shaheenahussain4932]

Bro 8:46 karlo nhi dikh raha

[@Mayur0509]

"Dubaara nayi video dekh k dubaara mod lagaaunga" 😂😂😂 Hat's off sir ji 😂😂

[@no_diets_plzzzz5956]

Hai ram. Aisa explanation for the masal ..epic 😂😂😂😂😀😂😀🤣😀🤣🤣😁🤣😁🤣😁🤣🤣😁

[@lokeshwaranvr]

2022 Lucknow Kutton Artists Association: Haamare saath nainsafi hui hai, uthane ande hame roz nahi mila jithna contract mein likha hai! CHALO DILLI!

[@lokeshwaranvr]

Thank you for the ❤️🙏🏼

[@jyotsanabadgujar8012]

You have done it so seriously ohh my god it was unbelievable and I can’t stop 😂😂😂😂😂😂😂😂😂😂😂😂

[@IDC73717]

No one literally no one Flying Beast : Signing contract with dog.

[@nishitbakiwala470]

Gourav bhai yeh planning sirf kree hai ( kutta contract ) Bcz wo wapis apni wife ko darange Phir wo gourav bhai ko nikal dengi ghar se. Then unko ghar dogs denge 🤣🤣🤣😂🤣😂😂😂😂🤣😂😂

[@d.a1494]

Bcoz he is himself a dog

[@utkarshverma013]

7:14 who's that guy on the stair climber in the background? 😂😂😂 Gaurav bhai next time you see him, meri taraf se charan sparsh karna unke! 😂

[@yashrathi9479]

Taneja bhaiye getting mad sitting at home talking about a month so called February lmao😂❤️⚡

[@bakulchoudhary7122]

Rashu k bina vlog pheeka pheeka sa tha. Plz ask uncle at Kanpur to daily record rashu and send it to you, so you can embed it in your vlog. What say? If anyone likes my idea, hit like

[@1BlueSkyy]

“Elon Musk” Randeep Hothi : Naam toh suna hee hoga 😂

[@himanshusinghal1774]

sir ur doubt is correct that if we are somehow able to maintain constant velocity, the object will escape the earth. Escape velocity is just the minimum velocity with which we should throw an object in order to make that object escape. conclulion- if u apply a force which always cancels the opposite force the object can escape with any initial velocity.

[@dhruvchandel6684]

8:58 gaurav bhai doing bakwaas hum log-- Gajab ka bakwaas hai bhai ❤️❤️😂😂

[@sanjeevroy601]

Best part of this vlog was the dog agreement, especially how you addressed him Kuttaji that was epic :::::::::))))))))))))))))))))))))))))

[@gigihadid3488]

kzbin.info/www/bejne/i4ivYmyCoZt1n6s

[@kunalagnihotri1185]

Being a CA student ( & your neighbour too😛) i am saying .... ''भैया जी काहे ?? काहे हमाये पेट पे लात मार रहे हो ? '' 😂😂🤣

[@sofiaasharma7674]

Sahi me ese nhi lag ra ki ye bcom se bhi Gail gujre hai.

[@neerajkumar-greedgamesstud1259]

We apply escape velocity once at once, you can even reach to space at 1 km/h if you apply constant force to maintain that constant velocity 1 km/h. (And it's not called escape velocity when you apply force throughout the path).

[@nidhikumari60]

He is the only person jo february ko justice dilane ke liye khade h 🤣🤣🤣

[@pallavimahajan321]

😂😂

[@dhruvgupta1929]

Sde ki shukla diaries dekhna usme ye bataya hai ki feb main 29 din kyu hai wo ek spoof hai !Maza aayega

[@Hardikkkk]

3:52 the level that he has reached in making us laugh is outstanding Much love bhaiya 😂😂😂

[@pratiksrivastava9377]

It will start revolving around the earth... as it is less than the escape velocity

[@Nageshh1]

It Makes sense

[@manassheth47]

Bhaiya answer to your question ke agar hum ek constant speed se rocket ko chhod de toh upar kyu nahi jayenga?? . So basically gravity is not a constant force it changes with height, the higher and higher you go the more and more amt of gravitational pull you will feel . So when we a rocket is launched by a speed which is less than the escape velocity (11.2km/s) , on it the force acting downwards increases and the upward force (upthrust) which was given during the take off decreases. Let's say, the escape velocity is V. You launched the rocket with velocity V/2 , then initially the forces acting upwards are more in number than the forces acting on the down (ie mg of the rocket) {also one point to be noted is the higher and higher you go, the mass decreases } . Ok so back to point , when the rocket covers some distance , it is having the air friction and the mg which is pulling it down and only the velocity which is taking it up (note the upthrust can't be considered here) . So in this case the rocket will come down and crash that's why the minimum escape velocity is given which is 11.2km/s.

[@rohankaila532]

CA's be like: Mai kya kru job chod doon phir 😂😂😂😂

[@puneetgarg7921]

CA ke pass to fir bhi jana pdega hi 😁

[@keshabkataruka7485]

Solution, Escape velocity is the initial speed with which an object is thrown, it will get to the space. What you are telling v/2, it will require continuous power to get there while in first case just the initial speed is enough😎 Ritu bhabhi was right you confused her👍👍

[@jashaswi4edits]

3:28 sach main vlogers ke pass kitna khali time hota hai 😂😂😂

[@Kartikey_Sharma-ks]

Sach me? Think twice✌️

[@jashaswi4edits]

@@Kartikey_Sharma-ks what if I think trice and what if I don't think about it 🙄

[@Kartikey_Sharma-ks]

@@jashaswi4edits koi ni vro faltu me soch ke mental pain mat lo

[@deltechdiaries5907]

answer to Gaurav bhai 's question at 10:00 If you managed to maintain the object going at a constant velocity, then it means that you somehow have managed to counter the force applied by gravity at every instant, so in way, gravity has now been countered provided you apply a force as a function of time f(t) = G*m*M/(R-vt)^2 , which can be calculated using simple formulae, so yeah if you manage to maintain it at a constant velocity , you can make it escape