What if there's friction between the rope and the pulley? (Atwood machine)

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Dr Ben Yelverton

Dr Ben Yelverton

Күн бұрын

Пікірлер: 28
@jebsong5908
@jebsong5908 2 жыл бұрын
Really clear explanation. It's criminal that you don't have more subscribers!
@DrBenYelverton
@DrBenYelverton 2 жыл бұрын
Thanks for your kind words!
@ayushprasad1197
@ayushprasad1197 3 жыл бұрын
Thanks for a great explanation. I had searched out the topic on friction between pulley and string out of curiosity and found out this video. Thanks once again.
@DrBenYelverton
@DrBenYelverton 3 жыл бұрын
Happy to hear that the video helped! It's an interesting problem and not one that seems to get discussed often.
@DaTopDJ
@DaTopDJ 3 жыл бұрын
Quite an elegant explanation. Nice video! 👍
@DrBenYelverton
@DrBenYelverton 3 жыл бұрын
Thanks. I enjoyed making this one as I hadn't seen the frictional case discussed before!
@jawspeak
@jawspeak 2 жыл бұрын
Very helpful explanation as the simplistic other videos leave out so much interesting and relevant factors. I am subscribing!
@suryakantabehera5599
@suryakantabehera5599 Жыл бұрын
Thank you sir ,well explained 😊
@rashmitabiswal1389
@rashmitabiswal1389 2 жыл бұрын
Thank you sir these videos are amazing for JEE advance
@DrBenYelverton
@DrBenYelverton 2 жыл бұрын
Happy to help, thanks for watching!
@snehashisnayakgugu3796
@snehashisnayakgugu3796 8 ай бұрын
best sir….please make some vdo for olympiad physics questions
@chawnneal3103
@chawnneal3103 2 жыл бұрын
Thanks so much, like some of the others my first question out of curiosity was, okay T1 = T2 w/o friction, but what if we wanted to solve with T1 and T2 and what justification lead to the initial T1 = T2! Specifically what mathematical model lead to T1 = T2 as I understood their (frictionless pulley) statement was telling us they were simplifying some model! Anyways thanks so much for this video! I'm going to checkout your other video, you allude to, about the derivation!
@DrBenYelverton
@DrBenYelverton 2 жыл бұрын
Thanks for watching - yes, always good to question where these assumptions come from!
@tasneemkt4797
@tasneemkt4797 2 жыл бұрын
Nice problem! Can you do a similar problem where the pulley can rotate meaning it has a mass m and some radius r and the rope has mass too? 😅 And what's the condition for the pulley doesn't slip?
@DrBenYelverton
@DrBenYelverton 2 жыл бұрын
Thanks. It gets a lot more complicated if you want to include all three effects (friction, massive rope, and pulley rotation) as you need to set up an equation of motion for each element of the string. I think I tried this a few years ago and ended up with a differential equation that couldn't be solved analytically!
@arunkumarmamidala5685
@arunkumarmamidala5685 Жыл бұрын
​@@DrBenYelvertoncan we do in matlab
@shafin3365
@shafin3365 2 жыл бұрын
Respect from Bangladesh 👍
@Jay-hh4ul
@Jay-hh4ul Жыл бұрын
Sir as we've already considered m2 > m1 the inequality should be 1≤ m2/m1 ≤ e^πu
@DrBenYelverton
@DrBenYelverton Жыл бұрын
We assumed m₂ > m₁ at the beginning for simplicity, but for the final result we need to take into account the case where m₁ is larger. In fact, m₂/m₁ can be less than 1 with the system still in equilibrium, and by symmetry you'll only get slippage in the opposite direction if the mass ratio falls below the reciprocal of e^πμ.
@rtheben
@rtheben Жыл бұрын
Good exercise, but that is a strange pulley, normally one would thing that the pulley has a moment of inertia and can freely rotate and also you have no slippage of the rope to the pulley. In that setup one can calculate all dynamics and when you eventually get slippage or not
@LuizPoublan
@LuizPoublan 9 ай бұрын
What's the condition for the system to be moving with a constant velocity? Or that's impossible to happen?
@zdiac3255
@zdiac3255 Жыл бұрын
Interesting problem! But don't we assume system to be at equilibrium while deriving capstan equation? but clearly here rope is not at equilibrium, so is the equation still valid?
@DrBenYelverton
@DrBenYelverton Жыл бұрын
Well, it depends on our modelling assumptions. If we can neglect the mass of the rope, ΣF = ma becomes ΣF = 0 and the derivation of the capstan equation still applies. If not, then you're right and you need to apply Newton's second law to each element of the rope to come up with a new, and more complicated, equation of motion.
@aadih.n3438
@aadih.n3438 2 ай бұрын
hello why isn't t1>t2?
@innovativeskyline9946
@innovativeskyline9946 4 ай бұрын
It's a very good video
@DrBenYelverton
@DrBenYelverton 4 ай бұрын
Many thanks!
@nacicelik1954
@nacicelik1954 2 жыл бұрын
Does the system slipping or not slipping , does pulley turning?
@DrBenYelverton
@DrBenYelverton 2 жыл бұрын
In this example the pulley isn't turning and the rope is slipping over it.
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