6 Pulley Problems

[@inkandfubble816]

Five years later and you're still helping struggling students like me! Thank you so much for your work.

[@shirazqasmi5090]

Please don't delete this video. It'll help a lot of people. Your teaching style is awesome!

[@nathan6798]

You just cured my life time phobia of pulleys and FBDs. Thank you.

[@Fahimsy3d]

Literally the best video ive seen on pulleys.

[@PenandPaperScience]

Yeah, it's really good :)

[@JohnVKaravitis]

Scare to think that there are people out there who live for KZbin vids re pulleys.

[@notreallydavid]

You can scrub 'literally' - it isn't doing anything. Please kick me. All best.

[@cortwill4085]

​@@notreallydavid, shut up, your being rude! @#$&!

[@umarmuzammil7332]

I agree

[@generalkickass9237]

Love the way you explain and speak . These little things help ALOT

[@opufy]

You must be adored by your community, need more ppl like you in this world

[@shutupimlearning]

honestly a lifesaver man, i look at problems like these and think "theres no way i can solve this". Thanks for the video!

[@HasibAlRashid]

Undoubtedly a masterclass and literally the best video for pulleys on the internet. I can't find words on how to thank you mate

[@AnnekeFleming-qy5dy]

Thank you so much!! This video has finally helped me understand pulleys after months of hitting dead ends while studying for the MCAT

[@abdelrahmanmohammed3561]

Thank you very much. This is such a systematic and organized way of thinking and solving.

[@PhysicsNinja]

Thank you for the kind words! I greatly appreciate comments like yours

[@corndawg5197]

You are amazing. I was strugling to understand this concept and you just explained it so well I didn't have to watch the full video. Thank you man.

[@CARNAGE25]

You have no idea how much this has helped me. I've been having problems with multiple pulleys like those in problem 5 & 6 and I have national exams in a week! While watching this video, something clicked and I was able to calculate everything myself perfectly without looking at your calculations. Thank you sir, I really appreciate this.

[@aspectratio4388]

Thank you so much teach, this really helped me to comprehend pulley problems way better now. Especially how the use of a pulley can help with lifting big weights. Amazing video and explanation!

[@Nick-xf6ck]

Why the best people are so under-rated Respect for you sir❤❤

[@ludi1787]

THIS VIDEO HELPED ME A LOT , COULDNT UNDERSTAND WHERE EACH FORCE COMPONENT CAME FROM BUT NOW I KNOW , THX SO MUCH

[@bellt4682]

this is soo good it makes me wanna cry.....helped a lot and i have a test tomorrow tnxxx

[@mariadragonbreath7130]

Your video made these pulley problems so much more understandable and simpler! Thank you so much for explaining the solutions clearly and in an organized way.

[@ashnadodd9054]

Thank you for this video, you explain this concept so clearly and simply!

[@PhysicsNinja]

Glad it was helpful!

[@yosefsisay4878]

you save me from fail physics exam fail thank you so much !

[@tirthpatel_1356]

Bros a saviour to the society kudos to you

[@subat9349]

Just wonderful. Easiest way for solving the pulley problems..watching from BANGLADESH

[@menglimarrero4296]

I like the animation. the lecturers intonation is not sleepy to hear. Very well explained how and why

[@Zavenge]

This video actually helped me understand pulleys better than my own class. Thank you so much!

[@NaginisFate]

Thanks a lot man, even if I am from totally different field and trying to get another job which involves physics, I am getting the hang of these pulleys, slopes etc. thanks to you. Appreciate it

[@PhysicsNinja]

You can do it!

[@andywong4382]

I have an AP physics exam in 30 hours, 20 MCQs and 3 FRQs. I feel invisible to any pulley problem.

[@taranidhubhghaill]

you are a lifesaver, idk why my lecturer won't explain the steps but now I know ty king

[@PhysicsNinja]

You got this!

[@blockybunny]

Thanks you man you are best from all our indian teachers You explained it very easily

[@PhysicsNinja]

So nice of you

[@Tchaikovsky391]

Thank God for you. My teacher hasn't explained any of this.

[@calebtourangeau9777]

you have no idea how much you saved my grade. tysm!

[@noonecandefeatme7866]

You can find acceleration easily by this trick Here : Net Force on the system / Total Mass of the system Tho you can't find the tension. Btw great video 👍

[@Pro_gamer69420]

thank you soo much for this explanation, I couldn't understand my teachers explanations at all, but thanks to this I have been enlighten.

[@Uygʻun-q2c]

The best explanation I have ever seen, thank you bro

[@PhysicsNinja]

Thank you so much!

[@fatimaarif8392]

May god bless you physics ninja. this had helped me a lot in solving past papers.

[@adityajha4936]

Of what???

[@fatimaarif8392]

@@adityajha4936 physics

[@adityajha4936]

@@fatimaarif8392 Hmmm

[@fibremurugan]

The best video for pulley questions 💯💯

[@SISKCERTWaJaVlogs]

pully problems were my kryptonite in physics class but with your videos, this helps resolves it keep up the great content

[@ravichandimal9417]

U ve got the art of teaching man...❤

[@hamida.1054]

Great method. I used to be afraid of choosing downward as positive y-axis. Now I am not. Great job!

[@PenandPaperScience]

Being brave enough to be flexible with your coordinate axes is a crucial skill to have in mathematics and physics :) It oftentimes reduces problem's difficulty enormously.

[@numberone6955]

@@PenandPaperScience you good

[@PenandPaperScience]

@@numberone6955 :D

[@bhuvneshbhaskar2431]

​@@PenandPaperScienceikr it would feel like a silly fear but as a beginner we all have been through these phases

[@galaxi6585]

Thank you so much, my school uses these models all the time and this will help massively

[@gamalkamel5487]

i've been looking for a video like this for hours you're a lifesaver

[@JenniferPChung]

omg thank you for explaining is so simply and not skipping your train of thought!

[@PhysicsNinja]

Glad it was helpful!

[@AbdurRahman-wo7ro]

honestly , the best pulley video on the platform ... mister it will more useful if you have explained the x y direction and cos thing more in depth 👍

[@alitr-tf1dc]

how can you not like this video, this man is awesome💙

[@riisastudent]

after struggling from 2 months to understand this concept it is finally clear. as a student preparing for neet this is an amazing vid to clear your basics and are there faster methods to calculate the acceleration cause i gotta solve it under a min anyways thank you for the lovely vid

[@CaliCity10]

This is such a good explanation that you now have a new sub.

[@keishakwok4333]

@Titus Solomon these sites don't work

[@dankastik6477]

Thankyou for the short and sweet explanation ! Do you have a full explanation of this Topic?

[@jayt675]

who would not like it. you are very helpful. Thanks alot

[@PhysicsNinja]

You're welcome!

[@mayurpol]

Please upload more videos for also other topic it very helpful sir liked it

[@afrinahmed1620]

I liked your channel to make the total number of likes divisible by 3 made with three consecutive natural numbers including the smallest of the set. I liked then when this happened. For thinkers the number is 123 which I liked and made for his video. I am an IIT JEE aspirant and these problems I did in my first basic paper solving of nlm for pulley mass systems during my preparation. Edited to say thank you for helping me refresh and revise a bit. I am still preparing and hope to get selected the next time. Please pray for me😊

[@rahulsharma9671]

Bhai aapka JEE ka exam ho gya??

[@holgerg3824]

Hi, I appreciate your ways of solving those problems. However, I think, the question a) of Example 5 is a bit imprecise: You ask: what is the force for lowering the weight with constant speed of 2 m/s and your answer is m/2*g. The answer is principally correct because a=0 and v=const. But, if you apply this force, nothing would move, if I assume that tha weight was at rest. So, you first have to decrease this force to a value lower than m/2*g to produce an acceleration. Then the weight is accelerated from v=0 to a velocity different from zero. If the speed of the weight has reached v = 2 m/s due to this acceleration, then you can change the force to m/2*g and now v=const=2 m/s. In numbers: If you apply a force of m/4*g then the acceleration is -5 m/s^2 and it takes 0.4 s to reach v=2 m/s. If you apply 80% of m/2*g= 0.4*m*g, then a = - 2 m/s^2 and it takes 1 second to reach v=2 m/s.

[@mattspence5963]

Man you are a life saver. I have been acing calc 2, but I was struggling so much with pulleys lol

[@PhysicsNinja]

You got this!

[@daphnecuevas3776]

Not to be dramatic, but I have been crying for the past 24 hours, petrified of failing my physics exam because none of my study material was making sense to me till i found this video. I cant thank you enough!!!!

[@PhysicsNinja]

You got this!

[@In_studies_I_am_like_RM]

That was the best explanation!

[@PhysicsNinja]

Glad you think so!

[@In_studies_I_am_like_RM]

@PhysicsNinja I have a question..in two pulley prblm ..if we pull the string with force F then wouldn't the tension forces be in opposite directions?

[@jelly1761]

I really enjoy physics but the time that it was taking to figure out every single concept was concerning as my teacher is a bit... unclear? Finding your channel has given me hope in not dropping the entire subject! :) Thank you!!!

[@pessexe8591]

Sir your voice is so cool! I can hear it all day🛐

[@afrinahmed1620]

You can also include the infinite pulley problems and the concept of equivalent mass.

[@YnaDayuha]

Thanks for the video it really helps me understand p6

[@PhysicsNinja]

Glad it helped

[@Player-pj9kt]

Thank you so much I had difficulty understanding tension and this video cleared it up

[@chilukurileelavathi749]

Sir, your are great In my class room ,I am responding in good way why because I am listening your class Thank you sir

[@MrPabodha]

Amazing videos. Really helps to recall the concepts. Thanks a lot. In problem 5a, isn't it better to state constant velocity?

[@Hackers-wrld]

You can feel the Tension between the blocks in his vohhice great video.

[@SatyamNautiyal-c1o]

understood all the concepts clearly thank u very much 😄

[@kusumareddy3115]

This channelll is underrated ✨ wish a few billion subscribers ahead! 😌

[@chloe-jw6nt]

thank you!!!!! these questions were the exact ones in my paper!!

[@tda8649]

I have a physics olympiad in 2 days and this really helped understand pulleys :)

[@PhysicsNinja]

Good luck! You’ve got this

[@adityajha4936]

Is it good for International Olympiads???

[@ganizanijosephy7873]

One of the best tutors 🔥 🔥

[@xbz24]

please dont delete this shit, still strong in 2024

[@ibrahimabbas3728]

Thank you so much for this video sir. I was struggling with these types of questions for a long time, I’m solving ib past papers that have to do with pulleys and I’m finally getting it.

[@yasmeenibrahim7104]

May Allah bless you and your family this is sooooo helpful

[@MulengaMutale-np6nc]

Thank you so very much may God bless you sir

[@umarmuzammil7332]

Wow all pulleys in one place helped a lot

[@williamgriffith2822]

The best video i have ever seen on pulleys, appreciate from brazil

[@spaceeDolphin]

Your explanations made it so easy to understand these concepts, thank you so much!

[@shobharani76]

Thank you for clear visualized explanation

[@aarohinuniwal7087]

Thank you for such a great explanation!!

[@manfredvonrichtofen3863]

Thank you so much, this video is very helpful!

[@nisalmasathmalee1217]

Superb Explanation !!!

[@spartaatrus5302]

Sir thanx u for helping; importantly the last question is such hard problem I appreciate it ❤

[@PhysicsNinja]

So nice of you

[@ashfa4558]

This is soooo helpul cause its free

[@tshepangmashapa4415]

Thank you very much Great explanation 🤝

[@omrmmmdzad6849]

T1 not= T2, because in the past we've been assuming that the tension in the rope is uniform everywhere. In this problem the rope is not slipping and the pulley is not massless, the tension is not constant in the rope. The tension depend on the mass. If Mass1 > mass2, tension 1 > tension 2 in the rope.

[@adityachandrasingh615]

❤️ from india 👍 fabulous video it clear all my doubt

[@wiktoriaklimczak7775]

good explanations, just wish you added the force of frictions as well.

[@faisalali2001]

Alternatively, you could treat it as one big object and directly add up/subtract the masses, ignoring tension for these problems. Lil shortcut to get to the same equation for a. Then pick a block to solve for T

[@clashofmagicofficial256]

Can't understand why you have only 17.9k subs only

[@PhysicsNinja]

I think that quite a lot for a physics channel. Thanks for the the support. I'll get there.....eventually.

[@AE-ix2iz]

Awesome video I have a question. Regarding question #1, if the bigger block is rendered immovable, is the tension on the rope the same as if it were moving?

[@modelhunt9873]

You're a genius mannn.. ❤❤

[@WritersDigest-b8f]

I like your teaching of physics. Could you cover problems from various aspects of physics with an aim to perfect mechanical comprehension. Improving mechanical comprehension through problem solving in physics would be a huge motivation to contnually learn physics. This approach would stick physics principles in mind and prompt the mind to question what why where how and reach the right conclusion. Thanks

[@natevegh4602]

Awesome video. Thank you!

[@you2uber530]

Great explanation. Thanks for posting.

[@user-oas]

I think making the equation for 6a be mg-6F=0 would follow the pattern of how you solve the other problems better

[@aradhyagaur9691]

Thank you brother. I am in 11th grade and your explanation is good. Kindly bring us some high level problems. BTW, all problems were pretty simple.

[@Arivarasu-o3i]

nice video man thanks a lot

[@PamelaBoshtani-pt7gm]

Can you help me with this problem:In a container of negligible mass, there are 100 grams of water at a temperature of 80 degrees Celsius, 150 grams of water at a temperature of 10 degrees Celsius are added. After the thermal equilibrium is established, a piece of ice at a temperature of -25 degrees Celsius is added. Find the temperature of the water before adding the ice. , the heat needed to melt the ice, the final temperature of the water in the glass.

[@panch2oo2]

Awesome 👍 thank you so much for all the work you're doing 😌

[@selamalemayehu6212]

You really helped dude Thank you so much🙏🙏

[@NamanSinha69]

This was better than my class. Thanks for the video Sir

[@ahmedkadry7717]

Thank you so much for this video!! It's really helpful ❤❤❤

[@salih3191]

4:20 why did we Substracted the weight from the tension how did we know that the weight is bigger because it might be the other way around because the inertia of the first object is bigger then the second object so the tension force would be bigger then the weight

[@re1ive456]

He defined the downward direction as positive, and since the mg vector is downwards (positive) and the T vector is upward (negative), the equation is mg -T = ma (which can also be written as -T + mg = ma).

[@nayrasadawy2098]

now this is a masterpiece 🌟

[@parvathi7779]

Please share video on blocks and springs