9:30 AM - RRB JE 2019 | GS by Neeraj Sir | Forces and Laws of Motion

[@swapniljain3378]

Awesome session by best faculty. Agar aisa physics koi 12th mein padhata tho hum 12th mein top marte, Thank u sir. Today's ans is: (C) 0.20 m/s

[@hanshlal9027]

Sahi kha Maine bhi 12th me ratta padhai ki agar aisa pdhane wale milte to kamal ho jata

[@praveentiwari8969]

0.2 m /sec

[@hanshlal9027]

@@praveentiwari8969 0.2 m/s = 0.20 m/s

[@sarcastic_shubham]

Bhai ye 12th mai nahi hai 10th class ka hai

[@swapniljain3378]

@Shah ali Anwar Graduation ka hi kuch yaad nahi. Tho phir yeah kahan se yaad rahega ki 10th mein kya padha tha aur kya 12th mein

[@dream12325]

Recoil velocity= -(mass of bullet * velocity of bullet)/mass of gun Recoil velocity =(0.1*100)/50 =0.2m/s Thank you sir ☺

[@CopNirajkumar]

👍 😊

[@jeetkamal420]

0.2m/sec

[@AbhishekKumar-dz9xj]

m=.1kg v1=100 m/s M=50kg so, recoil velocity v2= -(mv1)/M => v2= -(.1*100)/50 => v2= -0.2 m/s - sighn shows opposite direction so, Recoil velocity = 0.2 m/s

[@changerwarrior6176]

Sir really really really you are physics God for me

[@aniketsavita9524]

0.2 m/s zindgi m pehli baar physics smjh a rhi h 😍

[@shivaysingh4712]

mee to

[@armyboy9822]

😁😁

[@didyouknow411]

😁😁😁😁

[@kumarawanish2076]

Yes sir 0.2

[@khushijha9732]

Sir ki clss ko like kro guys ..itni mehnat se padhate Hain sir .but like jyade ni hoti .views 62 k but like 3.8k ..🙄🙄🙄🙄 Plzzz like kro SB 🙏🙏🙏🙏

[@ajeetthakur3795]

HW Ans-.2m/sec sol^n- vel.of recoil =(mass of bullet×vel. of bullet)/(mass of gun) (.1×100)÷(50) =.2m/sec Ans.... Thanku for the adorable session 👍👍👍👍 Ans. 100% correct hai Thanku👍👍👍

[@paliwalsisters]

Sir u r great ..............itni mehnat se pdhate ho .......... thank you so so much..............puri wi fi family ko thanks itna ach platform dene ke liye sch me mja aa jata h pdhai krke 😍😍😍🥰🥰

[@TDHAR120]

0.2 m/s Sir ghaar jaisa education milta hain, isi liya to wifistudy ghar hain hamara💝💝💝💝, Neeraj Sir u are great sir.., aap bohot accha parate ho. Strength of materials se app ka class kar raha hoon. Love you sir

[@thedeviljudge5062]

Sir..u made physics subject very interesting

[@mindexercise-io8oy]

Bahut tagda physics padhate hai aap..... Thank-you

[@JitendraKumar-hc9vd]

Bahut achha se batate hai sir thanks

[@only_------3371]

Aapka lecherous dil ko chhu लिया sir ji

[@mayanksharma9007]

Ji Sir Aage Piche Hone Ka concept Samjh Aa gya 🔫 🔫 Gun Ka. Sir Gun ka...😊. Gun ka... HW----🔫 = 0.2 m/s

[@kundankumarsinha15]

Bahut bahut thank q sir apka padhane ka style dimag se sth dil Ko touch krta h .....

[@aruntopal]

0.2m/s sir.....I like the way of your teaching.... wifistudy provides best study content....❣️❣️.

[@RaniKushwah-p6q]

Aj tka science samja aya he nhi but app na inti celery se samajh jo ashni se samjha a jatha hai thanku so much ❤

[@santoshkumar6072]

Greatest teacher in India

[@rkvlogs7309]

Best teacher😊😊😊😊😊😊har question ka answer h inke paas🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏 Mujhe regret ho rha h ki mene mechanical engg kyu nhi ki inse aur padhne ka chance milta

[@shubhamdey5552]

Bht zyada achha explain krte h sir aap. Bht Helpful video h sir thanq soo much 🙏🙏🙏🙏😊

[@mukulsaini3592]

AP jaise AP teacher bdi muskil se milte h😍 gzb pdhate ho sir

[@swarabindhu5049]

Aapki teaching bahuth simple and understanding language me he sir😍

[@amitat369]

Thanks alot sir.Apke padame ne me alag hi class hai maja aa gaya👏👏👏👏👏👏👏

[@Mr.Sooraj]

0.2m sec ..super sir physics padhte time phele muje nind aati thi but sach m apki class leta hu tho aesa maja ata h jyese video game khel rha hu .thank you wifi team aesa techer diya

[@anamsaniya9164]

U are so enthusiastic sir, these videos are really helpful for understanding the concept.

[@electronics2311]

Y are baby for answer

[@amankumarkumar4444]

Hi

[@shalinimishra8346]

Ans... 0.2m/s..thanku so much sir.. 🙏

[@Shubhamgamingzone45]

Shalini Mishra what a sexy girl you are

[@visualart5256]

Sir phli bar physics achhe se samagh me aa rhi h great

[@royalking00779]

Rate of change of momentum agar newton 2nd law hai to phir impulse kya hota hai

[@Astonished_world]

ans is C 0.2m/s velocity of gun(recoil velocity)

[@krishanJangid1102]

*संवेग संरक्षण जो की गति के तीसरे नियम पर आधारित ह् उसके अनुसार M1U1+M2U2=M1V1+M2V2 {जहा M1 - गोली का द्रव्यमान और m2-बन्दुक का द्रव्यमान( without bullete} Ab शुरू में बन्दुक और गोली दोनों विराम में यानि U1=U2=0 तब संवेग भी शून्य अब बन्दुक से गोली निकलने के बाद M1=0.1kg. ,V1=100m/s or M2=50kg , V2=? 0.1×100=50×v2 V2= 10/50=1/5=0.2* meter/second❤️

[@kittuvedu]

Sir aap bahut achha padhte hai

[@poshettyerram1685]

Such a good teacher you are sir... 👌👌

[@tarunmathur550]

Gun recoil velocity C. 2m/s

[@nikhilsaxena7155]

Bhut hi jyada bhdiya sir thank you

[@amanaj1426]

sir bhot aacha pdate ho kitne dino bad aab concept clear hiua

[@mansuralam9237]

Sir ap ki samjane ki tarika ache he

[@tssameerff4735]

0.2m/sec. Sir ap bhut a6a explain krto ho mene apki fm ar som ka lacture dekha h love u for wifi study team

[@pushpendradix52]

Sir bhut acha AAP pdta hay

[@vinodbaghel9631]

You really teach very well sir.. And Deepak sir also

[@Mr-Farhan009]

0.2m/sec Love u sir bcz ur talented faculty

[@abhaymahto8468]

Ans - 0.2 ya 0.2 Hoga .

[@vivekdewangan124]

Abhay mahto .2 aayga bcoz - sign pratikshep veg ko represent krta hai...

[@tapaskumarpradhan1597]

Thank you Sir💓

[@vikasdeshmukh5919]

Velocity of the Recoil is, v2=mv1/M v2=0.1* 100 / 50 v2= 0.2 m/s.

[@8427023818]

Sir amazing way at physics reading

[@digvijayk805]

V2=-(M1*V1)/M2 Velocity of recoil V2 is 0.2 m/sec ...

[@dhirajyadav7244]

Sir aap bahut acha padate h plz pysics ke sare chapter detel me padaye

[@jaiswal929]

Thnq❤

[@AshokVerma-ji1mf]

Velocity of Recoll ♦ 0.2 m/s

[@sabenoorruhi2830]

suprb amazing bht acha pdhty ho ap

[@99179601229]

0.2m/s Very Great Teaching sir.

[@jjoy1818]

0.2 m/sec is velocity of recoil.

[@bhanupant4699]

Thanks a lot sir.... Your way of teaching and ur patience level... Great

[@Rahul_chauhan..]

Thanks sir 👌👌👌👌👌👌

[@reenasaini9238]

best way of teaching awesome,, 0.2m/s

[@ravipujari263]

Recoil velocity = 0.2 m/sec 🙏🙏

[@kisunminz6722]

Wah sir class kerne maja aa gya...Thanks aa lot sir..Ab physics easy lag rha h sir....Love u sir ji

[@akshaykhobragadevolg9294]

Best padate ho sir aap

[@OurRajasthan-zp1kt]

Awesome sir

[@virendrasinghpal737]

H.W answer.......0.2 m/s ................thnku soo much sir ji..........

[@sktutorial5665]

Really a very good session

[@gunjankumar7762]

U are the best sir...

[@srinu1990babu]

ur super and awsome sir ji quality education

[@param4978]

Q= A bullet is fired vertically upwards with a velocity of 196m/s. What is the maximum height reached by the bullet? (Assuming g=9.8m/s²)

[@sanjaykumarrekwal2208]

Thank you so much sir for all vedio

[@sabyasachisarkar7518]

V2= - mv1/M V2 = - 0.1×100/50 V2 = -1×100/500 V2 = - 0.2 V2 = 0.2 ms-1

[@kalpanashekhar2067]

Superb session sir u r great & ur teaching way 🙏🙏 ans of HW is 0.2 m/s thanku sir💕💕

[@ranjeetgihar9505]

Hi

[@abhitiwari30]

Bahan hai tumhari...izzat do...yaha to loyal raho atleast .....selection ke lie discipline must hai ....thumb rule hai

[@sanghmitrasinghbaghel7520]

Recoil velocity 0.2 m/sec.. thanku

[@educationforbettertomorrow9139]

People who are giving dislike need to think once, as they are working hard to make things better

[@buddhipedawat6029]

WiFi study is the good platform to the preparation for government job Thanks WiFi study faculty

[@rajendrajidodiyar81]

Supppperrbbb sir....👌👌

[@preetiverma7540]

Homework answer: -0.2 m/ sec

[@dailylife4.3m2]

I have same ,,-0.2 ,,but no option 😕

[@inlimit20]

@@dailylife4.3m2 areee deewane negative sign recoil ke liye hota hai.... Aur questn mai phele se recoil bola hai,... Isliye option mai negative nhi hai 🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼

[@priyashiny3626]

🙏🏻🙏🏻🙏🏻 guruji

[@pawanmeena8182]

Recoil velocity = 0.2 m/s

[@shalinikarmakar803]

0.2 m/s ans...u r my fav...

[@manshisinha_heath_care983]

superb session sirr

[@sharuk3545]

sir momentum not always conserved. momentum is conserved when no external force applied on body.

[@vijay_laxmi_dhanka]

So good sir ji

[@IMRANkhan-xi7ox]

Recoil velocity =.1*100/50=.2m/s

[@Rahulchoudhary-zz5qd]

Excellent

[@roushanpandey5136]

Maza aa rha hai sir padhne me..

[@deepaliyadav8926]

Thank u sir H.W Ans- 0.2m/s

[@santukaran4507]

Excellent session sir 🙏🙏🙏🙏🙏🙏

[@KuldeepRana13]

Schedule of classes is nice

[@Sourav-RoyChoudhury]

Best faculty of science..

[@theoddone4491]

Power of Mechanical engineer Neeraj sir 😎😎

[@62santoshkumarpandit87]

VERY SUPERB SIR 🙏🙏

[@subratkhuntia1481]

Nice session.Thank u sir.. Ans- .2 m/s.

[@Rajaramdas_rj2212]

V2=0.1×100÷50 =0.2 m/s Thanku sir Best teacher@wifistudy❤

[@ashokraj4303]

Sir saath me dimensions formula bhi Bata diya kariye Please 🙏🙏🙏🙏🙏

[@rohitdake9673]

Home work ka ans sir 0.2 m/s Thanks sir nice session...

[@harishchandrarajbhar7182]

V2= 0.2m/s

[@pawanwaldia2943]

Kaash live pad pata aapse sir

[@syksuccessmy6985]

Very....................................................... good

[@satyaverma6814]

0.2m/s hoga sir thank you nice session

[@KK-ch5lw]

Sir plz make a playlist of your physics videos.

[@mdrofficial6627]

V2= -.2m/s were -( minus ) represents recoil

[@akashkumarsahu2996]

0.2m/sec ans hoga Very interesting class

[@ANANDRAJMOTIVATIONAL]

V2 = 0.2m/sec

[@ProudlyIndian01]

.2m/s Rocket conservation of momentum k concept p kaam karta hai yeh question cbt 1 me aya tha kash phle padaya hota aap ne

[@chourasiya.shikha]

Thanks sir Ans is c. .2m/s

[@minakshikumari2781]

0.2m/sec is recoll velocity