Work and Energy : Definition of Work in Physics

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[@jayanta375]

1) Force= 5N Displacement=150 cm = 1.5 m Work= Force x Displacement =7.5 J/ Nm 2) Work done is 0 when the angle between the for and the displacement is 90 degrees. 3) Work is a scalar quantity because it doesn't have distance but only magnitude. Thanks for the tutorial really helped! :)

[@brenzkimseysabado1675]

If I'm not mistaken, you can't change KG to N. Since the given is 5 kg, you will convert it to N, where N=((kg)(m)/(s^2). And F=mg. Where you will use the gravity in this situation. W=Fd F=mg F=(5kg)(-9.81m/s^2) F=49.05N Substitute, W=(-49.05N)(1.5m) W=-73.575Nm or -73.575J

[@kjkj841]

@@brenzkimseysabado1675 I do not believe the work done by the boy is a negative value since the boy lifted the book in the direction of the displacement. The work done by gravity would be negative since it is opposite of displacement. Have to be careful to know who, or what is doing the work. Yes, gravity is doing work in this problem yet that is not what was asked.

[@preetianweshaparamanik8118]

​@@brenzkimseysabado1675 yaa you're right! And since this is a 9th grade topic, you can use g=10m/s², it'll be easier So the answer actually is just 75J

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[@ItzDevil-nk3ry]

1) 75 J (Taking g=-10m/s^2) 2) Work done is zero , when force and displacement are perpendicular to each other 3) Scalar Quantity

[@mangadiary9782]

the first one taking g as 9.8m/s^2 is 73.5 J

[@SRINIVASsrinivas-yh4ld]

❤

[@chaitalikurmi4498]

Mass (m)= 50 kg Displacement(s)=150cm=>1.5 m Work Done(w)=F.s. W= 50*1.5 = 75J

[@Dr.HemendraSolanki-r6c]

Q1.Since mass and lifting i.e corelate with force of gravitation.g=10 SO,formula for work = mgh(m =mass,g=forceofgravitation,h= height or displacement) W=5kg^10^1.5m (150÷100=1.5m) W=75 joule or 75 Nm Q2.Work done is zero only if force is perpendicular to the object or when the angle between force and displacement is zero. Q3.Work is a SCALAR Quantity because it has magnitude only not direction. 😌Hope you all understand through my answers ,if your answers are wrong then do practice as it make the person PErfect💯 From 🇮🇳🇮🇳🪷🇮🇳🇮🇳🪷🇮🇳🇮🇳

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Try to get used to using 9.8 for gravitational potentil strength

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[@ayushkumar1183]

Thankyou sir The answer of the questions 1.75 J (5*10(accelaration due to gravity= 50 mass we have to convert 150 cm to meter which is 1.5 meter work=force*displacement 50*1.5=75J)) 2.When the force and displacement are perpendicular to each other 3.Work is a scaler quantity

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[@churchboy4609]

Great video! I would like to add something to this lesson though...at around 7:33 you teach something that everyone says when they teach this unit, that since the arm that's holding the bag has to resist gravity, then *all* the force HAS to be going straight up, so there can't be any work acting on the bag. My issue with that is we know the bag gets pulled to the side by the arm that's carrying it. Since there's a change in the motion of the bag, there has to be some force directing that bag sideways, meaning the angle isn't perfectly 90 degrees (maybe it's 89 degrees) and thus there is a small amount of work happening to kickstart the sideways motion. Ultimately, this isn't really going to change much about the calculations on the system, but as a student I always found the answer of "you don't do work after lifting the object" satisfying, since we're moving the object forwards. The work done wouldn't even be very large, since (if the object was going at a constant speed, meaning no acceleration or net force) it would be the momentum of the object keeping it moving forwards, not the work your arm does, but this clarification would probably satisfy students more, and tie in several different units for discussion in class.

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Work is a scalar quantity

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1)7.5J 2)when the direction force and displacement are perpendicular to each other 3)vetor quantity

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Q1) -75 J Q2) When the Q is 90°. When force is equal to zero and displacement is equal to zero Q3) It is a scalar quantity

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Did you use g= -10?

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You are correct only but that is .75J

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I got Q1) 750

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Q1 = 75 J

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(Answer of Q1) The minimum force applied by the boy is the weight of the box. Weight=mass X gravity =(5 X 9.8)N=49N As the force and displacement are in the same direction,we can use the formula Work=force X displacement =49N X 150cm =49N X 1.5m=73.5J (Answer of Q2) Under the following conditions, work done is zero ---- 1) When the force applied is zero, the work done is also zero. 2) When the displacement is zero, the work done is zero. 3) When the angle between the force and displacement is 90 degrees, work done is zero. (Answer of Q3) Work is a scalar quantity.

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How do you get 49

[@GAINEDITZ18]

@@onimolebolanle5740 f=ma Mass=5kg Gravitation (acceleration due to earth)=9.8m/s² m*a=5×9.8 F=49N

[@03alyanurul92]

the formula for Q1 isn't F.S.COS 180 DEGREES [-1]? cause that's the gravitational force which is in the opposite direction right? so cos 180 degrees

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[@dibakarchakrabarty7717]

Q1: -75J Q2: when F & S mutually perpendicular each other. Q3: Scalar quantity Sir, You are mind blowing teacher and thanks for the video.

[@hetvi9639]

isn't the first answer 7.5? like 150/100?

[@ghostrider1527]

@@hetvi9639 yes its 7.5J

[@mahamhamna6118]

@@hetvi9639 when you'll multiply 1.5m to 50N , it will be 75J.

[@Mascot17]

How to find acceleration?

[@supriyachintha9725]

@@Mascot17 Acceleration a= 9.81 m/s2 approximately 10m/s2. F=mxa=5x10=50N.

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1 - 5*10*1.5 =75joule 2- when force and displacement make 90 3 vector

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thanks sir for helping us well when we come to the question 1, 75 J 2, the angel is equal to 90 degree 3, Work is scalar physical quantity

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Yes, - 7.5 joule q2 at right angled q3 scaler quantity

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1)7.5 J 2) when force and displacement are perpendicular to each other 3)work is a scalar quantity

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1)-7.5

[@lubnanazneen1445]

-7.5J

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