Work Energy Theorem: Block on a Slope

[@JohnGPagani]

I took "Statics and Dynamics" during summer school at college in 1980. An eighth week intensive summer school program. All the professor's work was on a black board. White chalk only. (1) I enjoyed the pace of your presentation; AND, (2) I enjoyed your graphics.. Thank you.

[@normalperson8066]

You can get the same answer using law of conservation of energy potential energy initial + kinetic energy initial - non conservative force = potential energy final + Kinetic energy final

[@zakwanarif]

Now I understand how to use this method properly. When I checked on other KZbin video, they tend to neglect the work done by gravity when working on inclined plane problems like this. So I'm getting confused. Anyway thank you very much!

[@shadowkxm]

Perfect explanation. Appreciate it heaps!

[@PhysicsNinja]

Glad you liked it!

[@jaydenktan3548]

Excellent applications

[@rubenvegas7926]

I used mechanical energy, where the top had 0 KE and the bottom had 0 PE Ei+Wf=Ef where Wf is work done by friction 0.5mVi^2+mgHi+(-fk)=0.5mVf^2+mgHf where the initial kinetic energy and the final potential energy are 0, and fk is friction. Masses cancel, multiply 2 to the left hand side and square root it Sqrt(2[9.81*0.5-9.81cos(30°)*0.15])=Vf=2.92 m/s

[@yipyiphooray339]

why only Wf? What about the work done by gravity?

[@rubenvegas7926]

@@yipyiphooray339 E initial is the total mechanical energy at point A and B. On both sides i have MGH for the final and initial heights

[@panch2oo2]

I also used energy theory E (i)= E (f) MgH= 1/2 MVf^2 + Fr D 3×10×0.5= 1/2×3×Vf^2 + 3.89×1 V f= 2.72ms-1

[@rubenvegas7926]

@@panch2oo2 I think I forgot to zero one term out, otherwise our formulas are the exact same

[@davidalbigensechilengi]

Great

[@yerimirey]

You kinda made everything too complex more than what is necessary. But still, good video.

[@yipyiphooray339]

Subscribed!!

[@fizixx]

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