Work = Fdcos(theta) Everything you need to know about Work formula Physics

[@ajaysrivastava1012]

one of the most simple and informative videos about work.... exellent efforts

[@phrenologisto]

Not only is this series one of the best explanations of the foundations of physics/science I've ever seen, it also features the only time "no pun intended" has ever been used correctly and appropriately. EVER. Truly exceptional work! Cant thank you enough and will share!

[@leekelly4574]

I agree. And I love the insane amount of times he undid his drawings hahaha

[@mitchellcummings758]

im impressed by your ability to circle and undo everything you are referring to so quickly!

[@thefreegamer7928]

You are amazing ! One of the quickest and best explanation I have ever watched ! Keep going man !

[@alphajgdiff]

chuckled a bit when you said "no pun intended" LOL great video and thanks for the help. currently trying to watch every relevant vid before my mcat :)

[@widjadija]

your tablet REALLY wants you to know you can undo your paint stroke. all jokes aside, this was a great video. thanks so much for the help.

[@Patywak89]

Hey quick question. So since there was a resistant force while the force it being applied wouldn’t that mean we have to do 20J extra in order to move it those 10 meters? So why wouldn’t it be 120J of work done to over compensate for the fact that there’s 20J being pulled opposite direction?

[@Patywak89]

H R ^ sorry forgot to tag u

[@widjadija]

Patrick Horn the 2N in the negative direction doesn’t affect the work done by the 10N in the positive direction. The -2N slows down the box’s movement, but the 10N doesn’t need any additional force to keep moving. So whether the negative force was 1, 2, 4, 9, or 9.999, the work done in the positive direction will always be 10N x 10 m = 100 J. Of course, if the negative force is equal to or greater than the positive force, the direction of movement changes, and work will either not be done or will become negative. The only thing that changes is the net force and, therefore, the speed the box will move. But work done isn’t dependent on time or speed, it’s just dependent force and distance. So the best way to think of work for an individual force is to isolate each force as if no other forces are present, then use F x D = W. Hopefully that clears it up a little. It’s sort of difficult to explain the concept without showing you a diagram with arrows and numbers

[@Patywak89]

H R thank you that makes sense. Regardless we’re told that 10N is performed. So the 2N will take away from the 10N rather than the person changing their force. I guess it would’ve been 120J only if they asked like how much would have to be done in order to move the object at the same speed if 2N of resistance is applied in reverse

[@leekelly4574]

came to the comments for the undo part hahahhaa

[@Weere_the_great]

This is the best explanation I could find on youtube. Thank you!

[@Afrah-n9y]

The best explanation ever😊

[@artgonesavage]

This was the best explanation for that cos theta formula😂🤯🤯💥💥💥

[@graceugochukwu3831]

Love your videos!!

[@WernTheDRUID]

Thank you again, youre the best for these

[@mrwizard4708]

i like when he says negative. good work work man keep it up

[@marianmaea.ordeniza2166]

THANK YOU SO MUCH IT'S REALLY EASY

[@goddessdiaries8642]

You are the best. Am ready for my test now

[@sakshikumarikumari1971]

Perfect teach of the formula

[@jonasalia2066]

thank you so much!

[@rahulhalder6117]

He was in 🔥 All doubts have found the way to hell!!!!!?

[@darthkillhoon]

Lot easier than reading from a text book

[@adolfobaltodano3075]

Thank you very much!

[@micahlaquindanum4814]

You kinda sounds like sheldon from bigbang theory

[@smokeyxmovez2377]

It sounds like he is on speed

[@imosdefinite]

nah that's just genius @ work

[@tamikadiggs840]

Can someone tell me how the hell he got 5N? I thought 60/10=6, therefore it would be 60J.😕

[@petals3091]

10cos(60) = 5 Since we want to find out the force in the horizontal direction we would do 10(hypotenuse) * cos(60) which would give us the adjacent aka force in the horizontal direction

[@RDW1216]

too much repetition man

[@rebekahjohnson329]

Nah it helps the info to stick

[@patrickfazeli7514]

@@rebekahjohnson329 i agree i love the repetition. please don't stop doing that!! that's how i learn

[@graceugochukwu3831]

thats the best part!