one of the most simple and informative videos about work.... exellent efforts
@phrenologisto Жыл бұрын
Not only is this series one of the best explanations of the foundations of physics/science I've ever seen, it also features the only time "no pun intended" has ever been used correctly and appropriately. EVER. Truly exceptional work! Cant thank you enough and will share!
@leekelly4574 Жыл бұрын
I agree. And I love the insane amount of times he undid his drawings hahaha
@mitchellcummings7587 ай бұрын
im impressed by your ability to circle and undo everything you are referring to so quickly!
@thefreegamer79284 жыл бұрын
You are amazing ! One of the quickest and best explanation I have ever watched ! Keep going man !
@alphajgdiff9 ай бұрын
chuckled a bit when you said "no pun intended" LOL great video and thanks for the help. currently trying to watch every relevant vid before my mcat :)
@widjadija4 жыл бұрын
your tablet REALLY wants you to know you can undo your paint stroke. all jokes aside, this was a great video. thanks so much for the help.
@Patywak894 жыл бұрын
Hey quick question. So since there was a resistant force while the force it being applied wouldn’t that mean we have to do 20J extra in order to move it those 10 meters? So why wouldn’t it be 120J of work done to over compensate for the fact that there’s 20J being pulled opposite direction?
@Patywak894 жыл бұрын
H R ^ sorry forgot to tag u
@widjadija4 жыл бұрын
Patrick Horn the 2N in the negative direction doesn’t affect the work done by the 10N in the positive direction. The -2N slows down the box’s movement, but the 10N doesn’t need any additional force to keep moving. So whether the negative force was 1, 2, 4, 9, or 9.999, the work done in the positive direction will always be 10N x 10 m = 100 J. Of course, if the negative force is equal to or greater than the positive force, the direction of movement changes, and work will either not be done or will become negative. The only thing that changes is the net force and, therefore, the speed the box will move. But work done isn’t dependent on time or speed, it’s just dependent force and distance. So the best way to think of work for an individual force is to isolate each force as if no other forces are present, then use F x D = W. Hopefully that clears it up a little. It’s sort of difficult to explain the concept without showing you a diagram with arrows and numbers
@Patywak894 жыл бұрын
H R thank you that makes sense. Regardless we’re told that 10N is performed. So the 2N will take away from the 10N rather than the person changing their force. I guess it would’ve been 120J only if they asked like how much would have to be done in order to move the object at the same speed if 2N of resistance is applied in reverse
@leekelly4574 Жыл бұрын
came to the comments for the undo part hahahhaa
@Weere_the_great3 жыл бұрын
This is the best explanation I could find on youtube. Thank you!
@Afrah-n9y28 күн бұрын
The best explanation ever😊
@artgonesavage3 жыл бұрын
This was the best explanation for that cos theta formula😂🤯🤯💥💥💥
@graceugochukwu3831 Жыл бұрын
Love your videos!!
@WernTheDRUID2 жыл бұрын
Thank you again, youre the best for these
@mrwizard47082 жыл бұрын
i like when he says negative. good work work man keep it up
@marianmaea.ordeniza21662 жыл бұрын
THANK YOU SO MUCH IT'S REALLY EASY
@goddessdiaries86423 жыл бұрын
You are the best. Am ready for my test now
@sakshikumarikumari19713 жыл бұрын
Perfect teach of the formula
@jonasalia2066 Жыл бұрын
thank you so much!
@rahulhalder61173 жыл бұрын
He was in 🔥 All doubts have found the way to hell!!!!!?
@darthkillhoon2 жыл бұрын
Lot easier than reading from a text book
@adolfobaltodano30754 жыл бұрын
Thank you very much!
@micahlaquindanum48144 жыл бұрын
You kinda sounds like sheldon from bigbang theory
@smokeyxmovez23774 жыл бұрын
It sounds like he is on speed
@imosdefinite2 жыл бұрын
nah that's just genius @ work
@tamikadiggs8403 жыл бұрын
Can someone tell me how the hell he got 5N? I thought 60/10=6, therefore it would be 60J.😕
@petals30913 жыл бұрын
10cos(60) = 5 Since we want to find out the force in the horizontal direction we would do 10(hypotenuse) * cos(60) which would give us the adjacent aka force in the horizontal direction
@RDW1216 Жыл бұрын
too much repetition man
@rebekahjohnson329 Жыл бұрын
Nah it helps the info to stick
@patrickfazeli7514 Жыл бұрын
@@rebekahjohnson329 i agree i love the repetition. please don't stop doing that!! that's how i learn