Worked example: Determining a rate law using initial rates data | AP Chemistry | Khan Academy

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Helped so much!! Doesnt make sense that I pay thousands for tuition, only to come to Khan Academy to learn for free!

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absolutely right! going to donate a huge amount after I grow up

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thank god for khan academy. The tutoring service, Study Edge, at UF is crazy expensive and I was worried that i would fail my exam just because I can't afford it but Khan Academy is helping soooooo much.

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This is what I don't like how education has a price!

[@RealEverythingComputers]

Awesome tutorial! Way more simplified explanation than textbooks!

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Even after 8 years, this channel is underrated

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may be 9 😊

[@Sir_Lloyds]

Brilliantly articulated 🤝🏅🔥

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Wow this was so helpful 👏

[@shahed6010]

this was very helpful thank you Khan

[@Malika296]

fucking brilliant mate. this was a life saver

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Thank you for your help!!

[@vanessaescalera4117]

wow. this is what was went over in 2 lectures. saving my grade!!!

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that is amazing

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Khan academy videos are always the best! Thank you!

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Too bad I cannot use a calculator on the MCAT

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Thank You 😎

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THANK YOU!!!!!

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no u

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thank you

[@opufy]

7:27 RIP, my teacher would dock marks with a big smile for saying ".005 M" for sig figs because it's supposed to be "0.0050 M"

[@Bulbasauros]

For u lazy bois out there u can do ( ln ((r1/r2) ) / ( ln ( [1] / [2] ) ) [ ☆ ] Concentration 1 and 2 is for experiment 1 and 2 not other substance r stands for initial rate Make sure the concentration of the other reactant stays the same and this will give u the order of reaction without any thinking necessary

[@parkerr_88]

just saved me ass, its 7am and i have a quiz on this today 😭thanks so much

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I love y'all

[@VIXU_GAMING]

Tqq sir

[@spyfish981]

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[@zekeskulski7146]

Anybody know where I can get some sample problems?

[@marciewalters143]

Zeke Skulski Do you have a text book? Usually in the chapter there are practice problems.

[@boySomebody98]

hey, isn't 250 * 0,012^2 * 0,006 = 2,16*10^-4 ? (the answer to the last part of exercise)

[@kaonesebonego2510]

KvotheTheVegan Its to 2 decimal places

[@breathinginfood]

I love you.(sobbing)

[@nadeemakhtar3886]

What if we get a fraction?

[@coolguy3513]

God bless

[@coolguy3513]

God bless again (exam edition)

[@monikakhobragade1062]

Hi, if we arent given the experimental data how to determine the orders and can you give an example of methane and air order of reaction order of oxygen

[@crossfadez5521]

that was just amazing man, seriously you should charge us for these stuff.

[@aliceofei2813]

omg thank you sm! this made 0 sense to me in class lmao

[@mohamedalalami8936]

BRO thank u i couldn't understand my **** professor.

[@Jennieve_]

Is it possible to get the rate constant if one of the concentrations was never kept constant

[@PonzooonTheGreat]

I had a question where my rate constant units were mmol^(-5/2) L^(5/2) s^(-1) How do I change this into the sensible mmol L^(-1) s^(-1)??

[@dazzlelight711]

what do you do if the rate determine step is the second step?

[@CassieGrey21]

What if you get something like k [Y]^ x [Z]^ y? The data gives me 2^x = 2.5. Then x would approximately be 1.322 to get 2.500 on the calculator. If I end up with k [Y]^ 1.322 x [Z]^2, would the order of Y be 1.32 or 1?

[@KM-wb1yd]

omg Can you be my chemistry prof please

[@missmak559]

Asalam-O-Alaikum.....thank u sooo much......but.....isn't there anyway to find the order of reaction without experimental values???

[@JTurn916]

There is not

[@hammedyusrah4912]

Please you did not make use of the temperature

[@sarakazi9451]

But what if we have no rates to compare to?

[@salemalmuhairi4284]

:)

[@vanessaescalera4117]

exactly why i donate lol

[@rosegold2969]

Speak louder!!!!!

[@timcook3410]

aderinsola abayomi clean your ears!!!!!