Y−Parameters (Solved Problem 1)

Network Theory: Y−Parameters (Solved Problem 1)
Topics discussed:
1) Step by step procedure to calculate the Y-parameters of the given two-port network.
2) Conversion of Z-parameters to Y-parameters.
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Axol x Alex Skrindo - You [NCS Release]
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[@user-nw2of1xh9s]

Underrated Channel, Amazing and clear explanation. Go ahead Sir.

[@kapilumrania]

You're god sent sir!!

[@ravisumanthmuppana8383]

The video is really informative .. Change the playback speed to 1.25x and thank me later

[@Priyajit_Ghosh]

bruh, I am in 2x speed

[@100courses7]

Sir, U make the problem-solving look so easy. Amazing job sir. Honestly, your channel is underrated.

[@soar_hub]

Thanks so much for your lessons!

[@VAISHNADEVIGECEUG-]

NICE AND DETAILED EXPLANATION SIR THANK YOU SIR

[@sirjantudu7553]

thank you so much for clearing doubts

[@venkatramansampath]

Thank you Sir for the video

[@divyarao6280]

After redrawing the circuit. We can use a short cut sir as it was a T network.... name the resistors as Ź a, zb and Zc...now Z parameters will be Za+zb Zb Zb Zb+Zc

[@meerashende9470]

Whats about -ve sign

[@meerashende9470]

How he gave -z12 n 21 we don't take like this whil calculating adj.

[@vijayavardhantuntu5449]

Super Teaching sir ......Amazing ✨

[@srisaiteja9375]

Love u sir 💜 from vizag

[@avethakur9198]

We can also solve this problem by applying KVL in delta loop in circuit to obtain value of i' in form of i1 and can put it in our z parameters equations

[@basarrimon3301]

Yess

[@avijitdeyelectrical1551]

please sir upload more numerical problem on z , y parameter, h hybrids

[@nitishkumarprajapati6096]

Thanks Sir 😃😃

[@rupayansahaakapglucifer598]

The method shown is good but very lengthy. If you can convert this star network to delta or pi network and then directly using the short circuit admittance therom it will very easy and short

[@knoxxcruise6939]

Can we use I1=Y11V1+Y12V2 and I2=Y21V1+Y22V2 I

[@SarveshGupta-bu5ho]

Sir how to solve problem for capacitor and inductor

[@nani2543]

Directly we can solve through nodal analysis right ?

[@ganeshrajjoshi7559]

how can i solve if there is capacitor instead of 10ohm and 5ohm resistor

[@securitynandhmoni1553]

Which reference do you used🤔 please ,give a name

[@user-st9rw2vi3s]

I am getting Y11 = -Y21 = 31/260 and Y21 = - Y22 = 33/260

[@sharmachavali]

sir for the above problem if we have delta connection of capacitor how to solve it sir ?

[@syedameenali7361]

Can we convert the inner star to delta and apply kvl?

[@starkendeavours7072]

yes you can, both are convenient though.

[@syedameenali7361]

@@starkendeavours7072 thanks 👍

[@abhinavkarn5090]

After changing from Delta to star......what happened to those 10ohm and 5 ohm resistors

[@AcchuRocky]

All 3 resistors in delta is converted into 3 resistors in star form.. hence 20, 10, 5 ohms are disappeared to those 3 resistors..

[@rachitmittal448]

Sir can we solve the problem using KCL Equation? If we assume lower terminal as ground. Then V1 and V2 will be voltages as upper terminals. 20 ohm resistor between v1 and v2. T Network of other three in v1mand v2. We can assume A as intersection. Write KCL at 1,2,A.

[@theaerogirl]

I got the same idea. Can`t we do that?

[@UBUBYUTSE_REVIVAL_TV]

Real answer are: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12

[@sazidabintaislam2676]

In Z12 and Z21, how did get - sign?

[@levinraj2404]

its matrics rule

[@venkattelugumusic472]

Thank you so much sir for your explanation mind blowing my doubt was cleared in jntua question paper the Z paramaeters are given but find y- Parameters like addmittence my mind is not working to see the question,after seen this video it's easly iam solved.thank you bro for these video 👌🙏🎇🎆😍😍

[@-MEET--mv1eb]

Sir why whole current i2 will flow through 5 ohm only I think i2 will be divided into two branches initially through 5 ohm and 20 ohm

[@rishabhprasad8333]

Same doubt

[@avinashingle5491]

Sir pls provide transient topic of network which is most imp

[@tanyashankar9966]

can anyone please explain why can't we calculate simply y parameters simply from the circuit and not through the inverse process?

[@happysingh6586]

i think we can do that also by using kirchoffs current law and write current equations

[@UBUBYUTSE_REVIVAL_TV]

Me I calculated by using circuit for addmittance without using impedance and I get the same answer. as follows: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12

[@biswadeepchakraborty2460]

can we solve it directly using eq of Y parameters?

[@JaspreetSingh-er2qr]

same doubt i have

[@karthikvenkata6484]

I am getting different answers as Y11=0.025,Y12=-0.015,Y21=-0.025,Y22 =0.035

[@UBUBYUTSE_REVIVAL_TV]

Real answer are: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12

[@anshumanmishra4172]

Guys the best method is not this it is to use nodal analysis and directly obtain the Y parameters

[@nesoacademy]

This lecture is not about the best method but the conventional method. This solution is important to set the tone for the upcoming lectures.

[@hansrajbagaria794]

Sir why can't we take current(I2") through the 20 ohm resistor as : I2"= (V1-V2)/20. ??? Problem becomes very easy using the value of this current(I2") in terms of V1 and V2. I solved and got almost same answers not exactly the same. If anybody can tell my method is right or wrong? Thanks

[@yashmahalle5675]

Forget everything and use mesh analysis

[@yashmahalle5675]

Don't get complicated, use mesh analysis to calaculate current.

[@vinayadharsh9488]

genco and transco exams 1minute to solve the answers how will be time sufficient and with out calculator.

[@sumitsinghietlucknow7104]

Sir please make video on MATLAB

[@rickjljr11]

>> z1=10 z1 = 10 >> z2=20 z2 = 20 >> z3=5 z3 = 5 >> Ya=1/z1 Ya = 0.10000 >> Yb=1/z2 Yb = 0.050000 >> Yc=1/z3 Yc = 0.20000 >> Y=[Ya+Yb, -Yb; -Yb, Yb+Yc] Y = 0.150000 -0.050000 -0.050000 0.250000 >> Zs=inverse(Y)+40*ones(2) Zs = 47.143 41.429 41.429 44.286 🙂

[@syedismail1849]

🔥🔥🔥

[@theoldgamer3643]

13:32 / 13:53

[@abinokselvin]

Wheree did I²' & I²'' go

[@ranjithk1877]

Ok

[@s.m.senses7199]

🙏❣

[@prakharpandey7062]

For delta to wye connection, refer to this video: kzbin.info/www/bejne/bZ_TYpdrmt9kntU

[@fyesilyurt]

Bu çıkmaz

[@kishoreperam5162]

Sir,after getting Z values, can't we get Y parameters just by reciprocal of Z values