Zener diode & Zener breakdown | Class 12 (India) | Physics | Khan Academy

[@saisriharshagriddaluru9261]

I don't know why...I wanna name him MR.SKYROCKET..great explanation bro!

[@asmakhatoon6691]

TRUEEEE

[@snehaprasanth9139]

🙌🔥

[@nehaha7208]

Thanks a lot, for explaining so well I've been looking through many videos to clear some misconceptions . Now I'm on cloud nine 😇

[@meetrajpopat2348]

i'm student i don't have that much money to donate but in future i will came back to donate you thats my promise! Thank you for explanation and can you please make indian engineering video for basic electronics

[@HimanshuKumar-kz8rx]

Did you keep your promise?

[@architgupta5258]

This is the best explanation ever given by any sir or mentor..u r the best thanks a lott

[@jimtripathi]

Ohh man, you're genius it's really fun to know more stuff when you explain it.

[@aseelbasalem6083]

Amazing explanation. Thank you so much for your time.

[@_rtdp_]

A playlist on quantum mechanics plz 😭..... I'm asking because your explanations are fabulous....

[@abhinand9010]

Exactly... we need.. 🙏

[@ayeshaazmat230]

yes please

[@nainay3129]

Great explanation. Arigatou Sensei ❤️👍

[@lharsh175]

Great demonstration, everything was so smooth.

[@bharatchoudhury3383]

Sir ,tunneling 🤯🤯🤯 please make a separate video on it.huge fan🤑

[@annyman4743]

real dude

[@angelojacobo4302]

God, that is so clear than the tens of websites I read

[@nagarmalsharma9992]

I would like to voluntarily donate some money to mr. Mahesh shenoy, is there any way i can do that? I am a parent.

[@KhanAcademyIndiaEnglish]

Thanks a lot for this wonderful comment. It made my day :-). Yes you can donate to Khan academy from the link below. www.khanacademy.org/donate

[@a.pal_yt2018]

I love Mahesh and Ram sir. They both helped me to clear Board exams and olympiads with ease.

[@vidyapeeth.3514]

😢😢​@@KhanAcademyIndiaEnglish

[@_samin2566]

U can do that in his own channel float head physics

[@aswithasai4015]

No other channel in the you tube can explain better than you sir . Thank you so soooo much

[@tanashreekirpal7907]

I am preparing for neet and your videos are clearing all my doubts in semiconductors!! Thank you so much buddy!❤️

[@Itsanas2277]

How did it go?

[@sciencespectrum3855]

No one can explain like him😃

[@MS-eb8ps]

I am in awe. Thank u so much

[@d-01-moyukhdas57]

Can i get any source of where these things are thoroughly explained with much more details? The physical interpretation surely feels surreal.

[@shaikrafiq9498]

Superb👌👏👏👏👏👏👏👏👏🙋‍♀️

[@shabbirahmad7015]

Way better than my teacher in allen

[@vinayjangra1401]

💀💀

[@verysimplephysicsinthamil1436]

Sir, Really fantastic

[@dollyvaishali6464]

Thanks a lottttt ...I didn't understand it in my 12th, in bsc...I was so frustrated..but atleast I would die peacefully that I understood the concept..i wish my teachers would have explained like that or I had had sense before to watch your video 6 years before..still better late than never....THANK-YOU..KEEP TEACHING KEEP ROCKING❤🎉

[@apnvlogs7641]

dont know how to appreciate this

[@prakhargupta1409]

Truly amazing ! Thank u very much Khan academy !

[@abhijithas9976]

Thanks. I am looking for this for long time ......

[@ismatararoksana8088]

You are a great teacher.

[@varshinilolla3090]

4:29 So is the potential difference(voltage) across both the depletion layers the same? That is, even after heavily doping the diode, the depletion region has the same number of "space charges" except they are concentrated in a much "narrower" width? Or is it that due to increased diffusion current (which corresponds to the "rate" of majority charge carriers), more space charge is present in the depletion layer?

[@mitrasen2295]

Thanku so much sir it was amazing explanation

[@harshitkumarpandey8749]

Great explanation Fabulous

[@musicforever9020]

verywell explenation,love it

[@vikas1093]

This is the best explanation of the effects i have come across. Thanks!

[@navinuilangakoon3510]

great explanation thank you very much.

[@Hino_55]

Great Analogies! Thankyou SIr Mahesh!

[@starstudio143]

❤ Amazing explanation ❤

[@chimmyjimin9088]

Excellent teaching Thankyou so much😇

[@matinnezami378]

Thank you very much for your explanation one question? If the field of the discharge region in the zener diode is stronger than the normal (pn) diode, then why do we have only 0.7 V potential drop in the direct bias of both diodes Zener diode field is stronger so we have to apply more voltage in forward bias to overcome it

[@hugocampos7894]

Bruh... the graphics are so pretty... love it

[@baldaniyaniesh5041]

Greatest one..............,👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌

[@lavanyak2208]

Simply awesome😊

[@sharpmouse3013]

awesome, the quantum tunneling part was well handled

[@shaikrafiq9498]

Tq

[@niranjan7457]

Sir I have a doubt In Zener diodes, there is a very strong current flowing in the depletion region (as the depletion region is very small) 1. So the strong current in the depletion region is not caused by the voltage that is being supplied to it, right? 2. What is the purpose of reverse biasing it? Why not forward biasing? (It must conduct electricity very heavily, right? Because of an already small depletion region which is created by forward biasing, and if we dope it now, it will conduct much more) 3. Why should we even bias the Zener diode, if the current caused in the depletion region is not due to the voltage supplied, and removing the voltage supply (stopping reverse bias) will only aid in the process, since the reverse bias is causing the depletion region to become bigger, and if remove the voltage supply, won't the depletion region become smaller, and hence a much stronger current will flow through it. (Because lesser the depletion region, more thecurrent flowing through the depletion region, right?)

[@VersaceUnderwear]

i have roughly read this comment and have to say that, we dont want high currents passing by forward biasing, we have conductors for that

[@Kannan-c2h]

Purpose of a zener diode is to generate more current due to movement of minority charge carriers under reverse bias condition. That's why we don't apply forward bias. Depletion region becomes small due to dopping... The concentration of positive and negative ions increases so that... Electric field also generated. The purpose is to make diode to conduct more electricity under reverse bias condition then.. Why we have to apply forward bias...?. Then its right that the flow of charges is independent of voltage inside the depletion region outside the depletion region it is necessary to supply voltage because the minority charge carriers have to move across the barrier(depletion region)thats why we apply voltage . Dopping is inversely proportional to width of depletion region. Thats why the depletion region reduces not because of forward biasing and voltage supply would not interupt the width because due to strong electric field. There is no possibility to widen the depletion region width.

[@AvgUtubeWatcher]

Electric field is the slope, pd is the diff in height which is same

[@HariharanSekar-yy1wz]

Really good explanation. Looking forward to more videos.

[@sciencespectrum3855]

Amazing explanation 👏🎉

[@jainilsiroya]

Fabulous explanation

[@shasirekhasahoo2335]

Great explanation....

[@pranayborkar4021]

Thank you!😊😊😊😊😊😊😊

[@imsonecka]

amazing job

[@reetichauhan355]

@Khan Academy India - English why did you say the probability of a free electron knocking off another bound electron is less? If the width of depletion layer is less, then the ions will be more in that space( as also see in the diagram above) or will be tightly packed, so probability should be more....??

[@divstfuidonthaveaname7583]

The contributing factor here is the number of silicone atoms ,, number of p and b atoms are very low as compared to silicone,,,, P.s. --in zener diode number of doped atoms per unit volume is more ,, but the structure is same they are not tightly packed in the second scenario.

[@literallyfantastic2144]

Sir you explained great but please tell next time " Why small width of zener diode gives high electric field ? " with respect to V = fE * fr.

[@NiladriSarkar-fm6ot]

Awesome

[@livinglife3352]

Sir, Is it depletion layer is smaller then tunneling takes place and if depletion layer is bigger then tunneling won’t takes place?

[@shristiha8748]

I m just sad i didn't come across this earlier

[@vedprakashsinha4380]

Thanks bro

[@beinghuman1036]

Superb

[@girishdeshpande6843]

Sir won’t the glowing electron at 6:30 just REPLACE the electron which you said is DISPLACED from its position ? As we know when 2 objects of the same mass collide elastically and one of them is at rest, the their velocities get swapped. Here the stationary object is under the influence of a force(Lies in Si valence band) hence it should further lower its chance of just escaping out from the stable octet, and even if it does, the approaching glowing electron must readily replace it under the pretext of completing the octet. If what I argue is true then there should be no extra current generated in the depletion region...

[@thanjavurvlogs1307]

What is the software you use to create this

[@susmithatalupula9791]

Do electron and hole pairs develop outside the depletion region

[@yash_693]

I know it's late still - They do but they instantly recombine.

[@arnavgarg2466]

Yes recombination of electron hole pair takes place

[@malanihome2121]

I didn't know about tunneling

[@padakutamatar7077]

im scared that i'll fall in love with physics and eventually will wants to be a physicist then a doctor 😢jkk

[@spyzvarun5478]

Is the current in RB not affected by doping? (The saturated current)

[@wasaykhan5903]

sir plzzzz can you explain photo diodes

[@TAkash-ek3lx]

Why this avalanche effect and zener breakdown occur in forward bias

[@thamotharans2106]

If the current would exist above I (max) what would happen?

[@reetichauhan355]

@Khan Academy India - English I didn’t understand how electric field itself can “pull” electrons out..?

[@munsaffkhan617]

Why not ? Simply electric field will exert force on electron n due to strong force of attraction than the electron have in bond it will result into breakage of covalent bond and electron comes out.

[@r4k481]

this video was not in order .... I hope ... It mustbe just after Avalanche BD

[@parth6982]

How is the slope electric field

[@m17gaming51]

That's a V-I graph(Volt - Current). In normal conductors ,the speed of current depends on volt (i.e. More Volt Higher flow of current, less volt lower flow of current). But in this semi-conductor ,the voltage is limited even though u give higher amount volt all because of the property of the material. So, when u reach a certain volt, the flow of current peeks like anything(but do remember the volt is stable and stops at a certain point).

[@nihilisticboi3520]

The graph is a V-x graph (Volt - Distance). Here, the slope at a point will be dV/dx. This dV/dx is defined to be the magnitude of the electric field. The electric field is, in fact, a continuous gradient of electric potential.

[@aspirant8485]

Please join pw you are a gem of a teacher

[@dabluyadav1662]

Please make all video in hindi languge

[@phasorsystems6873]

If anyone could test this app i'd be grateful! Bump into androidcircuitsolver on google

[@shreyash5037]

Forced accent...why?

[@nagarmalsharma9992]

Obsession with accents.... why?

[@anktmshr]

@@nagarmalsharma9992 Sounds annoying and also leaves some quantum problem in understanding the topic. I don't understand …. why do we need to Khopy(copy) the Amerikhan(American) akhsent(accent)!!

[@girishdeshpande6843]

I think cause he is heavily influenced by SAL khan(don’t blame him for that) Notice his teaching style, his way of repeating the last words of a sentence is very similar to Sal sir...

[@p.harika]

Leave about the accent look at the way he is teaching. Have u seen such a KZbinr explaining concepts very clearly so that the student can understand very clearly

[@shaikrafiq9498]

Exactly

[@bsravani7298]

Tq very much sir very extraordinary explanation🎉

[@LOKANKSHASUKTELPHYSICS]

Amazing explanation