Yes

This video simply shows the principle, the idea. In another video I’m showing some simple uses of electromagnetic induction kzbin.info/www/bejne/bJfVZYmIaMt0q9ksi=9TiZDsZ7jNXobeZz

@@ibphysicshelp thank you. I am having trouble understanding how generators eill produce their current if the circuit requires switching in respect to the change in magnetic flux.

@gabrielware2777 the current generated with the setup shown here is called alternating current (a.c.). Many devices work just fine with a.c. Some need a higher or lower a.c. voltage (in such cases we use transformers to change the voltage). Some devices require direct current (d.c.) in which case we use a rectifier to turn a.c. Into d.c. (look it up)

@@ibphysicshelp thank you. Have been studying this for many years but when you dont do this stuff every day its incredibly easy to lose track of things. I 3d print parts and experiment with curcuits and have been trying to design a generator for a long time. I guess im stuck on the part where i need to, learn how to correctly wire my coils together, and then create a circuit where i can regulate the voltage and create a power source. I have a structure and parts printed out to test my experiments on, but am unsuccessful im producing a power source from the generator device

@@ibphysicshelp from my understanding. I need to really do the math. Fogure out what my output is after correctly wiring my coils. Then i need to learn how to calculate time constants and figure out how to create a "sine wave/ signal/frequency"? And doing so is Essentially " tuning" all of the components to operate with correct voltag and current?

Greetings David! I hope you are well.

Hi R.! Thanks! Hope you are well.

;)

Yes

If the circuit is open, I cannot think of an explanation for the discharge (I guess the air humidity cannot account for such a rapid discharge). When the a capacitor is discharged through a low resistance (for example a wire with almost 0 resistance) the time constant is very short and the discharge is almost instantaneous.

It usually refers to the specific heat of a container in which an heat exchange occurs. A calorimeter is a well insulated container. Let’s assume that you have a plastic cup (the “calorimeter”) and some water in it. Now let’s pour some hot water to make some lukewarm water. To find the final temperature of the mixture Ordinarily, you would consider only the heat exchange between cold and hot water (Q lost by hot = Q gained by cold). When the specific heat of the container is given a better equation would be Q lost by hot water = Q gained by cold water + Q gained by container. Or, in simple words, specific heat of a calorimeter is the specific heat of the material from which the cup is made of.

Îți îs interesting that the current has decreased. Initially I thought it was a short circuit due to damage to copper wire coating but since the current went down it is probably the battery used.

@@ibphysicshelp we are not using battery, We are using DC power supply. and we are operating this through motor driver IC.

@@ibphysicshelp Can this happen because of saturation?

It’s hard to say from a distance. I don’t know what exactly you mean by saturation in this case.

That is really hard to say. Probably trial and error is the way forward.

I think that either the electromagnet or the permanent magnet is way stronger than the other. You can have repulsion between the two when like poles face each other.but try to ensure that the bolt is NOT is contact with the magnet. Good luck!

@@ibphysicshelp Thanks, I had a suspicion that was the case

I’m not sure that I understand the question but yes, you can use the magnetic field of a magnet to induce a current in a coil moving/rotating relative to the magnet. But remember, you cannot create energy out of nothing. In fact, it does not matter how you get the magnetic field (permanent or electromagnet) as long as you move the coil relative to the field you can create an electric current.

@@ibphysicshelp ok as you say we cant get electric energy directly by this method, but in this situation i have mentioned in upper comment, may we convert magnet's force in mechanical energy, suppose electromagnet rod/shaft is free to move/rotate in magnetic field, finaly my question is that the output result(mechanical moving) will be dependent on what less powerful electromagnet or more powerful permanent magnet , or electromagnet use more and more power According to permanent magnet power(magnetism)

Conversion of mechanical energy into electrical energy is done in a generator (that uses a magnetic field). The reverse, electrical energy in mechanical energy is done in a motor (which also makes use of an electric field. You can have a loop of wire falling under the pull of gravity in a magnetic field and generate a current in the loop (also, a braking effect appears in this context)

Hi there. The answer to your question is not that straightforward.(I will probably do a video on this in the future). You can have the permanent magnet and electromagnet repelling (by choosing the correct direction for the current in the coil) but if the permanent magnet is much stronger, as soon as the magnet touches the iron core of the electromagnet it will re magnetised the iron core so it will produce attraction (in other words, once the strong magnet touches the core of the coil it rearranges the magnetic domains in the core in spite of the presence of the weaker magnetic field of the coil.)

Bună. Căldura pierdută de apă la răcire e de 3780 J. Cu valoarea acceptată pentru L e nevoie de 3430 J pentru topirea gheții, după cum spuneți. Apa provenită din gheață mai ia 691 J pentru a se încălzi la temperatura finală de echilibru. In total, căldura absorbită de gheață e de 4121 J. (Deci mai mult decât pierde apa aflată inițial în pahar! - ceea ce desigur, nu ar trebui să se întîmplă). Eu cred că aici factorul determinant e căldura absorbită de sistem din împrejurimi. Cu alte cuvinte, estimarea că gheata ar fi primit doar 3780 J de la apa existentă în pahar e o subestimare semnificativă. Desigur, e posibil ca și gheata folosită să fie in jur de -2 grade. In acest caz, caldura necesară pentru a o încălzi la 0 e doar de aproximativ 43 J.

Hi Dorin. That is an interesting question. I assume you’ve already watched my video on this topic. ( kzbin.info/www/bejne/f3W8qWR4n6mLsKc ). I used a relatively weak magnet so if the electromagnet has the right polarity then repulsion occurs even when the permanent magnet is is contact with the iron core. (See at 2:01 in video above). However, I can imagine that a strong neodymium magnet would “overwhelm” the magnetic field of the coil and would magnetize the iron core (I.e. realign the magnetic domains) so that it produces attraction after direct contact. I can’t check this right now (still on holiday :) but I will try the experiment with a neodymium magnet if I have the time (and even post a video if I find something worth showing). Assuming that my thinking is correct, you can “fix” the problem that you are describing by using a weaker permanent magnet or by increasing the current through the electromagnet. (Obviously, I don’t know the specific circumstances of your setup so be aware that a stronger current through the coil can burn it!). Good luck with your project!

Hello again. I can confirm your observation: I repeated the experiment but this time with a strong neodymium magnet. The coil and the magnet repelled each other when there was a small gap of a couple of cm but as soon as the neodymium magnet touched the iron core it magnetized it the other way and thus created attraction (magnet remained stuck to the core) The magnetic field of the coil is much weaker than the one of the magnet even for relatively high currents. Maybe I’ll find some time in the future to record a quick video update.

I’m afraid I don’t have that information. The voltage is several volts (5-10V). I would guess the current is a couple of Amps. The electromagnet was ready-made so I don’t know how many turns it has. Be careful when you make your own to ensure that the current is not too high to overheat or burn the copper wire.

Sure, will take care. Thanks.

First, try changing the direction of the current in the electromagnet (flip the terminals of the battery). If there is a change (repulsion) that means that you identified the poles of the electromagnet incorrectly (what you think is S is actually N). If there is no change it means that the electromagnet is probably not working and its iron core is attracted by both the N and the S of an electromagnet.

Yes after checking also its not working then i should again do the winding or change iron.

Absolutely! Make sure that the wire is thin and you fit as many turns as possible. Use enamelled copper wire (so coated with a thin insulation layer). You can use a small nail as the core.

The copper wire is covered with a varnish layer (a transparent, insulating coating). That is also the reason why the current flows through each loop and is not “jumping” across the loops to follow the path of least resistance. So the wire is not bare, it has an insulating layer.

Got it, Thanks for the reply.